继电保护习题与答案

Ω,ΩABCDEF1.5s2sDCD线路Ⅰ段配合，又要与于]IAkD.3316)]I12541568AIop2I15681803A13324)I1369A2k,minKsen1]IAkF.3130)I363543A1Ksenttt1op2IIIIA1Ksen11500022420)I927AKsenkE.min]t3.5s1CBcos0.9。30Ω10Ω12Ω30ΩI(3)k.max13103(6.310)]IKI(3)13101638A.relkI(2)k.min2(9.40.1510)I＞op[370001638Z2Z)2，minminLmin））BI(3)k.max461A3(6.330)IKI(3)461600Ak.））I(3)k.maxA3(6.312)I1.151.257551085Aop,。））I(2)k.minA2(9.410)Ksen]Ksen。910330.95350.9I174A.max]K.Krel1.21.3174IopI319Ass0.85.maxKreKsen]I(2)k.minA2(9.412)KsenI(3)k.minA3(9.430)]Ksen和,和负荷的自；保护的数1.15KK1.25K1.15K1.2I,(2020，，K0.85X15XX；A电源的,；B电源的，..sB.X25sB.A]I(3)k.max1210340)））BAI(3)k.max11103(2040)））,A2I(3)1770k.max340)180]I1.1517702040AE1151032XX8.192IL.mins.min8.1940X100%100%20.48%L.minX％AB1150003[(5520)24]5520I(3)k.max1720I1.2517202150Aop.BK：b.]K1b.min1.152150KIopI773Arel3.2op.BKb.min103K2I305A103opK2CK14b.max]X1032I(2)k.minAKsen4XX5XX0.4/km电源等值电抗，；线路、的电抗，1201X1.4/km0k20kmΩXX0.420X1.42028：：；；120XX0.45020X1.45070；；120XX0.1051102/31.540.33：。12求BXX13X36，20Ik0I(1.1)k0XX＞＞0]XII2XXk0k1]20EX2XsX.XXX2020XX＝201150001336)1336131336780A＝]3I3782340k0Ik01070336)]3I31073210k0XX9X22，201151033922)99Ik01250A93I31253750k0B115000I(3)k.B51103(5CXXX106，2031150003(3333106)33106333I81Ak03310633IAk03(33106)IIA31150003(25820.4L1.4L)3]14.4km0.520km]L＞33(50.4L21.4L)2]9]I11601670A2340Ksen1670ts0p,,I5110480AKsenKsenttts.A.B，1.3Kss为ADBC~SEKK=1.2，’’’relK’’’relrel）秒。BAC12SSXΩXΩXΩ11XΩ1XΩXΩ1XΩ00XΩ00=1.2。=0.85K=0.8KK’’’rel’’’rel00rel）秒。BAC1211IXΩS1UXΩ1k如图网络，对在A、B处配置的距离保护Ⅰ、Ⅱ进行整定计算并校验灵敏度。=0.85=K，zΩ/KM）K’’’。relrel1BACXDS11ΩΩS111XΩΩ1X10X30，AB.165Ω，阻抗角k652sAB、400Acos0.9IL.%10.5%215MVA、电压比110/6.6kVUA。kA0.850.453011.48Zop.A]ABZ0.850.453814.54op.BKXK]BbbB.ZK(ZLKZ)op.A1bop.BΩBZK(ZLKZ)T.minop.A1b]Z1010.51102/1510384.7TZ2T.minΩZ0.7(0.453042.35)39.09op.AZ23.83,即op.AKsentt。A0.9UZNcos()op.A0.9UNKKKIrelressL.maxsenL]0.931.251.1520.4cos(6526)Ωcos0.9261LKsenKb]Zop.AKZL1KZL1b.sZ0.45/km70km12540kmMZ、.Z20NZ25Z、15...MZZZ25400.4515K.maxsN.min3.93sMMN15b.maxZsN.min。KKK3.9313.93]bb助b汲ZZZ20400.4525K.minsN.max2.52sMMN25b.minZsN.maxZZZ0.85KNP20.575NP1ZZb.min[NP1NP2]KKK2.520.5751.35]ΩΩΩ，b助汲LMNM75，灵敏角Z40setsenMN,δ?δ??δEEEe157.4)jIMNMZe75100ej75j]UEZIMMMswiZ)jctgZ2m3ZmMZ103Z)j]e75j2m0.2236ej26.6100e22.36ej75j48.4ＺΩΩop]δZj)e75j2m28.3ej30Z4030)Δδ区中点在1802]tTsZ0.4/km65、1LBkm65km距A侧A30km和,AR,AAA?Z0.80.47524op.AZZ0.80.45016op.Bop.A0.8(0.47516)36.8在km在65kmZZ0.455220.46526；。mmA的I30kmRU(2)