版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领
文档简介
信号与系统SignalsandSystems吉林大学PropertiesofLaplacetransform:RightShiftinTimeProperty3:RightshiftintimeProof:Property3:Rightshiftintime(3)Property3:RightshiftintimeSolution:信号与系统SignalsandSystems吉林大学PropertiesofLaplaceTransform:TimeScalingProperty4:TimescalingProof:信号与系统SignalsandSystems吉林大学PropertiesofLaplaceTransform:ConvolutionTheoremsProperty5:Convolutioninthet-domainProof:Property5:Convolutioninthet-domainContinued:Property
6:Convolutioninthes-domainProof:信号与系统SignalsandSystems吉林大学PropertiesofLaplaceTransform:Differentiationinthet-domainProperty7:Differentiationinthet-domainProof:信号与系统SignalsandSystems吉林大学PropertiesofLaplaceTransform:Integrationinthet-domainProperty8:Integrationinthet-domainProof:Property8:Integrationinthet-domain信号与系统SignalsandSystems吉林大学PropertiesofLaplaceTransform:DifferentiationandIntegrationinthes-DomainProperty9:Differentiationinthes-domainProof:Property10:Integrationinthes-domainProof:信号与系统SignalsandSystems吉林大学PropertiesofLaplaceTransform:InitialandFinal-ValuetheoremsProperty11:Initial-valuetheoremProof:Property12:Final-valuetheoremProof:信号与系统SignalsandSystems吉林大学ComputationoftheInverseLaplaceTransform(Ⅱ)PartialFractionExpansionComputationoftheinverseLaplacetransform(Ⅱ)Partialfractionexpansion(1)Conditions:ComputationoftheinverseLaplacetransform(Ⅱ)Partialfractionexpansion(2)ComputationoftheinverseLaplacetransform(Ⅱ)Partialfractionexpansion(3)信号与系统SignalsandSystems吉林大学SolvingtheDifferentialEquationsinthes-DomainSolvingthedifferentialequationsinthes-domain[Example]Given:Find:
Solvingthedifferentialequationsinthes-domainSolvingthedifferentialequationsinthes-domainSolvingthedifferentialequationsinthes-domain信号与系统SignalsandSystems吉林大学Thes-DomainRepresentationsofCircuits(I)Thes-domainrepresentationsofcircuits(I)1Thes-domainequivalentcircuitelementsThesameresistanceThes-domainrepresentationsofcircuits(I)1Thes-domainequivalentcircuitelementsThes-domainimpedanceThes-domainrepresentationsofcircuits(I)1Thes-domainequivalentcircuitelementsThes-domainimpedanceThes-domainrepresentationsofcircuits(I)2TheformsofKVLandKCLinthes-domain信号与系统SignalsandSystems吉林大学TheBlockDiagramofaSysteminthes-DomainTheblockdiagramofasysteminthes-domainScalarmultiplier1Adder/Subtractor2Theblockdiagramofasysteminthes-domainIntegrator3信号与系统SignalsandSystems吉林大学TheDefinitionofTransferFunctionanditsSolutionsThedefinitionoftransferfunctionanditssolutionsThetransferfunctionⅠHowtofind21.GiventhesystemdifferentialequationThedefinitionoftransferfunctionanditssolutionsHowtofind21.GiventhesystemdifferentialequationThedefinitionoftransferfunctionanditssolutions2.Giventheimpulseresponseh(t)Thedefinitionoftransferfunctionanditssolutions3.GiventhestructureofthecircuitUsingthedefinitioninthes-domainrepresentationofthecircuit.4.Usingthepole-zeroplot信号与系统SignalsandSystems吉林大学TheTransferFunctionandthePole-ZeroPlotThetransferfunctionandthepole-zeroplotPolesandzeros1Zeros:Poles:Thetransferfunctionandthepole-zeroplotThepole-zeroplot2Aplotinthecomplexplaneshowingthelocationsofallthepoles(markedby×)andallthezeros(markedby○)iscalledthepole-zeroplot.Zeros:Poles:信号与系统SignalsandSystems吉林大学ApplicationsofthePole-ZeroPlot:DeterminingtheFormofh(t)Thepoles
beinglocatedintheopen
left-halfcomplexplane1Applicationsofthepole-zeroplot:Determiningtheformofh(t)Thepoles
beinglocatedintheopen
left-halfcomplexplane1Applicationsofthepole-zeroplot:Determiningtheformofh(t)Thepoles
beinglocatedattheorigin2Applicationsofthepole-zeroplot:Determiningtheformofh(t)Thepoles
beinglocatedontheimaginaryaxis3Applicationsofthepole-zeroplot:Determiningtheformofh(t)Thepoles
beinglocatedintheopen
right-halfcomplexplane4Applicationsofthepole-zeroplot:Determiningtheformofh(t)信号与系统SignalsandSystems吉林大学Time-DomainAnalysisofDiscrete-TimeSystemsDiscrete-TimeSignalsDiscrete-TimeSignalsAdiscrete-timesignalf(k)hasvaluesforsomediscontinuouspointwhilehasnotdefinitionforotherpoints.k—integerDefinitionDiscrete-TimeSignalsAnalyticalmethod:Graphicalmethod:Sequencemethod:k=0RepresentationDiscrete-TimeSignalEnergyandPowerEnergy:Power:OperationofDiscrete-TimeSignalsAddition:Multiplication:Difference:forwarddifference:backwarddifferenceRunningsum:OperationofDiscrete-TimeSignalsTimeshift(m>0)RightshiftLeftshiftTransformationsoftheIndependentVariableOperationofDiscrete-TimeSignalsTimereversalTransformationsoftheIndependentVariablef(-k)isobtainedfromthesignalf(k)
byareflectionaboutk=0.BasicDiscrete-TimeSignalsUnitImpulseSequence(UnitSampleSequence)BasicDiscrete-TimeSignalsUnitStepSequenceBasicDiscrete-TimeSignalsRelationshipbetweend(k)ande(k)BasicDiscrete-TimeSignalsRectangularSequenceBasicDiscrete-TimeSignalsUnilateralexponentialsequenceswithrealvalues:f(k)=ak
(k)(aisarealnumber)BasicDiscrete-TimeSignalsUnitrampsequenceSinusoidalSequencesComplexExponentialSequences:Canda:complexnumbers信号与系统SignalsandSystems吉林大学RepresentationsofDiscrete-TimeSystemsRepresentationsofDiscrete-TimeSystemsAdiscrete-timesystemisasystemthattransformsdiscrete-timeinputsintodiscrete-timeoutputs.Definitionf(k):inputy(k):outputInput-outputrelation:f(k)→
y(k)RepresentationsofDiscrete-TimeSystemsnth-orderLinearConstant-CoefficientDifferenceEquation:LTISystemsDescribedbyDifferenceEquatioconstantsRepresentationsofDiscrete-TimeSystemsBlockDiagramRepresentationBasicelementsMultiplicationbyacoefficientAdderUnitDelayElementRepresentationsofDiscrete-TimeSystemsInterconnectionsofSystemsSeries(Cascade)interconnectionParallelinterconnectionFeedbackinterconnection信号与系统SignalsandSystems吉林大学Linearinput/outputdifferenceequationswithconstantcoefficientsInput:f(k)=0fork<0InitialCondition:y(0),y(1),y(2),…,y(n-1)InitialState:y(-1),y(-2),…,y(-n)Linearinput/outputdifferenceequationswithconstantcoefficientsEquation:Solution:Linearinput/outputdifferenceequationswithconstantcoefficientsTheHomogeneousSolutionHomogeneousequation
CharacteristicequationCharacteristicroot
j(j=1,2,3,
,n)HomogeneoussolutionLinearinput/outputdifferenceequationswithconstantcoefficientsTheHomogeneousSolutionExample:y(k)+3y(k-1)+2y(k-2)=f(k),f(k)=2k,k
≥0,y(0)=0,y(1)=2.Findyh(k)
.Characteristicequation:Homogeneousequation
CharacteristicequationCharacteristicroot
j(j=1,2,3,
,n)HomogeneoussolutionLinearinput/outputdifferenceequationswithconstantcoefficientsTheParticularSolutionLinearinput/outputdifferenceequationswithconstantcoefficientsTheParticularSolutionExample:y(k)+3y(k-1)+2y(k-2)=f(k),f(k)=2k,k
≥0,y(0)=0,y(1)=2.Findyp(k),k
≥0.Letyp(k)=P·2k,k
≥0Substitutethesystemequation:信号与系统SignalsandSystems吉林大学TheZero-InputResponse
and
TheZero-StateResponseTheZero-InputResponse
Characteristicequation
j,(j=1,2,3,
,n)CharacteristicrootZero-InputResponse
yzi
(0),yzi
(1),…,yzi
(n-1)y(-1),y(-2),…,y(-n)
yzi(k)=y(k)-
yzs(k)=y(k),k<0InitialconditionCharacteristicequation:Characteristicroots:Zero-InputResponse:Example:TheZero-InputResponsey(k)+3y(k-1)+2y(k-2)=f(k),f(k)=2kε(k),y(-1)=0,y(-2)=1/2.Findyzi(k),k
≥0.yzi(k)+3yzi(k-1)+2yzi(k-2)=0TheZero-StateResponseCharacteristicequation
j
(j=1,2,3,
,n)Characteristicroot(distinctroots
j
)Zero-StateResponseyzs(-1)=yzs(-2)=…=yzs
(-n)=0Initialstateyzs(0),yzs
(1),…,yzs
(n-1)Initialcondition信号与系统SignalsandSystems吉林大学TheUnitSampleResponse
and
TheUnitStepResponseTheUnitSampleResponseDefinitionTheunitsampleresponseisthezero-stateresponseofthesystemresultingfromtheapplicationoftheunitpulse
(k).Denotedh(k)Initialstateh(-1)=h(-2)=…=h(-n)=0Initialconditionh(0),h(1),h(2),…,h(n-1)HowtofindSolvingadifferenceequationZ-transformTheUnitSampleResponseDeterminationk<0:
(k)
=0,h(k)=0k=0:
(k)
=1,h(0)——recursionk>0:
(k)
=0,h(k)——solutionofahomogeneousequationLTI
system:LetthenCi:determinedbyh1(1),h1(2),…,h1(n)TheUnitStepResponseDefinitionTheunitstepresponseisthezero-stateresponseofthesystemresultingfromtheapplicationoftheunitstepsequencee
(k).Denotedg(k)Initialstateg(-1)=g(-2)=…=g(-n)=0Relationshipbetweenh(k)andg(k)信号与系统SignalsandSystems吉林大学ConvolutionSumConvolutionSum
Ingeneral,twodiscrete-timesignalsf1(k)andf2(k)DefinitionExample1:ConvolutionSumConvolution-SumRepresentationofLTIdiscrete-timesystemsThezero-stateresponse:ConvolutionSum:GraphicalRepresentationGraphicalRepresentationoftheconvolutionsumProcedure:Step1.Drawf1(i)andf2(i)Step2.Reverse
f2(i):f2(i)
f2(-i)Step3.Shift
f2(-i)bykpositiontotheright:f2(-i)
f2(k-i)
Step4.Multiplicationoff1(i)withf2(k-i):
f1(i)f2(k-i)
Step5.Summationoftheproductforallvaluesofi
yieldsonevalueofy(k)Step6.Repeatsteps3and5forallvaluesofk信号与系统SignalsandSystems吉林大学PropertiesoftheConvolutionSumPropertiesoftheConvolutionSumCommutativityProof:PropertiesoftheConvolutionSumAssociativityProof:CascadeinterconnectionofLTIsystemsPropertiesoftheConvolutionSumDistributivitywithadditionProof:ParallelinterconnectionofLTIsystemsPropertiesoftheConvolutionConvolutionwiththeunitpulseProof:Ifk1=0,thenPropertiesoftheConvolutionShiftpropertyProof:Iff(k)=f1(k)*f2(k),then
信号与系统SignalsandSystems吉林大学TheAnalysisofDiscrete-TimeSystemsinthez-DomainThez-TransformDefinitionofthez-TransformDefinitionofthez-TransformIntuitionontheRelationbetweenZTandLTLT:Let:Definitionofthez-TransformDefinitionBilateral(two-sided)z-Transform:Unilateral(one-sided)z-Transform:Thetransformpairnotation:信号与系统SignalsandSystems吉林大学Thez-TransformCommonz-transformpairsCommonz-transformpairsUnitSampleSequenceCommonz-transformpairsOne-sideExponentialSequencewhereaisarealorcomplexnumber.UnitStepSequenceCommonz-transformpairswhere
aisarealorcomplexnumber.信号与系统SignalsandSystems吉林大学TheRegionofConvergenceforthez-TransformDefinitionTheRegionofConvergenceforthez-TransformThesetofallcomplexnumberszsuchthatthesummationontheright-handside
convergesiscalledtheregionofconvergence(ROC)ofthez-transformF(z).F(z)converges:f(k)z-kisabsolutelysummableFinite-durationsequenceTheRegionofConvergenceforthez-Transformf(k)=0,k
<k1,k>k2,k1<k2k1<0,k2>0:
k1<0,k2
0:k10,k2
>0:0<|z|<
|z|<
|z|>0Example:CausalsequenceTheRegionofConvergenceforthez-Transformf(k)=0,k<0Example:z-planeak
(k),aisarealorcomplexnumber.AnticausalsequenceTheRegionofConvergenceforthez-TransformExample:f(k)=0,k≥0f(k)=-ak
(-k-1),aisarealorcomplexnumber.Two-sidedsequenceTheRegionofConvergenceforthez-Transformk=-∞→+∞
0<R1<R2<:R1<|z|<R2
R1>R2
:
ROCdoesnotconvergeTheRegionofConvergenceforthez-TransformROCisboundedbypolesorextendstoinfinity.F(z)isrational:f(k)ROCrightsidedoutsidetheoutermostpole——outsidethecircleofradiusequaltothelargestmagnitudeofthepolesofF(z)leftsidedinsidetheinnermostnonzeropole——insidethecircleofradiusequaltothesmallestmagnitudeofthepolesofF(z)otherthananyatz=0andextendinginwardtoandpossiblyincludingz=0.信号与系统SignalsandSystems吉林大学Propertiesofthez-Transform——LinearityIff1(k)
F1(z),
1<
z
<
1,f2(k)
F2(z),
2<
z
<
2,thenLinearityExample:Iff1(k)
F1(z),
1<
z
<
1,f2(k)
F2(z),
2<
z
<
2,thenLinearityExample:信号与系统SignalsandSystems吉林大学Propertiesofthez-Transform——TimeShiftingTimeShiftingExample:Bilateralz-TransformIff(k)
F(z),
<
z
<
,thenwheremisapositiveinteger.TimeShiftingProof:Unilateralz-Transform——RightshiftIff(k)
F(z),
z
>
,thenwheremisapositiveinteger.TimeShiftingUnilateralz-Transform——RightshiftIff(k)=0,k<0,thenExample:Iff(k)
F(z),
z
>
,thenwheremisapositiveinteger.TimeShiftingUnilateralz-Transform——LeftshiftIff(k)
F(z),
z
>
,thenwheremisapositiveinteger.Proof:TimeShiftingUnilateralz-Transform——LeftshiftIff(k)
F(z),
z
>
,thenwheremisapositiveinteger.Example:
(k+1)信号与系统SignalsandSystems吉林大学Propertiesofthez-Transform——Scalinginthez-DomainScalinginthez-DomainProof:Iff(k)
F(z),R1<|z|<R2
,thenaisanonzerorealorcomplexnumber.ROCofF(z):ROCof
:Scalinginthez-DomainIff(k)
F(z),R1<|z|<R2
,thenaisanonzerorealorcomplexnumber.Example:
aksin(
k)
(k),0<a<1Scalinginthez-DomainIff(k)
F(z),R1<|z|<R2
,thenaisanonzerorealorcomplexnumber.Example:(-1)k
(k)信号与系统SignalsandSystems吉林大学Propertiesofthez-Transform——ConvolutionConvolutionProof:Iff1(k)
F1(z),
1<z<
1,f2(k)
F2(z),
2<z<
2,thenConvolutionIff1(k)
F1(z),
1<z<
1,f2(k)
F2(z),
2<z<
2,thenExample:(k+1)
(k)LTIsystems:信号与系统SignalsandSystems吉林大学Propertiesofthez-Transform——DifferentiationandIntegralinthez-DomainDifferentiationinthez-DomainProof:Iff(k)
F(z),
<
z
<
,then
wherekisanypositiveinteger.Differentiationinthez-DomainIff(k)
F(z),
<
z
<
,then
wherekisanypositiveinteger.Example:Ifa=1,thenDifferentiationinthez-DomainIff(k)
F(z),
<
z
<
,then
wherekisanypositiveinteger.Integralinthez-DomainProof:Iff(k)
F(z),
<
z
<
,then
(misaninteger,andk+m>0)Integralinthez-DomainIff(k)
F(z),
<
z
<
,then
(misaninteger,andk+m>0)Example:Integralinthez-DomainIff(k)
F(z),
<
z
<
,then
(misaninteger,andk+m>0)m=0,k>0:信号与系统SignalsandSystems吉林大学Propertiesofthez-Transform——Reflectioninthek-domainReflectioninthek-domainProof:Iff(k)
F(z),
<
z
<
,then
Example:信号与系统SignalsandSystems吉林大学Propertiesofthez-Transform——SummationSummationProof:Iff(k)
F(z),
<
z
<
,then
Example:信号与系统SignalsandSystems吉林大学Propertiesofthez-Transform——Initial-ValueTheoremandFinal-ValueTheoremInitial-ValueTheoremProof:Iff(k)=0,k<0,andf(k)
F(z),then
Example:0Thez-transformofacausalsequencef(k)isfindf(0).Final-ValueTheoremProof:Iff(k)=0,k<0,f(k)
F(z),a<
z<,0≤a<1,then
Final-ValueTheoremIff(k)=0,k<0,f(k)
F(z),a<
z<,0≤a<1,then
Example:f(k)=0,k<0. aisarealnumber,findf(
).Final-ValueTheorem√√××Final-ValueTheoremIff(k)=0,k<0,f(k)
F(z),a<
z<,0≤a<1,then
Example:f(k)=0,k<0. aisarealnumber,findf(
).Final-ValueTheoremIfF(z)isrationalandthepolesof(z-1)F(z)havemagnitudes<1,then
Example:Thez-transformofacausalsequencef(k)is
Poles:信号与系统SignalsandSystems吉林大学TheInversez-TransformTheInversez-Transform(IZT)Integral:DefinitionalongacounterclockwiseclosedcircularcontourthatiscontainedintheROCofF(z).AlternativeproceduresPower-seriesexpansionsPartialfractionexpansionsROCandtheInversez-TransformROCf(k)Causalsequence|z|>af1(k)e
(k)Anticausalsequence|z|<bf2(k)e
(-k-1)Two-sidedsequencea<|z|<b
f1(k)e(k)+
f2(k)e
(-k-1)信号与系统SignalsandSystems吉林大学TheInversez-Transform——PartialfractionexpansionsPartialfractionexpansionsRationalpolynomial:Procedure:PartialfractionexpansionsF(z)f(k)×zIZTPartialfractionexpansions
DistinctPolesSupposethatthepolesz1,z1,…,zNofF(z)aredistinctandareallnonzero.(1)|z|>2;(2)|z|<1;(3)1<|z|<2(1)Example:Partialfractionexpansions
DistinctPolesSupposethatthepolesz1,z1,…,zNofF(z)aredistinctandareallnonzero.(1)|z|>2;(2)|z|<1;(3)1<|z|<2(2)Example:Partialfractionexpansions
DistinctPolesSupposethatthepolesz1,z1,…,zNofF(z)aredistinctandareallnonzero.(1)|z|>2;(2)|z|<1;(3)1<|z|<2(3)Example:Partialfractionexpansions
DistinctPolesz1,2=ae±jbROC:|z|>
Complex
Poles:Partialfractionexpansions
DistinctPolesz1,2=ae±jbComplex
Poles:Example:PartialfractionexpansionsRepeatePolesSupposethatthepolez1isrepeatedrtimes.Matchingcoefficients:Example:PartialfractionexpansionsExample:Step1DividethroughtoobtainwhereF1(z)isstrictlyproper.Step2CarryoutthepartialfractionexpansionofF1(z)and,knowingtheROC,obtaintheinversez-transform.信号与系统SignalsandSystems吉林大学z-DomainAnalysis—TransformoftheInput/outputDifferenceEquationTransformoftheInput/outputDifferenceEquationLTIsystem:Input:f(k)=0,k<0Initialstate:y(-1),y(-2),…,y(-n)z-Transform:Y(z)=Yzi(z)+Yzs(z)IZT:y(k)=yzi(k)+yzs(k)TransformoftheInput/outputDifferenceEquationExample:y(k)-y(k-1)-2y(k-2)=f(k)+2f(k-2),y(-1)=2,y(-2)=-0.5,f(k)=e(k).Findyzi(k),yzs(k),y(k),k≥0.TransformoftheInput/outputDifferenceEquationExample:y(k)-y(k-1)-2y(k-2)=f(k)+2f(k-2),y(-1)=2,y(-2)=-0.5,f(k)=e(k).Findyzi(k),yzs(k),y(k),k≥0.TransformoftheInput/outputDifferenceEquationExample:y(k)-y(k-1)-2y(k-2)=f(k)+2f(k-2),y(-1)=2,y(-2)=-0.5,f(k)=e(k).Findyzi(k),yzs(k),y(k),k≥0.信号与系统SignalsandSystems吉林大学z-DomainAnalysis—TheSystemFunctionTheSystemFunction(TransferFunction)DefinitionDeterminationofthesystemfunction(1)
H(z)=Yzs(z)/F(z)(2)H(z)=Z[h(k)]SystemFunctionofInterconnectionsSeriesconnectionH(z)ParallelconnectionH(z)Parallelconnection
H(z)SystemFunctionforInterconnectionsofLTISystemsExample:Determinethezero-stateoftheLTIsystem.Pole-zeroPlotoftheSystemFunctionPole-zeroplotExample:Aplotofthelocationsinthecomplexplaneofthepolesandzeros.Zerosro
温馨提示
- 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
- 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
- 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
- 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
- 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
- 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
- 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
最新文档
- 2024年专业饭馆业务承接协议规范文本版
- 2024借款居间合同模板
- 2024年专用废纸采购销售协议版B版
- 上海市建平实验中学2024-2025学年九年级上学期期中英语试题(解析版)
- 佳木斯大学《专业创新创业拓展》2021-2022学年第一学期期末试卷
- 二零二四年度版权使用与授权协议2篇
- 2024年云计算数据中心建设和运营合同
- 2024专项工程项目设备供应协议版B版
- 佳木斯大学《大美劳动》2021-2022学年第一学期期末试卷
- 暨南大学《思想道德与法治》2021-2022学年第一学期期末试卷
- Unit 5 Fun clubs section B project 说课稿 -2024-2025学年人教版英语七年级上册
- 实验室设备安装调试及技术支持方案
- 糖尿病健康知识讲座
- 机器人感知智能 课件 第3、4章 机器人视觉感知、机器人接近觉感知
- 2024年再生资源回收与利用合作协议
- 生物-江西省稳派上进联考2024-2025学年2025届高三上学期11月调研测试试题和答案
- 《胶轮车操作工》(司机、检修)理论知识考试及答案
- 森林康养基地建设项目可行性研究报告
- 机械行业质量奖惩制度
- 23J916-1 住宅排气道(一)
- 古典诗词鉴赏学习通超星期末考试答案章节答案2024年
评论
0/150
提交评论