人教版二年级下册被除数、除数、商和余数的关系习题

1、1、写出五个商是6,余数4的有余数除法算式。()+ ()=64()+ ()=64()+ ()=64()+ ()=64()+ ()=642、当余数最大时，求被除数。 TOC o 1-5 h z ()+7=9()()+9=3()()+6=4()()+8=5()()+9=8()3、当除数最小时，求被除数？()-()=98()-()=36()-()=57()-()=84().-()=65 TOC o 1-5 h z 4、求除数。29+()=7174+()=8251+ ()=8359+()=6535+()=435、当除数最小时，求被除数。()+()=4 5()+()=57()+()=83()+()=9

2、46、求被除数()+ 6=52()+ 5=54()+ 6=53()+ 9=8645+ () =7332+ () =5235+ () =8326+ () =3522+ () =4251+() =6337+()=9154+()=7545+()=7.332+()=5.235+()=8.326+()=3.522+ () =4.251+() =6.337+()=9.154+()=7.58、求出下列算式中的被除数。()田=3.2()+4=7.3()+7=3.4()4=7.5()田=4.5()y=9.1()y=6.3()+8=9.69、下列算式中，除数和商各是多少？ 19+()=()5 TOC o 1-5

3、h z 47+()=()222+()=()634+()=()425+()=()710、列式计算。1、被除数是57,除数是7,商和余数各是多少?2、已知除数是5,商是4,余数是2,被除数是多少?7、求出下列算式中的除数。3、被除数是41,商是5,除数和余数各是多少？4、被除数是23,商是5,余数是3,除数是多少?22+3 =20+ 6 =12+7=61 +7 =14+3 =24+ 7 =14+ 8=26 +3 =7+2=28+6 =16+ 8=12 +9 =9+2=32+6 =13+ 3=20 +9 =19+3 =15+ 6 =21 + 4=26 +8 =20+3 =32+9 =22+4=23

4、+5 =23+3 =4+ 3=25+ 4=47 +6 =29+5 =6+ 4=34+ 4=34 +5 =37 +5 =8+3=17+ 5=37 +7 =36+5 =14+ 3 =16+3=36 +7 =14+4 =22+3 =27+2=18 +4 =18+4 =27+ 3 =36+ 5=32 +9 =12+5 =22+5 =45+ 7=45 +7 =16+5 =32+5 =36+ 7=14 +4 =9+ 5=32+5 =17+ 5=41 +5 =10+3 =4+ 3=10+ 7=14 +3 =12+5 =8+3=12+7=13 +8 =14+3 =12+5 =12+7=30 +8 =16+3 =16+ 3 =18+7=23 +7 =3+2=10+ 6 =28 + 8 =41 +8 =12696865341631104170461877252979+ 5 =+ 8