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1Alexander-SadikuFundamentals
of
Electric
CircuitsChapter
19Two-Port
NetworksCopyright
©
The
McGraw-Hill
Companies,
Inc.
Permission
required
for
reproduction
or
display.2Two
Port
NetworksChapter
19IntroductionImpedance
parameters
zAdmittance
parameters
yHybrid
parameters
hTransmission
parameters
T3Whatis
a
port?It
is
a
pair
of
terminalsthroughwhich
a
current
may
enter
orleave
a
network.19.1
Introduction(1)4One
port
or
twoterminal
circuitTwo
port
or
fourterminal
circuitIt
is
an
electricalnetwork
with
twoseparate
ports
forinput
and
output.No
independent sources.19.1
Introduction(2)19.2
Impedance
parameters
(1)Assume
no
independent
source
in
thenetworkV1
=
z11I1
+
z12I2V2
=
z21I1
+
z22I2
2
21 22
2
2
I
I
zz12
I1
I1
=
[z]
V
z
V1
z11=where
the
z
terms
are
called
the
impedance
parameters,or
simplyz
parameters,
and
have
units
of
ohms.5619.2
Impedance
parameters
(2)z11
=
Open-circuit
inputimpedancez21
=
Open-circuit
transferimpedance
from
port
1
toport
2z12
=
Open-circuit
transferimpedance
from
port
2
toport
1z22=
Open-circuit
outputimpedance121111Iand
zIzI2
=0 I2
=0=
V2=
V1222212Iand
zIzI1
=0I1
=0=
V1
=
V2719.2
Impedance
parameters
(2a)12111II2
=01
I2=0=
V2and
zI=
V1z222212Iand
zIzI1
=0
I1
=0=
V2=
V1•When
z11
=
z22,
the
two-portnetwork
is
said
to
be
symmetrical.•When
the
two-port
network
islinear
and
has
no
dependentsources,
the
transfer
impedancesare
equal
(z12
=
z21),
and
the
two-port
is
said
to
be
reciprocal.8V1V2I2I1Example1Determine
the
Z-parameters
of
the
following
circuit.19.2
Impedance
parameters
(3)121111Iand
zIzI2
=0I2
=0=
V2=
V1222212Iand
zIzI1
=0I1
=0=
V2=
V1Answer:
40
70
60
40
Wz
=W
21 22
12z
zzz
=
z1119.3
Admittance
parameters
(1)Assume
no
independent
source
in
thenetworkI1
=
y11V1
+
y12V2I2
=
y21V1
+
y22V2
2
21 22
2
2
V
V
yy12
V1
V1
=
[y]
I
y
I1
y11=where
the
y
terms
are
called
the
admittanceparameters,or
simply
y
parameters,
and
they
have
units
of
Siemens.910222212Vand
yVyV1
=0V1
=0=
I1
=
I219.3
Admittance
parameters
(2)y11
=
Short-circuit
inputadmittancey21
=
Short-circuit
transferadmittance
from
port
1
toport
2y12
=
Short-circuit
transferadmittance
from
port
2
toport
1y22=
Short-circuit
outputadmittance121111Vand
yVyV2
=0V2
=0=
I2=
I111V1V2I1I2Example2Determine
the
y-parameters
of
the
following
circuit.19.3
Admittance
parameters
(3)121111Vand
yVyV2
=0V2
=0=
I1
=
I20.625
-
0.5-
0.5
Sy
=
0.75Answer:222212Vand
yVyV1
=0V1
=0=
I2=
I1Syy12
y
21 22
y
=
y1112V1V2I2I1=iExample3Determine
the
y-parameters
of
the
following
circuit.19.3
Admittance
parameters
(4)I1
=
y11V1
+
y12V2I2
=
y21V1
+
y22V20.25
-
0.25-
0.05
Sy
=
0.15Answer:I1
=
0.15V1
-
0.05V2I2
=
-0.25V1
+
0.25V2V1
=
8I1
+
2(I1
+
I2
)V2
=
4(2i
+
I2
)
+
2(I1
+
I2
)Apply
KVL1319.4
Hybrid
parameters
(1)Assume
no
independent
source
in
thenetworkV1
=
h11I1
+
h12V2I2
=
h
21I1
+
h22
V2
2
2
21 22
2
V
I
=
[h]
1h
I
h
V
V1
h11
h12
I1=where
the
h
terms
are
called
the
impedance
parameters,
orsimply
h
parameters,
and
each
parameter
has
different
units,refer
above.1419.4
Hybrid
parameters
(2)121111IhIhV2
=0V2
=0=
I2=
V1222212VhVhI1
=0I1
=0=
I2=
V1h11=
short-circuitinput
impedance
(W
)H2
=
short-circuitforward
current
gainH12
=
open-circuitreverse
voltage-gainH22
=
open-circuitoutput
admittance
(S)Assume
no
independent
source
in
thenetwork15V1V2I1
I2Example4Determine
the
h-parameters
of
the
following
circuit.19.4
Hybrid
parameters
(3)121111Iand
hIhV2
=0V2
=0=
V1
=
I2S
4Ωh=
2
13
9
3
-
2
Answer:222212Vand
hVhI1
=0I1
=0=
I2=
V1
h
Ωh
=h22S
h21h12111619.5
Transmission
parameters
(1)Assumenoindependent
source
inthenetworkV1
=
AV2
-
BI2I1
=
CV2
-
DI2
2
1
2
-
I
V
=
[T]
2D
-
I
B
V2
I
C
V1
A=where
the
T
terms
are
called
the
transmission
parameters,or
simply
T
or
ABCD
parameters,
and
each
parameter
hasdifferent
units.1719.5
Transmission
parameters
(2)22I
=0I
=0A=
V1V2C
=
I1V222V
=0V
=0B
=
-
V1I2D
=
-
I1I2A=open-circuitvoltage
ratioC=
open-circuittransfer
admittance(S)B=
negative
short-circuit
transferimpedance
(W
)D=negative
short-circuit
current
ratio18V1V2Example5Determine
the
T-parameters
of
the
following
circuit.19.5
Transmission
parameters
(3)
1
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