C程序设计第四版谭浩强-课后习题答案-共11章

1-5#include<stdio.h>intmain()printf(" VeryGood!\n\n");printf(\n");intmain()printf(" VeryGood!\n\n");printf(\n");return0;l-6#include<stdio.h>intmain(){inta,b,c,max;printf("pleaseinputa,b,c:\n");scanf("%d,%d,%d",&a,&b,&c);max=a;if(max<b)max=b;if(max<c)max=c;printf("Thelargestnumberis%d\n",max);return0;)习题36习题823-1#include<stdio.h>#include<math.h>intmain(){floatp,r,n;r=0.1;n=10;p=pow((1+r),n);printf("p=%f\n",p);return0;)3-2-1#include<stdio.h>#include<math.h>intmain(){floatr5,r3,r2,rl,rO,p,pI,p2,p3,p4,p5;p=1000;r5=0.0585;r3=0.054;r2=0.0468;rl=0.0414;r0=0.0072;pl=p*((l+r5)*5);p2=p*(l+2*r2)*(1+3*r3);息再存3年期p3=p*(l+3*r3)*(l+2*⑵；息再存2年期p4=p*pow(l+rl,5);存再存1年期,连续存5次p5=p*pow(l+r0/4,4*5);ー季度结算ー次printf("pl=%f\n",p1);和printf("p2=%f\n",p2);和//一次存5年期//先存2年期,到期后将本//先存3年期,到期后将本//存1年期,到期后将本息//存活期存款。活期利息每/Z输出按第1方案得到的本息/Z输出按第2方案得到的本息printf("p3=%f\n",p3);/Z输出按第3方案得到的本息和/Z输出按第/Z输出按第4方案得到的本息/Z输出按第5方案得到的本息和printf("p5=%f\n",p5);和return0;)3-2-2#include<stdio.h>#include<math.h>intmain(){doubler5,r3,r2,rl,r0,p,pI,p2,p3,p4,p5;p=1000;r5=0.0585;r3=0.054;r2=0.0468;rl=0.0414;r0=0.0072;pl=p*((l+r5)*5);//一次存5年期p2=p*(l+2*r2)*(l+3*r3);息再存3年期p3=p*(l+3*r3)*(l+2*r2);息再存2年期p4=p*pow(l+rl,5);存再存1年期,连续存5次p5=p*pow(l+r0/4,4*5);一季度结算一次printf("pl=%f\n",pl);和printf(,'p2=%f\n',,p2);和printf("p3=%f\n",p3);和printf("p4=%f\n",p4);和printf("p5=%f\n",p5);和return0;//先存2年期,到期后将本//先存3年期,到期后将本〃存1年期,到期后将本息//存活期存款。活期利息每/Z输出按第1方案得到的本息/Z输出按第2方案得到的本息/Z输出按第3方案得到的本息/Z输出按第4方案得到的本息/Z输出按第5方案得到的本息3-2-3#include<stdio.h>#include<math.h>intmain(){floatr5,r3,r2,rl,rO,p,pI,p2,p3,p4,p5;p=1000;r5=0.0585;r3=0.054;r2=0.0468;rl=0.0414;r0=0.0072;pl=p*((l+r5)*5); 〃ー次存5年期p2=p*(l+2*i*2)*(l+3*r3); //先存2年期,到期后将本息再存3年期p3=p*(l+3*r3)*(l+2*r2); //先存3年期,到期后将本息再存2年期p4=p*pow(l+rl,5); 〃存1年期,到期后将本息存再存1年期,连续存5次p5=p*pow(l+r0/4,4*5); //存活期存款。活期利息每ー季度结算ー次printf("pl=%10.2f\n",pl);〃输出按第1方案得到的

本息和方案得到的方案得到的方案得到的方案得到的方案得到的方案得到的方案得到的本息和printf("p3=%10.2An",p3); /Z输出按第本息和printf("p4=%10.2f\n",p4); //输出按第本息和printf("p5=%10.2f\n",p5); /Z输出按第本息和return0;)3-3.#include<stdio.h>#include<math.h>intmain(){floatd=300000,p=6000,r=0.0l,m;m=log10(p/(p-d*r))/log10(1+r);printf("m=%6.2f\n",m);return0;3-4#include<stdio.h>intmain(){intcl,c2;cl=197;c2=198;printf("cl=%c,c2=%c\n",c1,c2);printf("cl=%d,c2=%d\n",cl,c2);return0;)3-5#include<stdio.h>intmain(){inta,b;floatx,y;charcl,c2;scanf("a=%db=%d",&a,&b);scanf("%f%e",&x,&y);scanf("%c%c",&cl,&c2);printf("a=%d,b=%d,x=%f,y=%f,cl=%c,c2=%c\n",a,b,x,y,cl,c2)return0;)3-6#include<stdio.h>intmain()(charcl='C',c2='h',c3='i',c4='n',c5='a';cl=cl+4;c2=c2+4;c3=c3+4;c4=c4+4;

c5=c5+4;printf("passworis%c%c%c%c%c\n",cl,c2,c3,c4,c5);return0;)3-7#include<stdio.h>intmain(){floath,r,l,s,sq,vq,vz;floatpi=3.141526;printf("请输入圆半径r,圆柱高h：");scanf("%f,%f,,&r,&h);〃要求输入圆半径r和圆柱咼hl=2*pi*r;〃计算圆周长1s=r*r*pi;〃计算圆面积sq=4*pi*r*r;〃计算圆球表面积sqvq=3.0/4.0*pi*r*r*r;〃计算圆球体积vqvz=pi*r*r*h;vz=pi*r*r*h;〃计算圆柱体积vzprintf("圆周长为:l=%6.2f\n",l);printf("圆面积为:s=%6.2f\n",s);printf("圆球表面积为:sq=%6.2f\n",sq);printf("圆球体积为:v=%6.2f\n",vq);printf("圆柱体积为: vz=％6.2f\n",vz);return0;3-8-1#include<stdio.h>intmain()(intcl,c2; 〃整型定义printf("请输入两个整数cl,c2:");scanf("%d,%d",&cl,&c2);printf("按字符输出结果果");printf("%c,%c\n",cl,c2);printf("按ASCII码输出结果为:\n")；printf("%d,%d\n",cl,c2);return0;)3-8-2#include<stdio.h>intmain()charcl,c2;charcl,c2;〃定义字符型变〃定义整型变量〃赋值给整型〃定义整型变量〃赋值给整型〃定〃定义intil,i2;printf("请输入两个字符cl,c2:");scanf("%c,%c",&cl,&c2);il=cl;变量i2=c2;printf("按字符输出结果:'n");printf("%c,%c\n",il,i2);printf("按整数输出结果:'n");printf("%d,%d\n",cl,c2);return0;)3-8-3#include<stdio.h>intmain()(charcl,c2;义为字符型intil,i2;为整型printf("请输入两个整数il,i2:");scanf("%d,%d",&il,&i2);cl=il; 〃将整数赋值给字符变量c2=i2;printf("按字符输出结果:\ゼ);printf("%c,%c\n",cl,c2);printf("按整数输出结果:'n");printf("%d,%d\n",cl,c2);return0;3-8#include<stdio.h>intmain()(charcl,c2;printf("请输入两个字符cl,c2:");cl=getchar();c2=getchar();printf("用putchar语句输出结果为putchar(cl);putchar(c2);printf("\n");printf("用printf语句输出结果为ド);printf("%c%c\n",cl,c2);return0;)习题1114-4-1#include<stdio.h>intmain()(inta,b,c;printf("请输入三个整数:")；scanf("%d,%d,%d",&a,&b,&c);if(a<b)if(b<c)printf("max=%d\n",c);elseprintf("max=%d\n",b);elseif(a<c)printf("max=%d\n",c);elseprintf("max=%d\n",a);return0;)4-4-2#include<stdio.h>intmain(){inta,b,c,temp,max;printf("请输入三个整数:");scanf("%d,%d,%d",&a,&b,&c);temp=(a>b)?a:b; /・将a和b中的大者存入temp中・/max=(temp>c)?temp:c; /・将a和b中的大者与c比较,取最大者・/printf("三个整数的最大数是％d\n",max);return0;#include<stdio.h>#include<math.h>#defineM1000intmain()(inti,k;printf("请输入一个小于％d的整数scanf("%d",&i);while(i>M){printf(”输入的数不符合要求,请重新输入一个小于％d的整数i：”,M);scanf("%d",&i);)k=sqrt(i);printf("%d的平方根的整数部分是:%d\n",i,k);return0;)4-5#include<stdio.h>#include<math.h>#defineM1000intmain()(inti,k;printf("请输入一个小于％d的整数scanf("%d",&i);if(i>M){printf("输入的数不符合要求,请重新输入一个小于％d的整数scanf("%d",&i);)k=sqrt(i);printf("%d的平方根的整数部分是:%d\n",i,k);return0;4-6.#include<stdio.h>intmain(){intx,y;printf("输入x:");scanf("%d",&x);if(x<1){y=x；printf("x=%3d,}elseif(x<10){y=2*x-l;printf("x=%d,}else{y=3*x-ll;printf("x=%d,}return0;/*x<l*/y=x=%d\n",x,y);/*l=<x<10*/y=2*x-l=%d\n",x,y);/*x>=10*/y=3*x-11=%d\n",x,y)#include<stdio.h>intmain()(intx,y;printf("enterx:");scanf("%d",&x);y=-i;if(x!=O)if(x>0)y=l;elsey=0;printf("x=%d,y=%d\n",x,y);return0;)4-7-2#include<stdio.h>intmain()intx,y;printf("pleaseenterx:");scanf("%d",&x);y=0;if(x>=0)if(x>0)y=l;elsey="l;printf("x=%d,y=%d\n",x,y);return0;)4-8#include<stdio.h>intmain(){floatscore;chargrade;printf(”请输入学生成绩:")；scanf("%f",&score);while(score>100llscore<0){printf("\n输入有误,请重输つ;scanf("%f',&score);switch((int)(score/10)){case10:case9:grade='A';break;case8:grade='B';break;case7:grade='C;break;case6:grade='D';break;case5:case4:case3:case2:case1:case0:grade='E';),score,grade);printf("成绩是％5.1f,相应的等级是％c\nreturn0;,score,grade);)4-9#include<stdio.h>#include<math.h>intmain()int num,indiv,ten,hundred,thousand,ten_thousand,place;〃分别代表个位,十位,百位,千位,万位和位数printf("请输入ー个整数(〇ー99999)ゴ);scanf("%d",&num);if(num>9999)place=5;elseif(num>999)place=4;elseif(num>99)place=3;elseif(num>9)place=2;elseplace=l;printf("位数:％d\n",place);printf("每位数字为:")；ten_thousand=num/10000;thousand=(int)(num-ten_thousand*10000)/1000;hundred=(int)(num-ten_thousand*10000-thousand*1000)/100;ten=(int)(num-ten_thousand*10000-thousand*1000-hundred*100)/10;indiv=(int)(num-ten_thousand*1OOOO-thousand*1000-hundred*100-ten*10);switch(place){case5:printf("%d,%d,%d,%d,%d",ten_thousand,thousand,hundred,ten,indiv);printf("\n反序数字为ゴ);printf("%d%d%d%d%d\n",indiv,ten,hundred,thousand,ten_thousand);break;case4:printf("%d,%d,%d,%d",thousand,hundred,ten,indiv);printf("\n反序数字为ア);printf("%d%d%d%d\n",indiv,ten,hundred,thousand);break;case3:printf("%d,%d,%d",hundred,ten,indiv);printf("\n反序数字为ぐ);printf("%d%d%d\n",indiv,ten,hundred);break;case2:printf("%d,%d",ten,indiv);printf("\n反序数字为ア)；printf("%d%d\n",indiv,ten);break;case1:printf("%d",indiv);printf("\n反序数字为ア);printf("%d\n",indiv);break;}return0;4-10-1#include<stdio.h>intmain()(inti;doublebonus,bon1,bon2,bon4,bon6,bon10;bon1=100000*0.1;bon2=bon1+100000*0.075;bon4=bon2+l00000*0.05;bon6=bon4+100000*0.03;bonl0=bon6+400000*0.015;printf("请输入利润i:");scanf("%d",&i);if(i<=100000)bonus=i*0.1;elseif(i<=200000)bonus=bon1+(i-l00000)*0.075;elseif(i<=400000)bonus=bon2+(i-200000)*0.05;elseif(i<=600000)bonus=bon4+(i-400000)*0.03;elseif(i<=1000000)bonus=bon6+(i-600000)*0.015;elsebonus=bon10+(i-l000000)*0.01;printf("奖金是:%10.2f\n",bonus);return0;4-10-2#include<stdio.h>intmain()(inti;doublebonus,bon1,bon2,bon4,bon6,bon10;intbranch;bon1=100000*0.1;bon2=bon1+100000*0.075;bon4=bon2+200000*0.05;bon6=bon4+200000*0.03;bon10=bon6+400000*0.015;printf("请输入利润i:");scanf("%d",&i);branch=i/100000;if(branch>10)branch=10;switch(branch){case0:bonus=i*0.1;break;casel:bonus=bonl+(i-l00000)*0.075;break;case2;case3;bonus=bon2+(i-200000)*0.05;break;bonus=bon4+(i-400000)*0.03;break;bonus=bon6+(i-600000)*0.015;break;bonus=bon10+(i-1000000)*0.01;Iprintf("奖金是%10.2f\n",bonus);return0;4-11#include<stdio.h>intmain(){intt,a,b,c,d;printf("请输入四个数:")；scanf("%d,%d,%d,%d",&a,&b,&c,&d);printf("a=%d,b=%d,c=%d,d=%d\n",a,b,c,d);if(a>b){t=a;a=b;b=t;}if(a>c){t=a;a=c;c=t;}if(a>d){t=a;a=d;d=t;}if(b>c){t=b;b=c;c=t;}if(b>d){t=b;b=d;d=t;}if(c>d){t=c;c=d;d=t;}printf("排序结果如下:'n");printf("%d%d%d%d\n" ,a,b,c,d);return0;4-12#include<stdio.h>intmain()(inth=10;floatx1=2,y1=2,x2=-2,y2=2,x3=-2,y3=-2,x4=2,y4=-2,x,y,dI,d2,d3,d4；printf("请输入ー个点(x,y)ゴ);scanf("%f,%f",&x,&y);dI=(x-x4)*(x-x4)+(y-y4)*(y-y4); /・求该点到各中心点距离・/d2=(x-xl)*(x-x1)+(y-yl)*(y-y1);d3=(x-x2)*(x-x2)+(y-y2)*(y-y2);d4=(x-x3)*(x-x3)+(y-y3)*(y-y3);if(dl>l&&d2>l&&d3>l&&d4>l) h=0;/・判断该点是否在塔外・/printf("该点高度为%d\n",h);return0;)习题1405-2#include<stdio.h>#include<math.h> //程序中用到数学函数fabs,应包含头文件math.nintmain()(intsign=l,count=0; 〃sign用来表示数值的符号,count符号,count用来统计循环次数doublepi=0.0,n=1.0,term=1.0;值,最后代表冗的值,n代表分母,while(fabs(term)>=1e-8)绝对值是否大于或等于!0的(-6)次方pi=pi+term;到pi中n=n+2;母sign=-sign;项的符号与上一项符号相反term=sign/n;termcount++;Ipi=pi*4;以4,オ是冗的近似值printf("pi=%10.8f\n",pi);printf("count=%d\n",count);return0;//pi开始代表多项式的term代表当前项的值/Z检查当前项term的//把当前项term累加〃n+2是下ー项的分〃sign代表符号,下ー/Z求出下ー项的值//count累加1/Z多项式的和pi乘〃输出兀的近似值/Z输出循环次数5-3#include<stdio.h>intmain()(intp,r,n,m,temp;printf("请输入两个正整数n,m:");scanf("%d,%d,",&n,&m);if(n<m){temp=n;n=m;m=temp;}p=n*m;while(m!=O)(r=n%m;n=m;m=r;printf("它们的最大公约数为:％d\n”,n);printf("它们的最小公倍数为:％d\n",p/n);return0;)5-4#include<stdio.h>intmain(){charc;intIetters=0,space=0,digit=0,other=0;printf("请输入一行字符:'n")；while((c=getchar())!=*\n,)(if(c>='a'&&c<='z'IIc>='A'&&c<='Z')letters++;elseif(c=='')space++;elseif(c>='0'&&c<='9')digit++;elseother++;printf("字母数:％d\n空格数:%d\n数字数:%d\n其它字符数:％d\n”,letters,space,digit,other);return0;)5-5#include<stdio.h>intmain()(inta,n,i=1,sn=0,tn=0;printf("a,n=:");scanf("%d,%d",&a,&n);while(i<=n)(tn=tn+a;/・赋值后的tn为i个a组成数的值・/sn=sn+tn;/*赋值后的sn为多项式前i项之和・/a=a*10;++i；)printf("a+aa+aaa+...=%d\n",sn);return0;)5-6#include<stdio.h>intmain(){doubles=O,t=l;intn;for(n=l;n<=20;n++)(t=t*n;s=s+t;Iprintf("l!+2!+...+20!=%22.15e\n",s);return0;)5-7#include<stdio.h>intmain()intnl=100,n2=50,n3=10;doublek,sl=0,s2=0,s3=0;for(k=l;k<=nl;k++)/・计算1至U100的和・/{sl=sl+k;}for(k=l;k<=n2;k++)/・计算1至U50各数的平方和・/{s2=s2+k*k;}for(k=l;k<=n3;k++)/・计算1至!J10的各倒数和・/{s3=s3+l/k;}printf("sum=%15.6f\n",sl+s2+s3);return0;5-8#include<stdio.h>intmain()inti,j,k,n;printf("parcissusnumbersare");for(n=100;n<1000;n++)

i=n/100;j=n/10-i*10;k=n%10;if(n==i*i*i+j*j*j+k*k*k)printf("%d",n);)printf("\n");return0;)5-9-1#defineM1000 /・定义寻找范围・/#include<stdio.h>intmain()(intkl,k2,k3,k4,k5,k6,k7,k8,k9,kl0;inti,a,n,s;for(a=2;a<=M;a++) /*a是2-1000之间的整数,检查它是否完数ッ

{n=0;/*它是否完数ッ

{n=0;/*n用来累计a的因子的个数*/s=a; /*s用来存放尚未求出的因子之和,开始时等于a*/for(i=l;i<a;i++) /・检查i是否a的因子・/if(a%i==0) /*如果i是a的因子*/{n++; /*n加1,表示新找到ー个因子*/s=s-i; /*是尚未求出的因子之和s=s-i; /*是尚未求出的因子之和・/switch(n) /*klO*/{case1:kl=i;break;/*k2=i;break; /*k3=i;break; /*k4=i;break; /*k5=i;break; /*s减去已找到的因子,s的新值将找到的因子赋给kl...k9,或找出的笫1个因子赋给kl*/找出的笫2个因子赋给k2*/找出的笫3个因子赋给k3ッ找出的笫4个因子赋给k4*/找出的笫5个因子赋给k5qk6=i;break;/・找出的笫6个因子赋给k6*/k7=i;break;/・找出的笫7个因子赋给k7*/k8=i;break;/・找出的笫8个因子赋给k8*/k9=i;break; /・找出的笫9个因子赋给k9*/kl0=i;break;/・找出的笫10个因子赋给klO*/if(s==0){printf("%d,Itsfactorsare",a);if(n>l)printf("%d,%d",kl,k2); /*n>l表示a至少有2个因子・/if(n>2)printf(",%d",k3); /*n>2表示至少有3个因子,故应再输出ー个因子・/if(n>3)printf(",%d",k4); /*n>3表示至少有4个因子,故应再输出ー个因子・//・/・以下类似*/if(n>5)printf(",%d",k6);if(n>6)printf(",%d",k7);if(n>7)printf(",%d",k8);if(n>8)printf(",%d",k9);if(n>9)printf(",%d",klO);printf("\n");)}return0;)5-9-2#include<stdio.h>intmain(){intm,s,i;for(m=2;m<1000;m++){s=0；for(i=l;i<m;i++)if((m%i)==0)s=s+i;if(s==m){printf("%d,itsfactorsare",m);for(i=l;i<m;i++)if(m%i==0)printf("%d",i);printf("\n");))return0;5-10#include<stdio.h>intmain()(inti,n=20;doublea=2,b=l,s=0,t;for(i=l；i<=n;i++)(s=s+a/b;t=a,a=a+b,b=t;printf("sum=%16.1Of\n",s);return0;5-11#include<stdio.h>intmain()(doublesn=100,hn=sn/2;intn;for(n=2;n<=10;n++){sn=sn+2*hn; /・第n次落地时共经过的米数・/hn=hn/2;/・第n次反跳高度・/}printf("第10次落地时共经过％f米、n",sn);printf("第10次反弹％£米、n”,hn);return0;#include<stdio.h>intmain()(intday,xl,x2;day=9;x2=l;while(day>0){xl=(x2+l)*2; /*第1天的桃子数是第2天桃子数加1后的2倍.*/x2=x1;day—;)printf("total=%d\n",x1);return0;5-13#include<stdio.h>#include<math.h>intmain()floata,xO,xl;printf("enterapositivenumber:");scanf("%f",&a);x0=a/2;xl=(x0+a/x0)/2;do{xO=x1;xl=(x0+a/x0)/2;}while(fabs(x0-xl)>=le-5);printf("Thesquarerootof%5.2fis%8.5f\n",a,xl);return0;5-14#include<stdio.h>#include<math.h>intmain(){doublexl,x0,f,fl；xl=1.5;do{x0=x1;f=((2*x0-4)*x0+3)*x0-6;fl=(6*xO-8)*xO+3;xl=xO-f/fl;}while(fabs(xl-xO)>=le-5);printf("Therootofequationis%5.2f\n",xl);return0;)5-15#include<stdio.h>#include<math.h>intmain(){floatx0,xl,x2,fx0,fxl,fx2;do{printf("enterxl&x2:");scanf("%f,%f",&xl,&x2);fxl=xl*((2*xl-4)*xl+3)-6;fx2=x2*((2*x2-4)*x2+3)-6;}while(fx1*fx2>0);do{x0=(xl+x2)/2;fx0=x0*((2*x0-4)*x0+3)-6;if((fx0*fxl)<0){x2=x0;fx2=fx0;}else{xl=xO;fxl=fxO;)}while(fabs(fxO)>=le-5);printf("x=%6.2f\n",x0);return0;5-16#include<stdio.h>intmain(){inti,j,k;for(i=0;i<=3;i++){for(j=0;j<=2-i;j++)printf("");for(k=0;k<=2*i;k++)printf("*");printf("\n");)for(i=0;i<=2;i++){for(j=O；j<=i；j++)printf("");for(k=0;k<=4-2*i;k++)printf("*");printf("\n");}return0;)5-17#include<stdio.h>intmain()(chari,j,k; /・是a的对手;j是b的对手;k是c的对手・/for(i='x';i<='z';i++)for(j='x';j<='z';j++)if(i!=j)for(k='x';k<='z';k++)if(i!=k&&j!=k)if(i!='x'&&k!='x'&&k!='z')printf("A—%c\nB—%c\nC—%c\n",i,j,k);return0;I第6章利用数组处理批量数据142#include<stdio.h>#include<math.h>intmain(){inti,j,n,a[101];for(i=l;i<=100;i++)a[i]=i；a[l]=0；for(i=2;i<sqrt(100);i++)for(j=i+1;j<=100;j++){if(a[i]!=0&&a[j]!=O)if(a[j]%a[i]==0)a[j]=O；printf("\n");for(i=2,n=0;i<=100;i++){if(a[i]!=0){printf("%5d",a[i]);n++;)if(n==10){printf("\n");n=0;)}printf("\n");return0;)6-2#include<stdio.h>intmain(){inti,j,min,temp,a[11];printf("enterdata:\n");for(i=l;i<=10;i++){printf("a[%d]=",i);scanf("%d",&a[i]);printf("\n");printf("Theorginalnumbers:\n");for(i=l;i<=10；i++)printf("%5d",a[i]);printf("\n");for(i=l；i<=9;i++){min=i;for(j=i+l;j<=10;j++)if(a[min]>a[j])min=j;temp=a[i];a[i]=a[min];a[min]=temp;)printf("\nThesortednumbers:\n");for(i=l;i<=10；i++)printf("%5d",a[i]);printf("\n");return0;6-3#include<stdio.h>intmain()(inta[3][3],sum=0;inti,j;printf("enterdata:\nH);for(i=0;i<3;i++)for(j=O；j<3;j++)scanf(H%3dn,&a[i][j]);for(i=0;i<3;i++)sum=sum+a[i][i];printf("sum二％6d\n”,sum);return0;)6-4#include<stdio.h>intmain(){inta[ll]={1,4,6,9,13,16,19,28,40,100)；inttemp1,temp2,number,end,i,j;printf("arraya:\n");for(i=0;i<10;i++)printf("%5d",a[i]);printf("\n");printf("insertdata:");scanf("%d",&number);end=a[9];if(number>end)a[10]=number;else{for(i=0;i<10;i++){if(a[i]>number){templ=a[i];a[i]=number;for(j=i+l;j<ll;j++){temp2=a[j];a[j]=templ;templ=temp2;break;)printf("Nowarraya:\n");for(i=0;i<ll;i++)printf("%5d",a[i]);printf("\n");return0;6-5#include<stdio.h>#defineN5intmain()(inta[N],i,temp;printf(Henterarraya:\nu);for(i=0;i<N;i++)scanf(H%dH,&a[i]);printf(Harraya:\n")；for(i=0;ivN;i++)printf(',%4d",a[i]);〃循环的〃循环的作用是将对称的元素的值互换{temp=a[i];a[i]=a[N-i-l];a[N-i-l]=temp;)printf("\nNow,arraya:\n")；for(i=0;i<N;i++)printf(n%4dn,a[i]);printf(H\n");return0;6-6#include<stdio.h>#defineN10intmain(){inti,j,a[N][N];for(i=0;i<N;i++){a[i][i]=l；a[i][0]=l；for(i=2;i<N;i++)for(j=l；j<=i-l；j++)a[i][j]=a[i-l][j-l]+a[i-l][j];for(i=0;i<N;i++){for(j=O;j<=i;j++)printf("%6d",a[i][j]);printf("\n");)printf("\n");return0;)6-7#include<stdio.h>intmain(){inta[15][15],i,j,k,p,n;p=l；while(p==l){printf("entern(n=1—15):");scanf("%d",&n);if((n!=0)&&(n<=15)&&(n%2!=0))P=0;for(i=l；i<=n;i++)for(j=l;j<=n;j++)a[i][j]=0；j=n/2+l;a[l]U]=l；for(k=2;k<=n*n;k++){i=i-l；j=j+Uif((i<l)&&(j>n)){i=i+2;)else{if(i<l)i=n;if(j>n)j=l;)if(a[i]U]==0)a[i][j]=k；else{i=i+2；j=j-l;a[i][j]=k;for(i=l；i<=n;i++){for(j=l;j<=n;j++)printf("%5d",a[i][j]);printf("\n");)return0;6-8#include<stdio.h>#defineN4#defineM5 /・数组为4行5列・/intmain()(inti,j,k,a[N][M],max,maxj,flag;printf("pleaseinputmatrix:\n");for(i=0;i<N;i++)for(j=O；j<M;j++)scanf("%d",&a[i][j]);for(i=0;i<N;i++)

{max=a[i][0];*/maxj=0;存・/for(j=O;j<M;j++)if(a[i][j]>max)

{max=a[i][j];max中・/maxj=j;放在maxj中・/)flag=l;为1代表・/for(k=0;k<N;k++)if(max>a[k][maxj])比・/{flag=0;表示不是鞍点令flagl为0・//・输入数组・//・开始时假设a[i][0]最大/・将列号〇赋给maxj保/・找出第i行中的最大数・//・将本行的最大数存放在/・将最大数所在的列号存/・先假设是鞍点,以flag/・将最大数和其同列元素相/・如果max不是同列最小,continue;}if(flag) /・如果flagl为1表示是鞍点・/{printf("a[%d][%d]=%d\n",i,maxj,max);/*输出鞍点的值和所在行列号ッbreak;})if(!flag) /・如果flag为。表示鞍点不存在・/printf("Itisnotexist!\n");return0;6-9#include<stdio.h>#defineN15intmain(){inti,number,top,bott,mid,loca,a[N],flag=l,sign;charc;printf("enterdata:\n");scanf("%d",&a[O]);i=l；while(i<N){scanf("%d",&a[i]);if(a[i]>=a[i-l])i++；elseprintf("enterthisdataagainAn");}printf("\n");for(i=0;i<N;i++)printf("%5d",a[i]);printf("\n");while(flag){printf("inputnumbertolookfor:");scanf("%d",&number);sign=0;top=0; 〃top是査找区间的起始位置bott=N-l; 〃bott是查找区间的最末位置if((number<a[O])ll(number>a[N-1]))〃要查的数不在查找区间内loca=-1;//表不找不到while((!sign)&&(top<=bott)){mid=(bott+top)/2;if(number==a[mid]){loca=mid;positionprintf("Hasfound%d,is%d\n",number,loca+l);positionsign=l;}elseif(number<a[mid])bott=mid-l;elsetop=mid+l;}if(!signllloca==-l)printf("cannotfind%d.\n",number);;printf("continuornot(Y/N)?");scanf("%c",&c);if(c=='N'llc=='n')flag=0;return0;6-10#include<stdio.h>intmain(){inti,j,upp,low,dig,spa,oth;chartext[3][80];upp=low=dig=spa=oth=0;for(i=0;i<3;i++){printf("pleaseinputline%d:\n",i+l);gets(text[i]);for(j=0;j<80&&text[i][j]!='\O';j++){if(text[i][j]>='A'&&text[i][j]<='Z')upp++；elseif(text[i][j]>='a'&&text[i][j]<='z')low++;elseif(text[i][j]>=(0'&&text[i][j]<='9')dig++;elseif(text[i][j]=='')spa++;elseoth++;printf("\nuppercase:%d\n",upp);printf("lowercase:%d\n",low);printf("digit:%d\n",dig);printf("space :%d\n",spa);printf("other :%d\n",oth);return0;)6-11#include<stdio.h>intmain(){chara[5]={inti,j,k;charspace='for(i=0;i<5;i++){printf("\n");printf("");for(j=l;j<=i;j++)printf("%c",space);for(k=0;k<5;k++)printf("%c",a[k]);)printf("\n");return0;6-12a-c#include<stdio.h>intmain(){intj,n;charch[80],tran[80];printf("inputciphercode:");gets(ch);printf("\nciphercode:%s",ch);j=0；while(chU]!='\0'){if((ch[j]>='A')&&(ch[j]<='Z'))tran[j]=155-ch[j];elseif((ch[j]>='a')&&(ch[j]<='z'))tran[j]=219-ch[j];elsetran[j]=ch[j];j++；)n=j；printf("\noriginaltext:");for(j=O；j<n;j++)putchar(tran[j]);printf("\n");return0;6-12b#include<stdio.h>intmain(){intj,n;charch[80];printf("inputciphercode:\n");gets(ch);printf("\nciphercode:%s\n",ch);j=0;while(chU]!='\0'){if((ch[j]>='A')&&(ch[j]<='Z'))ch[j]=155-ch[j];elseif((ch[j]>='a')&&(ch[j]<='z'))ch[j]=219-ch[j];elsech[j]=ch[j];j++；)n=j；printf("originaltext:");for(j=O;j<n;j++)putchar(ch[j]);printf("\n");return0;6-13#include<stdio.h>intmain()(charsl[80],s2[40];inti=O,j=O;printf("inputstring!scanf(H%sn,sl);printf(Hinputstring2:H);scanf("%sn,s2);while(sl[i]!='\Of)i++；while(s2[j]!=,\0,)sl[i++]=s2[j++];sl[i]=\O,;printf(H\nThenewstringis:%s\n",sl);return0;#include<stdio.h>intmain(){inti,resu;charsl[100],s2[100];printf("inputstring1:");gets(sl);printf("\ninputstring2:");gets(s2);i=0;while((sl[i]==s2[i])&&(sl[i]!='\O'))i++;if(sl[i]=='\O'&&s2[i]=='\0')resu=O;elseresu=sl[i]-s2[i];printf("\nresult:%d.\n",resu);return0;6-15#include<stdio.h>#include<string.h>intmain(){charsl[80],s2[80];inti;printf("inputs2:");scanf("%s",s2);for(i=0;i<=strlen(s2);i++)sl[i]=s2[i];printf("sl:%s\n",sl);return0;习题2187-1-1#include<stdio.h>intmain(){inthcf(int,int);intlcd(int,int,int);intu,v,h,l;scanf("%d,%d",&u,&v);h=hcf(u,v);printf("H.C.F=%d\n",h);l=lcd(u,v,h);printf("L.C.D=%d\n",l);return0;)inthcf(intu,intv){intt,r;if(v>u){t=u;u=v;v=t;}while((r=u%v)!=0){u=v；v=r;}retum(v);)intlcd(intu,intv,inth)(return(u*v/h);7-1-2#include<stdio.h>intHcf,Lcd;intmain(){voidhcf(int,int);voidlcd(int,int);intu,v;scanf("%d,%d",&u,&v);hcf(u,v);lcd(u,v);printf("H.C.F=%d\n",Hcf);printf("L.C.D=%d\n",Lcd);return0;)voidhcf(intu,intv){intt,r;if(v>u){t=u;u=v;v=t;}while((r=u%v)!=0){u=v;v=r;)Hcf=v;)voidlcd(intu,intv){Lcd=u*v/Hcf;)7-2#include<stdio.h>#include<math.h>floatxl,x2,disc,p,q;intmain(){voidgreater_than_zero(float,float);voidequal_to_zero(float,float);voidsmaller_than_zero(float,float);floata,b,c;printf("inputa,b,c:");scanf("%f,%f,%f",&a,&b,&c);printf("equation:%5.2f*x*x+%5.2f*x+%5.2f=0\n",a,b,c);disc二b*b-4*a*c;printf("root:\n");if(disc>0)(greater_than_zero(a,b);printf("xl=%f\t\tx2=%f\n",xl,x2);)elseif(disc==0){equal_to_zero(a,b);printf("xl=%f\t\tx2=%f\n",xl,x2);)else{smaller_than_zero(a,b);printf("xl=%f+%fi\tx2=%f-%fi\n",p,q,p,q);)return0;)voidgreater_than_zero(floata,floatb){x1=(-b+sqrt(disc))/(2*a);x2=(-b-sqrt(disc))/(2*a);voidequal_to_zero(floata,floatb)(xl=x2=(-b)/(2*a);)voidsmaller_than_zero(floata,floatb){p=-b/(2*a);q=sqrt(-disc)/(2*a);7-3#include<stdio.h>intmain(){intprime(int);intn;printf("inputaninteger:");scanf(”％d”,&n);if(prime(n))printf(n%disaprimeAn”,n);elseprintf(n%disnotaprime.\nn,n);return0;)intprime(intn){intflag=l,i;for(i=2;i<n/2&&flag==l;i++)if(n%i==0)flag=0;return(flag);)7-4#include<stdio.h>#defineN3intarray[N][N];intmain(){voidconvert(intarray[][3]);intij;printf(Hinputarray:\nn);for(i=0;i<N;i++)for(j=O；j<N;j++)scanf(n%d",&array[i][j]);printf(n\noriginalarray:\nn);for(i=0;i<N;i++){for(j=O;j<N;j++)printf(n%5dn,array[i][j]);printf(H\nn);)convert(array);printf(nconvertarray:\nn);for(i=0;i<N;i++){for(j=O;j<N;j++)printf(n%5d",array[i][j]);printf(n\nn);)return0;)voidconvert(intarray[][3]){inti,j,t;for(i=0;i<N;i++)for(j=i+l;j<N;j++){t=array[i][j];array[i][j]=array[j][i];array[j][i]=t;))7.5#include<stdio.h>#include<string.h>intmain(){voidinverse(charstr[]);charstr[100];printf(ninputstring:H);scanf(n%sH,str);inverse(str);printf(Hinversestring:%s\n",str);return0;voidinverse(charstr[]){chart;inti,j;for(i=0,j=strlen(str);i<(strlen(str)/2);i4-+,j—){t=str[i];str[i]=str[j-l];str[j-l]=t;7-6#include<stdio.h>intmain(){voidconcatenate(charstring1[],charstring2[],charstring[]);charsl[100],s2[100],s[100];printf("inputstring1:");scanf("%s",sl);printf("inputstring2:");scanf("%s",s2);concatenate(sl,s2,s);printf("\nThenewstringis%s\n",s);return0;}voidconcatenate(charstring1[],charstring2[],charstring[]){inti,j;for(i=0;stringl[i]!='\0';i++)string[i]=stringl[i];for(j=0;string2[j]!='\0';j++)string[i+j]=string2[j];string[i+j]='\0';)7-7#include<stdio.h>intmain()voidcpy(char[],char[]);charstr[80],c[80];printf(ninputstring:n);gets(str);cpy(str,c);printf(HThevowellettersare:%s\nH,c);return0;)voidcpy(chars[],charc[])(inti,j;for(i=O,j=O;s[i]!=,\O';i++)if(s[i]==,a,lls[i]==,A,lls[i]==,e,lls[i]==E,lls[i]==,i,ls[i]==Tlls[i]==,o,lls[i]==,O,lls[i]==,u,lls[i]==,U,){c[j]=s[i];j++；}c[j]=\O';7-8#include<stdio.h>#include<string.h>intmain()(charstr[80];voidinsert(char[]);printf("inputfourdigits:*');scanf("%s",str);insert(str);return0;)voidinsert(charstr[]){inti;for(i=strlen(str);i>O;i—){str[2*i]=str[i];str[2*i-l]='}printf("output:\n%s\n",str);7-9#include<stdio.h>intletter,digit,space,others;intmain()(voidcount(char[]);chartext[80];printf(ninputstring:\nH);gets(text);printf("string:");puts(text);letter=0;digit=O;space=0;others=0;count(text);printf("\nletter:%d\ndigit:%d\nspace:%d\nothers:%d\n",letter,digit,space,others);return0;voidcount(charstr[])(inti;for(i=O;str[i]!=,\O,;i++)if((str[i]>=,a'&&str[i]<=,z,)ll(str[i]>='A,&&str[i]<='Z'))letter++;elseif(str[i]>='0'&&str[i]<=,9,)digit++;elseif(str[i]==32)space++;elseothers++;)7-10#include<stdio.h>#include<string.h>intmain(){intalphabetic(char);intlongest(char[]);inti;charline[100];printf("inputoneline:\n");gets(line);printf("Thelongestwordisfor(i=longest(line);alphabetic(line[i]);i++)printf("%c",Iine[i]);printf("\n");return0;)intalphabetic(charc){if((c>='a'&&c<='z')ll(c>='A'&&c<=,z,))retum(l);elseretum(O);)intlongest(charstring[]){intlen=O,i,length=O,flag=l,place=0,point;for(i=O;i<=strlen(string);i++)if(alphabetic(string[i]))if(flag){point=i;flag=0;)elselen++;else{flag=l;if(len>=length){length=len;place=point;len=0;)}retum(place);)7-11#include<stdio.h>#include<string.h>#defineN10charstr[N];intmain(){voidsort(char[]);inti,flag;for(flag=1;flag==1;){printf("inputstring:\n");scanf("%s",&str);if(strlen(str)>N)printf("stringtoolong,inputagain!");elseflag=0;)sort(str);printf("stringsorted:\n");for(i=0;i<N;i++)printf("%c",str[i]);printf("\n");return0;)voidsort(charstr[]){inti,j;chart;for(j=l;j<N;j++)for(i=O;(i<N-j)&&(str[i]!='\0');i++)if(str[i]>str[i+l]){t=str[i];str[i]=str[i+l];str[i+l]=t;))7-12#include<stdio.h>#include<math.h>intmain(){floatsolut(floata,floatb,floatc,floatd);floata,b,c,d;printf("inputa,b,c,d:");scanf("%f,%f,%f,%f",&a,&b,&c,&d);printf("x=%10.7f\n",solut(a,b,c,d));return0;floatsolut(floata,floatb,floatc,floatd){floatx=l,xO,f,fl;do{xO=x;f=((a*xO+b)*xO+c)*xO+d;f1=(3*a*x0+2*b)*x0+c;x=xO-f/fl;}while(fabs(x-x0)>=le-3);retum(x);)7-13#include<stdio.h>#defineN10#defineM5floatscore[N][M];floata_stu[N],a_cour[M];intr,c;intmain(){inti,j;floath;floats_var(void);floathighest();voidinput_stu(void);voidaver_stu(void);voidaver_cour(void);input_stu();aver_stu();aver_cour();cour4printf("\nNO.courlcour2cour3cour5aver\n");cour4for(i=0;i<N;i++){printf("\nNO%2d",i+l);for(j=0;j<M;j++)printf("%8.2f",score[i][j]);printf("%8.2f\n",a_stu[i]);printf("\naveragefor(j=O;j<M;j++)printf("%8.2f",a_cour[j]);printf("\n");h=highest();printf("highest:%7.2fNO.%2dcourse%2d\n",h,r,c);printf("variance%8.2f\n",s_var());return0;)voidinput_stu(void){inti,j;for(i=0;i<N;i++){printf("\ninputscoreofstudent%2d:\n",i+1);for(j=O;j<M;j++)scanf("%f',&score[i][j]);voidaver_stu(void){inti,j;floats;{for(j=O,s=O;j<M;j++)s+=score[i][j];a_stu[i]=s/5.0;voidaver_cour(void){inti,j;floats;for(j=O;j<M;j++){s=0;for(i=0;i<N;i++)s+=score[i][j];a_cour[j]=s/(float)N;floathighest(){floathigh;inti,j;high=score[0][0];for(j=O;j<M;j++)if(score[i][j]>high){high=score[i][j];r=i+l;c=j+l；}retum(high);)floats_var(void){inti;floatsumx,sumxn;sumx=0.0;sumxn=0.0;for(i=0;i<N;i++){sumx+=a_stu[i]*a_stu[i];sumxn+=a_stu[i];retum(sumx/N-(sumxn/N)*(sumxn/N));

7-*14#include<stdio.h>#defineN10#defineM5floatscore[N][M];floata_stu[N],a_cour[M];intr,c;intmain(){inti,j;floath;floats_var(void);floathighest();voidinput_stu(void);voidaver_stu(void);voidaver_cour(void);i