C语言程序设计实验与习题指导同步自测答案

C语言程序设计实验与习题指导同步自测答案C语言程序设计实验与习题指导同步自测答案C语言程序设计实验与习题指导同步自测答案xxx公司C语言程序设计实验与习题指导同步自测答案文件编号：文件日期：修订次数：第1.0次更改批准审核制定方案设计，管理制度C语言程序设计实验与习题指导同步自测答案2.1.3同步自测一、选择题二、填空题1.①c②exe2.①main3.①函数说明部分②函数体4.①主或main②主或main5.①;2.2一、选择题2.3一、选择题2.4一、选择题二．编程题1.#include<>voidmain(){intx,y;printf("请输入自变量x的值:");scanf("%d",&x);if(x<0)y=3*x+1;elseif(x<5)y=2*x;elsey=x+2;printf("\n函数y的值为:%d",y);}2.#include<>voidmain(){inta,b,c,d,t;printf("请输入四个整数:\n");scanf("%d%d%d%d",&a,&b,&c,&d);if(a>b){t=a;a=b;b=t;}if(a>c){t=a;a=c;c=t;}if(a>d){t=a;a=d;d=t;}if(b>c){t=b;b=c;c=t;}if(b>d){t=b;b=d;d=t;}if(c>d){t=c;c=d;d=t;}printf("按新顺序输出的数为:%d%d%d%d",a,b,c,d);}2.5一、选择题二、填空题1.①getchar()2.①n++3.①′\n′②num++；4.①n<=m②total=total+sum5.①(i/100)*(i/100)*(i/100)+((i/10)%10)*((i/10)%10)*((i/10)%10)+(i%10)*(i%10)*(i%10)②g==i6.①107.①i%j==08.①b9.①y=1②x%i==010.①2*x+4*y==90三．读程序写结果题1.8，172.57233.4四．编程题1.main(){intx,y,a,b;for(x=100;x<1000;x++){y=0;a=x;while(a){y=y*10+a%10;a=a/10;}if(x+y==1333)printf("a=%d;b=%d;c=%d\n",x/100,(x/10)%10,x%10);}}2.main(){longx,y/*存放x*/,n/*记录x的位数*/,s/*存放x*x*/;longz/*存放被取的顺序从右到左的相应部位数字*/,t/*十进制的权*/;for(x=1;x<=100;x++){y=x;n=0;z=0;t=1;while(y){n++;/*记录x的位数*/y=y/10;}s=x*x;for(;n>0;n--){z+=(s%10)*t;/*取相应部位数字*/t*=10;s=s/10;}if(x==z)printf("%-10ld",x);}}3.main(){inti;for(i=1;i<=100;i++)if((i+3)%5==0&&(i-3)%6==0){printf("%d",i);break;}}4.main(){intx,a,b,c;for(x=100;x<1000;x++){a=x/100;b=(x/10)%10;c=x%10;if(a*a*a+b*b*b+c*c*c==1099)printf("%-10d",x);}}5.main(){intx,a,b,c,count=0;for(x=100;x<1000;x++){a=x/100;b=(x/10)%10;c=x%10;if(a+b+c==5)count++;}printf("共有%d个其各位数字之和是5的数字",count);}2.6一、选择题二、填空题1.①fac(n-1)2.①a*a%8!=13.①a%b4.①i++5.①j!=0或j②n%10+’06.①x>=’a’&&x<=’z’7.①x=n②n%10③x三、读程序写结果题4.1231.9,192.f=63.4.1235.306.-5,-12,-77.10,20,308.!EDCBA9.432110.715.12345633-22,5,115.12345633-22,5,1123,45614.1,7,310,7,31,7,410,7,46,7,412.17,7,717,8,1113.5,2516.j=216.j=2S=1017.15,14518.6四、编程题1.#include<>voiddelspace(char*s){inti,j;for(i=0,j=0;s[i]!=’\0’;i++)if(s[i]!=’’){s[j]=s[i];j++}s[j]=’\0’;}2.#include<>#include<>voidmain()2.#include<>#include<>voidmain(){intadddigit(intnum);intn;scanf(“%d”,&n);printf(“sum=%d\n”,addigit(n));}intaddigit(intnum){ints=0;num=abs(num);do{s+=num%10;num/=10;}while(num);returns;}{char*str;printf(“inputstring:”);gets(str);delspace(str);printf(“%s”,str);}3.#include<>#include<>voidmain(){intisprime(intx);inta;printf(“pleaseinputthenumber:\n”);scanf(“%d”,&a);if(isprime(a))printf(“the%disaprime\n”,a);elseprintf(“the%disnotaprime\n”,a);}intisprime(intx){intj;for(j=2;j<=sqrt(x);j++)if(x%j==0)return0;return1;}2.7一、选择题二、填空题1.①k=p2.①a[i][j]<min3.①i+j==24.①continue5.①j=3②a[j-1][k-1]6.①x/10或int(x/10)7.①!(s[i]>=’0’&&s[i]<=’98.①a[n-i-1]=temp三、读程序写结果题1.max=10,row=2,colum=12.18,103.countryside4.xbcdBCD四、编程题1.参考程序及评分标准一：#include<>#defineN5viodmain(){inta[N+1],x,i,k;for(i=0;i<N;i++)scanf("%d",&a[i]);scanf("%d",&x);#include<>#include<>voidmain(){voidcopystr(char*p1,char*p2,intm);2.#include<>#include<>voidmain()2.#include<>#include<>voidmain(){voidreverse(chars[]);chars1[80];gets(s1);reverse(s1);puts(s1);}voidreverse(chars[]){inti,j,c;for(i=0,j=strlen(s)-1;i<j;i++,j--){c=s[i];s[i]=s[j];s[j]=c;}}scanf(“%s”,str1);scanf(“%d”,&m);if(strlen(str1)<m)printf(“inputerror”);else{copystr(str1,str2,m);printf(“theresu