土木工程英语2课件_第1页
土木工程英语2课件_第2页
土木工程英语2课件_第3页
土木工程英语2课件_第4页
土木工程英语2课件_第5页
已阅读5页,还剩26页未读 继续免费阅读

下载本文档

版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领

文档简介

1.2DeterminateandIndeterminateStructures

静定和超静定结构StaticallyDeterminateStructuresStructuresaresaidtobestaticallydeterminatewhentheforcesandreactionsproducedbyagivenloadingcanbecalculatedusingonlytheequationsofequilibrium.StaticallydeterminatestructureStaticallyDeterminateStructuresThesimplysupportedbeamshowninFigure1.3isstaticallydeterminate.Wecansolveforthethreeunknownreactionsusingtheequationsofequilibriumandthencalculatetheinternalforcessuchasbendingmoment,shearforce,andaxialforceatanygivenlocationalongthelengthofthebeam.StaticallydeterminatestructureStaticallyIndeterminateStructuresFourunknownreactionsThreeindependentequilibriumequations,StaticallyIndeterminateStructuresStaticallyindeterminatebeamSaticallyindeterminateframeSaticallyindeterminatecompositeStructuresForceMethod力法Theforcemethod(alsocalledtheflexibilitymethod)isusedtocalculateinternalforcesandreactionsinstaticallyindeterminatestructuresduetoloadsandimposeddeformations.ForceMethod力法Thestepsintheforcemethod1.Determinethedegreeofstaticalindeterminacyofthestructure.Parameternwillbeusedtodenotethedegreeofindeterminacy.确定超静定次数

FPFPFAxFAyMAX1静定结构AABBCCThestepsintheforcemethod2Transformthestructureintoastaticallydeterminatesystembyreleasinganumberofstaticalconstraintsequaltothedegreeofstaticalindeterminacy,n.FPFPFAxFAyMAX1基本体系AABBCCprimarysystemThestepsintheforcemethodThisisaccomplishedbyreleasingexternalsupportconditionscreatinginternalhinges.Thesystemthusformediscalledtheprimarysystem.Numberthereleasedconstraintsfrom1ton.primarysystemqqqAABBCCllX1X1b)基本体系a)一次超静定结构3.Foragivenreleasedconstraintj,introduceanunknownredundant[ri5dQndEnt]force

Xj

correspondingtothetypeanddirectionofthereleasedconstraint.多余未知力redundantforce

基本体系沿多余未知力方向的位移应与原结构位移相同FPFPFAxFAyMAX1基本体系AABBCCqqqAABBCCllX1X1X14.Applythegivenloadingorimposeddeformationtotheprimarysystem.Calculatedisplacements

duetothegivenloadingateachofthereleasedconstraintsintheprimarysystem.ThesedisplacementsarecalledΔ1P

,Δ2P

,ΔnP

..,.FPAABBCΔ1PX1ABX1=1d11Δ11

=d11X1FPABCEIl/2l/2X1基本体系(Δ1=ΔB=0)=+5.Foragivenreleasedconstraint

j,applyaunitload

Xj

=1

totheprimarysystem.Calculatedisplacementsdueto

Xj

=1

ateachofthereleasedconstraintsintheprimarysystem.Thesedisplacementsarecalled

,,ABX1=1d11FPABCEIl/2l/2X1基本体系(Δ1=ΔB=0)=FPAABBCΔ1PX1Δ11

=d11X1+unitload单位力,...,.

6.Solveforredundantforcesx1throughxnbyimposingthecompatibilityconditionsoftheoriginalstructure.Theseconditionstransformtheprimarysystembacktotheoriginalstructurebyfindingthecombinationofredundantforcesthatmakedisplacementateachofthereleasedconstraintsequaltozero.CalculateforceSatagivenlocationinthestructureusingForcecanbebendingmoment,shear,axialforce,orreaction.TheClassicalDisplacementMethodTheforcemethod:unknownsareforcequantities(theredundantforces)basedongeometricalconditions(compatibilityconditionsatthelocationofeachredundantforce).Theclassicaldisplacementmethodunknownsaredisplacementquantitiesbasedonstaticalconditions(equilibriumconditions).=Z1↷R211234↷134P↷R2P12234R22R12R11R1PZ2Thestepsintheclassicaldisplacementmethod1.Foragivenstructureandloading,considerthejointstobefullyfixedagainstrotation.PL1234EI=常数Z1Z2(a)(b)基本结构1234=Z1Z2↷R1=0=0PR2Thestepsintheclassicaldisplacementmethod2.Calculatethemomentsineachmemberofthestructureduetothegivenloads,R1P

,R2P,assumingfullfixityatthejoints.Thesemomentsarecalledfixed-endmoments.3.Calculatemomentsr11、r12attheendsofeachmemberduetounitdisplacementsofthejoints.4.Expressthetotalmomentateachendofagivenmemberasthesumofthefixed-endmoments

MP

,andtheproductofunknownjointdisplacements

z1,z2

timesthemomentsM1、M2

producedbyunitjointdisplacementsZ1,Z2,calculatedinStep3.5.Generateanequationofmomentequilibriumateachjoint.

基本结构在荷载等外因和结点位移的共同作用下,每一个附加联系中的附加反力矩或反力都应等于零(静力平衡条件)。6.Solvethesystemofequationsfortheunknownjointdisplacements.

7.CalculatethememberendmomentsusingtheexpressionsderivedinStep4andthevaluesofjointdisplacementscalculatedinStep6.r11Z1+r12Z2+R1P=0r21Z1+r22Z2+R2P=0r11Z1+r12Z2+R1P=0r21Z1+r22Z2+R2P=0R1=R11+R12+R1P=0R2=R21+R22+R2P=08.Calculateallremainingforcesinthestructure(shearforcesandaxialforces).Forcemethodcansolveallstaticallyindeterminatestructures.computationalcomplexityprohibitiveforstructureswithmorethanthreeunknownforces.Classicaldisplacementmethodallowsasolutionbasedonamember-by-memberprocedure,ratherthanonethatrequiresconsiderationofthestructureasawhole;basedonthepre-solutionofstandardcasesofintermediate媒介物loadanddisplacementreducethenumberofunknownsinagivensolution.MomentDistributionMethod

力矩分配法Themomentdistributionmethodisusedforstaticallyindeterminatebeamsandframesbysimplehandcalculations.Thisisbasicallyaniterative[5itErEtiv]迭代的process.Theprocedureinvolvesartificiallyrestrainingtemporarilyallthejointsagainstrotationandwritingdownthefixedendmomentsforallthemembers.restrainallthejointsagainstrotationWritedownthefixedendmomentsThejointsarethenreleasedonebyoneinsuccession[sEk5seFEn]连续.Ateachreleasedjointtheunbalancedmomentsaredistributedtoalltheendsofthemembersmeetingatthatjoint.Acertainfractionofthesedistributedmomentsarecarriedovertothefarendsofmembers.Thereleasedjointisagainrestrainedtemporarilybeforeproceedingtothenextjoint.Thesamesetofoperationsarecarriedoutateachjointtillal

温馨提示

  • 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
  • 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
  • 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
  • 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
  • 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
  • 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
  • 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。

评论

0/150

提交评论