云南省高三语文第二次高中毕业生复习统一检测测试(理)人教版-1375

2022年云南省第二次高中毕业生复习统一检测数学试题（理）本试卷分第I卷（选择题）和第II卷（非选择题）两部分考试结束后，将本试卷第答题卡一并交回满分150分，考试用时120分钟第Ⅰ卷（选择题，共60分）注意事项：1．答题前，考生务心用黑色碳素笔将自己的姓名、准考据号、考场号、座位号在答题卡上填写清楚，并仔细批准条形码上的准考据号、姓名、考场号、座位号及科目，在规定的地点贴好条形码2．每题选出答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑如需变动，用橡皮擦洁净后，再选涂其余答案标号答在试卷上的答案无效参照公式：如果事件A、B互斥，那么S4R2V球4R3Pn(k)CnkPk(1P)nka1a312,那么a263~B(n,p),且E12,D12,4243M(x0,y0)55555x2y2r2x0xy0yr2x2y2r2(1i)22ia3e12e2,bxe13e2ab99l22b//,c//b//,cb,cb,c//f(x)3x2,x0f(x1)1,x0f(4)4x24yx24yABAC30334911f1(x),f1(x)log3(x3)f(x12)0422ysin(2x6)ysin(2x)61212ABCPAPBPCABPBC6ABC3211x41(ax1)6r1:r21:2S1:Slimx3ax2x3b,43232xx3x3limanbn1ABCm(1,sin(BA))n(sinCsin(2A),1).an1bnnc2,C,且ABC的面积S3,mn,ABC32ay3x|OA|2|OB|24|OA|2|OB|2l:ykx430,证明:lna1f(x)x2ln(12x).ba(ab)(ab1).2x3b1f(x)x0,使f(x0)x0,yf(x)yf(x)yf(x)ab2x7x1且x7f(x)a与8(xa)an1且an7,a11an1f(an)22f(x)bxb22ABC的面积等于3,a2b2ab4,13.a2b2ab4,2,b2.absinCab4,解得a2ab4.a2.mn,sinCsin2Asin(BA)0.cosA(sinBsinA)0.csoA0或sinBsinA0.cosA0时,A2,ABCsinBsinA0时,即sinBsinAba,ABCABCab50473.60.12.P(xD且yB)P(xD)P(yB).bab7b4.50b10b4,解得b505050ab3,1.a2.a2,b1.PDC505050CEDP.ABC中,BCE90,BC2,CE3,tanCEBBC2323.⊥CD交AB于M，CE3,arctan3以O为原点，OM、OC、PD(0,1,3),BC(2,0,0).1,3),OP(0,0,3)PDBC0,PDBC;E(0,PCD22PDBC.CEPD.BD(2,2,0),BP|BD||BP|22.BEPD.arccos21.x2y27a2b2

(2,1,EB(2,3,3),EC(0,3,3),3),2222CEBEBEC21.cosBEC|EB||EC|7b3y21,a3.x2kx4a1,b1.l:ya2b24a2b2330、N对于直线对称，由lMN,直线MN的方程为y1xm,k则M、N两点的坐标知足方程组y1xm,消去得(32222k1)x2kmx(m3)k0.k3x2y23.显然3210,k(2km)24(3k21)[(m23)k2]0.即k2m23k210.设线段MN中点为D(x0,y0),x0km,则3k213k2m.y03k21D(x0,y0)在直线l:ykx4上,3k2mk2m10分3k213k24.1即2m321.kkk2m3k21k2m23k2.10k2m2mk20,解得m0或m1.3k210或3k211.k2k2k21或k21.34|k|3或|k|1,且k0.32(,3)(1,0)(0,1)(3,)1232232112I()2ln(12),fxxx12x0.x1,{x|xR,x12}.22f'(x)2x12x4x22x2,212xf'(x)0x1得4x22x20.2x1,1x1.222当1x1时,函数f(x)4221得f'(x)0且x4x22x20.2x1,x1.22当x1时,函数f(x)62当x1时,函数f(x)2f(1)1ln2.241f(x)7ln2.4IIba0,b1a11.222Ix1时,函数f(x)2f(b1)f(a1).22(b1)2ln[12(b1)](a1)2ln[12(a222lna1(ab)(ab1).b1lna1(ab)(ab1).b12212I2x3x,2x25x30.2x7x11,x23.212x3x1,x23是方程x22x71,x2函数yf(x)x13.2IIIa3,b1,2x3238x24x32x782x311.xx12x7222f(x)a与8(xa)f(x)bxbIIIan1且an7,22IIf(an)38(an3),f(an