《路面结构设计原理》作业2010[1].12.30

1、路面结构课程设计 谭诗亮 1、背景基于KENLAYER计算机程序的路面结构设计。2、 输入数据KENLAYER程序中菜单栏的目录项依次输入下列数据。General MATL=1，NDAMA=0，NPY=1，NLG=1，DEL=0.001，NL=3，NZ=3，ICL=80，NSTD=9,NBOND=1，NLBT=1，NLTC=1，NUNIT=1Zcoord ZC1=1，ZC2=9.9，ZC3=15.1Layer TH1=10，TH2=15， PR1=0.35，PR2=0.35，PR3=0.45Moduli E1=700000，E2=300000，E3=20000，Load LOAD=1，CR=1

2、0，CP=700，YW=30，XW=0，NP OR NPT=2 XPT1=0, YPT1=-10, XPY2=0, YTP2=15基于上述基数，变换base厚度，同时设两个时期，E：60 ，E：-10 输出结果如下： 以h15.1为例，表示h=15时，60下的结果输出，如下：INPUT FILE NAME -C:KENPAVEh15.1.DATNUMBER OF PROBLEMS TO BE SOLVED = 1 TITLE -h152MATL = 1 FOR LINEAR ELASTIC LAYERED SYSTEMNDAMA = 0, SO DAMAGE ANALYSIS WILL NOT

3、 BE PERFORMEDNUMBER OF PERIODS PER YEAR (NPY) = 1 NUMBER OF LOAD GROUPS (NLG) = 1 TOLERANCE FOR INTEGRATION (DEL) - = .001 NUMBER OF LAYERS (NL)- = 3 NUMBER OF Z COORDINATES (NZ)- = 3 LIMIT OF INTEGRATION CYCLES (ICL)- = 80 COMPUTING CODE (NSTD)- = 9 SYSTEM OF UNITS (NUNIT)-= 1 Length and displaceme

4、nt in cm, stress and modulus in kPaunit weight in kN/m3, and temperature in CTHICKNESSES OF LAYERS (TH) ARE : 10 15 POISSON'S RATIOS OF LAYERS (PR) ARE : .35 .35 .45 VERTICAL COORDINATES OF POINTS (ZC) ARE: 1 9.9 25.1 ALL INTERFACES ARE FULLY BONDEDFOR PERIOD NO. 1 LAYER NO. AND MODULUS ARE : 1

5、7.000E+05 2 3.000E+05 3 2.000E+04LOAD GROUP NO. 1 HAS 2 CONTACT AREASCONTACT RADIUS (CR)- = 10 CONTACT PRESSURE (CP)- = 700 NO. OF POINTS AT WHICH RESULTS ARE DESIRED (NPT)- = 2 WHEEL SPACING ALONG X-AXIS (XW)- = 0 WHEEL SPACING ALONG Y-AXIS (YW)- = 30 RESPONSE PT. NO. AND (XPT, YPT) ARE: 1 0.000 -1

6、0.000 2 0.000 15.000PERIOD NO. 1 LOAD GROUP NO. 1 POINT VERTICAL VERTICAL VERTICAL MAJOR MINOR INTERMEDIATE DISPL. PRINCIPAL PRINCIPAL PRINCIPAL NO. COORDINATE (HORIZONTAL STRESS STRESS STRESS STRESS P. STRAIN) (STRAIN) (STRAIN) (STRAIN) (STRAIN) 1 1.00000 0.16026 337.592 701.439 169.481 662.674 (ST

7、RAIN) 2.618E-04 -1.157E-04 5.860E-04 -4.399E-04 5.112E-04 1 9.90000 0.15909 176.331 274.446 -144.993 -111.160 (STRAIN) -2.888E-04 3.309E-04 5.201E-04 -2.888E-04 -2.235E-04 1 25.10000 0.15056 38.840 42.593 7.376 8.964 (STRAIN) -7.912E-04 1.490E-03 1.762E-03 -7.912E-04 -6.761E-04 2 1.00000 0.17562 1.3

8、34 608.622 1.333 410.986 (STRAIN) 2.821E-04 -5.079E-04 6.633E-04 -5.079E-04 2.821E-04 2 9.90000 0.17711 137.955 137.955 -146.987 132.767 (STRAIN) -3.453E-04 2.042E-04 2.042E-04 -3.453E-04 1.942E-04 2 25.10000 0.16736 48.689 48.689 8.058 13.392 (STRAIN) -9.939E-04 1.952E-03 1.952E-03 -9.939E-04 -6.07

9、2E-04 POINT VERTICAL NORMAL X NORMAL Y SHEAR XY SHEAR YZ SHEAR XZ STRESS STRESS STRESS STRESS STRESS NO. COORDINATE (STRAIN) (STRAIN) (STRAIN) (STRAIN) (STRAIN) 1 1.00000 6.627E+02 5.333E+02 0.000E+00 -2.473E+02 0.000E+00 (STRAIN) 5.112E-04 2.618E-04 0.000E+00 -9.539E-04 0.000E+00 1 9.90000 -1.450E+

10、02 -1.304E+01 0.000E+00 -1.679E+02 0.000E+00 (STRAIN) -2.888E-04 -3.430E-05 0.000E+00 -6.478E-04 0.000E+00 1 25.10000 7.376E+00 1.272E+01 0.000E+00 -1.059E+01 0.000E+00 (STRAIN) -7.912E-04 -4.040E-04 0.000E+00 -1.535E-03 0.000E+00 2 1.00000 6.086E+02 4.110E+02 0.000E+00 0.000E+00 0.000E+00 (STRAIN)

11、6.633E-04 2.821E-04 0.000E+00 0.000E+00 0.000E+00 2 9.90000 -1.470E+02 1.328E+02 0.000E+00 0.000E+00 0.000E+00 (STRAIN) -3.453E-04 1.942E-04 0.000E+00 0.000E+00 0.000E+00 2 25.10000 8.058E+00 1.339E+01 0.000E+00 0.000E+00 0.000E+00 (STRAIN) -9.939E-04 -6.072E-04 0.000E+00 0.000E+00 0.000E+00 从上述输出结果

12、可以看出，在E=700MPa的情况下，A点压应变(VERTICAL STRAIN)=1.952E-03，B点拉应力(NORMAL X STRESS)=-1.470E+02，C点剪应力(SHEAR YZ STRESS)=-2.473E+02。（见图中灰底部分数据） 以h15.2为例，表示h=15时，-10下的结果输出，如下：INPUT FILE NAME -C:KENPAVEh152.DATNUMBER OF PROBLEMS TO BE SOLVED = 1 TITLE -h152MATL = 1 FOR LINEAR ELASTIC LAYERED SYSTEMNDAMA = 0, SO D

13、AMAGE ANALYSIS WILL NOT BE PERFORMEDNUMBER OF PERIODS PER YEAR (NPY) = 1 NUMBER OF LOAD GROUPS (NLG) = 1 TOLERANCE FOR INTEGRATION (DEL) - = .001 NUMBER OF LAYERS (NL)- = 3 NUMBER OF Z COORDINATES (NZ)- = 3 LIMIT OF INTEGRATION CYCLES (ICL)- = 80 COMPUTING CODE (NSTD)- = 9 SYSTEM OF UNITS (NUNIT)-=

14、1 Length and displacement in cm, stress and modulus in kPaunit weight in kN/m3, and temperature in CTHICKNESSES OF LAYERS (TH) ARE : 10 15 POISSON'S RATIOS OF LAYERS (PR) ARE : .35 .35 .45 VERTICAL COORDINATES OF POINTS (ZC) ARE: 1 9.9 25.1 ALL INTERFACES ARE FULLY BONDEDFOR PERIOD NO. 1 LAYER N

15、O. AND MODULUS ARE : 1 1.000E+07 2 3.000E+05 3 2.000E+04LOAD GROUP NO. 1 HAS 2 CONTACT AREASCONTACT RADIUS (CR)- = 10 CONTACT PRESSURE (CP)- = 700 NO. OF POINTS AT WHICH RESULTS ARE DESIRED (NPT)- = 2 WHEEL SPACING ALONG X-AXIS (XW)- = 0 WHEEL SPACING ALONG Y-AXIS (YW)- = 30 RESPONSE PT. NO. AND (XP

16、T, YPT) ARE: 1 0.000 -10.000 2 0.000 15.000PERIOD NO. 1 LOAD GROUP NO. 1 POINT VERTICAL VERTICAL VERTICAL MAJOR MINOR INTERMEDIATE DISPL. PRINCIPAL PRINCIPAL PRINCIPAL NO. COORDINATE (HORIZONTAL STRESS STRESS STRESS STRESS P. STRAIN) (STRAIN) (STRAIN) (STRAIN) (STRAIN) 1 1.00000 0.11582 333.676 2049

17、.151 253.664 1673.241 (STRAIN) 7.592E-05 -9.412E-05 1.375E-04 -1.049E-04 8.673E-05 1 9.90000 0.11566 61.816 64.931 -2131.948 -1496.364 (STRAIN) -1.631E-04 1.331E-04 1.335E-04 -1.631E-04 -7.729E-05 1 25.10000 0.11118 20.780 21.965 4.796 5.408 (STRAIN) -3.761E-04 7.828E-04 8.686E-04 -3.761E-04 -3.317E

18、-04 2 1.00000 0.12383 -0.773 2324.611 -0.773 1785.773 (STRAIN) 9.724E-05 -1.439E-04 1.700E-04 -1.439E-04 9.724E-05 2 9.90000 0.12378 70.720 70.720 -2563.319 -1706.254 (STRAIN) -1.991E-04 1.565E-04 1.565E-04 -1.991E-04 -8.338E-05 2 25.10000 0.11825 24.450 24.450 5.025 6.256 (STRAIN) -4.396E-04 9.687E

19、-04 9.687E-04 -4.396E-04 -3.504E-04 POINT VERTICAL NORMAL X NORMAL Y SHEAR XY SHEAR YZ SHEAR XZ STRESS STRESS STRESS STRESS STRESS NO. COORDINATE (STRAIN) (STRAIN) (STRAIN) (STRAIN) (STRAIN) 1 1.00000 2.049E+03 1.593E+03 0.000E+00 -3.274E+02 0.000E+00 (STRAIN) 1.375E-04 7.592E-05 0.000E+00 -8.839E-0

20、5 0.000E+00 1 9.90000 -2.132E+03 -1.493E+03 0.000E+00 -6.967E+01 0.000E+00 (STRAIN) -1.631E-04 -7.687E-05 0.000E+00 -1.881E-05 0.000E+00 1 25.10000 4.796E+00 6.593E+00 0.000E+00 -4.267E+00 0.000E+00 (STRAIN) -3.761E-04 -2.458E-04 0.000E+00 -6.187E-04 0.000E+00 2 1.00000 2.325E+03 1.786E+03 0.000E+00

21、 0.000E+00 0.000E+00 (STRAIN) 1.700E-04 9.724E-05 0.000E+00 0.000E+00 0.000E+00 2 9.90000 -2.563E+03 -1.706E+03 0.000E+00 0.000E+00 0.000E+00 (STRAIN) -1.991E-04 -8.338E-05 0.000E+00 0.000E+00 0.000E+00 2 25.10000 5.025E+00 6.256E+00 0.000E+00 0.000E+00 0.000E+00 (STRAIN) -4.396E-04 -3.504E-04 0.000

22、E+00 0.000E+00 0.000E+00从上述输出结果可以看出，在E=700MPa的情况下，A点压应变(VERTICAL STRAIN)=9.687E-04，B点拉应力(NORMAL X STRESS)=-2.563E+03，C点剪应力(SHEAR YZ STRESS)=-3.274E+02。（见图中灰底部分数据）3、 分析讨论A、对高速公路，一级公路，二级公路沥青混凝土面层和半刚性材料的基层和底基层，应验算拉应力是否满足容许拉应力的要求，如不满足，调整路面结构层厚度，或变更路面结构，或调整配合比，提高材料的极限抗拉厚度，重新计算。采用弹性多层体系理论编制的程序进行。对于冰冻地区，尚应

23、验算防冻厚度是否满足要求。 分析全部输出结果，并且列出各种基层厚度在不同模量情况下A、B、C点的应力应变情况，列表如下：基层厚度A点压应变(VERTICAL STRAIN)B点拉应力(NORMAL X STRESS)C点剪应力(SHEAR YZ STRESS)E=700MPaE=10000MPaE=700MPaE=10000MPaE=700MPaE=10000MPah=151.952E-039.687E-04-1.470E+02-2.563E+03-2.473E+02-3.274E+02h=201.564E-038.604E-04-8.183E+01-2.260E+03-2.431E+02-3

24、.213E+02h=251.274E-037.539E-04-5.312E+01-2.037E+03-2.406E+02-3.168E+02h=301.052E-036.585E-04-4.103E+01-1.874E+03-2.390E+02-3.136E+02h=358.809E-045.762E-04-3.690E+01-1.755E+03-2.379E+02-3.113E+02h=407.463E-045.061E-04-3.664E+01-1.667E+03-2.372E+02-3.096E+02h=456.391E-044.466E-04-3.826E+01-1.602E+03-2

25、.367E+02-3.083E+02考察上述数据，找出在两种不同模量情况下满足c 0.5mpa ，b1.5 mpa ，a9.7mic 的厚度。从上表可以看出，从h=35起，A点压应变满足要求，C点剪应力也满足要求，B点拉应力在E=700MPa时也满足要求，仅仅B点拉应力在E=10000MPa时不满足要求，且基层厚度达到最大h=45时B点拉应力在E=10000MPa时也不满足要求。因此需要改变面层厚度。B、沥青面层和半刚性基层底面拉应力验算指标是用于避免结构层的不合理组合或材料的不合理选用，引起相对薄弱环节处出现某种类型的破坏，所以设置了相应的单项控制指标。但是在层间接触为连续的情况下，沥青面层

26、底面的应力虽处于受压状态，在层间接触为滑动的情况下，沥青面层底面的应力虽处于受拉状态，但沥青面层的疲劳寿命仍大于半刚性基层，因而，沥青面层底面拉应力验算指标在设计中不会起控制作用。我国沥青路面设计体系采用的是力学-经验法，其路面模型借鉴于SHEL的理论设计法，把路面作为一种多层弹性体系。设计弯沉是表征路面整体刚度大小的指标，是路面厚度设计的主要依据，层底拉应力作为验算指标。更改设计参数，重新输入设计数据，即可输出数据。下面列出在基层厚度h=35，面层厚度h0=12；基层厚度h=35，面层厚度h0=13；基层厚度h=40，面层厚度h0=12三种情况下A、B、C点的应力应变情况。分析讨论是否满足要求。基层厚度（h）面层厚度（h0）A点压应变(VERTICAL STRAIN)B点拉应力(NORMAL X STRESS)C点剪应力(SHEAR YZ STRESS)E=700MPaE=10000MPaE=700MPaE=10000MPaE=700MPaE=10000MPah=35(h0=12)8.110E-044.879