直流主轴电动机转速控制系统

1、4.4.2 Speed control system of d-c spindle motor（直流主轴电动机转速控 制系统） -朱钦松 PPT模板下载： 行业PPT模板： 节日PPT模板： PPT素材下载： PPT背景图片： PPT图表下载： 优秀PPT下载： PPT教程： Word教程： Excel教程： 资料下载： PPT课件下载： 范文下载： 试卷下载： 教案下载： 1111 1. 给定转速信号 2.电流测量和放大 3.被控电源2 4.给定基本转 速电势 5.电动机 6 励磁电流测量 7.电压测量和放大 8.比例放 大器 9.反电势处理器 10.测速发电机 11.被控电源1 PPT模板

2、下载： 行业PPT模板： 节日PPT模板： PPT素材下载： PPT背景图片： PPT图表下载： 优秀PPT下载： PPT教程： Word教程： Excel教程： 资料下载： PPT课件下载： 范文下载： 试卷下载： 教案下载： 1111 Fig.4.13 shows the speed control loop of a d-c spindle motor,in which the “given speed signal” Fig.4.13 shows the speed control loop of a d-c spindle motor,in which the “given spee

3、d signal” comes from CNC unit,“speed feedback signal”comes from tachometer generator and ASR is a comes from CNC unit,“speed feedback signal”comes from tachometer generator and ASR is a speed controller.Current feedback signal is picked up from the voltage of resistance R1connected speed controller.

4、Current feedback signal is picked up from the voltage of resistance R1connected uniaxially with the motor armature, which is amplified by the current measuring-amplifier as current uniaxially with the motor armature, which is amplified by the current measuring-amplifier as current feedback signal. f

5、eedback signal. 图 4.13 表示一直流主轴电动机的转速控制回路，其中“给定转速信号”来自计算机， “转速反馈信号”来自测速发电机，ASR 则是转速控制器。 电流反馈信号取自电阻 R 1 处的电压，R 1 与电动机的电枢同轴连接， 该电压由电流测量放大器放大为电流反馈信号。 PPT模板下载： 行业PPT模板： 节日PPT模板： PPT素材下载： PPT背景图片： PPT图表下载： 优秀PPT下载： PPT教程： Word教程： Excel教程： 资料下载： PPT课件下载： 范文下载： 试卷下载： 教案下载： 1111 ACR is a current controller.T

6、he “controlled ACR is a current controller.The “controlled source 1”11 provides the armature with end source 1”11 provides the armature with end voltage,whose value is controlled by the signal voltage,whose value is controlled by the signal output of ACR.Practical circuit of “controlled output of AC

7、R.Practical circuit of “controlled source 1”may be a transistor d-c wave source 1”may be a transistor d-c wave chopper.Partial armature voltage,in terms ochopper.Partial armature voltage,in terms of resistance R2 and R3,is amplified by voltage measring-amplifying link 7 and sent to inverse resistanc

8、e R2 and R3,is amplified by voltage measring-amplifying link 7 and sent to inverse potential operator9.In fact it is a minus circuit which calculates inverse potential according to the potential operator9.In fact it is a minus circuit which calculates inverse potential according to the equation equa

9、tion E=UE=Ua a- -IRIR ACR 是电流控制器。 “被控电源1”供给电枢端电压， 其值由 ACR 的输出信号所控制。 “被控电源 1”的电路可 以是直流晶体管斩波器。 用 R 2 和 R 3 分压的部分 电枢电压，经电压测量-放大环节 7 放大并传送至反电势处理器 9。 它其实是一个减法电路，用以下等式来计算反电势。 PPT模板下载： 行业PPT模板： 节日PPT模板： PPT素材下载： PPT背景图片： PPT图表下载： 优秀PPT下载： PPT教程： Word教程： Excel教程： 资料下载： PPT课件下载： 范文下载： 试卷下载： 教案下载： where.where

10、. E-inverse potential E-inverse potential U Ua a-armature voltage of motor -armature voltage of motor I-armature current of motor I-armature current of motor R-armature resistance of motor R-armature resistance of motor 式中 反电动势 电动机的电枢电压 电动机的电枢电流 电动机的电枢电阻 AMR is a magnetized current controller.The “g

11、iven basic speed potential” refers to the given AMR is a magnetized current controller.The “given basic speed potential” refers to the given inverse potential at rating speed,thus the feedback signal to AMR are of two signals,i.e.,the inverse inverse potential at rating speed,thus the feedback signa

12、l to AMR are of two signals,i.e.,the inverse potential feedback and the magnetized current feedback .Two diodes VD1 and VD2 are used to potential feedback and the magnetized current feedback .Two diodes VD1 and VD2 are used to block minor feedback signal but open to greater feedback signal.block min

13、or feedback signal but open to greater feedback signal. AMR 是一励磁电流控制器。 “给定基本转速电势”是在额定转速时的给定反电势, 这样，进入AMR 的反馈信号有两个， 即反电势反馈信号和励磁电流的反馈信号。 阻止较小的反馈信号但让较大的反馈信号通过。 两个二极管 VD 1 和 VD 2系用于 1111 PPT模板下载： 行业PPT模板： 节日PPT模板： PPT素材下载： PPT背景图片： PPT图表下载： 优秀PPT下载： PPT教程： Word教程： Excel教程： 资料下载： PPT课件下载： 范文下载： 试卷下载： 教案下

14、载： 1111 Under rating speed the greater one is the magnetized current feedback signal,so that only the Under rating speed the greater one is the magnetized current feedback signal,so that only the magnetized current feedback is active to construct the current closed loop and performs constant-magneti

15、zed current feedback is active to construct the current closed loop and performs constant- power speed control.Up the rating speed only inverse potential is active to construct potential power speed control.Up the rating speed only inverse potential is active to construct potential closed loop and keep constant potential thus to perforn constant-moment speed control.closed loop and keep constant potential thus to perforn const