电网10KV系统短路电流整定计算书

10KV电网短路电流计算,,,,,,,,,,

"假定电网短路容量为300MVA,基准电压Uj=10KV,基准电流Ij=9.16KA,冲击系数Kch.s取1.8.各元件有效电阻较小,短路电路中总电阻不大于总电抗的1/3,不予考虑.",,,,,,,,,,

10KV|---2.0Km3X300电缆------10KV变配电所SS2|F1--------2.5Km3X185电缆--------F4|SS110/0.4KV变压器|F5b|---SS210/0.4KV变压器|F2|----0.8Km3X70电缆----10KV电机|F6b|----1.5Km3X70电缆----10KV电机|F3b|----------1.5Km3X185电缆--------F7|SS310/0.4KV变压器|F8b|----1.0Km3X70电缆----10KV电机|F9,,,,,,,,,,

序号,电路元件,变压器/电网容量SrT/SksMVA,电缆长度Km,变压器Uk%,,短路电路总电抗Xjs,超瞬变短路电流KA,短路容量MVA,短路全电流KA,折算到高压侧的短路电流(KA)

,,,,阻抗/Km,计算公式,短路元件电抗(标值),"I""s=I0.2=Ik=Ij/Xjs*","Ss""=Sj/Xjs*","ich.s=1.414*Kch.s*I""",I1=I2/(1.732*nl)

1,电网,300,10,,X1*=Sj/Sks,0.333,,,,

2,进线电缆,YJV-3X300,2,0.079,X2*=L*X(Sj/Uj^2),0.143,,,,

短路点F1,SS210KV母线,,,,Xjs1*=X1*+X2*,0.477,19.218,209.80,48.91,

3,SS2变压器(基准电压10KV),0.63,,4.50%,X3*=(Uk%/100)*(Sj/SrT)*(0.4^2/10^2),0.0114,,,,

短路点F2,SS2变压器低压侧,,,,Xjs2*=X1*+X2*+X3*,0.345,26.569,290.06,67.62,0.614

4,SS2-10KV电机,YJV-3X70,0.8,0.071,X4*=L*X(Sj/Uj^2),0.052,,,,

短路点F3,,,,,Xjs3*=X1*+X2*+X4*,0.528,17.343,189.34,44.14,

5,SS2-SS1电缆,YJV-3X185,2.5,0.063,X5*=L*X(Sj/Uj^2),0.143,,,,

短路点F4,SS110KV母线,,,,Xjs4*=X1*+X2*+X5*,0.620,14.786,161.42,37.63,

6,SS1变压器(基准电压10KV),0.25,,4.50%,X6*=(Uk%/100)*(Sj/SrT)*(0.4^2/10^2),0.0288,,,,

短路点F5,SS1变压器低压侧,,,,Xjs5*=X1*+X2*+X5*+X6*,0.648,14.129,154.25,35.96,0.326

7,SS1-10KV电机,YJV-3X70,0.8,0.071,X7*=L*X(Sj/Uj^2),0.052,,,,

短路点F6,,,,,Xjs3*=X1*+X2*+X5*+X7*,0.671,13.651,149.03,34.74,

8,SS2-SS3电缆,YJV-3X185,1.5,0.063,X8*=L*X(Sj/Uj^2),0.086,,,,

短路点F7,SS310KV母线,,,,Xjs3*=X1*+X2*+X8*,0.562,16.289,177.82,41.46,

9,SS3变压器(基准电压10KV),0.5,,4.50%,X9*=(Uk%/100)*(Sj/SrT)*(0.4^2/10^2),0.0144,,,,

短路点F8,SS3变压器低压侧,,,,xjs4*=X1*+X2*+X8*+X9*,0.577,15.882,173.38,40.42,0.367

10,SS3-10KV电机,YJV-3X70,0.8,0.071,X10*=L*