C++面向对象程序的设计编程题

1、C+面向对象程序设计2010期末考试编程题，如果可以1、编写一个程序根据输入的三角形的三条边判断是否能组成三角形 则输出它的面积和三角形类型(等边、等腰、直角三角形)。#in clude<iostream>#in clude<math.h>using n amespace std;int main()double a,b,c;double v,p;coutvv"请输入三角形三条边:"<<endl;cin> >a>>b>>c;if(a+b>c&&a+c>b&&b

2、+c>a)p=(a+b+c)/2;v=sqrt(p*(p-a)*(p-b)*(p-c);cout«"该三角形面积是"<<v<<endl;if(a=b&&a=c)coutvv"该三角形是等边三角形！ "<<endl;elseif(a=b&&a!=c|a=c&&a!=b|b=c&&b!=a)coutvv"该三角形是等腰三角形！ "vvendl;if(a*a+b*b=c*c)|(a*a+c*c=b*b)|(c*c+b*b=a*

3、a)coutvv"该三角形是直角三角形！ "<<endl;elsecoutvv"这三条边组不成三角形！ "vvendl;return 0;2、定义一个学生类，其中有3个数据成员：学号、姓名、年龄，以及若干成员函数。同时编写main函数使用这个类，实现对学生数据的赋值和输出。#i nclude <iostream>#in cludevstri ng>using n amespace std;class stude ntint num;stri ng n ame;int age;public:stude nt() num=O;n

4、 ame='O'age=O;stude nt(i nt,stri ng,i nt);void show();stude nt:stude nt(i nt a,stri ng b,i nt c):nu m(a), name(b),age(c) void stude nt:show()cout<<"stude nt nu mber:"«e nds< <num <<e ndl;cout< <"n ame:"<<e nds< <n ame<<e ndl;

5、cout<<"age:"<<e ndsvvagevve ndl;int main()student s1(200803986,"梅寒芳",23);s1.show();return 0;3、从键盘输入若干个学生成绩，统计并输出最高成绩和最低成绩，当输入负数时结束输入。#in clude<iostream>using n amespace std;int main()double a100;double max=0 ,min=100,t;int i;for(i=0;i<100;i+)cin> >ai;if

6、(ai<0)break;elseif(ai>max)max=ai;if(ai<mi n)min=ai;coutvv" 最大值是："vvmaxvvendl;coutvv"最小值是:"<<minvvendl;return 0;4、编写一个程序，从键盘输入半径和高，输出圆柱体的底面积和体积#in clude<iostream>using n amespace std;int main()double a,h,s,v;coutvv"半径为："<<endl;cin> >a;cou

7、tvv"高为："vvendl;cin> >h;s=3.14159*a*a;v=s*h;coutvv"底面积为:"vvsvvendl;coutvv"体积为："vvvvvendl;return 0;5、编写一个程序，输入年、月，打印出该年份该月的天数#i nclude<stdio.h>mai n()int y,m,d;prin tf("year mon th=");sca nf("%d%d", &y,&m);switch(m)case 1:case 3:cas

8、e 5:case 7:case 8:case 10:case 12:d=31;break;case 4:case 6:case 9:case 11:d=30;break;case 2:if (y%4=0 && y%100!=0 | y%400=0) d=29; else d=28;prin tf("days=%dn",d);并在主函6编写函数将化氏温度转换为摄氏温度,公式为C= (F-32) *5/9 ; 数中调用。#in clude<iostream>using n amespace std;double fun( double a);int

9、main()double f=37.5,c;c=fu n(f);cout«"华氏温度为:"vvfvv" T "<<endl;cout«"摄氏温度为:"<<c<<" °C "<<endl;return 0;double fun( double a)b=(a-32)*5/9;return b;7、声明一个Tree (树)类，有成员ages(树龄)，成员函数grow(int years)用以对 ages加上years, showage()用以显

10、示tree对象的ages值。在主函数中定义Tree类对象，并调用成员函数(学生自行指定实参数#in clude<iostream>using n amespace std;class Treeprivate:int ages;public:int grow(i nt years)ages=ages+years;retur n ages;void getage()cout«"输入树的树龄："<<endl;cin> >ages;void showage()cout«"该树的年龄是:"vvagesvven

11、dl;；int main()Tree ages,years;ages.getage();ages.grow(5);ages.showage();return 0;8、定义一个复数类，用友元函数实现对双目运算符+ ”的运算符重载，使其适用于复数运算。#include<iostream.h>class Complexprivate:double real;double imag;public:Complex()real=0;imag=0;Complex(double r,double i):real(r),imag(i)friend Complex operator+(Complex

12、&c1,Complex &c2);void display。；;void Complex:display()coutvvrealvv"+"vvimagvv"i"v<e ndl;Complex operator+(Complex &c1,Complex &c2)retur n Complex(c1.real+c2.real,c1.imag+c2.imag);int main()Complex c1(3,4);Complex c2(4,2.3);Complex c3;c3.display();return 0;9、有一个

13、函数如下：输入x的值，计算出相应的y值。#in clude<iostream>using n amespace std;int main()int x,y;cin> >x;if(x<5) y=5;if(x>=5&& x<15) y=x+6;if(x>=15) y=x-6;coutvvyvve ndl;return 0;，分别求出整型数的两数10、14、17、使用函数重载的方法定义两个重名函数 之和和浮点数的两数之和，并在主函数中调用。#in clude<iostream>using n amespace std;tem

14、platevtype name T>T add(T a,T b)T c;c=a+b;return c;int main()int a,b,c;float x,y,z;coutvv"请输入两个整型数："<<endl;cin> >a>>b;coutvv"请输入两个浮点数："<<endl;cin> >x>>y;c=add(a,b);z=add(x,y);coutvv"整型数之和是："vvcvvendl;coutvv"浮点数之和是:"vvzvve

15、ndl;return 0;、梯形、圆计算不同形11、定义一个抽象类shape用以计算面积,从中派生出计算长方形 形面积的派生类。程序中通过基类指针来调用派生类中的虚函数 ， 状的面积。#i nclude <iostream>#define PI 3.1415926using n amespace std;class Shapepublic:void show();protected:double s;void Shape:show()cout«"面积："<<s<<endl;class Circle :public Shapepu

16、blic:void GetArea();Circle(double);private:double r;；Circle:Circle(double a) r=a;void Circle:GetArea()s=r*r*PI;int main()Circle C(6);C.GetArea();return 0;可进行增值和减12、定义计数器类Counter。要求具有以下成员：计数器值;值记数;可提供记数值。#include <iostream>using n amespace std;class Coun terpublic:Coun ter(i nt );Coun ter opera

17、tor +();Coun ter operator -();void display();private:int i;Coun ter:Co un ter(i nt a)i=a;void Coun ter:display()cout«i;Coun ter Coun ter: operator +()return Coun ter (+i);Coun ter Coun ter: operator -()return Cou nter(-i);int main()Cou nter C1(5);cout«"C1="C1.display();+C1;cout&#

18、171;e ndl<v"C 仁"C1.display();-C1;cout«e ndl<v"C 仁"C1.display();cout«e ndl;return 0;13、输入一个自然数，输出其各因子的连乘形式，如输入12,贝U输出12=1*2*2*3。#in clude<iostream>using n amespace std;int main()int i,n;cin>>n;cout«" n="<<"1"for(i=2;i<=

19、n;)if(n %i=0)n=n/i;cout<<"*"<<i;con ti nue;cout«e ndl;return 0;15、定义一个基类：点类，包括x坐标和y坐标，从它派生一个圆类，增加数据 成员r (半径)，圆类成员函数包括构造函数、求面积的函数和输出显示圆心坐标及圆半径的函数。#in clude<iostream>using n amespace std;class Dotpublic:int x;int y;Dot();class Circle:public Dotprivate:int r;public:Circ

20、le():Dot()void get();void area();void show();；void Circle:get()cout«"输入圆心坐标、圆的半径："<<endl;cin> >x>>y>>r;void Circle:area()double s=0;s=3.14159*r*r;cout«"圆的面积是："vvsvvendl;void Circle:show()coutvv"圆心坐标是：("vvxvv","vvyvv")&quo

21、t;vvendl;coutvv"圆的半径是："vvrvvendl;int main() Circle d;d.get();d.area();d.show();return 0;16、N个整数从小到大排列，输入一个新数插入其中，使N+1个整数仍然有序。#in clude<iostream>using n amespace std;int main()int a11=10,20,30,40,50,60,70,80,90,100;int i,j,n;cout«"原顺序为："<<endl;for(i=0;i<10;i+)c

22、out<<ai<<""cout«e ndl;cout«"请输入一个新数："<<endl;cin>>n;if(aO> n)for(i=9;i>=0;i-)ai+1=ai;a0=n;if(a9< n) a10=n; if(n> a0&&n< a9) for(i=1;i<9;i+)if(n> ai) j=i+1;for(i=9;i>=j;i-)ai+1=ai;aj=n;for(i=0;i<11;i+) cout<<

23、;ai<<"" cout«e ndl;return 0;18、编写一个矩形rectangle类，有数据成员长len和宽wid ,构造函数retange(int,int).和友元函数int area(recta ngle T)和int fun (recta ngle T)分别计算给定长方形的周长和面积。#i nclude <iostream>using n amespace std;class recta nglepublic:recta ngle(i nt ,i nt );friend int area(recta ngle T);frie

24、nd int fun (rectangle T);private:int len ,wid;recta ngle:recta ngle(i nt a, int b)len=a;wid=b;int area(recta ngle T) return (Ten *T.wid);int fun (recta ngle T)return (2*(T.le n+T.wid);int main()rectangle R(20,30);cout«"面积:"<<area(R)<<endl;cout«"周长："vvfun(R)&

25、#171;endl;return 0;19、定义一个复数类，用友元函数实现对双目运算符+和*的运算符重载，使其适用于复数运算。#include <cmath>#i nclude <iostream.h>class CComplex#defi ne err 0.00000001 double _x,_y;public:CComplex(double x=0,double y=0)：_x(x),_y(y)CComplex operator+(c onst CComplex&z);CComplex operator*(c onst CComplex&z);fr

26、iend ostream&operator <<(ostrea m&os,c onst CComplex&z);friend istream&operator >>(istrea m&is,CComplex&z);int main()CComplex z1(0,1.2);CComplex z2(1,1.2);cout<<z1+z2<<e ndl;cout<<z1*z2<<e ndl;cin> >z1;cout<<z1<<e ndl;retu

27、rn 0;CComplex CComplex:operator+(c onst CComplex&z)CComplex c;c._x=_x+z._x;c._y=_y+z._y;return c;CComplex CComplex:operator*(c onst CComplex&z)CComplex c;c._x=_x*z._x-_y* z._yc._y=_x*z._y+_y*z._x;return c;ostrea m&operator <<(ostrea m&os,c onst CComplex&z)if(fabs(z._x)>e

28、rr)cout<<z._x;if(fabs(z._y-1)<err)cout<<(fabs(z._x)>err?"+i":"i");else if(fabs(z._y+1)<err)cout«"-i"else if(z._y >err)cout<v(fabs(z._x)>err?"+":"")vv z._y<<" i"else if(z._y<-err)cout<<z._y&l

29、t;<" i"return os;istrea m&operator >>(istream&is,CComplex&z)is>>z._x>>z._y;return is;,并输出平均值20、输入10个同学的成绩,统计80分以上和不及格的人数#in clude<iostream>using n amespace std;int main()double a10,sum=0,var;int i,j=O,k=O;cout«"请输入10个学生成绩："<<endl;

30、for(i=0;i<10;i+)cin> >ai;sum=sum+ai;if(ai>=80)j+;if(ai<60)k+;var=sum/10;cout<<"80 分以上的人数是："vvjvvendl;cout«"不及格的人数是："vvkvvendl;cout«"平均分是:"vvvarvvendl;return 0;21、声明一个类String1 ,其数据成员为char head100,构造函数String(char *Head)实现head的初始化，成员函数void Re

31、verse ()实现head内 字符串的逆序存放，成员函数void Print()实现head内字符串的输出。#in clude <stri ng>#i nclude <iostream> using n amespace std;class String public:String (char *Head);void Reverse。；void Print ();private:char head100;Strin g:Stri ng(char *Head)int i=0;char *p=Head;while(*p!='0')headi=*p;i+;P

32、+； headi='0' void Strin g:Reverse()int i=0;char h100,*p=head; while(*p!='0') p+; while(*p!=head0)p-;hi=*p;i+;hi='0'while(i>=0)headi=hi;i-; void Stri ng:Pri nt() char *p=head;for(;(*p)!='0'p+) cout«(*p); cout«e ndl;int main()char *Head="abcdefgh"

33、Stri ng s(Head);cout«"正序："；s.Pri nt();s.Reverse();cout«"逆序："；s.Pri nt();return 0;22编写程序形成如下矩阵。2 14 3 A=4321 32112111 111111 1111 #in clude<iostream> using n amespace std; int main()int a55;int iijj;for (ii = 0; ii< 5; ii+)for (jj = 0; jj < 5; jj+)if (ii - jj

34、 < 1)aiijj = 1;elseaiijj = ii+1 - jj;for(ii=0;ii<5;ii+)for(jj=0；jj<5;jj+)cout«aiijjvv""cout«e ndl;return 0;23、定义盒子Box类,要求具有以下成员：可设置盒子形状;可计算盒子体积；可计算盒子的表面积。#include <iostream>using n amespace std;class Boxpublic:Box(double,double,double);double area();double v();priv

35、ate:double x,y,z;Box:Box(double x1,double y1,double z1)x=x1;y=yi;z=z1;double Box:area()return (2*(x*y+y*z+x*z);double Box:v()return (x*y*z);int main()Box B(2,3,4);cout«"表面积："v<B.area()v<endl;cout«"体积："v<B.v()v<endl;return 0;24、33、声明一个哺乳动物 Mammal类，再由此派生出狗Dog类

36、，声明一个 Dog类的对象，观察基类与派生类的构造函数与析构函数的调用顺序。#in clude<iostream>using n amespace std;class mammalpublic:mammal()默认构造函数cout<<"mammal's con structor"<<e ndl;mammal()cout<<"mammal'a destucor"<<e ndl;public:dog()cout«"dog's con structor&qu

37、ot;«e ndl;dog()cout<<"dog's destructor"<<e ndl;；int main()dog a;return 0;25、30、定义一个基类有姓名、性别、年龄，再由基类派生出教师类和学生 类，教师类增加工号、职称和工资，学生类增加学号、班级、专业和入学成绩。#in clude <stri ng>#in elude <iostream> using n amespace std;class pers onpublic:pers on( stri ng ,stri ng,i nt);

38、protected:stri ng n ame;stri ng sex;int age;pers on:pers on( stri ng n, stri ng s, int a)n ame=n;sex=s;age=a;class teacher :public pers onteacher(string ,string,int,string,string,double);void display。；private:stri ng work_ num;string title;double wage;teacher:teacher(stri ng n, stri ng s, int a, str

39、i ng wo, stri ng t, double wa):pers on( n, s,a) work_ num=wo;title=t;wage=wa;void teacher:display()cout«"姓名："<<name<<endl<<"性别："vvsexvvendl<<"年龄工资:"<<age<<e ndl;cout«"工号："v<work_numv<endl<<"职称：&quo

40、t;vvtitlevvendl<<""vvwagevve ndl;public:stude nt(stri ng,stri ng,i nt,stri ng,stri ng,stri ng,double);void show();private:stri ng num;stri ng grade;string major;double score;stude nt:stude nt(stri ng n, stri ng s, int a, stri ng nu, stri ng g, stri ng m, double sc):pers on(n, s,a)/注意

41、：只写n,不是string nnum=nu;grade=g;major=m;score=sc;void stude nt:show()cout«"姓名："<<name«endl<<"性别："vvsexvvendl<<"年龄："vvagevve ndl;cout«" 学号:"<<num<<endl<<"年级:"<<grade<<endl<<"专业:&q

42、uot;vvmajorvvendlvv"入学成绩:"<<score<<e ndl;int main()teacher t("侯传旺","男",20,"200901001010","教授",2100);t.display();student s("秦洪敏","女",21,"200902002026","大二","应用心理学",540);s.show();return 0;26

43、、写一个Complex类，将运算符+ ”重载为适用于复数加法，重载函数不作 为成员函数，而放在类外，作为Complex类的友元函数。如例题10.3#i nclude <iostream.h>class complexprivate:double a;double b;public:complex。；complex(double i,double j);friend complex operator +(complex&,complex);void setreal(double x);void setimag(double y);void getreal();void get

44、imag();friend ostream& operator <<(ostream& out,complex& x);friend istream& operator >>(istream& in, complex& x);complex:complex():a(O),b(O)complex:complex(double i,double j):a(i),b(j)complex operator +(complex&x,complex y)return complex(y.a,y.b);ostream&

45、operator«(ostream& out,complex &x)outvvx.avv'+'vvx.bvv'i'return out;istream& operator >>(istream& in, complex& x)in> >x.a>>x.b;return in;void complex:setreal(double x)a=x;void complex:setimag(double y)b=y;void complex:getreal()cin> >a;

46、void complex:getimag()cin> >b;complex a;complex b;cin> >a>>b;/coutvvavve ndl;/coutvvbvve ndl;coutvva+bvve ndl;/coutvvavve ndl;/coutvvbvve ndl;return 0;27、实现一个名为SimpleCircle的简单圆类，其数据成员int *itsRadius为一个 指向其半径值的指针，设计对数据成员的各种操作，给出这个类的完整实现并 测试这个类。#i nclude <iostream>#define PI 3.1

47、415926using n amespace std;class SimpleCirclepublic:SimpleCircle(i nt *);double fun();double area();private:int *itsRadius;；SimpleCircle:SimpleCircle( int * i)itsRadius=i;double SimpleCircle:fu n()return (2 * PI * (*itsRadius);double SimpleCircle:area()return (PI*PI*(*itsRadius);int main()int a;cout

48、vv"请输入一个整数："；cin>>a;SimpleCircle S1(&a);cout«"周长:"<<S1.fun()<<endl;cout«"面积："v<S1.area()v<endl;return 0;28、有一个Time类，包含数据成员minute(分)和sec(秒),模拟秒表，每次走 一秒，满60秒进一分钟，此时秒又从0开始算。要求输出分和秒的值。(提 示：重载单目运算符+)#i nclude <iostream>using n ames

49、pace std;class Timepublic:Time(i nt ,i nt);void operator +();void display();private:int minu te,sec;Time:Time(i nt a,i nt b)minu te=a;sec=b;void Time:operator +()if (sec<59)sec+;elseminu te+;sec=0;void Time:display()cout« minu te<<":"<<sec<<e ndl;Time T1(3,59);T1.

50、display();T1+;T1.display();return 0;29、有一个学生类student,包括学生姓名、成绩,设计一个友元函数,输出成 绩对应的等级：大于等于90:优；8090 :良；7079 :中；6069 :及格；小于60:不及格。#in clude <stri ng >#i nclude <iostream>using n amespace std;class stude ntpublic:friend void grade(stude nt & );stude nt (stri ng ,in t);private :stri ng n a

51、me;stude nt:stude nt(stri ng n ,i nt s)n ame=n;score=s;void grade (stude nt & s)if(s.score >=90)cout«"姓名："<<«endl<<"获得：优"<<endl;if (s.score<90 && s.score>=80)cout«"姓名："<<«endl<<"获得：良"<<endl;if (s.score>=70&&s.score<80)cout«"姓名："<<vvendl<<"获得：中"<<endl;if (s.score>=60&&s.score<70)cout«"姓名："<<«endl<<" 获得：及格"<