习题答案最新整理

1、第五章习题5-1下面的程序运行后，(AL)=, CF=oMOV CL, 8MOV AL, 0NOT ALROL AL, CLCMP AL, OFFHJZ NEXTMOV AL, 0NEXT:答：(AL)二OFFH, CF=O5-2在下面的程序段中，“DEC CX”指令执行了次。MOV CX, 6JCXZ NEXTLI:DEC CXJNZL1NEXT:(A) 0(B) 5(C) 6(D) 7答：C5-3设有单字节有符号数X, Y与乙 如果X+Y200,贝I俅X-Z,否则求X+Z,运算结果存储在SUM字单元中。DATA SEGMENTX DB 120YDB 100ZDB 20SUM DB 0DAT

2、A ENDSSTACK 1 SEGMENT STACKDB 20H(?)STACK1 ENDSCODE SEGMENTASSUME CS:CODE, DS:DATA, SS:STACK1BEGIN:MOV AX, DATAMOV DS, AXXOR AH, AHMOV AL, XXOR BH, BHMOV BL, YADD AX, BX/注意这里用的是16位的寄存器，想想原因？CMP AX, 200MOV AL, XJG SUB0；判断ADD AL, ZJMPENDOSUBO: SUB AL, ZENDO: XOR AH,AHMOV SUM, AXMOV AH,4CHINT21HCODE EN

3、DSEND BEGIN5-4下面的程序段执行后，BUF1的前5个字节单元内容分别是多少?DATA SEGMENTDAIDW123H, 456H, 0AB00HDA2DB $-DA2DB 12H, 34H, 56H, OABHBUF1 DB10HDUP(l,2,3)BUF2 DB10H, 20H, 30HDATA ENDSMOVSI, OFFSET DAIMOVDI, OFFSET BUF1MOVCX, 5LOP:MOV AL, SIMOVDI, ALINCSIINCDILOOPLOP答:BUF1mi5-5阅读下列程序，回答下列问题：(1) 该程序完成什么功能？ 程序中的“INCSI”可否用指令

4、“ADDSI, 1”代替，为什么? 程序中的指令LEA SI, DATA1可用指令代替。(4) CLC的目的是。DATA SEGMENTDATA1 DB 85H, 27H, 4AHDATA2 DB 93H, 87H, 65HLEGH DW 3SUM DB 0, 0, 0DATA ENDSCODE SEGMENTASSUME CS:CODE, DS:DATABEGIN: MOV AX, DATAMOV DS, AXLEA SI, DATA1LEA BX, DATA2LEA DI, SUMMOV CX, LEGHCLCAGAIN: MOV AL, SIADC AL, BXMOV DI, ALINC

5、 SIINC BXINC DILOOP AGAINMOV AH, 4CHINT 21HCODE ENDSEND BEGIN答：（1）功能是把DATA1和DATA2定义的两个3字节多精度数的相加放入 SUM 中。（2）不能，因为使用的带进位的加法指令，如果使用ADD SI, 1,会影响CF 标志位导致进位清零，不能完成多精度数的加法。（3）LEA SI, DATA1 可用 MOV SI, OFFSET DATA 1 代替。（4）CLC的LI的是使第一次加法前CF清零，这样使用ADC指令不会影响 第一次加法运算结果。5-6数据段的ARY数组中存放有10个带符号数，编写一个程序使数组按照从 小到大的

6、顺序排列。DATA DA COUNTDATASEGMENTDB 80,3,-20,116,9,120,-6,62,-32,42EQU $-DAENDSSTACK 1 SEGMENT PARA STACKDW 20H DUP(O)STACK1 ENDSCOSEG SEGMENTASSUME CS:COSEG.DS:DATA,SS:STACK1SORT:MOV AX,DATAMOV DS,AXMOV DX,COUNT-1 ;置比较次数初值SORT1: MOV BL,0;置交换标志初值MOVCX,DX;置内循环比较次数MOVSLO;置数据指针初值SORT2:MOV AL, DASICMP AL, D

7、ASI+1;比较JLE NOXCHG ;小于等于则转不交换XCHG AL,DASI+1;交换MOVMOVNOXCHG:INC SIDASI,ALBL,0FFH ;置已交换标志;修改地址;修改比较次数;检查交换标志;有交换，继续LOOPSORT2DEC DXJE ENDO;CMP BL,0JNE SORT1ENDO:MOV AH,4CHINT 21HCOSEGENDSEND SORT傩亢灶，山徧瞬大好讥亲曲傥曾讼i,疇含席26勺人JU烯哮祐6人”。何訂過人*也 辱 习抑鬼桓6沁理仆含強文灵缺就我見加怪僂T-斯席习Q吨要枚“人用仏，工密何好，必务工 il34HOct6乙，各fj各強从強人灵必询彳-

8、断6尊习，冬捉爲”fcj栩兴扣汶，才殆弘上企业发思6勺 势代，；祐开必钊非总应#血6丁君丈4文揣乜电、力我工仆空老丈人灵编插，文席中可融金咗）拜渓如垢询渓 ifiSH-1,不卅感漱！At the end, Xiao Bian gives you a passage. Minand once said, people who learn to learn are very happy people. In every wonderful life, learning is an eternal theme. As a professional clerical and teaching posi

9、tion, I understand the importance of continuous learning, vvlife is diligent, nothing can be gained1, only continuous learning can achieve better self Only by constantly learning and mastering the latest relevant knowledge, can employees from all walks of life keep up with the pace off enterprise development and innovate to meet the needs off the marke