版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领
文档简介
1、【飛行動力學】AIRCRAFT DYNAMICS成功大學航空太空工程學系Text book【Flight Stability and Automatic Control】 - NelsonReferences【Aircraft Dynamics and Automatic Control】 - McRuler & Ashkenas【Stability and Control of Airplanes and Helicopter】 - Seckel【Aerodynamics, Aeronautics and Flight Mechanics】 - McCormick【Automatic
2、 Flight Control Systems】 - Donald McLeanFlight Mechanics Course Content2A. Review of dynamics- Derive the basic governing equationof motion (EOM) of an aircraft- Decouple the EOM into a longitudinalmotion and a lateral motionB. Longitudinal motion analysis B.1 Static Longitudinal analysis and elevat
3、or angles for Level flight B.2 Dynamic Longitudinal analysis equations of motionAerodynamic derivatives dynamic analysisthe longitudinal dynamic (I) - Simplified longitudinal motions the longitudinal dynamic (II) - Complete longitudinal analysistC. Lateral motion analysis C.1 Linearization of the la
4、teral EOM C.2 Static lateral analysis C.3 Lateral-directional aerodynamic Derivatives lateral derivatives C.4 Dynamic lateral analysis eristics of lateral dynamics Appendix: Taylor series expansion of analytic function 13【課前預習】 - 請於下週上課前預習下列項目1. 基本動力學(I),有關牛頓運動定律的問題。2. 基本動力學(II),有關靜態穩定/不穩定以及動態穩定/不穩定
5、等的定義。3. 基本向量數學(I),有關一個旋轉座標中之向量的微分問題,如:假設為定義於座標之向量,而且座標之旋轉速度為,則對於慣性座標之微分定義為。4. 基本向量數學(II),有關向量外積的定義,如: 若及,則可寫為,因此。5. 基本工程數學,如常係數微分方程式之求解、線性函數之拉普拉斯轉換、等。6. 基本空氣動力學,尤其是有關翼面在流場中所受的力與力矩之關係,譬如:a.升力與力矩與流場之速度、攻角,以及翼面積、形狀,等的關係。b. Aspect ratio、Downwash angle、Aerodynamic center等名辭為何義?7. 基本自動控制學理論,如:a.所謂線性系統、轉移函
6、數、極點、零點、等之定義為何?b.何謂根軌跡設計法? 何謂一個系統之穩定邊限?A. Review of DynamicsDefine a coordinate system - Fixed in body: Axis fixed in body, right handed. Basic governing equations: The coordinate system thus defined is rotating at a speed , hence is a non-inertial frame. For any vector defined therein, its time der
7、ivative with respect to the inertial frame will be: . The inertial force, , is derived as follows: 1. The acceleration of the aircraft is given by 2. We can write ; hence, . 3. As a result, the inertial force of the motion can be written as follows:. Collectively, we haveThe inertial moment, , is de
8、rived next.1. The inertial moment of an aircraft can be obtained by differentiating its angular momentum with respect to time.2. The angular momentum of an aircraft is found by integrating, over the body, the infinitesimal angular momentum of the mass element spread over the aircraft. For the mass e
9、lement shown in the figure on next page, its angular momentum will be as follows:Note that is the position vector of , and is the linear velocity, of , due to rotation . The value of can be computed as: 3. Substitute this into , and we have: 4. The above vector cross product can be expanded into as
10、follows: 5. The angular momentum of the whole aircraft is found by integrating over the entire aircraft body, or: . 6. Expand into , this implies that:- Note that and are independent of position, hence are moved out of the integration. 7. We can recognize the following moments of inertia terms: and
11、the following product of inertia terms: 8. In general, the origin of the coordinates is at the center of mass and the aircraft is symmetrical right and left. Then, ; hence, . 9. We can now compute the inertia moment : a. - is a vector in a non-inertial frame. b. c. 10. Then, the following expression
12、s of the inertial moment result:. whereGoverning equations of motion of an aircraft.1. and . 2. and can be expanded into the following forms: and .3. As a result, the following 6 equations of motion are obtained: and4. A computable equation of motion will require expansion of and in terms of the sys
13、tem variables, , and their derivatives. This portion of work will constitute most part of this course.Decoupling of the governing equation of motion 1. Approximations on and of aircraft motion: a. The following conditions are mostly true for aircraft in general: b. As a result, some second order ter
14、ms of the equation become negligible, and the following approximations on and can be made: and is preserved in and is preserved in because they do not affect decoupling. We may also let to include , but it is often small c. Approximated in this way, the 6 inertial terms can be separated into two unc
15、oupled group of equations; each group of equations define a specific class of motion, termed the longitudinal motion and the lateral motion, respectively: Longitudinal motion equations Lateral motion equations 2. The uncouple phenomenon also apply to the components of and . Therefore, the subsequent discussions on aircraft motion will be done in two separate pa
温馨提示
- 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
- 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
- 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
- 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
- 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
- 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
- 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
最新文档
- 教育机构教师备课资源库教育方案
- 企业风险管理七项措施手册
- 航空货运物流流程标准化手册
- 销售业务接待与跟进流程手册
- 客户需求分析模板与服务改进方案
- 建筑工程项目管理规范与质量控制方案
- 人教部编版七年级下册回忆鲁迅先生获奖教学设计
- 第二节 排定次序-排序教学设计初中信息技术河大音像版2020八年级下册-河大音像版2020
- 2026年健康管理师(健康管理服务协调)自测试题及答案
- 第四章 光的世界 教学设计及反思 -物理教科版八年级上学期
- 天津市十二区重点学校2025-2026学年高三下学期毕业联考-语文试卷
- 2026年全国社会工作者职业资格证考试模拟试卷及答案(共六套)
- 公路危大工程监理实施细则
- 2026安徽省供销集团有限公司集团本部招聘7人笔试参考题库及答案解析
- 2026年山西药科职业学院单招综合素质考试题库及答案详解(基础+提升)
- 福利院食品卫生安全制度
- 5G通信网络规划与优化-课程标准
- 肾单位模型改进课件
- 茶楼劳动合同
- 中数联物流运营有限公司招聘笔试题库2026
- 高压线路新建监理规划书
评论
0/150
提交评论