第二次上机实验报告

1、西安电子科技大学软件学院面向对象程序设计课程上机报告班 级：131214学 号：13121398姓 名：文琬灵实验日期：2014年 5月 14 日第 二 次实验学号：13121398姓名：文琬灵一、实验环境1.软件环境：Windows, Dev C+集成开发环境 2.硬件环境：无特殊要求二、实验内容下面分题目列出上机实验的要求：题目1：写出一个类似“Hello，world！”的函数，他以一个名字作为命令行参数，并写出“Hello，name!”（其中name是实际的命令行参数）。修改这个程序，使它能以一系列名字作为参数，并对每个名字分别说Hello。 题目2：考虑：struct Tnode st

2、ring word; int count;struct treenode * left; struct treenode * right;写一个函数向Tnode的树中插入新的单词。写一个函数将Tnode的树打印出来。写一函数将Tnode的树按照单词的字典顺序打印出来。修改Tnode，使得它只存储一个到任意长度的单词的指针，该单词存储在一个由new分配的数组里。修改上述函数，使它们使用新的Tnode。题目3：写一个error函数，它取一个printf风格的包含%c,%s和%d指示符的格式串，以及任意多个参数。请不要使用printf()。使用<cstdarg>。题目四：写一个函数，实现

3、为5.913定义的Date加上一天，一年，一月的功能。写一个函数对于所给的Date给出对应的星期几。写一个函数给出Date之后的打一个星期一对应的Date。 三、源代码及运行结果针对实验内容及要求，给出各题目的源代码，并给出所用的输入数据和对应的输出数据。题目1：源代码如下：#include<cstdarg>#include<iostream>#include<string>using namespace std;void Print_name(const char *abc.) va_list ap; va_start(ap, abc); const ch

4、ar *s; cout << "Hello," << abc << " !" <<endl; while(s = va_arg(ap, const char*) if(s = "end") break; cout << "Hello," << s << " !" <<endl; va_end(ap);int main() Print_name("zhangsan","li

5、si","wangwu","chener","zhaoping","end"); system("pause"); return 0;题目1的运行结果如下（应给出输入和对应的输出）： 输出：Hello，zhangsan ! Hello,lisi ! Hello,wangwu ! Hello,chener ! Hello,zhaoping !题目2：源代码如下：#include <iostream>#include <iomanip>#include <cm

6、ath>#include<cstdlib>#define EQ(a,b) ( (a) = (b) )#define LT(a,b) ( (a) < (b) )#define LQ(a,b) ( (a) <= (b) )#define FALSE 0#define TRUE 1using namespace std;typedef struct treenode struct treenode * left; string word; struct treenode * right;BiTreenode, * BiTreep;void init_tree(BiTre

7、ep & root) root = NULL;int SearchBST(BiTreep & rt, string key, BiTreep father, BiTreep & p)/查找元素 if ( ! rt) p = father; return FALSE; else if (EQ(key,rt->word) p = rt; return TRUE; else if (LT(key,rt -> word) return SearchBST(rt -> left,key,rt,p); else return SearchBST(rt ->

8、right,key,rt,p); int InsertBST(BiTreep & rt, string key)/查找元素后不在树里，就加入 BiTreep p; BiTreep s; if ( ! SearchBST(rt,key,NULL,p) s = new BiTreenode;/(BiTreep)malloc( sizeof (BiTreenode); s -> word = key; s -> left = s -> right = NULL; if ( ! p) rt = s; else if (LT(key,p -> word) p ->

9、left = s; else p -> right = s; return TRUE; else return FALSE;void mid_order(BiTreep & rt) if (rt != NULL) mid_order(rt -> left); cout << rt -> word << " " ; mid_order(rt -> right); void pre_order(BiTreep & rt) if( rt != NULL) cout << rt -> word <

10、;< " " pre_order(rt -> left); pre_order(rt -> right); void behind_order(BiTreep & rt) if( rt != NULL) behind_order(rt -> left); behind_order(rt -> right); cout << rt -> word << " " int serach_tree(BiTreep & rt, string key) if (rt = NULL) retu

11、rn FALSE; else if (rt -> word = key) return TRUE; else if (LT(key,rt -> word) return serach_tree(rt -> left,key); else return serach_tree(rt -> right,key); int main() string val,s; BiTreep root; init_tree(root); cout << "Input the string you want to create a tree:" <&l

12、t; endl; /while(cin>>val) /if(val = "end") break; /InsertBST(root,val); / while(cin >> val && val != "end") InsertBST(root,val); cout << "Print the tree (pre_order):" << endl; pre_order(root); cout << endl << "order:"

13、; << endl; mid_order(root); cout << endl; system("pause"); return 0 ;题目2的运行结果如下（应给出输入和对应的输出）： 输出: Input the string you want to create a tree: 输入: efg ab hij cd end 输出：Print the tree (pre_order): 输出：efg ab cd hij 输出：sort： 输出：ab cd efg hij题目3的源代码如下：#include<iostream>#includ

14、e<stdarg.h>using namespace std;void error(char const *abc, .) va_list ap; va_start(ap, abc); for(char const *s=abc; *s; +s) if(*s != '%') cerr.put(*s); else switch(*(+s) case 'd':cerr << va_arg(ap, int);break; case 's':cerr << va_arg(ap, char const*);break;

15、case 'c':cerr << va_arg(ap, int);break; case 'f':cerr << va_arg(ap,double);break; /case 'db':cerr<<va_arg(t,double);break; va_end(ap);int main() error("%s %d %s %c %c %c","There are",3,"errors .nThe list of errors :n",'a'

16、;,'D','v'); cout << endl; system("pause"); return 0;题目3的运行结果如下（应给出输入和对应的输出）：输出：There are 3 errors . The list of errors : 97 68 118题目四的源代码如下：#include<iostream>#include<cmath>using namespace std;struct year_m_dint year;int month;int day;/struct year_m_d date

17、;int leap_day12 = 31,29,31,30,31,30,31,31,30,31,30,31;int not_leap_day12 = 31,28,31,30,31,30,31,31,30,31,30,31;int weeka7 = 7,6,5,4,3,2,1;int weekb7 = 1,2,3,4,5,6,7;int check_leap(year_m_d date);int check_year_m_d(year_m_d date);year_m_d add_year(year_m_d date);year_m_d add_month(year_m_d date);year

18、_m_d add_day(year_m_d date);int week(year_m_d date);year_m_d Monday(year_m_d &date); int main() int i; year_m_d date1,dates,datec;/必须要 有一个dates来将date1的值赋给它，否则调用函数输出的始终是date1刚开始的值 cin >> date1.year >> date1.month >> date1.day; if(check_year_m_d(date1) i = week(date1); cout <&

19、lt; "所给日期是星期:" << endl << i << endl; datec = date1; dates = Monday(datec); cout << "下一个星期一是：" << endl << dates.year << "年" << dates.month << "月" << dates.day << "日" << endl;dates

20、 = add_year(date1);cout << "加上一年：" << endl << dates.year << "年" << dates.month << "月" << dates.day << "日" << endl;dates = add_month(date1);cout << "加上一月：" << endl << dates.year &

21、lt;< "年" << dates.month << "月" << dates.day << "日" << endl;dates = add_day(date1);cout << "加上一日：" << endl << dates.year << "年" << dates.month << "月" << dates.day <

22、;< "日" << endl;else cout << "输入错误 ！" << endl;system("pause");return 0;int check_leap(year_m_d date)if(date.year % 400 = 0) | (date.year % 100 != 0) && (date.year % 4 = 0) return 1;else return 0;int check_year_m_d(year_m_d date)if(date.year &

23、lt; 0)return 0;else if(date.month < 1 | date.month > 12) return 0;else if(check_leap(date)if(date.day > leap_daydate.month-1)return 0;else return 1;/注意加上这一行和没有这一行的区别 else if(date.day > not_leap_daydate.month-1) return 0;else return 1;year_m_d add_year(year_m_d date)if(check_year_m_d(date

24、)date.year += 1;return date;year_m_d add_month(year_m_d date)if(check_year_m_d(date)if(date.month = 12)date.month = 1;date.year += 1; else date.month += 1;return date;year_m_d add_day(year_m_d date)if(check_year_m_d (date)if(check_leap(date)if(date.day = leap_daydate.month-1) if(date.month = 12) dat

25、e.month = 1; date.day = 1; date.year += 1; else date.month += 1; date.day = 1; else date.day += 1; else if(date.day = not_leap_daydate.month-1) if(date.month = 12) date.month = 1; date.day = 1; date.year += 1; else date.month += 1; date.day = 1; else date.day += 1;return date;int week(year_m_d date) int day = 0; for(int year = 1970;year != date.year;+ year) if(check_leap(date) day +=