程序设计语言a2010期中试卷参

上海交 大 试卷（A）参考答（2009至2010学年第_二_学期期中考班级 学 课程名称 成绩 一．填空题（每题1分，共10分C++源文件名的后缀是 编写C++语言源程序并上机运行的一般过程为编辑、编译、和执行。其中，编辑的件，的作用是将此目标文件与被调用到的其他目标文件在一起。如果A是已经定义好的一个类，r2是A类的一个对象，p是指向A类对象的指针。执pnewA(r2)时，系统会自动调用拷贝构造函数，执行deletep系统会自动调用析构函数。5。类的私有成员只能通过它的成员函数以及来。无论哪种派生方法，基类中的私有成员既不许外部函数，也不许派生类中的成员函数。6。公有继承时，基类的保护成员在派生类中是保护成员成员，基类中的公有成员在派生类中是公有成员成员。承诺人 二．看程序，写结果（每题5分，共30分）1．写出下列程序执行结果【构造函数和析构函数的顺序】 Point{ x,Point(inta=1,intb={x=a;y=cout<<"Point("<<x<<","<<y<<")"<<}~Point(){cout<<"Point["<<x<<","<<y<<"]"<<endl; Point { origin,*pp=newPoint(3,{Pointpoint1(-5,}Pointpoint2(1,2);deletepp;return}class{friendostream&operator<<(ostream&os,constCST&ob);CST(intv1=0){data=v1;++count;cout<<“constructing“<<data<<~CST(){ count--;cout<<“deconstructing“<<data<<endl;}operatorint()const{returndata;}staticintcount;intostream&operator<<(ostream&os,constCST&ob{os<<"data="<<os<<“,count=”<<ob.count<<endl;returnos;}ConstructingCST::count=ConstructingCST::count=Constructingdata=4,count=deconstructingCST::count=1Constructing10deconstructing10data=10,count=1deconstructingint{CSTcs,intcout<<"CST::count="<<CST::count<<ptr1=newcout<<deletecout<<"CST::count="<<CST::count<<ptr2=*ptr2=cout<<value=cout<<value<<return}}class{intx,y;coord(inti=0,intj=0){x=i;y=j;voidprint(){cout<<"x:"<<x<<",y:"<<y<<endl;}coordoperator++(){++x;return*this;}coordoperator++(intn){coordtmp=*this;++y;returnx:x:5,y:x:5,y:x:5,y:int{coord(ob++).print();print2（x=5,y=10ob.print();operator++(intny1，xx=5,y=11return}classcomplexintreal;//intimag;//complex(intr=0,inti=0){real=r;imag=complex(constcomplex&t){real=t.real+2;imag=t.imag+1;}voidshow(){cout<<real<<"+"<<imag<<"I";}};void{complex c2=cout<<c1= 赋值运算，调用的是默认的赋值函数，c2的成员变量值赋给c1。写出下列程序的执行结果classC_AC_A(charvalue=‘@’){data cout<<"Object"<<data<<"constructor" C_A(constC_A&obj){ obj.data+cout<<"Object"<<data<<"constructor"{cout<<"Object"<<data<<"destructor"<<endl;} ObjectaconstructorObject8constructorObject9constructorObjectmconstructorObjectmdestructorObject8destructorObjectbconstructorObjectObjectaconstructorObject8constructorObject9constructorObjectmconstructorObjectmdestructorObject8destructorObjectbconstructorObjectmconstructorObjectmdestructorObjectbdestructorObjectadestructorObject9destructor staticC_Af // Objectbconstructorintmain(){C_Areturn}classCBaseCBase(int{m_data=cout<<"ConstructorofCBase.m_data="<<m_data}virtual~CBase(){cout<<"DestructorofCBase.m_data="<<m_data<<endl;}virtualvoidprint(){cout<<"CBase::m_data="<<m_data<<endl;}intclassCDerived:public{CDerived(int

{cout<<"ConstructorofCDerived."<<endl;）~CDerived(){cout<<"DestructorofCDerived."voidprint(){cout<<"CDerived::m_data="<<m_data<<endl;}intint{CBase*p=newCDerived(67),baseObj=p-ConstructorofCBase.m_data=63ConstructorofCDerived.deletereturn}DestructorofDestructorofCBase.DestructorofCBase.二．程序填空（每空2分，共30分classA{ operator==(constA&a1constA&a2)//判两数据成员指向的对象相{return *(a1.a)==*(a2.a) ;}A(intaa0a newint(aa) //aa初始化aA A&obj a=new *a= } delete }//释放动态空int*在如下Rational类的基础上又定义了一个Complex类。复数类具有输入输出和加能。classRationalfriendistream&operator>>(istream&in,Rational&obj);//friendostream&operator<<(ostream&os,constRational&obj);//输出重载函数friendRationaloperator+(constRational&r1,constRational&r2运算符重载friendRationaloperator*(constRational&r1,constRational&r2);//*运算符重载intnum;intden;void Rational(intn0,intd1)numn;dend;ReductFraction();}operatordouble //double型{ (double(num)/den);classfriendComplexoperator+(constComplex&x,constComplex&y)；friendistream&operator>>(istream&is, Complex&obj friendostream&operator<<(ostream&os,constComplex&obj);Rationalreal; Rational Complex(intr1=0,intr2=1,inti1=0,inti2= real(r0,r1),imag(i1, Complexoperator+(constComplex&x,constComplex{Complextmp.real=x.real+ tmp.imag=x.imag+y.imag }三。编程（每题10分，共30分int //输出：10 //输出：21 //输出：为1号服务 //输出：30 //3return} 4构造函 2Come函 2Go函 2classintco{covoid{co}void{if(com-goNum==0) } void{Aa1(3,15),a2(2,5),a3,a3=a1+a2;a4=a1-a2;cout<<a3;cout<<a4}