答案无机化学第三版武大吉大第11章.pdf

? ? 1? ? ?1? PbO2+ Cl Pb +2 + Cl2? ?2? Br2 BrO 3+Br ? ?3? HgS+2NO 3+Cl HgCl 2 4 +2NO2? ?4? CrO 2 4 +HSnO 2 HSnO 3+CrO 2 ? ?5? CuS +CN +OH Cu(CN) 3 4 +NCO +S ? 2? ? ?1?MnO 4 MnO2? ?2?CrO 2 4 Cr(OH)3 ? ?3?H2O2H2O ? ?4?H3AsO4H3AsO3 ? ?5?O2H2O2(aq) ? ? ? ? 3? ? KMnO4, K2Cr2O7, CuCl2, FeCl2, I2, Br2, Cl2, F2? !“#$% ) !? ?5AB?C ? 4? ?FeCl2, SnCl2, H2, KI, Li, Mg, Al, !“#$%A()*+,DE? ?-.)/01?2A345678?9:;) !?5 ?b 3I- = I 3+2e , =0.535VCf?5?v? H3AsO3 + I 3 + H2O = H3AsO4 + 3I - + 2H+?cp5 Ph=7)?h ?cp5H+=6mol_dm-3)?h ? ? ? 10? a? 422 / PPOH = -1.82V? 422 / PPOH = -1.18V ?f?b P4-PH35DE? ?-)5?yk?)?5?yk?h ? 14? *?f?5DEZ#QrG m (a) MnO2 + 4H+ + 2Br Mn2+ + 2H2O + Br2 (b) Br2 + HNO2 + H2O2Br + NO 3 + 3H + (c) I2 + Sn2+2 I + Sn4+ (d) NO 3 +3H + +2Fe2+ 2Fe3+ +HNO2 + H2O (e) Cl2 + 2Br Br2 +2Cl ? (a) MnO2 + 4H+ + 2e Mn2+ + 2H2O ? =1.23V 2Br 2e Br2 ? =1.0652V E= ? ? =0.1648V QrG m= nEF= 31.806kJ_mol 1 ? ? (b) Br2 + 2e 2Br ? =1.065V HNO2 + H2O2e NO 3 + 3H + ? =0.94V E= ? ? =0.125V QrG m= nEF= 24.125kJ_mol 1 (c)I2 + 2e 2 I ? =0.5355V Sn2+2e Sn4+ ? =0.15V E= ? ? =0.3855V QrG m= nEF= 74.407kJ_mol 1 (d) 2Fe2+ 2e 2Fe3+ ? =0.771V HNO2 + H2O2e NO 3 + 3H + ? =0.94V E= ? ? =0.169V QrG m= nEF= 32.617kJ_mol 1 (e) Cl2 + 2e 2Cl ? =1.36V 2Br 2e Br2 ? =1.065V E= ? ? =0.295V QrG m= nEF= 56.935kJ_mol 1 15?a?5DE?-? CrO 2 4 (aq) + 4H2O(l) + 3e Cr(OH)3(s) + 5OH (aq) = -0.11V Cu(NH3)+(aq) + e Cu(s) + 2 NH3(aq) = -0.10V *?f? H2A CrO 2 4 PCu(NH3)+O5 ) QrG mP K C ?C ? 0.000.050.100.150.20 0.5 1.0 1.5 2.0 2.5 3.0 E / V I / A B E=3.0V 20?*?)?d% 5000A)?% 94.5%)? 3h?7O? ?)#? kg?h ? ? ? I= t