控制Java线程超时后中止的解决方案

1、这里使用JDK5+的java.util.concurrent包下的API实现，采用这种方式是相对比较安全的。实现效果：启动一个任务，然后等待任务的计算结果同时设定一个超时时间，如果等待时间超出预设定的超时时间，则中止任务。代码实现：Java代码：import java.util.concurrent.Callable;import java.util.concurrent.ExecutionException;import java.util.concurrent.ExecutorService;import java.util.concurrent.Executors;import java

2、.util.concurrent.Future;import java.util.concurrent.TimeUnit;import java.util.concurrent.TimeoutException;/* 启动一个任务，然后等待任务的计算结果，如果等待时间超出预设定的超时时间，则中止任务。 天骄无双：* author Chen Feng*/public class TaskTimeoutDemo public static void main(String args) System.out.println("Start .");ExecutorService e

3、xec = Executors.newCachedThreadPool();testTask(exec, 15); / 任务成功结束后等待计算结果，不需要等到15秒testTask(exec, 5); / 只等待5秒，任务还没结束，所以将任务中止exec.shutdown();System.out.println("End!");public static void testTask(ExecutorService exec, int timeout) MyTask task = new MyTask();Future<Boolean> future = exe

4、c.submit(task);Boolean taskResult = null;String failReason = null;try / 等待计算结果，最长等待timeout秒，timeout秒后中止任务taskResult = future.get(timeout, TimeUnit.SECONDS); catch (InterruptedException e) failReason = "主线程在等待计算结果时被中断！" 九星天辰诀： catch (ExecutionException e) failReason = "主线程等待计算结果，但计算抛出异

5、常！" catch (TimeoutException e) failReason = "主线程等待计算结果超时，因此中断任务线程！"exec.shutdownNow();System.out.println("ntaskResult : " + taskResult);System.out.println("failReason : " + failReason);class MyTask implements Callable<Boolean> Overridepublic Boolean call() th

6、rows Exception / 总计耗时约10秒 帝尊：for (int i = 0; i < 100L; i+) Thread.sleep(100); / 睡眠0.1秒System.out.print('-');return Boolean.TRUE;运行结果：Java代码：Start .-taskResult : truefailReason : null-taskResult : nullfailReason : 主线程等待计算结果超时，因此中断任务线程！End!several group number, then with b 

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