程式检定题库解答程度基本

1、【程式檢定題庫解答程度：基本】A1、#include #include int main(void) int n,i=1,fact=1;/* 設定迴圈初值 */ do printf(請輸入n值 (n0): ); scanf(%d,&n); while (n=0);/* 當n=0時重複輸入n的值 */ do fact*=i+; while (i = n);/* 當i=n時執行累乘的動作 */ printf(%d!=%dn,n,fact); system(pause); return 0;A2、#include #include int main(void) /* i、j 為迴圈變數, n 是多項

2、式項數, sum 是總和 */ int i,j,n,sum=0; printf(計算多項式 (1+2)+(2+4)+(3+6).+(n+2*n) 的值n); printf(請輸入 n 值n); scanf(%d,&n); for(i=1,j=2;i=n,j=2*n;i+,j=j+2) /* 兩個變數的迴圈 */ sum=sum+(i+j);/* 計算總和 */ printf(%d+%d)+,i,j);/* 將多項式每一項從螢幕輸出 */ printf(b = %dn,sum); system(pause); return 0;A3、#include #include int main(void

3、) int num,n; printf(請輸入一個正整數: ); scanf(%d,&num); printf(%d的因數有 ,num); for(n=1;n=num;n+) if(num%n=0) printf(%d ,n); system(pause); return 0;A4、01 #include 02 #include 0304 int main(void)05 06 int i,num,sum=0;07 int x,y,z;0809 printf(Armstrong 數有 );10 for(num=100;num=999;num+)11 12 sum=0;13 x=num/100;

4、14 y=(num/10)%10;15 z=(num%100)%10;16 sum=x*x*x+y*y*y+z*z*z;17 if(sum=num)18 printf(%d ,num);19 2021 system(pause);22 return 0;23 /* OUTPUT-Armstrong 數有 153 370 371 407-*/A5、#include #include int palindrome(unsigned n);int reverse(unsigned n);main()unsigned n;printf(Please enter a positive integer:)

5、;while(scanf(%d,&n)if(palindrome(n)=1)printf(%d is a palindrome.n,n);elseprintf(%d is not a palindrome.n,n);printf(Please enter a positive integer:);return 0;int palindrome(unsigned n)if(n=reverse(n)return 1;elsereturn 0;int reverse(unsigned n)int reverse=0,a=0,b,i;for(i=1;i1)b=pow(10,a-1);reverse=r

6、everse+n%10*b;n/=10;a-;reverse+=n;return reverse;A6、#include main()int n,count,i,mask=1,x=0;count=8*sizeof(int)-1;printf(Please enter an integer, or enter -1 to exit:);while(scanf(%d,&n)&(n!=-1)printf(bit 1 at );for(i=0;i=count;i+)if(maski&n)!=0)printf(%d,i);printf(bn);for(i=0;i=count;i+)if(maski&n)

7、!=0)x=x+1;printf(bit 1 has %dn,x);x=0;printf(Please enter an integer, or enter -1 to exit:);if(x=-1)break;return 0;A7、#include #include using namespace std;void find(int , int, double *, double *); int main(void) int a, b; double aMean, gMean; cout a; cout b; cout endl; find(a, b, &aMean, &gMean); c

8、out 第一個整數為： a endl; cout 第二個整數為： b endl; cout 算數平均值為： aMean endl; if (gMean != -1) cout 幾何平均數為： gMean endl; else cout 幾何平均數為：實數值不存在！ = 0) *gMean = pow(a * b, 0.5); else *gMean = -1; #include #include using namespace std;void find(int , int, double &, double &); int main(void) int a, b; double aMean,

9、 gMean; cout a; cout b; cout endl; find(a, b, aMean, gMean); cout 第一個整數為： a endl; cout 第二個整數為： b endl; cout 算數平均值為： aMean endl; if (gMean != -1) cout 幾何平均數為： gMean endl; else cout 幾何平均數為：實數值不存在！ = 0) gMean = pow(a * b, 0.5); else gMean = -1; A8、#include #include int main(void) int hours; float salar

10、y; printf(工作時數=); scanf(%d,&hours); if (hours60 & hours=75) salary=60*75+(hours-60)*75*1.25; else salary=60*75+15*75*1.25+(hours-75)*75*1.75; printf(實領薪資=%10.1f元n,salary); system(pause); return 0;A9、#include #include int main(void) int i=1, j=1;/* 設定迴圈控制變數的初值 */ do/* 外層迴圈 */ do/* 內層迴圈 */ printf(%d*%

11、d=%2d ,j,i,i*j); j+; while (j=9); printf(n); i+; j=1; while (i=9); system(pause); return 0;A10、#include #include void sum(int), fac(int);/* 定義函數的原型 */int main(void) int n; printf(請輸入整數 n=); scanf(%d,&n); fac(n);/* 呼叫fac()函數 */ sum(n); /* 呼叫sum()函數 */ system(pause); return 0;void fac(int a)/* 自訂函數fac

12、()，計算a! */ int i,total=1; for(i=1;i=a;i+) total*=i; printf(fac(%d)=1*2*.*%d=%dn,a,a,total);/* 印出a!的結果 */void sum(int a)/* 自訂函數sum()，計算1+2+.+a的結果*/ int i,total=0; for(i=1;i=a;i+) total+=i; printf(sum(%d)=1+2+.+%d=%dn,a,a,total);/* 印出加總的結果 */A11、#include int main( void ) int a, b; int c = 4 + (a = 3 +

13、 (b = 4 + 5); float d = 10.0 + 2.0 * 4.0 - 6.0 / 3.0; int e = 10 % 3; int f = 5 + 3 * 8 / 2 + 3; int g = ( 5 + 3 ) * 8 / 2 + 3; int h = 2 * 4 3 * 5; printf(c= %dn, c); printf(d= %fn, d); printf(e= %dn, e); printf(f= %dn, f); printf(g= %dn, g); printf(h= %dn, h); getchar(); return 0;c= 16d= 16.000000

14、e= 1f= 20g= 35h= 0A12、 2x2 - 4x + 1，x = 3.0、4.0和2/3 = 7.0、17.0、1.0#include int main( void ) float x; printf(x=); scanf(%f, &x); printf(f= %fn, 2*x*x-4*x+1); system(PAUSE); return 0; a2 + b，a = 2.0、4.0和2/3，b = 10.0、5.0和12.0 = 14.0、21.0、4.0#include int main( void ) float a, b; printf(a,b=); scanf(%f,%

15、f, &a, &b); printf(f= %fn, a*a+b); system(PAUSE); return 0; 3y2 + 8y + 4，y = 2.0、4.0和2/3 = 32.0、84.0、32.0#include int main( void ) float y; printf(y=); scanf(%f, &y); printf(f= %fn, 3*y*y+8*y+4); system(PAUSE); return 0;A13、#include int main( void ) int a = 0277; int b = 0xcc; int c = 0xab; int d =

16、0333; int e = 0555; int f = 0xff; printf(a= %dn, a); printf(b= %dn, b); printf(c= %dn, c); printf(d= %dn, d); printf(e= %dn, e); printf(f= %dn, f); system(PAUSE); return 0;a= 191b= 204c= 171d= 219e= 365f= 255請按任意鍵繼續 . . .A14、#include int main( void ) int a = 200; printf(幾打= %dn, a/12); printf(剩幾個= %

17、dn, a%12); system(PAUSE); return 0;幾打= 16剩幾個= 8請按任意鍵繼續 . . .A15、#include int main(void) int a; printf(請輸入a的值: ); scanf(%d, &a); printf(十進位: %dn, a); printf(八進位: %on, a); printf(十六進位: %xn, a); system(PAUSE); return 0;A16、#include int main(void) int i, total = 0; for (i = 1; i = 45 & i = 67) total +=

18、i; printf(%dn, i); printf(總和: %dn, total); getchar(); return 0;454749515355575961636567總和: 672A17、#include int main(void) int i; for (i = 1; i = 20; i+) printf(%dt%dn, i, i*i); getchar(); return 0;1 12 43 94 165 256 367 498 649 8110 10011 12112 14413 16914 19615 22516 25617 28918 32419 36120 400A18、

19、#include int main(void) float amount; printf(輸入金額=); scanf(%f, &amount); if ( amount = 1000 ) amount *= 0.8; printf(付款金額: %fn, amount); system(PAUSE); return 0;輸入金額=2500付款金額: 2000.000000請按任意鍵繼續 . . .A19、#include int main(void) float weight, fee; printf(輸入重量=); scanf(%f, &weight); if ( weight 10運費: 5

20、99.000000請按任意鍵繼續 . . .A20、#include main() int i, j , k, t; t = 1; for ( i = 7; i = 1; i- ) for ( j = 1; j = i; j+ ) if ( j = i ) for ( k = 1; k = t; k+ ) printf(* ); else printf( ); t += 1; printf(n); getchar();A21、#include int sum(int n) if (n = 1) return n; else return n + sum(n-1);int main(void)

21、printf(sum(5) = %dn, sum(5); system( PAUSE ); return 0;sum(5) = 15請按任意鍵繼續 . . .A22、#include #define MAX(a, b) (a = b) ? a : b#define MIN(a, b) (a = b) ? a : bint main(void) printf(10, 15的最大值 = %dn, MAX(10,15); system( PAUSE ); printf(10, 15的最小值 = %dn, MIN(10,15); system( PAUSE ); return 0;A23、#inclu

22、de #define SQUARE(a) a*a#define CUBE(a) a*a*aint main(void) printf(10的平方 = %dn, SQUARE(10); printf(10的三次方 = %dn, CUBE(10); system( PAUSE ); return 0;A24、#include int main(void) int arr15 = 2, 34, 33, 23, 67; int arr25 = 3, 56, 10, 20, 73; int i, result5; for ( i = 0; i 5; i+ ) resulti = arr1i + arr2

23、i; printf(索引tarr1tarr2tresultn); for ( i = 0; i 5; i+ ) printf(%dt%d +t%d =t%dn,i,arr1i,arr2i,resulti); getchar(); return 0;A25、#include #include #define LEN 5int arrMax(int data, int len) int i, max = 0; /* 使用for迴圈找尋最小值 */ for ( i = 0; i max ) max = datai; return max;int main(void) int i, dataLEN =

24、 81,13,27,39,69 ; printf(陣列最大值: %dn, arrMax(data,LEN); getchar(); return 0;陣列最大值: 81A26、#include #include using namespace std;int main() int n, nMin = 1, nMax = 49; /* Seed the random-number generator with current time so that the numbers will be different every time we run. */ srand(unsigned)time(N

25、ULL); cout 開獎號碼：; /* Display the big lotto winners numbers. */ for (int i = 1; i 8; i+) n = (int)(double)rand() / (double)RAND_MAX * (nMax - nMin) + nMin); if (i != 7) cout n ; else cout 特別號： n endl; system(pause); return EXIT_SUCCESS;A27、/* prog7_12, 巢狀迴圈，將整數反過來列印 */#include #include int main(void)

26、 int a,r; while(1) do printf(Input an integer:); scanf(%d,&a); while (a=0); /* 必須輸入大於0的正整數 */ printf(The reverse is ); while (a!=0)/* 將正整數倒過來輸出 */ r=a%10;/* 計算a/10的餘數 */ a/=10;/* 計算a/10，再把結果設回給a */ printf(%d,r); printf(nn); system(pause); return 0;A28、#include #include int main(void) double x,power=

27、1.0, sum=0.0; int n,k,fac=1; printf(請輸入x=); scanf(%lf,&x); printf(請輸入n=); scanf(%d,&n); for(k=1;k=n;k+) power*=x; fac*=k; sum+=power/fac; printf(my_fun(%1f,%d)=%1fn,x,n,sum); system(pause); return 0;A29、#include#includeint main(void) /* * a b c 為三邊長 max mid min拿來儲存三邊長的最大最小值 */ int a, b, c, tmp; int

28、max, mid, min; do fflush(stdin); printf(請輸入第一個正整數:); tmp = scanf(%d, &a); while( (tmp = 0) | (a 1); do fflush(stdin); printf(請輸入第二個正整數:); tmp = scanf(%d, &b); while( (tmp = 0) | (b 1); do fflush(stdin); printf(請輸入第三個正整數:); tmp = scanf(%d, &c); while( (tmp = 0) | (c max ) max = b; if( c max ) max = c

29、; if( b min ) min = b; if( c min ) min = c; mid = tmp - max - min; /* * 從得到的min、mid、max來判斷是否為三角形 */ if( min + mid = max ) printf(無法形成三角形n); else if( max = min ) printf(正三角形n); else if( max = mid | mid = min ) printf(等腰三角形n); else printf(一般三角形n); system(pause); return 0;A30、參考程式碼-#include #include in

30、t main(void) int h, m; float degree_h, degree_m, angle; printf(請輸入現在時間 (小時:分鐘)n); scanf(%d:%d, &h, &m); degree_h = 30.0 * (h + m/60.0); degree_m = 6.0 * m; angle = degree_m - degree_h; if(angle 180) /角度應在0-180度間 angle = 360-angle; printf( %d 點 %d 分時，時針與分針之夾角為 %5.1f 度n, h, m, angle); system(pause); r

31、eturn 0;A31、#include int gcd(int, int);main()int num1,num2;printf(以遞迴方式求兩個正整數的最大公因數 gcd(a, b)n);printf(請輸入第一個正整數a：);scanf(%d, &num1);printf(請輸入第二個正整數b：);scanf(%d, &num2);printf(%d與%d的最大公因數=%dn,num1,num2,gcd(num1,num2);int gcd(int num1,int num2)if (num2 = 0)return num1;else if (num2 0)return gcd(num2

32、,num1%num2); A32、#include #include #include void bubble_sort(int *data, int n);void main(void) int i,N,*number; scanf(%d,&N); number = new intN; for(i=0;iN;i+) numberi= rand()%99; printf(%d ,numberi); bubble_sort(number,N); printf(n); for(i=0;iN;i+) printf(%d ,numberi); delete number; while ( getch(

33、)=n)void bubble_sort(int *data, int n) int i,j,temp; for(i=0;in-1;i+) for(j=0;jdataj+1) temp=dataj; dataj=dataj+1; dataj+1=temp; A33、#include #include #include #include void main(void) double a,b,c,D; scanf(%lf %lf %lf,&a,&b,&c); D=b*b-4*a*c; if(D=0) printf(X1=%lf X2=%lf,(-1*b+sqrt(D)/2/a,(-1*b-sqrt

34、(D)/2/a); else printf(X1=%lf+%lfi X2=%lf-%lfi,-1*b/2/a,sqrt(-1*D)/2/a ,-1*b/2/a,sqrt(-1*D)/2/a ); while ( getch()=n)A34、#include #include #include #include void main(void) int N,year=1; double X,R,amount; scanf(%lf %lf %d,&X,&R,&N); amount=0; do amount=amount+X; amount=amount*(1+R/100); year+; while

35、(year=N); printf(%d,(int)(amount+0.5); while ( getch()=n)A35、#include #include void main(void) int n, count = 0; int i, j; bool prime; scanf(%d,&n); for(i = 1; i = n; i+) prime = true; switch(i) case 1 : / 1 非質數 prime = false; break; case 2 :/ 2 是最小的質數 break; default : for(j = 2; j i; j+) if(i % j)

36、= 0)/ i 可被 j 整除，非質數 prime = false; break; else; if(prime = true)/ 印出質數 count +; printf(%d ,i); if(count % 10 = 0)/ 每印滿10個質數就跳下一行 printf(n); else; else; printf(nThere are %d primes,count); while ( getch()=n)A36、#include #include int main(void) int num1,num2;/* 要求最大公因數的兩個數 */ int a,b,c; /* 依次為除數、被除數、餘數 */ printf(請輸入兩個數字n); scanf(%d %d,&num1,&num2); c = n