二次根式的乘除法-巩固练习(提高)(最新整理)

1、二次根式的乘除法（提高）5【巩固练习】一、 选择题1. 若 x 0,b 0) 等于（）.1ab1ab a2b1a. b. ab2abc. d . b- 1m4. 把 m根号外的因式移到根号内，得（）mm- m- m30.54a. b -c -d25. 设= a,= b, 用含 a, b 的式子表示，则下列表示正确的是（）.a. 0.3abb. 3abc. 0.1abd. 0.1a2b6. 若ba - b - 2 3+ (a + b - 2 2)2 = 0 ,那么 a 的值是（）.6a1b.-1c. 5 - 2d. 2- 5660二、 填空题7. 计算30 =, 2a 1a =.0.25a228

2、.=.xx2 + 6x + 59. 若-2004与+互为相反数，则 x=.x200410. 已知 x + 3 =5，则=.11. 计算(-xb ) （- abx )(-2ab x )(x 0) =.baaxa12. 计算： 2bab5 (- 32a3b ) 3=.三、综合题13. 若 y =+ +，求的值.2x - 33 - 2x4 - xxy(3m + 1)(2 - m)3m + 12 - m9m2 + 6m + 114. 若9 + 13和9- 13的小数部分分别是a和b,求ab - 4a - 3b -12的值.15. 若=成立，化简 m - 4 + m - 2 .【答案与解析】一、选择题1

3、. 【答案】 a【解析】q x 0,所以 a 0, b 0 ，所以(-xb ) （- abx )(-2abx )(x 0) =-x a 2ab xaxab bx x aa= -2a2b bx = -2ab2 x aab12. 【答案】 -a2bbaab5 a3b ab【解析】 2ab5 (- 3a3b ) 3= - 2 3 1 b2b 2 3ab= -a2b三、解答题.13. 【解析】因为 y =32x - 33 - 2x4 - x10+，所以 2x-30,3-2x0，即 x= ，y=2261036则 x =2 =2=15 .y1010513132214. 【解析】因为9 +13和9- 13的

4、小数部分分别是a和b ，所以 a = 9 +-12 =- 31313b = 9 - 5 = 4 -13所以 ab - 4a - 3b -12 = (- 3)(4 -13) - 4(- 3) - 3(4 -13) -121313= 6- 37 .15【解析】因为=成立(3m + 1)(2 - m)3m + 12 - m所以3m +10, 2 - m01即- m239m2 + 6m + 1则 m - 4 + m - 2(3m +1)2= 4 - m += 6 - 2m + 3m +1=7+ m+ 2 - m“”“”at the end, xiao bian gives you a passage.

5、 minand once said, people who learn to learn are very happy people. in every wonderful life, learning is an eternal theme. as a professional clerical and teaching position, i understand the importance of continuous learning, life is diligent, nothing can be gained, only continuous learning can achieve better self. only by constantly learning and mastering the latest relevant knowledge, can employees from all walks of life keep up with the pace of enterprise development and innovate to meet the needs of the market. this document is also edited by my studio profes