扑克牌生成与洗牌程序

1、扑克牌生成与洗牌程序使用JAVA编写以下程序：1、请左义一个名为Card的扑克牌类，该类有两个private访问权限的字符串变量face和suit： 分别描述一张牌的牌面值（如：A、K、Q、J、10、9、3、2等）和花色（如：“黑桃”、“红桃”、“梅花”、"方块”）；泄义Card类中的public访问权限的构造方法，为类中的变量 赋值：左义protected访问权限的方法getFace（）,得到扑克牌的牌面值；立义protected访问 权限的方法getSuitO,得到扑克牌的花色：泄义方法toStringO,返回表示扑克牌的花色和牌 而值字符串（如“红桃A”、“梅花10”等）。2、

2、若应用程序的main方法中，龙义字符串数组f和s：分别表示扑克牌的牌面值和花色： 圧义52个元素的Card类型数组deck,用来存放4个花色的52张牌。如下所示。String f =;String s = "黑桃”，"红桃"，"梅花"，"方块"Card deck = new Card（52；（1）使用Card类的构造方法给deck数组的52张牌赋值，要求数组中先存放黑桃花色的A、 2、3、K：然后是红桃花色的A、2、3、K；梅花花色的A、2、3、K； 方块花色的A、2、3、K。请写出实现上述功能的程序段。（2）请编写模拟洗牌

3、的完整程序，即把数组deck中的扑克牌随机打乱存放顺序。原题如下：引用内容private String face; /A. K. Q. J. 10,. 2private String suit; / Spade, Heart. Club, Diamondpublic Card（String suit. String face） this.face = face; this.suit = suit: protected String getFace（） return face; protected String getSuitO return suit; public String toStri

4、ngO return suit + "" + face;）解题，完成程序解：程序代码package poker;public class Card private String face; /A, K. Q, J, 10,. 2private String suit; / Spade, Heart, Club, Diamondpublic Card(String suit. String face) this.face = face; this.suit = suit: protected String getFace() return face; protected St

5、ring getSuit() return suit; public String toStringO return suit + ” ” + face; public static void shuffle(Card deck, int startindex, int size, int splitindex) /shuffle 洗牌 MstartIndex:H + startindex);if (splitindex * 2 > size) /if rand is 30 Card.swap(deck. startindex, splitindex, size splitindex);

6、 52、0. 30、22shuffle(deck, size splitlndcx. splitlndcx, size splitlndcx); 52、22、30、22 else if (splitindex * 2 < size) /if rnd is 10Card.swap(deck, startindex, size - splitindex, splitindex); 52、0 42、10shuffle(deck, startindex, size - splitindex, splitindex); /752x 0、42、10 else Card.swap(deck, star

7、tindex, splitindex, splitindex);)public static void swap(Card deck, int srclndex, int dstlndcx, int size) 交换/SRC是在本位豊显示：source的缩写，源的意思HREF是点击后连接的目标：HyperlinkReference,超链接引用String face =,M,;String suit =,n,;for (int i = 0; i < size; i+) face = decksrclndex + ij.face;suit = decksrclndcx + ij.suit;d

8、ecksrclndcx + ij.face = deckjdstlndex + ij.face;deckfsrclndex + ij.suit = deckfdstlndex + ij.suit;deckfdstlndex + ij.face = face;deckdstlndex + ij.suit = suit;/* * ©param args */public static void main(String args) /第一问解答Card deck = new Card52J;String f =H3H, M4H, M5 M6H, UT H8 H9H, TO”，叩JQ； K;

9、String s = HSpadeH, uHearf ”Club”，”Diamond”;for (int i = 0; i < sength; i+)for (int j = 0; j < f.length;j+) decki * 13 + j = newCard(si, fj);/依次存入数组之中，每 13 张一回合 第二问解答int rnd = 0;int numOfShuffle = 10;for (int i = 0; i < numOfShuffle; i+) rnd = (int) Math.abs(Math.random() * 52);/Math.random

10、。返回大于或等于0.0但小于1.0的伪随机double值。Card.shuffle(deck, 0, deck.length, rnd); / Testfor (int i=0; i<deck.length: i+) PS：函数shuffle是模拟洗牌的过程，这里的算法比较粗燥，随机产生一个52以内数字n, 把牌分为两份，和n-52,然后把两份牌交换一下顺序，这里做了十次切牌。shuffle是 一个递归函数，startindex表示切牌的开始序号，splitindex表示切牌的序号，即上面的n getXXX是用来得到牌的花色和数字，第二问用不到本文来自 CSDN 博客，转载请标明岀处：

11、hUD：/blogcsdnnc"wcishaofci/archivc/2009/07/28/4386710asDXpublic class DeckOfCards extends Applet private Card deck;private int currentCard;private Button dealButton, shuffleButton;private TextField displayCard;public void init()String faces = ,rAce Deuce1； Three1； HFourH, Tive1； ”Six”，HSevenH,E

12、ight1； KNineM, ”Ten”，“Jack”，”Queen”, "King” ;String suits| =Hearts”，“Diamonds”，”Clubs”，"Spades1' ;deck = new Card 52 ;currentCard = -l;for( int i = 0; i < deck.length; i+ )deck i = new Card( faces i % 13 , suitsf i/ 13 );dcalButton = new Button(”Deal card1');shufflcButton = new

13、Button( "shuffle cards");displayCard = new TextField( 20 );displayCard.setEditable( false);add( dealButton);add( shufflcButton);add( displayCard);)public boolean action( Event event. Object object)if( event.target = dealButton )Card dealt = dealCard();if( dealt != null)displayCard.setText(

14、 dealt.toStringO);showStatus( HCard #:M + currentCard );else displayCard.setText( “NO MORE CARDS TO DEAL!”); showStatus( ''Shuffle cards to continue!n);)else if( event.target = shufflcButton ) displayCard.setText( ”SHUFFLE CARDS.”); showStatus();shuffle();displayCard.setText( HDECK IS SHUFFL

15、ED!");return true:public void shuffle()currentCard = -1;for( int i = 0; i < deck .length; i+ )int j = (int)( Math.random() * 52 );Card temp = dcck i ;deck i = deck j ;deck j = temp;dealButton.enabIe();public Card dcalCard()if( +currentCard < deck length )return deck currentCard ;else deal

16、Button.disableO;return null;)class Cardprivate String face;private String suit;public Card( String f, String s ) face = f;suit = s;public String toString()return face + M ofN + suit;)两种洗牌一发牌程序收藏用指针实现，这种比较低效include <stdio.h>include <time.h>void shuffle(int 13)；void deal(int 13, char *, ch

17、ar );int main(void)char *suit4 =hearts", "diamonds”，"clubs”，"spades”;char face13 = "one1； ntwo HthreeM, Hfour “five”，HsixN, Mseven ,eight,；,nineM, Hten, eleven1； “twelve”, Hthrteen,'srand(time(NULL);int deck413=0;shuffle(deck);dcal(deck, face, suit);return 0; void shuffl

18、e(int deck13)int card, row, column;for (card = 1; card <= 52: card+) row = rand() % 4;column = rand() % 13;while (deckrowcolumn != 0) row = rand() % 4;column = rand() % 13;deckrow column = card;void deal(int deck13, char *face, char *suit(J)int card, row, column;for (card = 1; card <= 52: card

19、+)for (row = 0; row <= 3： row+)for (column = 0; column <= 12; column+)if (deckrowcolumn = card) printf("%s of %snM, facecolumn, suitfrow);第二种是直接用结构体实现，比较高效#include <stdio.h>include <time.h>struct card char *suit;char *face;);typcdcf stnict card Card:void fillDeck(Card *, char

20、*, char *); void shuffle(Card *);void dcaI(Card *);int main(void)Card card52;char *suit4 =hearts", "diamonds”，"clubs", "spades”;char *face13 = "one1； ”two'； HthreeM, Mfour Hfive "six11, Hsevenn, Meightu；,nine, Mten eleven1； “twelve”, Hthrteen,'srand(time(NU

21、LL);fillDeck(card, face, suit);shuffle(card);deal(card);return 0;)严void shuffle(int deck13)int card, row, column;for (card = 1; card <= 52; card+) row = rand() % 4;column = rand() % 13;while (deckrowcolumn != 0) row = rand() % 4;column = rand() % 13;deckjrow column = card;void deal(int dcck13, ch

22、ar *face, char *suit)int card, row, column;for (card = 1; card <= 52; card+)for (row = 0; row <= 3; row+)for (column = 0; column <= 12; column+)if (deck|rowcolumn = card)printf(M%s of %snM, facecolumn, suitrow);*/ void fillDeck(Card *dcck. char *facet char *suit) int i;for (i = 0; i < 52

23、; i+) decki.face = facei % 13;decki.suit = suitfi / 13;void shuffle(Card *deck)int ij;Card temp:for (i = 0; i < 52; i+) j = rand() % 52;temp = decki;decki = deck|j;dcckfj = temp;void deal(Card *deck)int i;for (i = 0; i < 52; i+) printf("%s of %sn", decki.face, deck(ij.suit);用c卄写的扑克牌洗

24、牌、发牌和检测牌质量的程序代 码(2010-12-12 23:00:09)转载标签：C、扑克牌辻用C+写的扑克牌洗牌、发牌和检测牌质量的程序代码编译器我用的是VS2008 oC:Wi ndowssystem32cmd.exe3956K4K3106很好！里面有3对牌方黑方梅:ft4286979ft2IS黯評潮块在里面喔执行结果如图：源文件：有三个文件，一个是主函数文件扑克牌游戏.cpp,个是类函数成员的实现文件dapai. cpp,还有一个是系统生成的stdafx. app<>/ stdafx.h :标准系统包含文件的包含文件，这个是系统生成K stdafx. h /或是经常使用但不

25、常更改的/特定于项目的包含文件/从Windows头中排除极少使用的资料pragma once ttdefine WIN32_LEAN_ANDJIEAN #include <stdio. h>nclude <tcharh>/ TODO:在此处引用程序需要的其他头文件/扑克牌游戏.cpp :定义控制台应用程序的入口点。主函数文件#include "stdafx h#i nclude"iosti?e&nr#include z，dapai h"using namespace std;void compare( int ( *pl) 13 ,

26、 int (*p2) 4 )检测哪手牌比较好 int max=*p2:int rowl = 0;for ( int i = 0; i < 4; i+ )for ( int j =0; j < 4; j卄)if ( *(*(p2 + i)+j) >max )max = *(*(p2 + i)+j);rowl = i;if ( max >=5 )cout«，z第"rowl+1手牌比较好! zz«endl;int _tmain(int argc, _TCHAR* argvL)dapai A;docout«"你要发儿手牌？ &q

27、uot;endl;cin>>A m;cout«"你要发多少张牌?，«endl;cin»A n;if ( A. m*A. n > 52 )cout«z/输入非法，一副扑克牌只有52张，请重新输入!n; if ( A. m > 4)cout«z/输入非法，只允许发4手牌以内！ zz«endl; while (A. m*A. n > 52 A. m > 4 );A. xipai ();A. fapai (A. m, A. n);compare (A. a, A. b);/dapai cpp 文件

28、 include "StdAfx. h" #include ，?dapaih" ttinclude "cstdlib" #include "ctime" nclude "iomanip" #include "iostreanT using namespace std;/构造函数开始 dapai:dapai(void)for ( int i = 0; i < 4; i+ )for( int j = 0; j < 13; j+ ) aij=0;for (int i 二 0; i 4; i

29、+ )for(int j = 0; bij二 0;color 0 color 1 _color 2 Jcolor 3 j < 4;j+ )桃花块桃 黑梅方红facet 0 _*;2”3” L ”0厂6 ;7“89"l(rfacet 1 facet 2 J facet 3 facet 4 facet 5 facet 6 face 7 face 8 facet 9 facet 10 二，zrfacet 11 = ©facet 12 二 *for ( int row = 0; row < 4; row +)for ( int column = 0; column &l

30、t; 13; column +)pukeF row column _ 二0;srand( time( 0 ) ) ;/获得出前的时间作为随机数的种子 /构造函数结束 洗牌void dapai : : xipai ()int row;int column;for ( int pai = 1; pai <= 52; pai +)dorow = rand () % 4; column = rand() % 13; while ( pukeL row _ column !二0 ); pukeL row J column J = pai:/洗牌结束 开始发牌5手牌，每手牌n张 void dapai

31、 : : fapai ( int m, int n)int pai = 1:int k = n;for( int j = 0; j < m; j+ )cout«，z第手牌为:，z«endl; for ( ; pai <= n; pai + )for ( int row = 0; row < 4; row + )for ( int column = 0; column < 13; column + )if ( pukeL row _ column J = pai )cout«setw( 8 ) «right«color r

32、ow « /z«face column «endl:alj.column. +;bjrow +;是否有连续的五张牌岀现标记 成对牌出现的对数三张同号牌出现的个数/四张同号牌一起出现的标记n = n+k;0000countOcount2count3count4=0;/连对标记i 二 0; i < 13; i + )count222for (int辻（二二 2 ）/一对牌count2+;/cout«，/有一对，«facei«，/在里面，/«endl;辻(= 3)/三张一样的牌count3+;/cout«，z有三张

33、同号牌facei«"在里面，z«endl;if (= 4 )/四张一样的牌count4+;/cout«，/有四张同号牌facei«在里面"endl;检测是否有顺子牌(五张连续的牌)for (int i = 0; i < 12; i+ )if (= 0 )countO =0;elsecount0+;if ( countO = 5)break; 顺子牌检测结束for ( int i = 0; i < 12; i+ )if ( a j i < 2 )count222 = 0;elsecount222+;辻(count222

34、 =3 )break;判断对牌并输出if ( count2 != 0 )cout «，ztt 很好！里面有/z«count2«/z对牌z，«endl;/对牌输出结束辻(count3 !二0 )cout «z/tt里面有三张同号牌"<endl;辻(count4 != 0 )cout «，ztt里面有四张同号牌/z<<endl:if ( countO = 5 )cout«z/tt非常棒！注意看，里面有顺子牌(五张连续的牌)®z，«endl;辻(count222 = 3 )cout&

35、#171;，ztt不错，里面有连对喔!，z«endl;判断输出是否有五张同花的牌for (int i 二 0; i 4; i + )if ( bji二二 5 )cout«，ztt 手气不错!有 5 张"color i <<"在里面喔"endl;/同花判断结束发牌结束dapai:dapai(void)/ stdafx.cpp :只包括标准包含文件的源文件，这个是系统生成的/扑克牌游戏pch将作为预编译头/ stdafx. obj将包含预编译类型信息#include "stdafx h/ TODO:在 STDAFX. H 中/引用任何所需的附加头文件，而不是在此文件中引用#incl