C面向对象实验报告

1、C+面向对象程序设计实验报告专 业： 计算机科学与技术 班 级： 2012级软件方向 学 号： 2012020244 姓 名： 孙 浩 C+面向对象程序设计实验卡片实验编号：01实验名称及学时：代码组织案例1姓 名：孙浩班 级：2班计本二班学 号：44实 验 室：实验情况评价（教师填写）：建议实验成绩（教师填写）：1.实验内容(1) 熟悉VC+6.0开发环境,能进行项目和相关文件的建立,程序的编译和调试.(2) 复数是个很有用的概念,在数字信号处理等方面发挥了重要作用.在C+的标准程序库中对它进行了实现.本次任务: (A)以C的程序结构来实现进行复数的基本运算,两个复数加,减,乘,除. (B)

2、根据面向对象的程序设计方法,创建相关复数类实现复数的相关运算. (C)分析自己的复数类,有那些方面有待改进.2.预习内容VC开发环境的使用,回顾C语言解决问题的基本流程,面向对象分析,使用抽象,封装实现类的编写测试.3.实验类型验证型4.实验目的(1) 掌握VC+ 6.0开发环境的使用,程序的调试方法.(2) 回顾复习C的结构体及函数的使用,来解决数学问题.(3) 掌握面向对象的分析方法,会从问题域中抽象出相关的类,及在VC6.0中使用C+规则描述类的属性和行为.(4) 使用面向对象的分析方法,对程序进行分析5.实验要求(1) 打开VC环境直接创建源文件进行编码测试,请使用C和C+两种方式解决

3、问题.(2) 完成实验内容要求并进行测试，分析结果,对比两种方式优缺点。6.实验过程（源文件、步骤及结果分析）8 / 8文档可自由编辑打印#include<stdio.h> #include<stdlib.h> typedef struct fushu/抽象数据类型定义 float real;/数据对象 float image; fushu; fushu ComplexNumberInput(float a,float b)/构造二元组 fushu c; c.real=a;/实部 c.image=b;/虚部 return(c); fushu ComplexNumberA

4、dd(fushu c1,fushu c2)/求和运算 fushu sum; sum.real=c1.real+c2.real; sum.image=c1.image+c2.image; return (sum); fushu ComplexNumberSub(fushu c1,fushu c2)/求差运算 fushu sub; sub.real=c1.real-c2.real; sub.image=c1.image-c2.image; return (sub); fushu ComplexNumberMul(fushu c1,fushu c2)/求积运算 fushu Mul; Mul.real

5、=c1.real*c2.real-c1.image*c2.image; Mul.image=c1.real*c2.image+c1.image*c2.real; return (Mul); fushu ComplexNumberDiv(fushu c1,fushu c2)/求商运算 fushu div; float d1,d2,d3,d4; d1=c1.real*c2.real+c1.image*c2.image; d2=c2.real*c2.real+c2.image*c2.image; d3=c1.image*c2.real-c1.real*c2.image; d4=c2.real*c2.

6、real+c2.image*c2.image; if(d2!=0&&d4!=0) div.real=d1/d2; div.image=d3/d4; return(div); else div.real=0; div.image=0; return(div); void ComplexNumberOutput(fushu c)/输出运算结果 if(c.real=0.0&&c.image=0.0) printf("0n"); if(c.real=0.0&&c.image!=0.0) printf("%fin",

7、c.image); if(c.real!=0.0&&c.image=0.0) printf("%fn",c.real); if(c.real!=0.0&&c.image!=0.0) printf("%f+(%fi)n",c.real,c.image); void main()/主函数 int choice; int k; float a1,a2,b1,b2; struct fushu c1,c2,sum,sub,mult,div; printf("欢迎进行复数的基本代数运算n"); printf(&qu

8、ot;1: 复数加法运算n"); printf("2: 复数减法运算n"); printf("3: 复数乘法运算n"); printf("4: 复数除法运算n"); printf("0: 推出系统n"); printf("请分别输入第一个复数的实部和虚部: "); scanf("%f%f",&a1,&b1); c1 = ComplexNumberInput(a1,b1); printf("第一个复数为: "); ComplexNu

9、mberOutput(c1); printf("请分别输入第二个复数的实部和虚部: "); scanf("%f%f",&a2,&b2); c2 = ComplexNumberInput(a2,b2); printf("第二个复数为: "); ComplexNumberOutput(c2); for(;) printf("请输入你选择的功能: "); scanf("%d",&choice); switch(choice) case 0:exit(0); break; cas

10、e 1:sum = ComplexNumberAdd(c1,c2); printf("求和后结果为: "); ComplexNumberOutput(sum); break; case 2:sub = ComplexNumberSub(c1,c2); printf("求差后结果为: "); ComplexNumberOutput(sub); break; case 3:mult = ComplexNumberMul(c1,c2); printf("求积后结果为: "); ComplexNumberOutput(mult ); brea

11、k; case 4:div=ComplexNumberDiv(c1,c2); if(div.real!=0&&div.image!=0) printf("求商后结果: "); ComplexNumberOutput(div); break; else printf("除零错误，请重新输入第二个复数；n"); k=0; exit(k); #include<iostream> #include<cmath> #include<cstring> using namespace std;class Comple

12、xpublic:double real,imag; Complex()real=0.0;imag=0.0; Complex(double r,double i) /构造函数 real=r; imag=i; Complex() Complex operator+(Complex &c) /加法重载 Complex sum; sum.real=real+c.real; /实部相加 sum.imag=imag+c.imag; /虚部相加 return sum; Complex operator-(Complex &c) /减法重载 Complex sub; sub.real=real

13、-c.real; /实部相减 sub.imag=imag-c.imag; /虚部相减 return sub; Complex operator*(Complex &c) /乘法重载 Complex multi; multi.real=real*c.real-imag*c.imag; /实部乘积 multi.imag=real*c.imag+imag*c.real; /虚部乘积 return multi; Complex operator/(Complex &c) /除法重载 Complex div; div.real=(real*c.real+imag*c.imag)/(c.r

14、eal*c.real+c.imag*c.imag); /实部除积 div.imag=(imag*c.real-real*c.imag)/(c.real*c.real+c.imag*c.imag); /虚部除积 return div; int Complex: operator=(Complex &c)if(real=c.real&&imag=c.imag)return 1;elsereturn 0; int Complex: operator!=(Complex &c)if(real=c.real&&imag=c.imag)return 0;el

15、sereturn 1; void Add() /复数加法运算函数 double a,b,c,d; cout<<"加法计算n"<<"最少输入两个复数,并且以0结束n" cout<<"第1个复数的实部和虚部:" cin>>a>>b; cout<<"第2个复数的实部和虚部:" cin>>c>>d; Complex num1(a,b),num2(c,d),sum,zero(0,0); sum=num1+num2; double

16、x,y; cout<<"第3个复数的实部和虚部:" cin>>x>>y;Complex num(x,y); int i=4; while(!(num=zero) sum=sum+num; cout<<"第"<<i<<"个复数的实部和虚部:" cin>>a>>b; num.real =a; num.imag =b; i+; if(sum.imag >0) cout<<"加法结果是:"<<sum

17、.real<<"+"<<sum.imag<<"j"<<endl; else cout<<"加法结果是:"<<sum.real<<sum.imag<<"j"<<endl; cout<<"请按任意键继续n" void Sub() /复数减法运算函数 double a,b,c,d; cout<<"减法计算n"<<"最少输入两个复数

18、,并且以0结束n" cout<<"第1个复数的实部和虚部:" cin>>a>>b; cout<<"第2个复数的实部和虚部:" cin>>c>>d; Complex num1(a,b),num2(c,d),sub,zero(0,0); sub=num1-num2; double x,y; cout<<"第3个复数的实部和虚部:" cin>>x>>y;Complex num(x,y); int i=4; while(!(n

19、um=zero) sub=sub-num; cout<<"第"<<i<<"个复数的实部和虚部:" cin>>a>>b; num.real =a; num.imag =b; i+; if(sub.imag>0) cout<<"减法结果是:"<<sub.real<<"+"<<sub.imag<<"j"<<endl; else cout<<"减

20、法结果是:"<<sub.real<<sub.imag<<"j"<<endl; cout<<"请按任意键继续n" void Mul() /复数乘法运算函数 double a,b,c,d; cout<<"乘法计算n"<<"最少输入两个复数,并且以0结束n" cout<<"第1个复数的实部和虚部:" cin>>a>>b; cout<<"第2个复数的实部

21、和虚部:" cin>>c>>d; Complex num1(a,b),num2(c,d),mul,zero(0,0); mul=num1*num2; double x,y; cout<<"第3个复数的实部和虚部:" cin>>x>>y;Complex num(x,y); int i=4; while(!(num=zero) mul=mul*num; cout<<"第"<<i<<"个复数的实部和虚部:" cin>>a&g

22、t;>b; num.real =a; num.imag =b; i+; if(mul.imag >0) cout<<"乘法结果是:"<<mul.real<<"+"<<mul.imag<<"j"<<endl; else cout<<"乘法结果是:"<<mul.real<<mul.imag<<"j"<<endl; cout<<"请按任意

23、键继续n" void Div() /复数除法运算函数 double a,b,c,d; cout<<"除法计算n"<<"最少输入两个复数,并且以0结束n" cout<<"第1个复数的实部和虚部:" cin>>a>>b; cout<<"第2个复数的实部和虚部:" cin>>c>>d; Complex num1(a,b),num2(c,d),div,zero(0,0); div=num1/num2; double x

24、,y; cout<<"第3个复数的实部和虚部:" cin>>x>>y;Complex num(x,y); int i=4; while(num!=zero) div=div/num; cout<<"第"<<i<<"个复数的实部和虚部:" cin>>a>>b; num.real =a; num.imag =b; i+; if(div.imag>0) cout<<"除法结果是:"<<div.real<<"+"<<div.imag<<"j"<<endl; else cout<<"除法结果是:"<<div.real<<div.imag<<"j"<<endl; cout<<"请按任意键继续n" void main() /主函数开始 cha