C程序设计上机实验操作题参考答案

定义两个实数变量a和b，使a中存放5.2245，b中存放2.4678，要求输出结果为：

a=5.22,b=2.468

请编写完整应用程序实现。#include<stdio.h>intmain(intargc,char*argv[]){ floata,b; a=5.2245; b=2.4678; printf("a=%6.2f,b=%5.3f",a,b); return0;}请编写完整应用程序，要求输出结果为：

######

****

Linsaid：”Starcharactersaccountfor40%”.#include<stdio.h>intmain(intargc,char*argv[]){ printf("######\n"); printf("****\n"); printf("Linsaid:\"Starcharactersaccountfor40%%\"\n"); return0;}从键盘输入一个大写字母，将它转换成小写字母输出，并输出其对应的ASCII码。#include<stdio.h>intmain(){ charch; do { printf("Pleaseinputupperletters:\n"); scanf("%c",&ch); }while(!(ch>='A'&&ch<='Z')); ch=ch+32; printf("对应的小写字母:%c\n",ch); printf("对应的ASCII:%d\n",ch); return0;}从键盘输入圆柱体的半径和高，按公式V=πr2h计算并输出圆柱体的体积。#include<stdio.h>#definePI3.14intmain(){ floatr,h,V; printf("inputradiusandheight:\n"); scanf("%f%f",&r,&h); V=PI*r*r*h; printf("CylinderVolume:%.2f\n",V); return0;}.定义下列变量a、b、x、y、c1、c2，从键盘输入各个变量的存放数据，要求a和b中存放3和7，要求x和y中分别存放71.82和8.5，要求c1和c2中分别存放大写的字母‘A’和小写字母‘a’。最后输出各个变量的值，并给出提示。#include<stdio.h>intmain(){ inta,b; floatx,y; charc1,c2; printf("inputintegera,b:"); scanf("%d%d",&a,&b); printf("inputfloatx,y:"); scanf("%f%f",&x,&y); printf("inputcharc1,c2:"); getchar(); scanf("%c%c",&c1,&c2); printf("a=%d,b=%d\n",a,b); printf("x=%f,y=%f\n",x,y); printf("c1=%c,c2=%c\n",c1,c2); return0;}#include<stdio.h>intmain(){ charch1,ch2; printf("inputtwocharacters:\n"); ch1=getchar(); ch2=getchar(); putchar(ch1); putchar('\n'); printf("%c\n",ch2); return0;}编写程序，用getchar函数输入两个字符，并分别应用putchar函数和printf函数输出这两个字符#include<stdio.h>intmain(){ floatx,a,b,c,d,y; do { printf("inputx,a,b,c,d:\n"); scanf("%f%f%f%f%f",&x,&a,&b,&c,&d); }while(c+d==0); y=x+(a-b)/(c+d); printf("对应的f:%.2f\n",y); return0;}#include<stdio.h>#definePI3.14intmain(){ floatrad,angle,y; printf("inputangle:\n"); scanf("%f",&angle); rad=PI*angle/180; y=sin(rad)+cos(rad); printf("angle->rad:%.2f\n",y); return0;} 编程判断输入整数x的正负性和奇偶性。#include<stdio.h>intmain(){ intx; printf("inputintegerx:\n"); scanf("%d",&x); if(x>0)printf("%d是正数\n",x); if(x<0)printf("%d是负数\n",x); if(x%2==0) printf("%d是偶数\n",x); else printf("%d是奇数\n",x); return0;}要求编程解决以下问题，然后上机调试运行程序。用scanf函数输入x的值，求y的值。#include<stdio.h>intmain(){ floatx,y; printf("inputrealnumberx:\n"); scanf("%f",&x); if(x<1) y=x; elseif(x>=1&&x<10) y=2*x-1; else y=3*x-11; printf("resulty=%.2f\n",y); return0;} 输入出租车类型和里程，计算打车的费用。计算方式为：3公里以内8元；3公里以上0车型每公里1.5元，3公里以上1车型每公里2元。#include<stdio.h>intmain(){ intcartype; floatmile,money; do { printf("inputcartype:\n"); scanf("%d",&cartype); }while(!(cartype==0||cartype==1)); do { printf("inputmiles:\n"); scanf("%f",&mile); }while(mile<0); if(mile<=3) money=8; elseif(cartype==0) money=8+1.5*(mile-3); else money=8+2*(mile-3); printf("resultmoney=%.2f\n",money); return0;}输入一个百分制的成绩，要求输出成绩等级Ａ、Ｂ、Ｃ、Ｄ、Ｅ。９０分及以上为Ａ，８０－８９为Ｂ，７０－７９为Ｃ，６０－６９为Ｄ，６０分以下为Ｅ。要求从键盘输入成绩，然后输出相应等级，用if语句实现。#include<stdio.h>intmain(){ floatscore; charclass; printf("inputscore:"); scanf("%f",&score); if(score>=90) class='A'; elseif(score>=80) class='B'; elseif(score>=70) class='C'; elseif(score>=60) class='D'; else class='E'; printf("等级为：%c\n",class); return0;}键盘输入三个整数a,b,c，输出值在中间（非最大，非最小）的数。#include<stdio.h>intmain(){ inta,b,c; inttemp; printf("inputthreeintegers:\n"); scanf("%d%d%d",&a,&b,&c); if(a>b) { temp=a; a=b; b=temp; } if(b>c) { temp=b; b=c; c=temp; if(a>b) { temp=a; a=b; b=temp; } } printf("%d<%d<%d\n",a,b,c); printf("middle:%d\n",b); return0;}企业发放的奖金根据利润提成。利润I低于或等于100000元的，奖金可提10%；利润高于100000元，低于200000元（100000＜I≤200000）时，低于100000元的部分按10%提成，高于100000元的部分，可提成7.5%；200000＜I≤400000时，低于200000元的部分仍按上述办法提成（下同）。高于200000元的部分按5%提成；400000<I<=600000时，高于40万元的部分按3%提成；600000<I<=1000000时，高于60万元的部分按1.5%提成；I>1000000时，超过100万元的部分按1%提成。从键盘输入当月利润I，求应发奖金总数。要求：⑴用if语言编程序；⑵用switch语句编程序#include<stdio.h>intmain(){ floatt0,t1,t2,t3,t4,m; inti; t0=100000*0.1; t1=100000*0.075+t0; t2=200000*0.05+t1; t3=200000*0.03+t2; t4=400000*0.015+t3; do{ printf("inputprofits:"); scanf("%d",&i); if(i<0) printf("\nErrorNumber\n"); }while(i<0); if(i<=100000) m=i*0.1; elseif(i<=200000) m=t0+(i-100000)*0.075; elseif(i<=400000) m=t1+(i-200000)*0.05; elseif(i<=600000) m=t2+(i-400000)*0.03; elseif(i<=1000000) m=t3+(i-600000)*0.015; else m=t4+(i-1000000)*0.01; printf("Commission:%.2f\n",m);}#include<stdio.h>intmain(){ floatt0,t1,t2,t3,t4,m; inti,t; t0=100000*0.1; t1=100000*0.075+t0; t2=200000*0.05+t1; t3=200000*0.03+t2; t4=400000*0.015+t3; do{ printf("inputprofits:"); scanf("%d",&i); if(i<0) printf("\nErrorNumber\n"); else { t=(int)(i/100000); if(t>=10)t=10; } }while(i<0); switch(t) { case0:m=i*0.1;break; case1:m=t0+(i-100000)*0.075;break; case2: case3:m=t1+(i-200000)*0.05;break; case4: case5:m=t2+(i-400000)*0.03;break; case6: case7: case8: case9:m=t3+(i-600000)*0.015;break; case10:m=t4+(i-1000000)*0.01; } printf("Commission:%.2f\n",m);}有四个圆塔，圆心分别为（2，2）、（-2，2）、（-2，-2）和（2，-2）。圆的半径为1米。这四个塔的高度均为10米，塔以外无任何建筑物。今输入任意一点的坐标，求出该点的建筑高度（塔外的高度为零）。#include<stdio.h>main(){ floatx,y; printf("x="); scanf("%f",&x); printf("y="); scanf("%f",&y); if(((x-2)*(x-2)+(y-2)*(y-2)<=1)||((x+2)*(x+2)+(y+2)*(y+2)<=1)||((x-2)*(x-2)+(y+2)*(y+2)<=1)||((x+2)*(x+2)+(y-2)*(y-2)<=1)) { printf("该点的高度为10"); printf("\n"); } else printf("该点的高度为0");}设计一个程序能够输出以下数列14710131619222528...的前20项#include<stdio.h>intmain(){ inti=1,count=0; do { printf("%4d",i); count++; if(count%5==0)printf("\n"); i=i+3; }while(count<=20); return0;}从键盘输入n的值，并求1到n的阶乘。#include<stdio.h>intmain(){ intn; longprod=1; do { printf("inputintegern:"); scanf("%d",&n); if(n<0) printf("inputnisnotlessthan0\n"); }while(n<0); while(n>0) { prod*=n; n--; } printf("product:%ld\n",prod); return0;}计算如下分数序列的和，1/1，1/3，1/5，1/7，......，1/101#include<stdio.h>intmain(intargc,char*argv[]){ inti=1; floatsum=0; while(i<=101) { sum+=(float)1/i; i+=2; } printf("sum:%.2f\n",sum); return0;}计算如下分数序列的前20项及他们的和：2/1，3/2，5/3，8/5，13/8，21/13，....#include<stdio.h>intmain(intargc,char*argv[]){ inta=2,b=1,count=0,temp; floatsum=0; do { printf("%d/%d\n",a,b); count++; sum+=(float)a/b; temp=a+b; b=a; a=temp; }while(count<=20); printf("sum:%.2f\n",sum); return0;}输入行数n，输出下列三角形图案#include<stdio.h>intmain(){ intn,i,j; printf("inputrownumber:"); scanf("%d",&n); for(i=1;i<=n;i++) { for(j=i;j<n;j++) printf(""); for(j=1;j<=2*i-1;j++) printf("*"); printf("\n"); } return0;}猴子吃桃问题。猴子第一天摘下若干个桃子，当即吃了一半，还不过瘾，又多吃了一个。第二天早上又将剩下的桃子吃掉了一半，又多吃了一个。以后每天早上都吃了前一天剩下的一半零一个。到第１０天早上想再吃时，见只剩下一个桃子了。求第一天共摘了多少桃子。#include<stdio.h>intmain(){ inttotal=1; intday; for(day=10;day>0;day--) total=(total+1)*2; printf("total:%d",total); return0;}输入一个正整数，输出平方根,取两位小数。#include<stdio.h>#include<math.h>intmain(){ intn; do { printf("inputplusinteger:"); scanf("%d",&n); if(n<0)printf("inputerror"); }while(n<0); printf("squareroot:%.2f\n",sqrt(n)); return0;}计算并输出如下分数序列的和，2/4，4/7，6/10，......，66/100。#include<stdio.h>intmain(){ inti=1,a=2,b=4; floatsum=0;do{ printf("%d/%d\n",a,b); sum+=(float)a/b; i++; a=2*i; b=1+3*i; }while(b<=100); printf("sum=%.2f\n",sum);}输入10个数，求平均值，输出所有大于平均值的数#include<stdio.h>#defineN10intmain(){ inta[N],i; floatsum=0; printf("input%dinterger:",N); for(i=0;i<N;i++) { scanf("%d",&a[i]); sum+=a[i]; }printf("average=%.2f\n",sum/N);printf("morethanaverage:\n"); for(i=0;i<N;i++) { if(a[i]>sum/N) printf("%5d",a[i]); } printf("\n"); return0;}从键盘输入20个整数到一维数组，输出其中最大的数。#include<stdio.h>#defineN20intmain(intargc,char*argv[]){ inta[N],max,i; for(i=0;i<N;i++) scanf("%d",&a[i]); max=a[0]; for(i=1;i<N;i++) if(max<a[i]) max=a[i]; printf("biggest:%d\n",max); return0;}输入10个整数到一个一维数组，将最大的元素与第一个元素交换，最小的元素与最后一个元素交换，然后输出数组所有元素#include<stdio.h>#defineN10intmain(intargc,char*argv[]){ inta[N],max,i,min,imax,imin,temp; for(i=0;i<N;i++) scanf("%d",&a[i]); max=a[0];min=a[N-1]; for(i=0;i<N;i++) { if(max<a[i]) { max=a[i]; imax=i; } if(min>a[i]) { min=a[i]; imin=i; } } if(max!=a[0]) { temp=a[0]; a[0]=a[imax]; a[imax]=temp; } if(min!=a[N-1]) { temp=a[N-1]; a[N-1]=a[imin]; a[imin]=temp; } for(i=0;i<N;i++) printf("%5d",a[i]); return0;}从键盘输入10个数到数组中，求数组所有元素的平均数#include<stdio.h>#defineN10intmain(){ inta[N],i; floatsum=0; printf("input%dinterger:",N); for(i=0;i<N;i++) { scanf("%d",&a[i]); sum+=a[i]; }printf("average=%.2f\n",sum/N); return0;}#include<stdio.h>#defineN5intmain(){ inta[N],i,j,temp,k; printf("input%dinterger:",N); for(i=0;i<N;i++) { scanf("%d",&a[i]); }for(i=0;i<N-1;i++){ k=i; for(j=i+1;j<N;j++) if(a[j]>a[k])k=j; if(k!=i) { temp=a[i]; a[i]=a[k]; a[k]=temp; }} for(i=0;i<N;i++) { printf("%5d",a[i]); if((i+1)%5==0)printf("\n"); } return0;}输入并运行下面的程序,查看编译时的出错信息，分析出错的原因,然后修改这个程序使其能够正常运行main(){ flo(9.9);}floatflo(floatm){ printf("%f",m); retutnm;}#include<stdio.h>#include<string.h>intmain(){ charstr[20],temp; inti,j; printf("inputstring:"); gets(str); for(i=0;str[i]!='\0';i++); for(j=--i,i=0;j>i;j--,i++) { temp=str[i]; str[i]=str[j]; str[j]=temp; } puts(str); return0;}#include<stdio.h>floatflo(floatm);main(){ flo(9.9);}floatflo(floatm){ printf("%f",m); returnm;}写四个函数分别用于计算圆周长、圆面积、圆柱表面积，圆柱体积。写一个主函数能够显示菜单，调用前面写的四个函数来计算圆周长、圆面积、圆柱表面积，圆柱体积，圆周率使用宏定义。#include<stdio.h>intprime(intdata){ inti; for(i=2;i<data/2;i++){ if(data%i==0) return0; } return1;}intmain(intargc,char**argv){ inta,b,i; printf("输入两个数\n"); scanf("%d%d",&a,&b); for(i=a;i<=b;i++) { if(prime(i)==1) printf("%d",i); } return0;}#include<stdio.h>#definepi(3.14)floatzhouchang(floatr){ return2*pi*r;}floatmianji(floatr){ returnpi*r*r;}floatyuanzhubiaomianji(floatr,floath){ returnpi*r*r*2+2*pi*r*h;}floatyuanzhutiji(floatr,floath){ returnpi*r*r*h;}voidprintMenu(){ printf("1.圆周长\n"); printf("2.圆面积\n"); printf("3.圆柱表面积\n"); printf("4.圆柱体积\n"); printf("0.退出\n");}intmain(intargc,char**argv){ intcmd; while(1) { printMenu(); scanf("%d",&cmd); switch(cmd) { case1: { floatr; scanf("%f",&r); printf("圆周长为%f\n",zhouchang(r)); break; } case2: { floatr; scanf("%f",&r); printf("圆面积为%f\n",mianji(r)); break; } case3: { floatr,h; scanf("%f",&r); scanf("%f",&h); printf("圆柱表面积为%f\n",yuanzhubiaomianji(r,h)); break; } case4: { floatr,h; scanf("%f",&r); scanf("%f",&h); printf("圆柱体积为%f\n",yuanzhutiji(r,h)); break; } case0: exit(); } }}#include<stdio.h>intjiecheng(inta){ inti=1,v=1; for(i=1;i<=a;i++) v=v*i; returnv;}intmain(intargc,char**argv){ intm,n; printf("请输入任意两个数字\n"); scanf("%d%d",&m,&n); printf("result=%d\n",jiecheng(m)/(jiecheng(n)*jiecheng(m-n)));}#include<stdio.h>floatjieduizhi(floata){ if(a>0) returna; else return-a;}intmain(intargc,char**argv){ floatm,n; printf("请输入任意两个数字\n"); scanf("%f%f",&m,&n); printf("result=%f\n",jieduizhi(m)+jieduizhi(n));}#include<stdio.h>intmain(intargc,char*argv[]){ inta[]={2,3,4,5,6}; int*p1; char*p2="computer\n"; p1=a; printf("%d\n",p1+2); printf("%d\n",*(p1+2)); p1=a+2; printf("%d\n",p1+2); printf("%d\n",*(p1+2)); printf("%d\n",p2+2); printf("%s\n",p2+2); return0;}定义一个可以保存10个整型数的一维数组，用数组初始化的方法将10个数据（3，7，9，8，5，4，3，1，0，2）赋值到数组，用指针操作数组依次输出这十个数，再以逆序输出这十个数。#include<stdio.h>intmain(intargc,char*argv[]){ inta[10]={3,7,9,8,5,4,3,1,0,2}; voidprintparr(int*p,intn); printparr(a,10); return0;}voidprintparr(int*p,intn){ inti; for(i=0;i<n;i++) { printf("%d",*(p+i)); } printf("\n"); for(i=n-1;i>=0;i--) { printf("%d",*(p+i)); }}写一个函数判断一个字符串是否一个11位的手机号码。然后在主函数中调用这个函数。#include<stdio.h>intmain(intargc,char*argv[]){ chartelephone[12]; intflag; intjudgetele(char*p); printf("请输入11位电话号码：\n"); scanf("%s",telephone); flag=judgetele(telephone); if(flag==1) printf("%shas11digits",telephone); else printf("%shasnot11digitsoftelephone",telephone); return0;}intjudgetele(char*p){ inti=0; if(*p=='1') for(p=p+1,i=1;*p!='\0';p++) { if(*p>='0'&&*p<='9') i++; else break; } if(i==11) return1; else return0; }#include<stdio.h>#defineN10voidsort(int*p,intn){ inti,j,k,temp; for(i=0;i<n-1;i++) { k=i; for(j=i+1;j<n;j++) if(*(p+k)>*(p+j)) k=j; if(k!=i) { temp=*(p+i); *(p+i)=*(p+k); *(p+k)=temp; } }}intmain(){ inta[N],i; printf("输入%d个数：",N); for(i=0;i<N;i++) scanf("%d",&a[i]); sort(a,N); for(i=0;i<N;i++) printf("%d",a[i]); return0;}#include<stdio.h>#defineN20floatdata[N]={0};intnum=0;intinsert(floata){ if(num<N) { data[num]=a; num++; return1; }else return0;}intdelete(intindex){ if(index>=0&&index<(num-1)) { memmove(&data[index],&data[index+1],(num-index-1)*sizeof(float)); num--; return1; }else return0;}voidsort(){ inti,j; for(i=0;i<num-1;i++) { for(j=i;j<num-1;j++) { if(data[j+1]<data[j]) { floattmp; tmp=data[j]; data[j]=data[j+1]; data[j+1]=tmp; } } }}voidprintData(){ inti; for(i=0;i<num;i++) { printf("%f\n",data[i]); }}写程序显示如下菜单1.insert(插入一个数据)2.delete(删除一个数据)3.sort(排序)4.print(输出表中所数据)0.exit(退出程序)voidprintMenu(){ printf("1.插入数据\n"); printf("2.删除数据\n"); printf("3.排序\n"); printf("4.打印数据\n"); printf("0.退出程序\n"); printf("pleaseinput0-4number\n");}intmain(intargc,char*argv[]){ intcmd=0; while(1) { printMenu(); scanf("%d",&cmd); switch(cmd) { case1: { floata; scanf("%f",&a); insert(a); break; } case2: { intindex; scanf("%d",&index); delete(index); break; } case3: { sort(); break; } case4: { printData(); break; } case0: exit(); } } return0;}#include<stdio.h>#include<string.h>intmain(intargc,char*argv[]){ structdate { intyear; intmonth; intday; }; structstudent { charname[20]; charstuID[10]; charsex[3]; structdatebirthday; floatenrollScore; }stu1; strcpy(,"timing"); strcpy(stu1.stuID,"1105"); strcpy(stu1.sex,"男"); stu1.birthday.year=1990; stu1.birthday.month=12; stu1.birthday.day=10; stu1.enrollScore=560; return0;}#include<stdio.h>#defineN2structstudent{ charstuID[10]; charname[20]; charsex[10]; intage; floatchinScore; floatmathScore; floatengScore; floattotalScore; floataverageScore;};voidprintScore(structstudent*stu,intnum){ inti; for(i=0;i<num;i++) { stu[i].totalScore=stu[i].chinScore+stu[i].mathScore+stu[i].engScore; stu[i].averageScore=stu[i].totalScore/3; printf("%s",stu[i].stuID); printf("%s",stu[i].name); printf("%s",stu[i].sex); printf("%d",stu[i].age); printf("%f",stu[i].chinScore); printf("%f",stu[i].mathScore); printf("%f",stu[i].engScore); printf("%f",stu[i].totalScore); printf("%f\n",stu[i].averageScore); }}intmain(intargc,char*argv[]){ inti; structstudentstu[N]; printf("input%dseries\nstuIDnamesexagechinScore\ mathScoreengScore",N); printf("totalScore\n"); for(i=0;i<N;i++) { scanf("%s",stu[i].stuID); scanf("%s",stu[i].name); scanf("%s",stu[i].sex); scanf("%d",&stu[i].age); scanf("%f",&stu[i].chinScore); scanf("%f",&stu[i].mathScore); scanf("%f",&stu[i].engScore); } printScore(stu,N); return0;}输入圆的面积输出圆的半径。#include<stdio.h>#include<math.h>#definePI3.14intmain(intargc,char*argv[]){ floatarea,r; printf("pleaseinputareaofcircle:"); scanf("%f",&area); r=sqrt(area/PI); printf("r=%.2f\n",r); return0;}某停车场按停车时间收费如下不足1小时收费7元，超过1小时的每小时收费12元，超过一天（24小时）的按每小时收费15元。#include<stdio.h>intmain(intargc,char*argv[]){ floatt,price; printf("pleas