Statistics for Management and Economics 10th Keller 课后答案SME10e_SM_ch15

1、Chapter 1515.1.1, .2, .3, .2, .2At least one is not equal to its specified value. Cell i 1 24300(.1) = 30-6 1.20 2 64300(.2) = 60 4.27 3 84300(.3) = 90 -6.40 4 72300(.2) = 60 122.40 5 56300(.2) = 60 -4 .27Total 300 300 = 4.54Rejection region: 13.3= 4.54, p-value = .3386. There is not enough evidence

2、 to infer that at least one is not equal to its specified value.15.2.1, .2, .3, .2, .2At least one is not equal to its specified value.Cell i 1 12150(.1) = 15 -3 .60 2 32150(.2) = 30 2 .13 3 42150(.3) = 45 -3 .20 4 36150(.2) = 30 6 1.20 5 28150(.2) = 30 -2 .13Total 150 150 = 2.26Rejection region: 13

3、.3= 2.26, p-value = .6868. There is not enough evidence to infer that at least one is not equal to its specified value.15.3.1, .2, .3, .2, .2At least one is not equal to its specified value.Cell i 1 675(.1) = 7.5 -1.5 .30 2 1675(.2) = 15 1 .07 3 2175(.3) = 22.5 -1.5 .10 4 1875(.2) = 15 3 .60 5 1470(

4、.2) = 15 -1 .07Total 75 75 = 1.14Rejection region: 13.3= 1.14, p-value = .8889. There is not enough evidence to infer that at least one is not equal to its specified value.15.4 Thestatistic decreases.15.5.3, .3, .2, .2At least one is not equal to its specified value.Cell i 1 38150(.3) = 45 -7 1.09 2

5、 50150(.3) = 45 5 0.56 3 38150(.2) = 30 8 2.13 4 24150(.2) = 30 -6 1.20Total 150 150 = 4.98Rejection region: 7.81= 4.98, p-value = .1734. There is not enough evidence to infer that at least one is not equal to its specified value.15.6.3, .3, .2, .2At least one is not equal to its specified value.Cel

6、l i 1 76300(.3) = 90 -14 2.18 2 100300(.3) = 90 10 1.11 3 76300(.2) = 60 16 4.27 4 48300(.2) = 60 -12 2.40Total 300 300 = 9.96Rejection region: 7.81= 9.96, p-value = .0189. There is enough evidence to infer that at least one is not equal to its specified value.15.7.2, .2, .2, .2, .2At least one is n

7、ot equal to its specified value.Cell i 1 28100(.2) = 20 8 3.20 2 17100(.2) = 20 -3 0.45 3 19100(.2) = 20 -1 0.05 4 17100(.2) = 20 -3 0.45 5 19100(.2) = 20 -1 0.05Total 100 100 = 4.20Rejection region: 7.78= 4.20, p-value = .3796. There is not enough evidence to infer that at least one is not equal to

8、 its specified value.15.8.15, .40, .35, .10At least one is not equal to its specified value.Cell i 1 41 233(.15) = 34.95 6.05 1.05 2 107 233(.40) = 93.20 13.80 2.04 3 66 233(.35) = 81.55 -15.55 2.97 4 19 233(.10) = 23.30 -4.30 0.79Total 233 233 = 6.85Rejection region: 7.81= 6.85, p-value = .0769. Th

9、ere is not enough evidence to infer that at least one is not equal to its specified value. 15.91/6, 1/6, 1/6, 1/6, 1/6, 1/6At least one is not equal to its specified value.Cell i 1 114600(1/6) = 100 14 1.96 2 92600(1/6) = 100 -8 0.64 3 84600(1/6) = 100 -16 2.56 4 101600(1/6) = 100 1 0.01 5 107600(1/

10、6) = 100 7 0.49 6 102600(1/6) = 100 2 0.04Total 600 600 = 5.70Rejection region: 11.1= 5.70, p-value = .3365. There is not enough evidence to infer that the die is not fair.15.10.05, .25 .40, .25 .05At least one is not equal to its specified value.Cell i 1 11 150(.05) = 7.5 3.5 1.63 2 32 150(.25) = 3

11、7.5 -5.5 0.81 3 62 150(.40) = 60.0 2.0 0.07 4 29 150(.25) = 37.5 -8.5 1.93 5 16 150(.05) = 7.5 8.5 9.63Total 150 150 = 14.07Rejection region: 7.78= 14.07, p-value = .0071. There is enough evidence to infer that grades are distributed differently from grades in the past.15.11.2, .2 .2, .2 .2At least

12、one is not equal to its specified value.Cell i 1 8 25(.2) = 5.0 3.0 1.80 2 4 25(.2) = 5.0 -1.0 0.20 3 3 25(.2) = 5.0 -2.0 0.80 4 8 25(.2) = 5.0 3.0 1.80 5 2 25(.2) = 5.0 -3.0 1.80Total 25 25 = 6.40Rejection region: 9.49= 6.40, p-value = .1712. There is not enough evidence to infer that the professor

13、 does not randomly distribute the correct answer over the five choices.15.12.72, .15, .10, .03At least one is not equal to its specified value.Cell i 1 159 250(.72) = 180.0 -21.0 2.45 2 28 250(.15) = 37.5 -9.5 2.41 3 47 250(.10) = 25.0 22.0 19.36 4 16 250(.03) = 7.5 8.5 9.63Total 250 250 = 33.85Reje

14、ction region: 7.81=33.85, p-value = 0. There is enough evidence to infer that the aging schedule has changed.15.13.15, .25, .40, .20At least one is not equal to its specified value.Cell i 1 36 250(.15) = 29.55 6.45 1.41 2 58 250(.25) = 49.25 8.75 1.55 3 74 250(.40) = 78.80 -4.80 0.29 4 29 250(.20) =

15、 39.40 -10.40 2.75Total 197 197 = 6.00Rejection region: 7.81= 6.00, p-value = .1116. There is not enough evidence to infer that certain sizes of cars are involved in a higher than expected percentage of accidents.15.14.31, .51, .18At least one is not equal to its specified value.Cell i 1 408 1200(.3

16、1) = 372 36 3.48 2 571 1200(.51) = 612 -41 2.75 3 221 1200(.18) = 216 5 0.12Total1200 1200 = 6.35Rejection region: 4.61= 6.35, p-value = .0419. There is enough evidence to infer that voter support has changed since the election.15.15.05, .07, .04, .84At least one is not equal to its specified value.

17、Cell i 1 19 250(.05) = 12.5 6.5 3.38 2 23 250(.07) = 17.5 5.5 1.73 3 14 250(.04) = 10.0 4.0 1.60 4 194 250(.84) = 210.0 -16.0 1.22Total 250 250 = 7.93Rejection region: 7.81= 7.93, p-value = .0475. There is enough evidence to infer that the reported side effects of the placebo differ from that of the

18、 cold remedy.15.16.23, .40, .15, .22At least one is not equal to its specified value.Cell i 1 63 320(.23) = 73.6 -10.61.53 2 125 320(.40) = 128.0 -3.00.07 3 45 320(.15) = 48.0 -3.00.19 4 87 320(.22) = 70.4 16.63.91 Total 320 320 = 5.70Rejection region: 7.81= 5.70, p-value = .1272. There is not enoug

19、h evidence to infer that there has been a change in proportions.15.17H0: p1 = .58, p2 = .06, p3 = .11, p4 = .25H1: At least one pi is not equal to its specified value.Marital statusObservedExpectedMarried& separated794 + 179 = 973.58(1782) = 1033.6Widowed281.06(1782) = 106.9Divorced66.11(1782) = 196

20、.0Never married & partnered432 + 30 = 462.25(1782) = 445.5Total1782= 373.9, p-value = 9.80E-81 0. There is sufficient evidence to conclude that the ANES in 2008 over represented at least one category of marital status.15.18H0: p1 = .79, p2 = .13, p3 = .08H1: At least one pi is not equal to its speci

21、fied value.RaceObservedExpectedWhite1477.79(1974) = 1559.5Black301.13(1974) = 256.6Other196.08(1974) = 157.9Total1974= 21.22, p-value = 0. There is enough evidence to infer that the GSS in 2012 overrepresented at least one race.15.19H0: p1 = .79, p2 = .13, p3 = .08H1: At least one pi is not equal to

22、 its specified value.RaceObservedExpectedWhite1550.79(2044) = 1614.8Black311.13(2044) = 265.7Other183.08(2044) = 163.5Total2044=12.63 p-value =.0018. There is enough evidence to infer that the GSS in 2010 overrepresented at least one race.15.20H0: p1 = .566, p2 = .062, p3 = .103, p4 = .269H1: At lea

23、st one pi is not equal to its specified value.Marital statusObservedExpectedMarried& separated900 + 68 = 968.566(1974) = 1117.3Widowed163.062(1974) = 122.4Divorced317.103(1974) = 203.3Never married526.269(1974) = 531.0Total1974= 97.05, p-value = 0. There is sufficient evidence to conclude that the G

24、SS in 2012 over represented at least one category of marital status.15.21H0: p1 = .566, p2 = .062, p3 = .103, p4 = .269H1: At least one pi is not equal to its specified value.Marital statusObservedExpectedMarried& separated891+65 = 956.566(2043) = 1156.3Widowed181.062(2043) = 126.7Divorced341.103(20

25、43) = 210.4Never married565.269(2043) = 549.6Total2043= 139.47, p-value = 0. There is sufficient evidence to conclude that the GSS in 2010 over represented at least one category of marital status.15.22 The two variables are independent The two variables are dependentCell i 1 28 96(84)/188 = 42.89 -1

26、4.89 5.17 2 68 96(104)/188 = 53.11 14.89 4.17 3 56 92(84)/188 = 41.11 14.89 5.40 4 36 92(104)/188 = 50.89 -14.89 4.36Total 188 188 = 19.10Rejection region: 3.84= 19.10, p-value = 0. There is enough evidence to infer that the two variables are dependent.15.23 The two variables are independent The two

27、 variables are dependentCell i 1 14 48(42)/188 = 21.45 -7.45 2.59 2 34 48(52)/188 = 26.55 7.45 2.09 3 28 46(42)/188 = 20.55 7.45 2.70 4 18 46(52)/188 = 25.45 -7.45 2.18Total 94 94 = 9.56Rejection region: 3.84= 9.56, p-value = .0020. There is enough evidence to infer that the two classifications L an

28、d M are dependent.15.24 The two variables are independent The two variables are dependentCell i 1 7 24(21)/188 = 10.72 -3.72 1.29 2 17 24(26)/188 = 13.28 3.72 1.04 3 14 23(21)/188 = 10.28 3.72 1.35 4 9 23(26)/188 = 12.72 -3.72 1.09Total 47 47 = 4.77Rejection region: 3.84= 4.77, p-value = .0289. Ther

29、e is enough evidence to infer that the two classifications L and M are dependent.15.25 Thestatistic decreases.15.26 The two variables are independent The two variables are dependentCell i 1 40 120(70)/250 = 33.60 6.40 1.22 2 32 120(80)/250 = 38.40 - 6.40 1.07 3 48 120(100)/250 = 48.00 0 0.00 4 30 13

30、0(70)/250 = 36.40 -6.40 1.13 5 48 130(80)/250 = 41.60 6.40 0.99 6 52 130(100)/250 = 52.00 0 0.00Total 250 250 = 4.41Rejection region: 4.61= 4.41, p-value = .1110. There is not enough evidence to infer that the two classifications R and C are dependent. 15.27 The two variables (responses and employee

31、 group) are independent The two variables are dependentCell i 1 67 110(130)/200 = 71.50 -4.500.28 2 32 110(50)/200 = 27.50 4.50 0.74 3 11 110(20)/200 = 11.00 0 0.00 4 63 90(130)/200 = 58.50 4.50 0.35 5 18 90(50)/200 = 22.50 -4.50 0.90 6 9 90(20)/200 = 9.00 0 0.00Total 200 200 = 2.27Rejection region:

32、 5.99= 2.27, p-value = .3221. There is not enough evidence to infer that responses differ among the three groups of employees.15.28 The two variables (shirt condition and shift) are independent The two variables are dependentCell i 1240570(250)/600 = 3 2191570(200)/600 = 190.01.0 .01 31395

33、70(150)/600 = 142.5-3.5 .09 410 30(250)/600 = 12.5 -2.5 .50 5 9 30(200)/600 = 10.0 -1.0 10 61130(150)/600 = 7.5 3.5 1.63Total 600 600 = 2.36Rejection region: 5.99= 2.36, p-value = .3087. There is not enough evidence to infer that there are differences in quality among the three shifts.15.29 The two

34、variables economic option and political affiliation) are independent The two variables are dependentCell i 1101444(331)/1000 = 146.96 -45.96 14.376 2282444(557)/1000 = 233.9948.01 9.852 361444(142)/1000 = 63.05-2.05 0.067 438 130(331)/1000 = 43.03 -5.03 0.588 5 67 130(557)/1000 = 68.51 -1.51 0.033 6

35、25130(142)/1000 = 18.466.54 2.317 7131250(331)/1000 = 82.7548.25 28.134 888250(557)/1000 = 131.75-43.75 14.528 931 250(142)/1000 = 35.50 -4.50 0.570 10 61 176(331)/1000 = 58.26 2.74 0.129 11 90 176(557)/1000 = 92.75-2.75 0.082 1225176(142)/1000 = 24.99 0.01 0.000Total 1000 1000 = 70.675Rejection reg

36、ion: 16.8= 70.675, p-value = 0. There is sufficient evidence to infer that political affiliation affects support for economic options.15.30 The two variables (inducement and return) are independent The two variables are dependentCell i 180300(200)/1000 = 60206.67 2100300(300)/1000 = 9010 1.11 312030

37、0(500)/1000 = 150-30 6.00 4120 700(200)/1000 = 140 -20 2.86 5 200 700(300)/1000 = 210 -10 0.50 6380700(500)/1000 = 350 30 2.57Total1000 1000 = 19.71Rejection region: 5.99= 19.71, p-value = .0001. There is sufficient evidence to infer that the return rates differ among the different inducements.15.31

38、 The two variables (newspaper and occupation) are independent The two variables are dependentCell i 127 120(89)/354=30.2-3,2 .33218120(112)/354=38.0-20.010.503 38120(81)/354=27.510.54.054 37120(72)/354=24.412.66.50529108(89)/354=3643108(112)/354=8721108(81)/354=24.7-3.7.56815108(7

39、2)/354=22.0-7.02.21933126(89)/354=61051126(112)/354=39.911.13.111122126(81)/354=28.8-6.81.621220126(72)/354=25.6-5.61.24Total 354 354 = 32.57Rejection region: 12.6= 32.57, p-value = 0. There is sufficient evidence to infer that occupation and newspaper are related.15.32a The two variables (predicted change and actual change) are independent The two variables are dependentCell i 165129(104)/216 =