法学案例分析模版课件6

案例分析

Harrigan大學學生背景之探討指導教授：楊錦洲教授學生：９４２４１０７李佳璟９４２４１０８連豈浩９４２４１１０黃郁智９４２４１２３陳大翔1大綱研究問題研究背景研究動機案例敘述題目探討總結2研究問題Harrigan大學對高中生來說是否比主要的競爭大學更具有選填志願的吸引力，並且能比主要的競爭大學更能吸引到名列前矛的學生。3研究背景在這個年代大學林立，學生所能夠選擇的志願也相對的多，為了使學校能夠持續的發展，以及能夠吸收優良的學生使學校能夠保持競爭力。4研究動機為了達到學校的持續發展和保持學校的競爭力這兩個主要的目的，所以對我們來說高中生是否對我們學校的興趣比我們的主要敵對大學還大。5案例敘述6案例敘述HarriganuniversityisaliberalartsuniversityintheMidwestthatattemptstoattractthehighestqualitystudents,especiallyfromitsregionofthecountry.Ithasgathereddataon178applicantswhowereacceptedbyHarrigan(arandomsamplefromallacceptableapplicantsoverthepastseveralyears).ThedataareinthefileHARRIGAN.XLS.Thevariablesare:7設定參數Accepted:whethertheapplicantacceptsHarrigan’soffertoenrollMainRival:whethertheapplicantenrollsatHarrigan’smainrivaluniversityHSClubs:numberofhighschoolclubsapplicantservedasanofficerHSSports:numberofvarsitylettersapplicantearnedHSGPA:applicant’shighschoolGPAHSSize:numberofstudentsinapplicant’sgraduatingclassSAT:applicant’scombinedSATscoreCombinedScore:acombinedscorefortheapplicantusedbyHarrigantorankapplicant8案例敘述ThederivationofthecombinedscoreisacloselykeptsecretbyHarrigan,butitisbasicallyaweightedaverageofthevariouscomponentsofhighschoolperformanceandSAT.Harriganisconcernedthatitisnotgettingenoughofthebeststudents,andworseyet,itisconcernedthatmanyofthesebeststudentsaregoingtoHarrigan’smainrival.Solvethefollowingproblemsandthen,basedonyouranalysis,commentonwhetherHarriganappearstohavealegitimateconcern.9題目探討10第一題Finda95%confidenceintervalfortheproportionofallacceptableapplicantswhoacceptHarrigan’sinvitationtoenroll.Dothesameforallacceptableapplicantswithacombinedscorelessthan330;withacombinedscoregreaterthan375.(Notethat330and375areapproximatelythefirstandthirdquartilesoftheScorevariable.)11求出交集NMeanStDevSEMean103345.7230.022.9695%CI(339.92,351.52)330以下和95%信賴區間的交集為0。375以上和95%信賴區間的交集為0。12第一題結論第一小題，主要是要讓我們了解到，錄取生的成績分佈，我們看這個圖可以看到落在四分位差和信賴區間中間的人數分布。此外我們再補充個圓餅圖，來更了解到整體的分佈13第二題Find95%confidenceintervalsforthemeancombinedscore,themeanhighschoolGPA,andthemeanSATscoreofallacceptablestudentswhoacceptHarrigan’sinvitationtoenroll.Dothesameforallacceptablestudentswhochoosetoenrollelsewhere.Thenfind95%confidenceintervalsforthedifferencesbetweenthesemeans,whereeachdifferenceisameanforstudentsenrollingatHarriganminusthesimilarmeanforstudentsenrollingelsewhere.141.CombinedScore比較Two-sampleTforC12vsC13NMeanStDevSEMeanC12104346.430.73.0C1328376.124.64.6Difference=mu(C12)-mu(C13)Estimatefordifference:-29.7195%CIfordifference:(-40.82,-18.60)T-Testofdifference=0(vsnot=):T-Value=-5.37P-Value=0.000DF=52152.SAT比較Two-sampleTforC15vsC16NMeanStDevSEMeanC15103118013513C1628118913024Difference=mu(C15)-mu(C16)Estimatefordifference:-9.095%CIfordifference:(-65.2,47.1)T-Testofdifference=0(vsnot=):T-Value=-0.32P-Value=0.748DF=44163.GPA比較Two-sampleTforC18vsC19NMeanStDevSEMeanC1810384.607.340.72C192887.375.921.1Difference=mu(C18)-mu(C19)Estimatefordifference:-2.7695%CIfordifference:(-5.44,-0.09)T-Testofdifference=0(vsnot=):T-Value=-2.07P-Value=0.043DF=5117第二題結論一開始我們先以總和分數來做分析，很明顯的發現，Harrigan的總和分數輸對方一節，因此我們再把它拆開成學測分數和平時分數來看，學測分數的表現上，Harrigan和競爭大學幾乎相差無幾，可是在平時成績上就輸了不少，所以想要在招收更優秀的學生的話，在平時成績上的入學要求，要在更加的提高。18第三題Harriganisinterested(asaremostschools)ingettingstudentswhoareinvolvedinextracurricularactivities(clubsandsports).Doesitappeartobedoingso?Finda95%confidenceintervalfortheproportionofallstudentswhodecidetoenrollatHarriganwhohavebeenofficersofatleasttwoclubs.Findasimilarconfidenceintervalforthosewhohaveearnedatleastfourvarsitylettersinsports.19體保生分數的信賴區間Theassumedstandarddeviation=24.84NMeanStDevSEMean60358.8524.843.2195%CI(352.56,365.14)20體保生和全部學生的分數比較圖NMeanStDevMeanSPORT60117314018SAT103118013513Difference=mu(SPORTSAT)-mu(SAT)Estimatefordifference:-7.595%CIfordifference:(-52.0,36.9)T-Testofdifference=0(vsnot=):T-Value=-0.34P-Value=0.738DF=11921第三題結論這題我們求出了，體育優良的學生綜合分數的信賴區間。此外我們還另外把體育優良的學生的學測成績，和所有學生的學測成績做比較，發現在學測成績上，學生們的成績幾乎相差無幾。也就是說，目前Harrigan大學，對於招收體育較為優良學生的方案可以說是非常的成功。22第四題ThecombinedscoreHarrigancalculatesforeachstudentgivessomeadvantagetostudentswhotankhighlyinasmallhighschool.Therefore,Harriganwonderswhetheritisrelativelymoresuccessfulinattractingstudentsfromlargehighschool.Developoneormoreconfidenceintervalsforrelevantparametersshedsomelightonthisissue.23區分大小學校VariableNN*MeanSEMeanC121030266.110.9StDevMinimumQ1MedianQ3110.745.0193.0271.0346.0以平均數266做區分出大小學校241.大小學校的GPA比較NMeanStDevSEMeanGPA15286.907.431.0GPA25182.266.520.91Difference=mu(GPA1)-mu(GAP2)Estimatefordifference:4.6495%CIfordifference:(1.90,7.37)T-Testofdifference=0(vsnot=):T-Value=3.37P-Value=0.001DF=99252.大小學校的SAT比較NMeanStDevSEMeanSAT.52120714220SAT251115312317Difference=mu(SAT1)-mu(SAT2)Estimatefordifference:53.295%CIfordifference:(1.4,105.0)T-Testofdifference=0(vsnot=):T