Ansys计算温度场操作流程学习资料

1、精品文档精品文档Instruction of Ansys temperature field calculationQuestion 1: Consider an infinite (in one direction) plate with initial temperature T 0. One end of the plate is exposed to the environment of which the temperature is T e (III type boundary condition). Analyze the temperature distribution in

2、the plate during the period of 2000s.问题 1：考虑一个方向无限长的平板，初始温度为 T0，一段暴露在温度为 Te的环境中，分析 其在 2000s 内温度分布情况。Basic parameters基本物性参数Geometry几何： a=1 m, b=0.1 mo 3 o Material 材料： =54 W/m·oC, =7800 kg/m3, cp=465 J/kg oC· Loads载荷： T0=0 oC, Te=1000 oC, h=50 W/mSet Material Properties 设置材料属性 Preprocessor

3、| Material Props | Material Models Thermal: Conductivity: Isotropic KXX=54 Thermal: Density=7800Thermal: Specific Heat=465·oCJobname and directory settings设置文件名、存储路径 Menu | File | Change JobnameMenu | File | Change DirectoryPreprocessing前处理(1) Define Element Type定义单元类型 Preprocessor | Element Ty

4、pe | Add/Edit/Delete Add: Thermal Mass | Solid | Quad 4node 55精品文档Modeling 建模(1) Create Node 1 建立节点 1Preprocessor | Modeling | Create | Nodes | In Active CS No.: 1, (x, y, z) = (0,0,0)(2) Create Node 12建立节点 12 Preprocessor | Modeling | Create | Nodes | In Active CS No.: 2, (x, y, z) = (0,1,0)(3) Fil

5、l Between Node 1 and 12在节点 1，12 间填充其余节点 Preprocessor | Modeling | Create | Nodes | Fill Between Nds Number of nodes to fill: 10Spacing ratio: 1(均匀网格 )(4) Create Node 1324 by copying复制生成节点 13 24 Preprocessor | Modeling | Copy | Nodes | Copy Pick All 选择所有节点Total number of copies: 2复制 2 份(包含原先的 1 份) X-

6、offset: 0.1 设置 X 方向偏移量(5) Create Element 1 生成单元 1 Preprocessor | Modeling | Create | Elements | Auto Numbered | Thru Nodes Select 1, 13, 14, 2(with mouse)(6) Copy Element 210 by copying复制生成其余单元 Preprocessor | Modeling | Copy | Elements | Auto Numbered Pick All 选择所有单元Total number of copies: 11复制 11 份

7、(包含原先的 1 份)Node number increment: 1设置节点增量Applying Loads 加载(设置边界条件和初始条件)(1) Apply convention loads on Node 12 and 2在4 节点 12， 24 上加对流载荷 Preprocessor | Loads | Define Loads | Apply | Thermal | Convection | On Nodes Pick 12, 24VALI Film coefficient: 50 换热系数VAL2L Bulk temperature: 1000 环境温度(2) Set initia

8、l temperature(uniform temperature)设置初始条件(均匀温度) Solution | Define Loads | Settings | Uniform TempUniform Temperature: 0Solution求解(1) Set Analysis Type as Transien设t 置分析类型为瞬态分析 Solution | Analysis Type | New AnalysisTransient精品文档(2) Set solution controls设置分析控制参数Solution | Analysis Type | So'ln Con

9、trols”Transient” Label: Stepped Loading”Basic” Label: Time at end of loadstep: 10000; Automatic time stepping: on; Time increment: 10; Frequency: Write every substep(3) Solve求解Solution | Solve | Current LSViewing Results查看结果(1) TimeHist Postpro 时间历程后处理器Add data 添加数据 :TimeHist Postpro | Add data: Nod

10、al Solution: DOF Solution: Nodal Temperature:Variable Name: T1; Node 1Variable Name: T5; Node 5Variable Name: T9; Node 9Variable Name: T11; Node 11(2) List/Graph 列表 /作图Select the variables选择变量 :List data/ Graph data(3) Save image保存图片Menu | PlotCtrls | Capture Image: File | Save as(4) General Postpro

11、通用后处理器Select the data of certain time选择某一时刻的数据 :General Postpro | Read Results | By pickPlot the contour map of temperature distribution 绘制该时刻温度分布等值线图 :General Postpro | Plot Results | Contour Plot | Nodal Solu | Nodal Solution: DOF Solution: Temperature(5) Save image保存图片Menu | PlotCtrls | Capture I

12、mage: File | Save as(6) Animate 生成动画Menu | PlotCtrls | Animate | Over TimeNumber of animation frames: 100Question 2: Consider a solid cylinder with initial temperature T 0. The top surface of the cylinder is exposed to the environment of which the temperature is Te (III type boundary condition) and

13、the other surfaces are heat insulation (II type boundary condition). Analyze the temperature distribution in the cylinder during the period of 1000s.问题 2：考虑一个初始温度为 T0 的圆柱体，一段暴露在温度为 Te的环境中，其余界面视为绝 热，分析其在 1000s 内温度分布情况。精品文档Basic parameters基本物性参数 Geometry几何： r=0.025 m, h=0.05 mMaterial 材料： =25 W/m·

14、;oC, =7800 kg/m Mesh 划分网格Preprocessor | Meshing | MeshTool SmartSize(optional): Mesh: select the cylinder选择圆柱体精品文档, cp=500 J/kg oC·Loads载荷： T0=25 oC, Te=100 oC, h=100 W/m2·oCJobname and directory settings设置文件名、存储路径Menu | File | Change JobnameMenu | File | Change DirectoryPreprocessing前处理(1

15、) Define Element Type定义单元类型 Preprocessor | Element Type | Add/Edit/Delete Thermal Mass: Solid : Brick 8node 70(2) Set Material Properties 设置材料属性 Preprocessor | Material Props | Material Models Thermal: Conductivity: Isotropic KXX=25 Thermal: Density=7800 Thermal: Specific Heat=500Modeling 建模(1) Crea

16、te the cylinder model建立圆柱体模型Preprocessor | Modeling | Create | oVlumes | Cylinder | Solid Cylinder WP X: 0WP Y: 0Radius: 0.025Depth: 0.05(2) Adjust the view 调整视图 Right Toolbar | Isometric View精品文档Applying Loads 加载(1) Apply convention loads on the top在上表面加对流载荷Preprocessor | Loads | Define Loads | App

17、ly | Thermal | Convection | On AreasPick the top surface by mouse选择上表面 ( 用鼠标 )VALI Film coefficient: 100 换热系数 VAL2L Bulk temperature: 100 环境温度(2) Set initial temperature(uniform temperature)设置初始条件(均匀温度)Solution | Define Loads | Settings | Uniform TempUniform Temperature: 25Solution求解(1) Set Analysis

18、 Type as Transien设t 置分析类型为瞬态分析Solution | Analysis Type | New AnalysisTransient(2) Set solution controls设置分析控制参数Solution | Analysis Type | So'ln Controls ”Transient” Label: Stepped Loading ”Basic”Label: Time at end of loadstep: 1000; Automatic time stepping: on; Time increment: 10; Frequency: Write every substep(3) Solve求解Solution | Solve | Current LSViewing Results查看结果(1) General Postpro通用后处理器Select the data of certain time选择某一时刻的数据 :General Postpro | Read Results | By pickPlot the contour map of temper