高频电子线路课后习题答案（第五版）-

1、高频电子第五版(pF.(L C H(.QR则L 取R f f Q (kHzf MHz解:f.159101*11591014321010010100101010121010990101211362620603670036700=-=-时,产生并联谐振。C L 或C L 当(时,产生串联谐振。C L 或C L 当(时,产生并联谐振。C L 或C L 当解:(22021101220211012202110111311211123=-R R C L R LC L(j R LC LR(j C L R C j R L j R C j L(R j (R 证明:Z =+=-+-+=+=-21121111332

2、20020020000(318010404501053514321121535100160512405354501605151431223202222H .C C L 故采用后一个不合理舍去pF -得C C C 由pF得C C C 由解:=+='+=+=+=+=+-。 L C C (m V V Q V V m A .R V I H .C L .R C 解:Q-Sm Com Lom -om om -21210121220510111210100105114321121251010010511432115330312260200126000=-(j .j .C jR Z .Q LQ L R

3、 pFC pF .L C C C C .V V Q H .C 解:L X X X X X X X S C 7967471020010143217471747100102531014321052102531014322001001025310143211100101025310100101432116312606666000626200122620-=-=-=-=-=+=-(。21k 0.5R,R ,故0.5Q Q ,则f 22f 因2320105105552310023100101501052220105010514321173000.70.7660036700012620电阻所以应并上=&#

4、39;='='=-=-.f f Q f f Q H .C 解:L . =-g Q Cf f C f C f 证明:.070007022483(MHz .Q f f .L R Q k .R C C C C R R R k .C LQ R MHz .LC f pF .C C C C C C C 解:C L .L P i P i 481228106412228108010641143210885885520202020920109201020201080100641103181080143212131820202020202059360706630221102126121260102

5、102=+= +=+=+=+=-R Z 30Z 20Z 1123f1f1f1=-解:(.j .j .Z M Z j .j C L j R Z pF .L C kHz .R f Q f f .R R L Q k C R R L Z .R M Z H .R M pF .L C C H .L L 解:f .f f f P 843768010020101831014321002010177101432110159101432201177101591095014321152281020102222425202010159101432325101592020101592020101831014322183

6、1014322011591015910143211159101432101133266222011126662*2322022361100706611101112611112662201160116261201216301121-=+=+=-+='-+='='=+=+=+=+=-(100101410222002010159105010159153367.00111236=-f f Q M R R C R L R f P 解:(013.02001122211222005101001032510102402051010010205101011632207.067101671

7、012671120126722011=-+=-+=+=+=-Q f f R L Q R M k R RL R R M R 解:f ab f 5.75.22303021103001010112118.111020*.325.22115.2225.11103001010112111732332001230233200=-='-=+= +='='+= '+=-Q Q Q Q f f Q I I C Q R Q Q f f Q I I 解:(=+=-L H L 并联联谐C L L 串联联谐C L 解:125375112183212125102501050501501时,

8、5012.1102501020501501时,20491025010501501时,154266200266200266200= += += += += += +=-TT T f f MHz f f f MHz f f f MHz f 当当解:当(m S j .j .j b a jb a g r C j b a jb a C j g g r C j g y m S j .j b a jb a g y m S j .j .j b a jb a C j g y m S .j .j .j b a jb a C j g y .r C b .g r a pF .f g C m S .r g m S .I

9、 g mb bc b c b c b m b b c b ce oe m fe c b cb re e b e b ieb b e b e b b b T m eb eb m E e b 68.0049.01011.01107.377011031014321733.3327.371011.01107.37187.00187.01011.0110310143241189501011.01102410143210754.010701024101432110754070112410250143210737273710754050754015026112674223127222222322221272

10、222127322127363300+= +-+-+-+=-=+-=+-=-=+-+-+-=+=+-+=+-+=+=+=+=+=-''''''-''-''-''-''-'-''解:(4124142701010042104010041704070121101241104221104210124212422124284-= -= -=+= -=+=-m mm m .r m .m.m vo v m .m.mvo v f f K Qf f f fQ A A Qf f

11、f f Q A A 故得令得解:令(1103101045952110830081020010286021830082501020025010237952258854tan 2tan 431100316116570316107102316104107102105228113151*5228104525025052281028604110200411023723710410010710211250205250205943326662262621222206070666022632162626222166001345213231>>+=+'+=+=+='-=-=+=-=

12、-=+=+=-.y y g g g g S S .p g p g g .Q Q K MH .Q f f .L g Q .A A .g y p p A S .g p g p g g S .L Q g .N N p .N N p refe L oe ie s ie p L oo re fe L Z L .L vo po fevo ie oe p p 解:(722169826680423822502566804247947961044445478212225904454610442261044122256519744541221224382250257821344541015801041071014

13、3222782115802438303015801503008203010037010370104107101432100111104444447070707041707041704147044436260070222122222156600.-.A A .A A .f f A A kHz .f f kHz .f f kHz .f f .A A kHz .f Lg f .g y p p A m S .g p g p R g g m S .L Q g vo vo vo vo.vo vo.vo vo .fevo ie oe p p ='-='='='='=-

14、=-'=-='=-=-=+=+=+=-解:(不能满足解:9.1K 522106250110511432121625011830500114r0.1122620221<=+=+=-H .C f L pF .C p C C oe(74.73.05.24.364.265.2144220=+=-refe S vo C y A 解:(163910601046522260104910100410465274104921040574513114910010100010465210620574513491001010001046521020100440574513100010044100

15、012051373118607311873118118101000104652111741030706123121206321123320202236123601012222236112563423612231201.K kH .Q f f g C Q .g y p p A S .Q C g p g S Q C g g pF .C p C C pF C C C .L L L L H C L .r Z L .L fevo i o i o =+ =+=+=+=+=+=+=+=+=+=-,则。若为临界耦合,即初、次级回路参数相等解:(nA .kTG i V .kTR v -n n n n 65121

16、010290103814f 46512101000290103814f 4:解204732327232=-(133221213132321321332211321332211332211232221232133221132133221133221123222124444444444214R R R R R R T R R T R R T R R G G G G T G T G T T f G G G kT f G T G T G T k f G kT f G kT f G kT i i i i 又R R R R T R T R T T f R R R kT f R T R T R T k f

17、R kT f R kT f R kT v v v v n n nn n n n n n n n nn n n n n n +=+=+=+=+=+=+=+=+=+=+=- 解:(略同理可证得代入消去由后相加得乘与乘由代入得证明:22y y 2y y 2y y y y y 2y 2y y 2y y y y y 6y 412y y y y 2y y y 62y y y 2y y y 4553243211184fefe r iefe feie fe ie ie 2ie i cb2fe 1fe fe ie fe ie ie 2ie b12cb21fe 21fe 2oefe ie o fe fe fe f

18、e f cb2fe 2oefe ie 1fe fe fe 212222122121121212122212121222111111y y y y y y y y y y y y y y y y y y V y y y y y y V y y y y y y I I V y y V y y y I y y I y y y y y y y y y y y y y y y y V y y y y y y V y y y y I y y y V y V y I y y V y I y y y V y V y I V V y V y y y V y I V y y V y V V y V y V y V

19、 y I V y y V y V V y V y V y V y I V y V y I V y V y I re oe re oe re ie re oe re oere ie re oe re oere ie re oe re be oe re ie re oe re c oe re be oe ie re c oe fe b re oe fe reoere ie re oe oere ie oe oere ie re oe be oe re ie oe c oere ie be fe cb re c oe fe cb oe c oere ie be fe cb re c ce cb re

20、 ce oe re ie be fe c ce oe fe cb oe ce cb oe ce fe ce oe be fe c ce re ie cb re ce cb re ce ie ce re be ie b ce oe be fe c ce re be ie b +-+=+-+=+-+=+=+-+-=+=+-+=+-+-=+-+=-+=-+-= -+-=+=+-= -+-=+=+=+=- (21733190226622163319221232321032.01020095.0110106.121295.0105001010195.011064.010*.12210226.010200

21、70192731038.144224A f qI i f f A f qI i V f kTr v n C cn n E en n b bn -=-=-= +=+=+=-解:(Qf df f f f Q f A df f A f n 221123402000202=-+=-证明:(dB .A A .A .A K F A F F F .T T F .dB F .dB F p p p p pc n p n n n i n n n 7628881lg 2088811020198131207199511120712906011倍98136倍99513244高高高高中高混高混中高=-+-+=-+-+=+

22、=+=-解:(R R R R R R R V R V P P P P A A P P P P P P F ss s s s so s s o p p ni no so ni n +=+=+=-1441125422no si 解: (sL L s s s s o s p so ni n G L rC G G L rC G G G I G I P P A P P P P F +=+=-144126422no si 解:(2849.15981.314981.3127.1A A 1F A 1F F F 849.1512dB A 981.36dB A C B A 274pB pA nC pA nB nA

23、 n pB PA =-+-+=-+-+=-倍倍为输出级。为中间级,为输入级,解:8.1F 1.0101995.110110F A A 1F A 1F F 1010P P P P F C B A 284nA nA pB pA nC pA nB nA 45no so ni si n -+-+=-+-+=-为下一级。为输入级,前置放大器,解:不能满足要求。设(得到近似线性特性。可只取其级数的前两项线弯曲部分,故围内变化,不会进入曲号电压在特性的线性范勒级数原则,可认为信很小时,根据泰部分,然后当在抛物线上段接近线性较大时,静态工作点选即当,似当成线性元件来处理,该非线性元件就能近时,当解:m 000

24、200022200202002V V cos 22cos 2121cos 2cos 85t V V V k i V V t V V t V V V k t V V k kv i m m m m m m +<< +=+=-BZm BB m BB BZ o o C C V V V V V V i -=+=-212160cos 60125。应为最大值,中的二次谐波振幅达到解:为了使(-=<>=-+-+-+-=为奇数为偶数当当解:n n n gV t td n t gV I gV t td gV I gV t td gV I tn I i t t tgV i m m n mm

25、m mn n m112cos cos 121cos 11cos 21cos 0cos 00cos cos 13522100( ,3,2,1k t cos2k 12k 1gV 4gV 2i 0cos 00cos cos i 0cos 00cos cos i i i 15501k 21k m m D2D1D2D1=-+=><=<>=+=-=-t t t gV t t t gV i mm当当当当解:( ,3,2,1k 142cos sin 2142cos 2sin 12i sin sin 10sin sin 100sin sin 11651201200000000= -+=+

26、=>+=<+-=k k k t k t m k t k t m gV tt m gV i t t m V i t t m V 时,当;时,解:当(21L 221221L D 2D 1L 0v v 4kR v v k v v k R i i R v 175=-+=-=-解:(2123213221221103213221221103213221221103213221221103142143208185v v b R v v b v v b v v b bR v v b v v b v v b b R v v b v v b v v b b R v v b v v b v v b b

27、R i i i i R i i R i i R v L LL L L L L L -=-+-+-+-+-+-+-+-+-+-+-+=-+=-+-=-解:(31310440330220302000cos 0304021304021003040304020300210330402203002134232116322183cos 6cos 2cos cos cos 61cos 21cos 1cos cos 25.121323cos cos cos 22cos 123cos 2cos 4cos 3cos 2432123500 += + + +=+ +=+=+=+=+=+=-=kT qV I kT qV

28、 I g g kT qV I kT qV I g tkT qV I t kT qV I t kT qV I t kT qV I t V kT q t V kT q t V kT q t V kT q aI e t V kTqaI dv di t g e v kT qaI dv di g V b V b g g V b V b g t t V b t V b V b t V b b tV b t V b t V b b dv di t g v b v b v b b dv di g om S om S m c om S om S m om S om S om S om S om om om om

29、 S t V kTqom S v v BECm v kTq BE S BE C m m m m c mm m m m m m m m m v v BEC m BEBE BE BEC m om B E B E B E 解:(+=-+-+-+-+-+-+-+-+-+=-+-=-03430402404303202010404303202010404303202010404303202010423116168255v v a v v a v v a v v a v v a v v a v v a a v v a v v a v v a v v a a v v a v v a v v a v v a a

30、 v v a v v a v v a v v a a i i i i i s s s s s s s s s s s s s s s s s s s 解:(dB f Q f A Q Q A A dB g g g A S g g m S I g g m S I r I I g i pc L pc pc oc ic c pc ce oc E eb ic E b b E T s E c 1.30122810100465211047322114010473004.055.046.94455.035265.0266.9265.05.0265.0261265.0295227.00max 20max 22m

31、ax02= -= -= -= +=-''解:(dB g G G g g A dB g g g A S g g m S I g g m S I r I I g ic L L oc c pc oc ic c pc ce oc E e b ic E b b E T s E c 231961.01.01.001.054.1289.59201.01.0454.14101.0302608.02654.12608.05.0265.0261265.03052222max02= += +=+=-''解:(+=+-+-+-+-+-+-+-+-+-+-+-+-+-+-+=+-=-03

32、430402404303202010404303202010404303202010404303202010432116168325v v a v v a v v a v v a v v a v v a v v a av v a v v a v v a v v a a v v a v v a v v a v v a a v v a v v a v v a v v a a i i i i i s s s s s s s s s s s s s s s s s s s 解:扰。信号,则能产生阻塞干互调干扰;若有强干扰,可能产生生交调干扰;有二次项不存在三次项,不会产时产生镜像干扰。由于就会产生中频

33、干扰;当进行混频。只要满足解:因存在二次项,能i0n i n f f f f f 345+=-,合理选择中频等。提高前端电路的选择性时产生。、的哨叫声在附近,和波段内的干扰在的情况。所以落于数,不考虑大于为本振和信号的谐波次、,因最终出现哨叫声。差拍检波,产生音频,的非线性效应,与中频通过检波器放大后加到检波器上,进入中频放大器,并被它就能和有用中频一道的通带内,合频率接近于中频放大组合频率,如果这些组还存在一些谐波频率和中频电流外,输出电流中,除需要的扰。这是由于混频器的此现象属于组合频率干解:.31396kHz 1394kHz 931kHz 929kHz 1kHz 1395kHz f 93

34、0kHz f 1605kHz 5353q p 465kHz f .2.1355S S i =-(。谐波较小,可以不考虑大于、,会产生互调干扰;,、,会产生互调干扰;,、,会产生互调干扰;,、,会产生互调干扰;,、,会产生互调干扰;,、,会产生互调干扰;,、,不会产生互调干扰;,、,则会产生互调干扰:解:若满足3q p MHz 5.42710357743f f 33q 3p MHz 4.3921035277432f 3f 2q 3p MHz 4.6531035377423f 2f 3q 2p MHz 3.61810357742f f 22q 2p MHz 2.58310357742f 2f 1q

35、 2p MHz 2.844103527742f f 2q 1p MHz 1.8091035774f f 1q 1p f qf pf 36521212121212121s 21=+=+=+=+=+=+=+=+=+=+=+=+=+=+=±±-(MHz f MHz f MHz f f f f f f MHz f f f f f f MHzf MHzf MHz f f f f f f MHz f f f f f f S s s s s s s S S S S S S S 16420302302123032302326.02.04.0232228.023222313750000000

36、0000000>=>+>+>+>+->+->+-<=<+-<+-<+-<+<+<+-解:(。,故没有互调信号输出、已知,则会产生互调干扰。解:若满足MHz 20323f f f 2MHz .19f 6MHz .19f f qf pf 395i 0s 21s 21=-=-=±±-(oc c cm c c CC cm cm CC cm p C CO CC I I g A V P V P I P V P V R P P W I V P 7776.125.042.0174.02452226.5752

37、2422%3.8365625.024*02020=-=查表得解:(W .P P P P W R I P .V V g c C k oc cm CC c c 714170111412915618101270226600220=-= -=-=-=查表得解:(%.I V P W .I R P m A .iI m A .I i c CC c m c p c o m c oc c 7409030221410200212114128250902823190909076002210max1100max =-解:(222228622020222022202220RI L R L R I L RC L R I

38、RC L L R I R V P km km km km P cm +=+=+=-证:(=-=-=-=-=-=-=16.2219.10225.212%3.7636.1319.1017.319.1036.1319.109592.025.21212136.135566.0249592.0436.02.2705566.0253.02.27025.218.02.22496202001001max 10max 0max min P V R P P W P P P W I V P W I V P A i I A i I V g i V v V V cm p C C cm cm c CC o c cm o

39、c c cr c CC c CC cm 解:(pF fX C X Q R Q R Q X H f X L Q R R R X pF fX C Q R X P V P V R R C L L L L C L L L C L C CC cm p 123957.2105014.3212157.2195.161020011001441011054.0105014.3295.16295.1611100144200200112214.14105014.321214.1410144144222422106622122126112122161111202021=-+= -+=-+=-+=-解: (。变化不大,

40、于欠压状态,减小一半,放大器工作;变化不大,于过压状态,增加一倍,放大器工作解:0P 2cm 0cm P 0P 2cm 0cm 2P 2/R I P I R 25P .02R /V P V 1116='='-P R(%4.5703.015100111111111262221221211=+=+=+='+'=-k Q Q M Q Q L L r r r k 解:(nH f X L X Q R Q R Q X pF fX C RRQ R X pF fX C Q R X Q P V V P V R L C L L L P L L C PLLLC C L P C L s

41、at CE CC cm P 9.191014.325.1225.125.5105011106610112905.51014.321215.51665010150112416.61014.321216.610661066125.012221368112221822222811120202=+= +=-+=-+=-=-=-则设解:( -+=+-+=+-+=+-+='-'=-+=+=+=+=''='+='+='+='+='=''''+=+=+=+='+'=-+=+=+=+='

42、;'='+='+='+='+='=''''-11111X 1111Q R X L R C R L R C R 111111111Q R X C R C R C R C R 146L122121L122121L121212121C 1212121L12L1222211L C21222L122L1222L1121212121121L12L12222L11212121122L1222L1212121211L1C112111211C2221221221221212121121212122222221212121211122

43、22222222212121212112122222222121212112222222212121211L1C122112211X Q R Q Q R Q Q R X Q R Q Q R Q Q R X R R X R X X R R X X R R X X X RR Q R X R X R X R Q R X R X R R R X X R R X X X R R X R X R X R R X R X R b X Q R Q Q R X R R Q Q Q R X R R X R X X X R R X X R R X X R R X X X RR Q R X R X R X R Q R

44、 X R X R R R X X R R X X X R R X R X R X R R X R X R a L LL L L L L L L L C C C C LL C C C C C C CL L L C L L L C C C C C C C C C C C L LC C C L C C C C C C C C C CC C,即匹配时并联电路,并设和串联电路改为和将,即匹配时并联电路,并设和串联电路改为和将证:(流表读数减小。电表读数略增,天线电欠压状态,集电极直流中介回路失谐,工作于读数增加;读数略增,天线电流表状态,集电极直流电表天线接地,工作于欠压;读数为读数减小,天线电流表状态

45、,集电极直流电表天线断开,工作于过压解:3201186-(%60106%70103103%7.8531062613101196=-=-=-=-=-=-=-=P P P P P P P P W P P P P A Cc C A kk C A 解:c 0021111c 1113k Q39Q Q 1Q Q 19r r %90r r r 1Q 1r r %50r r r 1206=''=''+-='='='+-=-k k k k kk c 故则若则时,解:当解:256-(。减小,工作于欠压状态,解:0o 1o 26060276P <-Li

46、R I VI VR 9339286=-解:(W P Q Q P W V I P V i g V V A i I A V V i V V V V V V V V L A cm cm C cr CC cm o C cm BZ B C BB bm B oBB BZ bm 52.847.9100101147.9201.2286.0202.2298.12486.0436.098.17098.126.055.4255.445.16670cos 45.16.0cos 2960010max 1max 1max = -= -=-=-=-=-=-=-=+=+=-解:(W P Q Q P W V I P V V V A i I A V V i V V V V V V V V L A cm cm CC cm o C cm BZ B C BB bm B oBB BZ bm 8.85.910010115.926.2188.026.21249.088.0436.002.27002.226.064.4264.45.114.614.670cos 5.16.0cos 30600101max 1max = -= -=-=-=-=-=+=+=-解:(馈式振荡电路。可能振荡,属于电容反电路计及容反馈式振荡电路时有可能振荡,属于电电路