空间任意两点之间槽盒及桥架的绘制

1、题目:在空间中以（x1,y1,z1）及（x2,y2,z2）为两端下边中点，绘制高为height，宽为width的槽盒。解法：所求两点间的距离为distance=1. 以（0,0,0）及（distance,0,0）为两端下边中点绘制高为height，宽为width的槽盒。绘制函数如下：glPushMatrix();glBegin(GL_QUADS);glVertex3f(0,0,-width/2);glVertex3f(distance,0,-width/2);glVertex3f(distance,height,-width/2);glVertex3f(0,height,-width/2);g

2、lEnd();glBegin(GL_QUADS);glVertex3f(0,0,-width/2);glVertex3f(0,0,width/2);glVertex3f(distance,0,width/2);glVertex3f(distance,0,-width/2);glEnd();glBegin(GL_QUADS);glVertex3f(0,0,width/2);glVertex3f(distance,0,width/2);glVertex3f(distance,height,width/2);glVertex3f(0,height,width/2);glEnd();glPopMatr

3、ix();2.求出两端点（x1,y1,z1）（x2,y2,z2）的向量vec1=（x2-x1,y2-y1,z2-z1）;求出向量vect1及向量的vect2=（distance,0,0）的夹角。求出求出vect3=vect1vect2。的求法:取三个点A（x2-x1,y2-y1,z2-z1）、B（0,0,0）、C（distance,0,0）由图可知|AB|=distance |BC|=distance |AC|=依据三角形余弦定理可知依据向量vect1和vect2求向量Vect3 的求法：设vect3（x3,y3,z3）则3.将1中的图移动glTransalted（x1,y1,z1），然后绕v

4、ec3逆时针旋转，即glRotatef（，vect3）;注:此处的vect3需将其三个坐标值写入已知向量v1(x1,y1,z1)及向量v2(x2,y2,z2),求它两的法向量v3(x3,y3,z3)桥架的绘制和槽盒大致相同，只需将上面的第1步稍作修改就可，修该后为：绿色为桥架间隔，红色为底边。设间隔长度为gap，单位底边长为len。如下图所示:int x=0;glBegin(GL_QUADS);glVertex3f(0,0,-width/2);glVertex3f(distance,0,-width/2);glVertex3f(distance,height,-width/2);glVerte

5、x3f(0,height,-width/2);glEnd();glBegin(GL_QUADS);glVertex3f(0,0,width/2);glVertex3f(distance,0,width/2);glVertex3f(distance,height,width/2);glVertex3f(0,height,width/2);glEnd();for (;x<=distance;)if (x+len<distance)glBegin(GL_QUADS);glVertex3f(x,0,-widht/2);glVertex3f(x,0,width/2);glVertex3f(x+len,0,width/2);glVertex3f(x+len,0,-width/2);glEnd();elseglBegin(GL_QUADS);glVertex3f(x,0,-width/2);glVertex3f(x,0,width/2);