面向对象程序设计编程 实验 上机

1、面向对象程序设计编程上机作业题目：（1） 调试构造函数pen（）例题using system;using system.collections.generic;using system.text;namespace consoleapplication2 class pen public string color; private int price; public pen() color=black; price=5; public void setprice(int newprice) price=newprice; public int getprice() return price;

2、public void setcolor(string newcolor) color=newcolor; public string getcolor() return color; class test public static void main()pen mypen=new pen() ;console.writeline(the price is 0,mypen.getprice();console.writeline(the color is 0,mypen.color); （2） 调试构造函数重载pen（）例题using system;class pen public stri

3、ng color; private int price; public pen() color = black; price = 5; public pen(string newcolor, int newprice) color = newcolor; price = newprice; public void setprice(int newprice) price = newprice; public void setprice() price = 5; public int getprice() return price; public void setcolor(string new

4、color) color = newcolor; public string getcolor() return color; class test public static void main() pen mypen = new pen(); pen hispen = new pen(green, 8); console.writeline(the price is 0, mypen.getprice(); console.writeline(the color is 0, mypen.color); console.writeline(the price is 0, hispen.get

5、price(); console.writeline(the color is 0, hispen.getcolor(); hispen.setprice(); console.writeline(the price is 0, hispen.getprice(); （3）使用重载方法求5和5.65的平方。using system;using system.collections.generic;using system.text;namespace consoleapplication8 class program public class app public int app1(int x

6、) return x * x; public double app1(double y) return y * y; static void main(string args) app x = new app(); console.writeline(5的平方是0, x.app1(5); console.writeline(5.65的平方是0, x.app1(5.65); （4）将运算符+和- -进行重载，使之可对字符型数据进行运算，即：对一个字符型变量a，当a=l时a+(或+a)的值为m, a- -(或- -a)的值为kusing system;using system.collection

7、s.generic;using system.text;namespace consoleapplication6 public class chartest private char ch; public chartest() this.ch = ; public chartest(char val) this.ch = val; public char c get return this.ch; set this.ch = value; static public chartest operator +(chartest orig) chartest result = new charte

8、st(); result.ch = (char)(orig.ch + 1); return result; static public chartest operator -(chartest orig) chartest result = new chartest(); result.ch = (char)(orig.ch - 1); return result; public class overloadapp public static void main() chartest a = new chartest(l); chartest b = new chartest(l); cons

9、ole.writeline(original value is :0,1, a.c, b.c); a = +a; b = -b; console.writeline(current value is :0.1, a.c, b.c); a = +a; b = -b; console.writeline(final value is:0,1, a.c, b.c); （5）编写一个控制台程序，完成下列功能并输出结果：创建一个类test1，用无参数的构造函数输出该类的类名；增加一个重载的构造函数，带有一个string类型的参数，在此构造函数中将传递的字符串打印出来；在main方法中创建属于test1类

10、的一个对象，不传递参数；在main方法中创建属于test1类的另一个对象，传递一个字符串“this is a string”；using system;using system.collections.generic;using system.text;namespace consoleapplication8 class program class test1 public string test; public test1() test = test1; public test1(string s) test = s; static void main(string args) strin

11、g x = this is a string; test1 app1 = new test1(); test1 app2 = new test1(x); console.writeline(0, app1.test); console.writeline(0, app2.test); （6）编写一个控制台程序，完成下列功能并输出结果：创建一个类a，在a中编写一个可以被重写的带int类型参数的方法mymethod,并在该方法中输出传递的整型值加10后的结果；再创建一个类b，使其继承自类a，然后重写a中的mymethod方法,将a中接收的整型值加50，并输出结果； 在main方法中分别创建类a和类

12、b的对象，并分别调用mymethod方法；using system;class classa public static int mymethod(int i) i=i+10; return i;class classb:classapublic static int mymethod(int i)i=i+50;return i;class testpublic static void main() classa a=new classa(); classb b=new classb(); console.writeline(请输入一个数：); string s=console.readlin

13、e(); int x=int32.parse(s); console.writeline(调用a类方法：0, classa.mymethod(x); console.writeline(调用b类方法：0, classb.mymethod(x); （7）利用委托实现：当用户输入一个字符1时，调用两个整数相加的方法，计算两整数之和；当用户输入一个字符2时，调用两个整数相减的方法，计算两整数之差。using system;class appdelegate int process(int a,int b); public static int add(int a,int b) return a+b; public static int sub(int a,int b) return a-b;static void main() string s,s1,s2; process pro; console.writeline(请输入一个数：); s1=console.readline(); int a=int32.parse(s1); console.wr