脱硫计算公式

石灰石/石膏湿法脱硫,,,,,,,,,,

1,校核煤质,,,,,,,,,

,Car=,64,%,,Nar=,1,%,,,

,Har=,5,%,,War=,8,%,,,

,Oar=,6.6,%,,Aar=,16,%,,,

,Sar=,0.4,%,,Var=,15,%,,,

,换算成干燥无灰基的元素含量,,,,,,,,,

,Cdaf=,84.21052632,%,取,Cdaf=,84,%,,,

,Hdaf=,6.578947368,%,,Hdaf=,6.6,%,,,

,Odaf=,8.684210526,%,,Odaf=,8.7,%,,,

,Sdaf=,0.526315789,%,,Sdaf=,0.5,%,,,

,"Qdaf,net=",339Cdaf+1030Hdaf-109(Odaf-Sdaf)=,,,,344.3447368,MJ/kg,,,

,,,,取,"Qdaf,net=",34.4,MJ/kg,,,

,换算成低位收到基发热量,,,,,,,,,

,"Qar,net=","Qdaf,net*76/100=",,,,26.144,MJ/kg,,,

,,,,取,"Qar,net=",25.8,MJ/kg,,,

,全厂效率为,,38,%,含硫量为,0.4,%,,,

,燃烧计算,,,,,,,,,

,mcoal=,,,,,,,,,

,mcoal=,0.073439412,=,73.4,t/h,,,,,

2,标准状况下理论空气量,,,,,,,,,

,Qa’=,4.76*（1.867CY+5.56HY+0.7SY-0.7OY）=,,,,6.8043248,m³/kg,,,

,,,,取,Qa’=,6.8,m³/kg,,,

3,标准状况下理论烟气量（空气含湿量为12.93g/m³）,,,,,,,,,

,Qs’=,1.867（CY+0.375SY)+11.2HY+1.24WY+0.016Qa'+0.79Qa'+0.8NY,,,,,,,,

,,,,,=,7.3456805,m³/kg,,,

,,,,取,Qs’=,7.35,m³/kg,,,

4,标准状况下实际烟气量,,,,,,,,,

,空气过剩系数,,α=,1.3,,,,,,

,Qs=,Qs’+1.016(α-1)Qa',,,=,9.42264,m³/kg,,,

,,,,取,Qs=,9.4,m³/kg,,,

5,标准状况下烟气含尘浓度,,,,,,,,,

,排烟中飞灰占煤中不可燃组分的比例,,,,dsh=,16,%,,,

,C=,,=,0.002723404,kg/m³,,,,,

,,取,C=,0.002723,kg/m³,,,,,

6,标准状况下烟气中浓度,,,,,,,,,

,CSO2=,,=,851.0638298,mg/m³,,,,,

,,取,CSO2=,852,mg/m³,,,,,

,SO2浓度的校准,,,基准氧含量为,,6,%,,,

,"CSO2,at4.6%=",,,,,,,,,

,"CSO2,at4.6%=",931.52,mg/m³,取,"CSO2,at4.6%=",932,mg/m³,,,

,二氧化硫排放标准（标准状态下）：,,,,200,mg/m³,,,,

,,,,"CSO2,at6%=",218.6666667,mg/m³,,,,

,,,取,"CSO2,at6%=",219,mg/m³,,,,

,除硫效率为,,76.5258216,%,,,,,,

,,取,77,%,,,,,,

7,标准状况下SO2燃烧产量,,,,,,,,,

,mSO2=,,,=,0.5872,t/h,,,,

,,,取,mSO2=,0.59,t/h,,,,

,SO2的脱除量,,,,,,,,,

,"mSO2,removal=",,0.4543,t/h,,,,,,

,取,"mSO2,removal=",0.45,t/h,,,,,,

8,烟气中水蒸气密度,,,,,,,,,

,由理想气体状态方程得,,,,,,,,,

,PVwater=nwaterRT,,,,,,,,,

,,,,,,,,,,,

,,,,,,,,,,,

,,,,,,,,,,,

,ρ=,0.778501328,kg/Nm³,,,,,,,

,取,ρ=,0.78,kg/Nm³,,,,,,

9,烟气体积流量,,,,,,,,,

,"Vfluegas,wet=mcoal.Vfluegas",,,,,,,,,

,"Vfluegas,wet=",,689960,Nm³/h,,,,,,

,取,"Vfluegas,wet=",,690000,Nm³/h,,,,,

,"Vfluegas，dry=Vfluegas,wet.(1-0.083)=",,,,632730,Nm³/h,,,,

,取,"Vfluegas,dry=",,633000,Nm³/h,,,,,

,Vwater=,57000,Nm³/h,,,,,,,

10,烟气质量流量,,,,,,,,,

,"mfluegas,dry=Vdry.ρfluegas,dry",,,,,,,,,

,烟气密度（标准状态）：ρ=,,,1.34,kg/m³,,,,,

,"mfluegas,dry=",,848220,kg/h,,,,,,

,取,"mfluegas,dry=",,848000,kg/h,,,,,

,"mfluegas,wet=mfluegas,dry+mwater",,,,,,,,,

,mwater=,44460,kg/h,,,,,,,

,"mfluegas,wet=",,892460,kg/h,,,,,,

,取,"mfluegas,wet=",,892000,kg/h,,,,,

11,吸收塔饱和温度计算,,,,,,,,,

,假定电除尘器出口温度为,,,135,°C,,,,,

,GGH出口温度为,,,108,°C,,,,,

,干烟气水含量,,,,,,,,,

,,,,,,,,,,,

,x1=,0.052429245,,,,,,,,

,取,x1=,0.052,,,,,,,

,"在h,x图上，108°C和0.052的交点的焓h=",,,,248,kJ/kg,,,,

,沿等焓线到饱和线可得到饱和温度T,,,,,,,,,

,T=,48,°C,,x2=,0.077,,,,

,"mwater,vapourised=(xwater,outlet-xwater,inlet).mfluegas,dry",,,,,,,,,

,"mwater,vapourised=",,21200,kg/h,,,,,,

,,,,=,27179.48718,Nm³/h,,,,

,,取,"Vwater,saturation=",,27000,Nm³/h,,,,

12,吸收塔出口净烟气的计算,,,,,,,,,

,"Vwater,vapourised,cleangas=Vwater+Vwater,saturation",,,,,,,,,

,"Vwater,vapourised,cleangas=",,84000,Nm³/h,,,,,,

,"Vcleangas,wet=Vinlet,dry+Vwater,vapourised,cleangas",,,,,,,,,

,"Vcleangas,wet=",,717000,Nm³/h,,,,,,

13,吸收塔烟气计算结果汇总,,,,,,,,,

,13.1吸收塔入口：,,,,,,,,,

,Vwet=,690000,Nm³/h,,,,,,,

,Vdry=,633000,Nm³/h,,,,,,,

,mwet=,892000,kg/h,,,,,,,

,mdry=,848000,kg/h,,,,,,,

,Vwater,57000,Nm³/h,,,,,,,

,mwatewr,44460,kg/h,,,,,,,

,T1=,108,°C,,,,,,,

,O2=,6,%(dry),,,,,,,

,SO2=,852,mg/m³,,,,,,,

,"SO2,6%O2=",932,mg/m³,,,,,,,

,13.2吸收塔出口：,,,,,,,,,

,Vwet=,717000,Nm³/h,,,,,,,

,Vdry=,633000,Nm³/h,,,,,,,

,mwet=,913200,kg/h,,,,,,,

,mdry=,848000,kg/h,,,,,,,

,Vwater,84000,Nm³/h,,,,,,,

,mwatewr,65520,kg/h,,,,,,,

,T1=,48,°C,,,,,,,

,O2=,,%(dry),,,,,,,

,SO2=,200,mg/m³,,,,,,,

,"SO2,6%O2=",219,mg/m³,,,,,,,

14,废水流量的计算,,,,,,,,,

,假定烟气中HCl的浓度CHCl，fluegas=,,,,46,mg/Nm³,HCl的去除率为,,98,%

,废水中Cl-含量保持,,15,g/L,,,,,,

,"mCl-=0.98.CHCl,fluegasVdry",,,,,,,,,

,mCl-=,28.53564,kg/h,,,,,,,

,取,mCl-=,28.5,kg/h,,,,,,

,,,,,,,,,,,

,mwater=,1900,kg/h,,,,,,,

15,石灰石消耗量/石膏产量,,,,,,,,,

,SO2+CaCO3+2H2O+1/2O2→CaSO4.2H2O+CO2,,,,,,,,,

,石灰石耗量,,,,,,,,,

,0.70984375,t/h,,取,0.7,t/h,,,,

,石膏产量,,,,,,,,,

,1.22093125,t/h,,取,1.2,t/h,,,,

16,工艺水消耗量,,,,,,,,,

,"mwater=mwater,vapourised+mwashwater+mcrystalwater+mgypsum,moisture",,,,,,,,,

,mwater=,23484.49612,kg/h,取,mwater=,23484,kg/h,,,

,Vmater=,23.484,m³/h,,,,,,,

17,石膏脱水（石膏密度ρgypsum=,,,2.3,kg/l,水的密度ρwater=,,1,kg/l,

,假定,,,,,,,,,

,吸收塔石膏浓度Cgypsum=,,,13,%,,,,,

,旋流器底流石膏浓度Cgypsum=,,,50,%,,,,,

,真空皮带机石膏浓度Cgypsum=,,,90,%,,,,,

,旋流器顶流石膏浓度Cgypsum=,,,3,%,,,,,

,17.1石膏浆液密度计算,,,,,,,,,

,,,,,,,,,,,

,,,,,,,,,,,

,ρs=,1.07930549,kg/l,,,,,,,

,取,ρs=,1.079,kg/l,,,,,,

,17.2旋流器底流密度计算,,,,,,,,,

,"ρs,hydrocyclone,underflow=",,,1.393939394,kg/l,,,,,

,取,"ρs,hydrocyclone,underflow=",,,1.394,kg/l,,,,

,17.3旋流器顶流密度计算,,,,,,,,,

,"ρs,hydrocyclone,overflow=",,,1.017249005,kg/l,,,,,

,取,"ρs,hydrocyclone,overflow=",,,1.017,kg/l,,,,

,17.4脱水石膏产量,,,,,,,,,

,mbeltfilter=,,,=,1333.333333,kg/h,,,,

,,,取,mbeltfilter=,1330,kg/h,,,,

,"mhydrocyclone,underflow=",,,,,=,2400,kg/h,,

,"Vhydrocyclone,underflow=",,,,,=,1.721664275,m³/h,,

,,,,取,"Vhydrocyclone,underflow=",,1.72,m³/h,,

,17.5吸收塔来石膏浆液计算,,,,,,,,,

,"mfrom,absorbor=mhydrocyclone,underflow+mhydeocyclone,overfloe",,,,,,,,,

,"mfrom,absorbor.Cgypsum=mhydrocyclone,underflow.Cgypsum,underflow+mhydeocyclone,overfloe.Cgypsum,overflow",,,,,,,,,

,联立以上方程组解得,,,,,,,,,

,"mfrom,absorbor=",,11280,kg/h,,,,,,

,"mgypsum=mfrom,absorbor.Cgypsum",,,,,,,,,

,mgypsum=,1466.4,kg/h,,取,mgypsum=,1466,kg/h,,

,"mwater=mfrom,absorbor-mgypsum=",,,9814,kg/h,,,,,

,"Vfrom,absorbor=",,,,=,10.45412419,m³/h,,,

,,,取,"Vfrom,absorbor=",,10.45,m³/h,,,

18,石灰石浆液供给,,,,,,,,,

,石灰石耗量mCaCO3=,,0.7,t/h,,,,,,

,假定石灰石浆液浓度CCaCO3=,,,30,%,,,,,

,石灰石固体密度ρCaCO3=,,,2.8,kg/l,,,,,

,18.1石灰石浆液质量流量,,,,,,,,,

,msuspension=,,,=,2.333333333,t/h,,,,

,,取,msuspension=,,2.33,t/h,,,,

,18.2石灰石浆液密度,,,,,,,,,

,,,,,,,,,,,

,,,,,,,,,,,

,ρsuspension=,,1.238938053,kg/l,,,,,,

,取,ρsuspension=,,1.24,kg/l,,,,,

,18.3石灰石浆液体积流量,,,,,,,,,

,Vsuspension=,,,=,1.879032258,m³/h,,,,

,,,取,Vsuspension=,1.88,m³/h,,,,

19,浆液池尺寸,,,,,,,,,

,假定浆液停留时间△t=,,,2,h,,,,,

,浆液罐体积,,,,,,,,,

,Vtank=Vsuspension.△t=,,3.76,m³,,,,,,

,D=(0.89.Vtank)1/3=,,1.495750938,m,,,,,,

,取,D=,1.5,m,,,,,,

,H=1.5×D=,,2.25,m,,,,,,

20,滤池箱尺寸计算,,,,,,,,,

,"假定滤布冲洗水量mwater,beltfilter=",,,5,t/h,,,,,

,以,50,%,的石膏质量流量作为石膏冲洗水量,,,,,,

,20.1滤液量,,,,,,,,,

,"mwater,filtrate=mwater,beltfilter+mwater,wash",,,,,,,,,

,"mwater,filtrate=",,5.6,t/h,,,,,,

,"Vwater,filtrate≈",,5.6,m³/h,,,,,,

,假定滤液箱停留时间△t=,,,1,h,,,,,

,20.2滤液箱容积,,,,,,,,,

,"Vtank=Vwater,filtrate.△t=",,,5.6,m³,,,,,

,D=(0.89.Vtank)1/3=,,1.708150023,m,,,,,,

,取,D=,1.7,m,,,,,,

,H=1.5×D=,,2.55,m,,,,,,

21,吸收塔尺寸的设计,,,,,,,,,

,21.1循环浆液流量,,,,,,,,,

,烟气流量Vwet=,,690000,Nm³/h,,,,,,

,二氧化硫浓度CSO2=,,932,mg/m³,,,,,,

,二氧化硫脱除率,,77,%,,,,,,

,假定液气比L/G=,,12,l/Nm³,,,,,,

,吸收塔出口净烟气温度T2=,,,48,°C,,,,,

,"Vwet,actual=",,,,,,,,,

,"Vwet,actual=",,842996.7051,Nm³/h,,,,,,

,取,"Vwet,actual=",,843000,Nm³/h,=,234.1666667,Nm³/s,,

,,,,取,"Vwet,actual=",,234,Nm³/s,,

,循环浆液流量,,,,,,,,,

,,,,10116,Nm³/h,,,,,

,设计喷淋塔层数为,,3,,,,,,,

,每层循环浆液流量,,,,,,,,,

,Q单循=,,3372,Nm³/h,=,0.936666667,Nm³/s,,,

,,,,取,Q单循=,0.937,Nm³/s,,,

,21.2吸收塔直径,,,,,,,,,

,假定吸收塔烟气流速ω=,,,3.7,m/s,,,,,

,d=,,,=,8.973505348,m,,,,

,,,取,d=,9,m,,,,

,21.3吸收塔循环区体积,,,,,,,,,

,假定循环浆液停留时间t=,,,4.3,min,,,,,

,Vabsorbersump=,,,724.98,m³,,,,,

,取,Vabsorbersump=,,725,m³,,,,,

,21.4吸收塔总高,,,,,,,,,

,浆液池位高度,,,,,,,,,

,H1=,,,11.39627988,m,,,,,

,,取,H1=,11.4,m,,,,,

,另外考虑到因注入氧化空气引起的吸收塔浆液液位波动，浆液液位高度增加,,,,,,,0.5,m,

,取,H1=,12,m,,,,,,

,浆液液面距入口烟道高度H2,,,,,,,,,

,考虑到浆液鼓入氧化空气和搅拌时液位有所波动，入口烟气温度较高、浆液温度较低可对进口管,,,,,,,,,

,底部有些降温影响，加之该区间需接近料管，H2一般定位800mm～1300mm范围为宜，此处,,,,,,,,,

,H2取,1.2,m,,,,,,,

,进口烟道高度H3=,,4,m,,,,,,

,进口烟道顶部距底层喷淋层高度H4=,,,,2.5,m,,,,

,喷淋层区域高度H5,,,,,,,,,

,设计喷淋层之间的间隔为,,,2,m,喷淋层数,3,层,,

,H5=,4,m,,,,,,,

,除雾区高度H6=,,4,m,,,,,,

,出口烟道高度H7=,,3,m,,,,,,

,吸收塔总高H=H1+H2+H3+H4+H5+H6+H7=,,,,30.7,m,,,,

22,喷淋层设计,,,,,,,,,

,单层喷淋层浆液流量Q单循=,,,3372,Nm³/h,=,937,L/s,,

,假定喷嘴流量为,,5,L/s,,,,,,

,n=,Q单循/5=,187.4,,,,,,,

,,取整为,188,,,,,,,

,假定单管可选最大直径Dmax=,,,0.06,m,,,,,

,喷淋管内最大流速Vmax=,,,15,m/s,,,,,

,单喷管最大流量,,,,,,,,,

,"Qmax,s=π/4.Dmax2.Vmax=",,,42.41150082,L/s,,,,,

,,取,Qmax=,42.4,L/s,,,,,

,单喷淋层主喷管数,,,,,,,,,

,,,23,,,,,,,

23,除雾器冲洗覆盖率,,,,,,,,,

,设计喷嘴数量n=,,90,喷射扩散角α=,,90,,,,

,除雾器有效流通面积A=,,,100,m2,,,,,

,冲洗喷嘴距除雾器表面垂直距离,,,0.8,m,,,,,

,冲洗覆盖率=,,,,,180.9557368,%,,,

,,,,,取,181,%,,,

24,烟道尺寸设计,,,,,,,,,

,24.1净烟气烟道直径,,,,,,,,,

,假定烟气出口流速ω=,,18,m/s,,,,,,

,d=,,,4.068428945,m,,,,,

,,,d=,4.1,m,,,,,

,24.2原烟气烟道直径,,,,,,,,,

,Vactual=,286.394838,Nm³/s,,,,,,,

,取,Vactual=,286,Nm³/s,,,,,,

,d=,,=,4.497817432,m,,,,,

,,取,d=,4.5,m,,,,,

25,增压风机烟气设计流量计算,,,,,,,,,

,"假定风机入口烟气温度Tfan,in=",,,135,°C,,,,,

,100%BMCR工况下风机入口处湿烟气流量,,,,,,,,,

,"Qfan,in=",690000,Nm³/h,,,,,,,

,"Qfan,in,act=",,,,322.7529135,Nm³/s,,,,

,,,取,"Qfan,in,act=",323,Nm³/s,,,,

26,增压风机总压损,,,,,,,,,

,假定吸收塔压损,,10,mbar,GGH压损,12,mbar,,,

,烟道压损,7,mbar,考虑,20,%的裕量,,,,

,△Pd=,34.8,mbar,,,,,,,

,取,△Pd=,35,mbar,=,3500,Pa,,,

27,"电机功率Pf,d",,,,,,,,,

,假定风机效率η1=,,85,%,电动机效率ηd=,,80,%,,

,增压风机所需功率Pf=,,,,1303.921569,kW,,,,

,,,取,Pf=,1