C语言题库及答案.doc

09级C语言参考答案说明：1. 由于时间有限，故本答案没有题目，请同学们自行上网看题目。2. P3-315、P3-316答案暂缺。（现已加上）3. 第四类题原有8小题，但总的来说只有两个类型，故在本答案中，每个类型只取一小题，即P4-411、P4-415。11P1-111#include int main (void)int x;double y;printf(nPlease input x:);scanf(%d, &x);if (x 0)y = (-5.0) * (double)x + 27;elseif (0 = x)y = 7909;elsey = 2.0 * (double)x - 1; printf(nF(%d) = %.0f, x, y);return 0;P1-112.#include int main (void)int year;float zzl, ycz, xcz; printf(nPlease input x:);scanf(%f, &zzl);year = 2006;ycz = 5000.0;xcz = ycz;while (xcz 2 * ycz)year+;xcz = xcz * (1.0 + zzl / 100.0);printf(nyear = %d nian, chanzhi = %.2f, year, xcz);return 0;P1-113#include int main (void)int benjin, cunqi;double lixi, lilv;printf(nPlease input benjin,cunqi:);scanf(%d,%d, &benjin, &cunqi);if (cunqi = 1)lilv = 3.15 / 100.0;else if (cunqi = 2)lilv = 3.63 / 100.0;else if (cunqi = 3)lilv = 4.02 / 100.0;else if (cunqi = 5)lilv = 4.69 / 100.0;else if (cunqi = 8)lilv = 5.36 / 100.0;lixi = benjin * lilv * cunqi;printf(nlixi = %.2f yuan, lixi);return 0;P1-114#includeint main(void)int data1, data2;char op;printf(Please input data1 op data2:);scanf(%d %c %d, &data1, &op, &data2);switch (op)case +:printf(%d+%d=%fn, data1, data2, (double)data1 + (double)data2);break;case -:printf(%d-%d=%dn, data1, data2, data1 - data2);break;case *:printf(%d*%d=%fn, data1, data2, (double)data1 * (double)data2);break;case /:if (data2 != 0)printf(%d/%d=%dn, data1, data2, (double)data1 / (double)data2);elseprintf(Error! chu shu wei 0.n);break;case %:if (data2 != 0)printf(%d%d=%dn, data1, data2, data1 % data2);elseprintf(Error! chu shu wei 0.n);break;default:printf(运算符错误！n);return 0;P2-211#include int main(void)int i, j, n;printf(nPlease input n:);scanf(%d, &n);printf(n);for (i = 1; i = n + 1; i+)for (j = 1; j = n + 1 - i; j+)printf( );for (j = 1; j = i * 2 - 1; j+)printf(#);printf(n);for (i = 0; i n; i+)for (j = 1; j = i + 1; j+)printf( );for (j = 1; j = 2 * (n - i) - 1; j+)printf(#);printf(n);return 0;P2-212#include int main(void)int num;int i, j;printf(Please input n:);scanf(%d, &num);for (i = 1; i = num; i+)for (j = i; j 1)for (j = 1; j = 1; i-)for (j = i; j 1)for (j = 1; j = 2 * (i - 1) - 1; j+)printf( );printf(%c, a + (i - 1);printf(n);return 0;P2-213#include int main(void)int num;int i, j;printf(Please input n:);scanf(%d, &num);for (i = 1; i = num; i+)for (j = 1; j = (i - 1); j+)printf( );printf(%c, );if (i num)for (j = 1; j = 1; i-)for (j = 1; j = (i - 1); j+)printf( );printf(%c, );for (j = 1; j = 2 * (num - i) - 1; j+)printf( );printf(%c, );printf(n);return 0;P2-214#include int main(void)int num;int i, j;printf(Please input n:);scanf(%d, &num);for (i = 1; i = num; i+)printf(%c, $);if (i num)for (j = 1; j = 1; i-)printf(%c, $);for (j = 1; j = num - 1 - i; j+)printf( );printf(%c, $);printf(n);return 0;P2-215#includeint main(void)int nn, i;double sum = 0, fac = 1;printf(Please input n:);scanf(%d, &nn);for (i = 1; i = nn; i+)fac = fac * i;sum = sum + 1 / fac;printf(S=1/1!+1/2!+.+1/%d!=%.16f, nn, sum);return 0;P2-216#include#define N 20int main(void)int i, j, x, y, m, max = 0;int arrNN;printf(nPlease input m:);scanf(%d, &m);printf(nPlease input array:n);for (i = 0; i m; i+)for (j = 0; j m; j+)scanf(%d, &arrij);for (i = 0; i m; i+)for (j = 0; j max)max = arrij;x = i;y = j;printf(nmax=%d,i=%d,j=%d, max, x, y);return 0;P2-217#include#define N 20int main(void)int i, j, m;long int sum = 0L;int arrNN;printf(nPlease input m:);scanf(%d, &m);printf(nplease input array:n);for (i = 0; i m; i+)for (j = 0; j m; j+)scanf(%d, &arrij);for (i = 0; i m; i+)for (j = 0; j m; j+)if (i = j | i + j = m - 1)sum = sum + arrij;printf(nsum=%ld, sum);return 0;P2-218#include#define N 20int main(void)int i, j, m;long int sum = 0L;int arrNN;printf(nPlease input m:);scanf(%d, &m);printf(nplease input array:n);for (i = 0; i m; i+)for (j = 0; j m; j+)scanf(%d, &arrij);for (i = 0; i m; i+)for (j = 0; j m; j+)if (i = 0 | i = m - 1 | j = 0 | j = m - 1)sum = sum + arrij;printf(nsum=%ld, sum);return 0;P2-219#include#includeint main(void)int i, j, len, num;char shuru128, jieguo128;printf(nPlease input string:);gets(shuru);len = strlen(shuru);num = 0;for (i = 0, j = 0; i = 0 & shurui = 9)num+;jieguoj = shurui;j+;jieguoj = 0;printf(nshu zu ge shu wei:%d, num);printf(nshu zi wei:%s, jieguo);return 0;P2-220#include#includeint main(void)int i, len, zimu, shuzi, kongge, qita;char str128;printf(nPlease input string:);gets(str);len = strlen(str);zimu = 0;shuzi = 0;kongge = 0;qita = 0;for (i = 0; i = a & stri = A & stri = 0 & stri = 9)shuzi+;else if (stri = )kongge+;elseqita+;printf(nzimu=%d,shuzi=%d,kongge=%d,qita=%d, zimu, shuzi, kongge, qita);return 0;P2-221#include#includeint main(void)char str128;int len, begin, end;printf(nPlease iuput string:);gets(str);len = strlen(str);begin = 0;end = len - 1;for (; begin = end)printf(n%s shi hui wen., str);elseprintf(n%s bu shi hui wen., str);return 0;P2-222#include#includeint main(void)int i;char str128;printf(nPlease input string:);gets(str);i = 0;while (stri != 0)if (stri = a & stri = A & stri = Z)stri = A + Z - stri;i+;printf(nzi fu chuan changdu:%d, strlen(str);printf(nmi wen:%s, str);return 0;P2-223#includeint main(void)int i, n;double sn, hn, ho = 10000.0;printf(Please input n:);scanf(%d, &n);sn = ho;for (i = 2; i = n; i+)ho = ho / 2.0;sn = sn + 2 * ho;hn = ho / 2.0;printf(sn=%f,hn=%fn, sn, hn);return 0;P2-224#includeint main(void)int i, n;long total = 1;printf(Please input n:);scanf(%d, &n);for (i = n - 1; i 0; i-)total = (total + 1L) * 2L;printf(total=%ldn, total);return 0;P3-311#include#include#define N 128int main(void)int i, j, len1, len2, len;char s1N * 2, s2N, s3N * 2;printf(Please input string1:);gets(s1);printf(Please input string1:);gets(s2);len1 = strlen(s1);len2 = strlen(s2);if (len1 len2)len = len1;elselen = len2;j = 0;for (i = 0; i len; i+)s3j = s1i;j+;s3j = s2i;j+;if (len1 len2)for (i = len1; i len2; i+)s3j = s2i;j+;elsefor (i = len2; i len1; i+)s3j = s1i;j+;s3j = 0;strcpy(s1, s3);printf(nstring1:);puts(s1);return 0;P3-312#include #include #include /*结构体类型定义*/struct shangpinchar pinming20;char guige12;long shuliang;float danjia;int main(void)int n; /*n存放指定查找商品的条数*/char sppm20;FILE *fp;struct shangpin sp;/*从键盘输入商品品名*/printf(nPlease input shang pin pin ming:);gets(sppm);/*打开文件*/fp = fopen(sp.dat, rb);if (fp = NULL)printf(file open error!);exit(0);/*处理查找商品*/n = 0;printf(ncha zhao qing kuang:);while (!feof(fp)/*文件未结束则循环*/*从文件中读一条商品数据，并判断读出是否正确*/If (fread(&sp, sizeof(struct shangpin), 1, fp) = 1)if (strcmp(sppm, sp.pinming) = 0)/*找到指定商品*/n+;printf(n%s,%s,%d,%.2f, sp.pinming, sp.guige, sp.shuliang, sp.danjia);/*给出未找到的输出*/if (n = 0)printf(nmei you shang pin %s, sppm);/*关闭文件*/fclose(fp);return 0;P3-313#include#define S 20int main(viod)int maxi, mini, i, j, m, n, k;int strSS;printf(nPlease input m and n:);scanf(%d%d, &m, &n);for (i = 0; i m; i+)for (j = 0; j n; j+)scanf(%d, &strij);for (i = 0; i m; i+)maxi = 0;for (j = 0; j n; j+)if (strimaxi strij)maxi = j;mini = 0;for(k = 0; k strkmaxi)mini = k;if (i = mini)break;if (i m)printf(nyou an dian, wei: a%d%d=%d, mini, maxi, strminimaxi);elseprintf(nmei you an dian.);P3-314#include #include #include /*结构体类型定义*/struct shangpinchar pinming20;char guige10;char shuliang6;char danjia5;int main(void)int n; /*n存放指定查找商品的条数*/char sppm20;FILE *fp;struct shangpin sp;/*从键盘输入商品品名*/printf(nPlease input shang pin pin ming:);gets(sppm);/*打开文件*/fp = fopen(sp.txt, r);if (fp = NULL)printf(file open error!);exit(0);/*处理查找商品*/n = 0;printf(ncha zhao qing kuang:);while (!feof(fp)/*文件未结束则循环*/*从文件中读一条商品数据，并判断读出是否正确*/if (fscanf(fp, %s %s %s %s, sp.pinming, sp.guige, sp.shuliang, sp.danjia) = 4)if (strcmp(sppm, sp.pinming) = 0)/*找到指定商品*/n+;printf(n%s,%s,%s,%s, sp.pinming, sp.guige, sp.shuliang, sp.danjia);/*给出未找到的输出*/if (n = 0)printf(nmei you shang pin %s, sppm);/*关闭文件*/fclose(fp);return 0;P3-315#include #include #include int main(void)char filename128, str21, hang200, ch;FILE *fp;int sum = 0, i = 0, first = -1, last = -1;printf(input the files name and the string: );scanf(%s %s, filename, str);printf(-File content:-n);fp=fopen(filename, r);if (fp = NULL)/* 打开文件 */printf(cannot open file!n);exit(1);while (!feof(fp)ch = fgetc(fp);if (ch = n | ch = EOF | i = 199)sum+;hangi = 0;putchar(n);i = 0;if (strstr(strupr(hang), strupr(str)if (first = -1)first = sum;last = sum;elsehangi = ch;putchar(ch);i+;printf(-File summary:-n);printf(%d lines, first line: %d, last line: %dn, sum, first, last);fclose(fp);return 0;P3-316#include#include/* GetString的功能是从键盘读入最多n个字符(遇到由endFlag指定的字符或回车则结束读并且该字符和回车均视为有效字符)存放在buf所指向的内存中并加上字符串结束符0函数返回值为读入的字符个数 */int GetString(char *buf, char endFlag, int n);/* CompDigit 的功能是分别统计指针s1、s2、s3、s4所指向的字符串中数字字符的个数，将包含最多数字字符(不考虑存在包含相同个数数字字符的情况)的字符串的长度放在指针mLen所指向的内存单元中，并通过函数返回值返回该字符串中第1个数字字符的地址 */char *CompDigit(char *s1, char *s2, char *s3, char *s4, int *mLen);/* clearRestInput的功能是将前一次读字符后到回车(含回车)之间的字符废弃 */void clearRestInput(char lastInput);int main(void)char str430, strM30, endChar, lastChar;int totalLen = 0, maxLen = -1, i;const int N = 29;printf(ninput endFlag char: );scanf(%c, &endChar);for (i=0, lastChar=endChar; i4; i+)clearRestInput(lastChar);printf(input string-%d: , i+1);totalLen += GetString(stri, endChar, N);lastChar = stristrlen(stri) - 1;strcpy(strM, CompDigit(str0, str1, str2, str3, &maxLen);printf(n-n%s, 4Len=%d, mLen=%dn, strM, totalLen, maxLen);return 0;void clearRestInput(char lastInput)while (lastInput != n)lastInput = getchar();/* 以上内容不能修改(包括本行和下一行)，否则将以0分计 */* 考生在此后完成函数GetString和CompDigit的设计(在其中不要使用printf函数) */int GetString(char *buf, char endFlag, int n)int i, count;char ch;i = 0;count = 0;ch = getchar();while (ch != endFlag & ch != n & count n)bufi = ch;i+;count+;/*若无此步，若字符串长度又刚好为29，ch将输入缓冲区的n读了,*/*则主函数中的调用清空输入缓冲区的函数clearRestInput(char lastInput)等着输入n*/if (count = n)break;ch = getchar();if (count = n)bufi = 0;else if (ch = endFlag | ch = n)bufi = ch;i+;count+;bufi = 0;return count;char *CompDigit(char *s1, char *s2, char *s3, char *s4, int *mLen)int i, j, count, flag, max = 0;char *s4 = s1, s2, s3, s4;char *p0, *p1;for (i=0; i= 0 & sij = 9)count+;if (flag = 0)flag = 1;p0 = &sij;j+;if (max count)max = count;*mLen = strlen(si);p1 = p0;return p1;P4-411#includeint main(void)int i, j, num = 0, tmp, count, data10000;printf(Please input numbers:);for (i = 0; 1; i+)scanf(%d, &datai);if (datai != -1111)num+;elsebreak;for (i = 0; i num - 1; i+)for (j = i; j num;