下载本文档
版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领
文档简介
1、Ansys 综合实例1第一章前处理第 1 例 关键点和线的创建实例一正弦 曲线AHFINISH/CLEAR, NOSTART /PREP7K,100,0,0,0CIRCLE,100,1,90CSYS,1KFILL,2,1,4,3,1K,7,1+3.1415926/2,0,0 CSYS,0KFILL,7,1,4,8,1KGEN,2,7,11,1,1LSTR,8,13LSTR,9,14LSTR,10,15LSTR,11,16LANG,5,6,90,0LANG,4,5,90,0LANG,3,4,90,0LANG,2,3,90,0BSPLIN,1,17,18,19,20,12LSEL,U,14LDEL
2、E,ALLLSEL,ALLKWPAVE,12CSYS,4LSYMM,X,14NUMMRG,KP, LOWLCOMB,ALL,0FINISH/CLEAR, NOSTART/PREP7PI=3.14159J=0*DO,l,0,PI,PI/10.0J=J+1X=IY=SIN(I)I=I+1K,J,X,Y*ENDDOBSPLIN,1,2,3,4,5,6BSPLIN,6,7,8,9,10,11csys,4KWPAVE,11LSYMM,y,1,2,0KWPAVE,11LSYMM,x,3,4,1以上程序有意没算到 2 二为了使用几个命令Ansys 综合实例2第 2 例 工作平面的应用实例一相交圆柱体本例提示
3、通过相交圆柱体的创建,本例主要介 绍了工作平面的使用方法。通过本例,读者可以了解 并掌握工作平面与所创建体的位置、 方向的关系, 学 习工作平面的设置、偏移、旋转和激活为当前坐标系 的方法。FINISH/CLEAR NOSTART/PREP7CYLIND,0.015,0,0,0.08,0,360CYLIND,0.03,0,0,0.08,0,360 /VIEW,1,1,1,1/PNUM,VOLU,1WP0FF,0,0.05,0.03WPROT,0,60CYLIND,0.012,0,0,0.055,0,360CYLIND,0.006,0,0,0.055,0,360 VSEL,S,2,3,1CM,V
4、V1,VOLU VSEL,INVECM,VV2,VOLU VSEL,ALLVSBV,VV1,VV2BLOCK,-0.002,0.002,-0.013,-0.009WPSTYLE,1CSYS,4 VGEN,3,1,120VSBV,5,1VSBV,4,2VSBV, 1,3 WPROT,0,0,90VSBW, ALLVDELE,1,4,3 VADD,ALL VPLOT/REPLOT,0,0.008Ansys 综合实例3第 3 例复杂形状实体的创建实例一螺栓/PREP7CSYS,1K,1,0.008,0,-0.002K,2,0.008,90,-0.0015K,3,0.008,180,-0.001K,4
5、,0.008,270,-0.0005K,5,0.008,0,0/VIEW,1,1,1,1L, 1,2L,2,3L,3,4L,4,5LGEN,7,ALL,0.002NUMMRG,KP, LOWLCOMB,ALLK,80,0.008+0.0015/4,90,0.012+0.002/4K,81,0.008+2*0.0015/4,180,0.012+2*0.002/4K,82,0.008+3*0.0015/4,270,0.012+3*0.002/4K, 83,0.008+4*0.0015/4,0,0.012+4*0.002/4L, 35,80L,80,81L,81,82L,82,83CSYS,0K,9
6、0,0.008,0,-0.00025K,91,0.006918,0,-0.002K,92,0.006918,0,0 /PNUM,KP,1 /PNU M,LINE,1GPLOTLSTR,1,90LSTR,91,92LANG,7,90,60,0本例提示 在使用 ANSYS软件进行结构分 析时,建立实体模型是最复杂最难以掌握的一个 过程。因此,有必要熟练掌握实体模型的创建。 本例使用ANSYS 软件提供的各种建模工具,对复 杂形状实体的创建进行了练习。Ansys 综合实例4LANG,7,1,120,0AL,6,9,10,11VDRAG,1,1,2,3,4,5/PNUM,KP,0/PNU M, LIN
7、E,0/PNUM,AREA,1/PNUM,VOLU,1CYLIND,0.0079,0,0.04,0,360VSEL,U,6CM,VVV2,V0LUALLSVSBV,6,VVV2/REPLOTK,93,0.0065,0,0K,94,0.0095,0,0.003K,95,0,0,0K,96,0,0,0.03LSTR,93,94AROTAT,6,95,96,360ASEL,S,1,4,1VSBA,7,ALLASEL,ALLVDELE,1,1RPRISM,0.04,0.05,6,0.0131CONE,0.03477,0.00549,0.03,0.055,0,360VINV,1,3/REPLOTVPLO
8、TFINISHAnsys 综合实例5第 4 例 复杂形状实体的创建实例一杯子本例提示为了进一步掌握实体模型的创建方法和技巧,本例使用ANSYS 软件提供的各种建模工具,对复杂形状实体的创建继续进行练习。/PREP7K,1,0,0,0K,2,0.0395,0,0 K,3,0.05,0.12,0K,4,0.047,0.12,0 K,5,0.03675,0.003,0K,6,0,0.003,0LSTR,1,2LSTR,2,3LSTR,3,4LSTR,4,5 LSTR,5,6 LSTR,6,1LFILLT,1,2,0.02 LFILLT,4,5,0.017 AL,ALLVROTAT,ALL,1,6,3
9、60 K,31,0,0.103,0K,32,0.078,0.103,0K,33,0.078,0.046,0 K,34,0,0.0011,0LSTR,31,32LSTR,32,33 LSTR,33,34 LFILLT,54,55,0.013LFILLT,55,56,0.028K,41,0,0.103+0.002,0.005K,42,0,0.103+0.002,-0.005K,43,0,0.103-0.002,-0.005K,44,0,0.103-0.002,0.005 LSTR,41,42LSTR,42,43 LSTR,43,44 LSTR,44,41LFILLT,59,60,0.001 LFI
10、LLT,60,61,0.001LFILLT,61,62,0.001 LFILLT,62,59,0.001AL,59,63,60,64,61,65,62,66VDRAG,33,54,57,55,58,56 VSEL,S,5,9,4ASEL,S,4,28,24 VSBA,ALL,ALLALLSEL,ALL VDELE,10,1 VDELE,13,1/PNUM,VOLU,1 /NUMBER/COLOR,VOLU,ORAN,ALL /REPLOTFINISHAnsys 综合实例6第二章结构静力学分析第 5 例杆系结构的静力学分析实例一平面桁架本例提示介绍了利用 ANSY 眯解杆系结构的方法、步骤和过程
11、/CLEAR/FILNAME,EXAMPLE5L=0.1A=1e-4/PREP7ET,1,BEAM3R,1,A MP,EX,1,2E11 MP,PRXY,1,0.3N,1N,2 ,LN,3,2*LN,4 ,L,LE,1,2E,2,3E,1,4E,2,4E,3,4FINISH/SOLUD,1,UXD,1,UYD,3,UYF,4,FY,-2000SOLVEFINISH/POST1ETABLE,FA,SMISC,1ETABLE,SA,LS,1PRETAB,FA,SAFINISHAnsys 综合实例7第 6 例杆系结构的静力学分析实例一悬臂梁本例提示介绍了利用 ANSYS 寸杆系结构进行静力学分析的方
12、法 程。/CLEAR/FILNAME,EXAMPLE6/PREP7ET, 1,BEAM3R,1,14.345e-4,245e-8,0.1MP,EX,1,2E11MP,NUXY,1,0.3K,1,0,0,0K,2,1,0,0LSTR,1,2 LESIZE,1,50LMESH,1FINISH/SOLUDK,1,UXDK,1,UYDK,1,ROTZFK, 2,FY,-10000SOLVEFINISH/POST1PLDISPFINISH、步骤和过Ansys 综合实例8第 7 例 平面问题的求解实例一厚壁圆筒问题本例提示介绍了利用 ANSYSS 行静力学分析的方法、步骤和过程,并对将/POST1PATH
13、,P1,2 ! 定义 2 个点PPATH,1,30 !第一个节点 30 号(左端)PPATH,2,1 ! 第二个节点 1 号(右端)PDEF,SR,S,X !描述径向应力 PDEF,ST,S,Y !描述周向应力PLPATH,SR,ST绘应力图FINISH空间问题简化为平面问题的条件、方法进行了简单的介绍。/CLEAR/FILNAME,EXAMPLE7/PREP7ET,1,PLANE183,2MP,EX,1,2E11MP,PRXY,1,0.3PCIRC,0.1,0.05,0,90LESIZE,4,6LESIZE,3,8MSHAPE,0MSHKEY,1AMESH,1FINISH/SOLUDL,4,
14、UYDL,2,UXSFL,3,PRES,10E6SOLVESAVEFINISHAnsys 综合实例9第 8 例静力学问题的求解实例一扳手的受力分析本例提示介绍了利用 ANSYS 进行空间问题静力学分析的方法、步骤和过程。/CLEAR, nostart /FILNAME,EXAMPLE8/PREP7ET,1,PLANE42ET,2,SOLID45MP,EX,1,2E11MP,PRXY,1,0.3RPR4,6,0,0,0.01K,7,0,0,0K,8,0,0,0.05K,9,0,0.1,0.05LSTR,7,8LSTR,8,9LFILLT,7,8,0.015LSTR,1,4ASBL,1,10LES
15、IZE,2,3LESIZE,3,3LESIZE,4,3LESIZE,7,0.01LESIZE,8,0.01Ansys 综合实例10LESIZE,9,0.01MSHAPE,0MSHKEY,1 AMESH,ALLVDRAG,ALL,7,9,8 ACLEAR,2,3,1 FINISH/SOLUDA,2,ALLDA,3,ALL KSEL,S,24,29,1 FK,ALL,FX,100 KSEL,ALLSOLVESAVEFINISH/POST1 /VIEW,1,1,1,1 PLDISP,2 PLNSOL,S,EQV,0,1NWPAVE,362 /TYPE,1,SECT /CPLANE,0 /REPLOT
16、FINISHAnsys 综合实例11第 9 例各种坐标系的应用实例一圆轴扭转分析本例提示 通过本例介绍了 ANSYS 坐标系统的特点、 应用场合和使用方 法、步骤,并使用解析解对有限元分析结果进行了验证。/CLEAR, nostart/FILNAME,EXAMPLE_9/PREP7ET,1,PLANE183ET,2,SOLID186MP,EX,1,2.08E11MP,PRXY,1,0.3RECTNG,0,0.025,0,0.12LESIZE,1,5LESIZE,2,8MSHAPE,0MSHKEY,1AMESH,1EXTOPT,ESIZE,5EXTOPT,ACLEAR,1VROTAT,1,1,4
17、,36O/VIEW,1,1,1,1WPROT,O,-9OCSWPLA,11,1,1,1NSEL,S, LOC,X,0.025 NROTAT,ALLFINISH/SOLUD,ALL,UXNSEL,R ,L OC,Z,0.12F,ALL,FY,1500ALLSEL,ALLDA,2,ALLDA,6,ALLDA,10,ALLDA,14,ALLSOLVESAVEFINISH/POST1PLDISP,1RSYS,11NSEL,S, LOC,Z,0.045NSEL,R, LOC,Y,0PRNSOL,U,YNSEL,S, LOC,Z,O,O.O45ESLN,R,1PLESOL,S,YZFINISHnhtrfE
18、LEWm SOLUTION5TEP=L SUB -1TIHE=1 srz RSYS-llDHX =T344E-04 SW-16502=T617E+DeAnsys 综合实例12第三章结构动力学分析第 10 例模态分析实例一均匀直杆的固有频率分析本例提示 介绍了利用 ANSYS 进行结构固有频率和振型研究即模态分析的 方法、步骤和过程,并使用解析解对有限元分析结果进行了验证。/CLEAR /FILNAME,EXAMPLE10 /PREP7ET,1,SOLID186 MP,EX,1,2E11 MP,PRXY,1,0.3MP,DENS,1,7800BLOCK,O,O.O1,O,O.O1,O,O.1LE
19、SIZE,1,3LESIZE,2,3LESIZE,9,15MSHAPE,0MSHKEY,1VMESH,1FINISH/SOLUANTYPE,MODALMODOPT,LANB,5MXPAND,5DA,1,UZDA,3,UYDA,5,UXSOLVESAVEFINISH/POST1SET,LISTSET,FIRST /VIEW,1,-1 /REPLOTPLDIANMODE,1O,O.5,O SET,NEXTPLDIANMODE,1O,O.5,OFINISH第 11 例 模态分析实例一斜齿圆柱齿轮的固有频率分析本例提示本例介绍了对一个复杂结构一斜齿圆柱齿轮模型的创建方法 ,以及利用 ANSYS 寸其进
20、行固有频率和振型研究即模态分析的方法、步骤和过程。Ansys 综合实例13/CLEAR,NOSTART /FILNAME,EXAMPLE11 /PREP7ET,1,SOLID45MP,EX,1,2E11MP,PRXY,1,0.3MP,DENS,1,7800K,1,21.87E-3K,2,22.82E-3,1.13E-3K,3,24.02E-3,1.47E-3K,4,24.62E-3,1.73E-3K,5,25.22E-3,2.08E-3K,6,25.82E-3,2.4E-3K,7,26.92E-3,3.23E-3K,8,27.11E-3BSPLIN,2,3,4,5,6,7LSYMM,Y,1LA
21、RC,2,9,1LARC,7,10,8AL,ALLCSYS,1 !柱坐标VEXT,1,0,18.412,20E-3VGEN,24,1,0,360/24CSYS,0CYL4,0,0,10E-3,0,26.37E-3,360,20E-3BL0CK,-3E-3,3E-3,0,12.8E-3,0,20E-3Ansys 综合实例14VSBV,25,ALLSMRTSIZE,9ESIZE,0.002MSHAPE,1MSHKEY,0VMESH,ALLCSYS,1NSEL,S, LOC,X,0.01NROTAT,ALLD,ALL,UXALLSEL,ALLFINISH/SOLUANTYPE,MODALMODOPT
22、,LANB,5MXPAND,5DA,208,UXNSEL,S, LOC,Z,0NSEL,A,LOC,Z,20E-3NSEL,R, LOC,X,0,15E-3D,ALL,UZALLSEL,ALLSOLVEFINISH/POST1SET,LISTFINISH第 12 例有预应力模态分析实例一弦的横向振动本例提示介绍了利用 ANSYSS 行有预应力模态分析的方法、步骤和过程,并使用解析解对有限元分析结果进行了验证。 有预应力模态分析分为两个大的步 骤:首先进行结构静应力分析,并把静应力作为预应力施加在模型上;然后进行 模态分析。/CLEAR/FILNAME,EXAMPLE12图 12-22 模态动画
23、对话框/PREP7ET, 1,LINK1 MP,EX,1,2E11 MP,PRXY,1,0.3 MP,DENS,1,7800 R,1,1E-6K,1,0,0,0 K,2,1,0,0 LSTR,1,2 LESIZE,1,50 LMESH,1 FINISH/SOLU DK,1,UX DK,1,UY DK,2,UYFK, 2,FX,2000 PSTRES,ON SOLVE SAVEFINISH/SOLU ANTYPE,MODAL MODOPT,LANB,10 MXPAND,10 DK,2,UXAnsys 综合实例15PSTRES,ON SOLVE FINISH/POST1SET,LISTSET,FI
24、RSTPLDIANMODE,10,0.5,0SET,NEXTPLDIANMODE,10,0.5,0FINISHAnsys 综合实例16第 14 例 瞬态动力学分析实例一凸轮从动件运动分析/CLEAR,NOSTART /FILNAME,EXAMPLE14 /PREP7ET,1,PLANE42ET,2,SOLID45MP,EX,1,2E11MP,PRXY,1,0.3MP,DENS,1,7800K,1,0,0,0K,2,0.015,0.015,0K,3,0.015,0.1,0K,4,0,0.1,0LSTR,1,2LSTR,2,3LSTR,3,4LSTR,4,1AL,ALLLESIZE,1,2LESI
25、ZE,3,2本例提示介绍了利用 ANSYSS 行瞬态动力学分析的方法、步骤和过程,并使用解析解对有限元分析结果进行了验证。瞬态动力学分析时,结构上的载荷可 以随时间呈任意规律变化,在任意一个载荷步内,约束和载荷都可以重新设定。Ansys 综合实例17LESIZE,2,10AATT,1,1,1!定义面的属性、参数、类型、坐标系、横截面的命令MSHAPE,0MSHKEY,1AMESH,ALLTYPE,2EXT0PT,ESIZE,4EXT0PT,ACLEAR,1VROTAT,1,1,4,360WPROT,0,-90CSWPLA,11,CYLINASEL,S,3,15,4NSLA,S,1NROTAT,
26、ALLFINISH加载荷第 1 个载荷步定义载荷步时间步长,最小最小步长0.2 最大 1指定荷载步内的斜坡形荷载加约束 2第 2 个载荷步第 3 个载荷步加约束 3第 4 个载荷步/POST26 NSOL,2,1,U,Y,uy DERIV,3,2,1 DERIV,4,3,1PLVAR,2,3PLVAR,2,4FINISH/SOLU D,ALL,UX !ALLSEL,ALLANTYPE,TRANSOUTRES,ALL,ALLFK,4,FY,-1000!TIME,10!AUTOTS,ONDELTIM,0.5,0.2,1KBC,0!DK,1,UY,0.02!LSWRITE,1TIME,20!LSWR
27、ITE,2TIME,35!DK,1,UY,0!LSWRITE,3TIME,45!LSWRITE,4LSSOLVE,1,4,1SAVEFINISH加约束 1求导计算 2 对 1 的导数赋值给 3Ansys 综合实例18第 15 例 连杆机构运动分析实例一曲柄滑块机构本例提示介绍了利用 ANSYS 寸连杆机构进行运动学分析的方法、步骤和过程,并使用解析解对有限元分析结果进行了验证。着重介绍了曲柄滑块机构模型 的创建以及约束的施加方法,介绍了三维铰链单元 C0MBIN7 勺使用方法。/CLEAR,NOSTART /FILNAME,EXAMPLE15/PREP7Pl=3.1415926R=0.25L=
28、0.62E=0.2OMGA1=30 T=60/OMGA1 FIO=ASIN(E/(R+L) AX=0AY=0BX=R*COS(FI0)BY=-R*SIN(FI0)CX=(R+L)*COS(FI0) CY=-EET,1,COMBIN7 ET,2,BEAM4 MP,EX,1,2E11 MP,PRXY,1,0.3MP,DENS,1,1E-14Ansys 综合实例19R,1,1E9,1E3,1E3,0R,2,4E-4,1.3333E-8,1.3333E-8,0.02,0.02N,1,AX,AYN,2,BX,BYN,3,BX,BYN,4,CX,CYN,5,BX,BY,-1TYPE,1REAL,1E,2,
29、3,5TYPE,2REAL,2E,1,2E,3,4FINISH /SOLUANTYPE,TRANSNLGEOM,ON!打开大变形选项DELTIM,T/70KBC,0 !每个子荷载步的荷载从前一个荷载步到本荷载步线性内插(斜坡形)TIME,TOUTRES,ALL,ALLCNVTOL,F,1,0.1CNVTOL,M,1,0.1D,ALL,UZD,ALL,ROTXD,ALL,ROTYD,1,ROTZ,2*PID,1,UXD,1,UYD,4,UYSOLVESAVEFINISH时间和频率总为变量 1将节点 4 的位移 X 定义为 2 号变量将 2 号变量对 1 号变量的导数定义为 3 号变量速度将 3
30、号变量对 1 号变量的导数定义为 4 号变量_加速度绘制 2 号变量(位移)随时间变化曲线绘制 3 号变量(速度)随时间变化曲线绘制 4 号变量(加速度)随时间变化曲线/POST26NSOL,2,4,U,XDERIV,3,2,1DERIV,4,3,1PLVAR,2PLVAR,3PLVAR,4FINISHAnsys 综合实例20第四章非线性分析第 16 例 接触分析实例一平行圆柱体承受法向载荷时的接触应力分析本例提示介绍了利用 ANSYS 寸结构进行接触分析的方法、步骤和过程,着重介绍了建立面一面接触对的方法和难点,为解决实际应用问题奠定了基础。/CLEAR/FILNAME,EXAMPLE16
31、/PREP7ET,1,PLANE183ET,2,SOLID186ET,3,TARGE170ET,4,CONTA174,1R,1,0.1MP,EX,1,2E11MP,PRXY,1,0.3CYL4,0,0,0.1,0,0,90CYL4,0,0.15,0.05,-90,0,0WPOFF,0.01WPROT,0,0,90ASBW,ALLAATT,1,1,1ESIZE,0.0075MSHAPE,0MSHKEY,0AMESH,ALLKREFINE,2,4,2,3TYPE,2EXTOPT,ESIZE,5EXTOPT,ACLEAR,1VEXT,ALL,0.01ASEL,S,14NSLA,S,1REAL,1TY
32、PE,3ESURFALLSASEL,S,18NSLA,S,1REAL,1TYPE,4ESURFALLSFINISHAnsys 综合实例21/SOLUDA,16,UYDA,8,UYDA,15,UXDA,20,UXDA,1,UZDA,9,UZDA,13,UZDA,17,UZASEL,S,11,19,8NSLA,S,1SFA,ALL,1,PRES,1E6CP,1,UY,ALLALLSLNSRCH,ONAUTOTS,ONNSUBST,5,10,3OUTRES,ALL,ALLSOLVEFINISH/POST1ESEL,S,TYPE,4ETABLE,PRES,CONT,PRESETABLE,ST,CONT
33、,STATETABLE,GAP,CONT,GAPESORT,ETAB,PRES,0 PRETAB,PRES,ST,GAP,PENE FINISHAnsys 综合实例22第 17 例 稳定性问题分析实例一屈曲分析本例提示 本例通过计算受压杆临界压力的实例, 介绍了利用 ANSYSS 行线 性屈曲分析的方法、步骤和过程,并使用解析解对有限元分析结果进行了验证。 线性屈曲分析分为两个大的步骤: 首先进行结构静应力分析, 分析时必须将预应 力开关打开;然后进行屈曲分析。/CLEAR/FILNAME,EXAMPLE17/PREP7ET, 1,BEAM4MP,EX,1,2E11MP,PRXY,1,0.3R
34、,1,9E-4,6.75E-8,6.75E-8,0.03,0.03,0K,1,0,0,0K,2,0,2,0LSTR,1,2LESIZE,1,10TYPE,1MAT,1REAL,1LMESH,1FINISH/SOLUANTYPE,STATICPSTRES,ONDK,1,UXDK,1,UYDK,1,UZDK,1,ROTXDK,1,ROTYDK,2,UXDK,2,UZDK,2,ROTXDK,2,ROTYFK, 2,FY,-1SOLVEFINISH/SOLUANTYPE,BUCKLEBUCOPT,LANB,1MXPAND,1OUTPR,ALL,ALLSOLVESAVEFINISH/POST1SET,F
35、IRSTSET,LISTPLDISP,2FINISH第 18 例弹塑性分析实例一厚壁圆筒问题Ansys 综合实例23本例提示 介绍了利用 ANSY 眯解弹塑性问题的方法和步骤, 介绍了在求解 弹塑性问题时定义材料模型的方法,并使用解析解对有限元分析结果进行了验 证。/CLEAR/FILNAME,EXAMPLE18/PREP7ET,1,183,2MP,EX,1,2E11MP,NUXY,1,.3TB,BKIN,1,1 TBTEMP,0 TBDATA,1,500E6,0 PCIRC,0.1,0.05,0,90ESIZE,0.003MSHKEY,1 MSHAPE,0 AMESH,ALL FINISH/
36、SOLUDL,4,UYDL,2,UXAUTOTS,ONDELTIM,0.2,0.1,0.3KBC,0TIME,1SFL,3,PRES,375E6LSWRITETIME,2SFL,3,PRES,0LSWRITELSSOLVE,1,2FINISH/POST1RSYS,1SET,1,LASTPLNSOL,S,EQVFINISHAnsys 综合实例24第 19 例非线性分析综合应用实例一冲击本例提示介绍了一个综合应用材料非线性、状态非线性、结构非线性研究 冲击过程力学行为的实例。/CLEAR /FILNAM,EXAMPLE19 /PREP7ET,1,SOLID45ET,2,SHELL43ET,3,CO
37、MBIN14ET,4,CONTA173ET,5,TARGE170MP,EX,1,2E11MP,NUXY,1,0.3MP,DENS,1,7800 TB,BKIN,1,1TBTEMP,0TBDATA,240E6,2E8 R,1,0.06R,2,100000R,3,0.5 /VIEW,1,1,1,1K,1,-0.8,0,-1.5K,2,-0.8,0,1.5K,3,0.8,0,1.5K,4,0.8,0,-1.5A,1,2,3,4TYPE,2REAL,1ESIZE,0.08AMESH,1BLOCK,-0.1,0.1,0.001,0.201,-0.1,0.1TYPE,1ESIZE,0.05VMESH,14
38、.i.-.gML*Al,f-T1flvl1li-41茁石(珞1MIEtc空度Ansys 综合实例25N,950,-0.8,-0.5,-1.5N,951,0.8,-0.5,-1.5N,952,0.8,-0.5,1.5N,953,-0.8,-0.5,1.5TYPE,3REAL,2E,1,950E,60,951E,40,952E,2,953NSEL,S,950,953,1D,ALL,ALLALLSELNSEL,S, LOC,Y,0NSEL,R, LOC,X,-0.3,0.3NSEL,R, LOC,Z,-0.3,0.3REAL,3TYPE,5ESURFALLSASEL,S,4NSLA,S,1REAL,
39、3TYPE,4ESURFALLSFINI/SOLUANTYPE,TRANSACEL,0,9.8VSEL,S,1NSLV,S,1IC,ALL,UY,-8D,ALL,UXD,ALL,UZALLSKBC,0LNSRCH,ONAUTOT,ONOUTRES,ALL,ALLTIME,0.0013DELTIM,2.5E-5,1E-6,4E-5SOLVEFINI/POST1PLNSOL,S,EQV,0,1.0FINI/POST26NSOL,2,880,U,YDERIV,3,2,1DERIV,4,3,1PLVAR,2FINI第 20 例非线性分析综合应用实例一钢板卷制成圆筒本例提示介绍了综合利用 ANSYS 非
40、线性分析功能模拟将钢板卷制成圆筒 的方法和步骤。Ansys 综合实例26/CONFIG,NRES,2000!前处理/PREP7/PNUM,VOLU,ONET,1,SHELL43ET,2,SOLID186MP,EX,1,2E11MP,DENS,1,7800MP,NUXY,1,0.3MP,EX,2,2E11MP,DENS,2,7800MP,NUXY,2,0.3TB,BKIN,2,1TBTEMP,0TBDATA,240E6,2E8R,1,0.02CYLIND,0.38/2,0,0.3,2.3,0,360CYLIND,0.38/4,0,0.3,0,0,360CYLIND,0.38/4,0,2.6,2.
41、3,0,360VGLUE,ALLVSEL,NONEWPOFF,0.54/2,-0.4CYLIND,0.3/2,0,0.3,2.3,0,360CYLIND,0.3/4,0,0.3,0,0,360CYLIND,0.3/4,0,2.6,2.3,0,360 VGLUE,ALLVSEL,NONEWPOFF,-0.54CYLIND,0.3/2,0,0.3,2.3,0,360CYLIND,0.3/4,0,0.3,0,0,360CYLIND,0.3/4,0,2.6,2.3,0,360VGLUE,ALLALLSVDELE,ALLHPTCREATE,AREA,5,C00RDHPTCREATE,AREA,10,CO
42、ORD,0,0,2.6HPTCREATE,AREA,34,C00RD,-0.54/2,-0.4,2.6HPTCREATE,AREA,29,C00RD,-0.54/2,-0.4,0HPTCREATE,AREA,22,C00RD,0.54/2,-0.4,2.6HPTCREATE,AREA,17,C00RD,0.54/2,-0.4,0 MAT,1!TYPE,1Ansys 综合实例27REAL,1ESIZE,0.05SMRTSIZE,8MSHAPE,1AMESH,ALLBL0CK,0.7,-1.0,0.3/2+.02,0.3/2+.02+0.03,0.5,2.1LESIZE,96,1MAT,2TYPE
43、,2MSHKEY,1MSHAPE,0ESIZE,0.05VMESH,ALLET,4,TARGE170ET,5,CONTA174KEYOPT,5,12,1R,10,0.1R,11,0.1R,12,0.1ASEL,S,40NSLA,S,1NSEL,U ,L OC,Z,0.8,1.8MAT,3REAL,10TYPE,4ESURFALLSASEL,S,3,4,1NSLA,S,1NSEL,U ,L OC,Z,0.9,1.7NSEL,U ,L 0C,Z,0.3,0.4NSEL,U ,L OC,Z,2.2,2.3MAT,3REAL,10TYPE,5ESURFALLSASEL,S,39NSLA,S,1NSEL
44、,U ,L OC,Z,0.8,1.8MAT,4REAL,11TYPE,4ESURFALLSASEL,S,27,28,1NSLA,S,1NSEL,U ,L OC,Z,0.9,1.7NSEL,U ,L OC,Z,0.3,0.4NSEL,U ,L OC,Z,2.2,2.3MAT,4REAL,11Ansys 综合实例28TYPE,5ESURFALLSASEL,S,39NSLA,S,1NSEL,U ,L OC,Z,0.8,1.8MAT,4REAL,12TYPE,4ESURFALLSASEL,S,15,16,1NSLA,S,1NSEL,U ,L OC,Z,0.9,1.7NSEL,U ,L OC,Z,0.3
45、,0.4NSEL,U ,L OC,Z,2.2,2.3MAT,4REAL,12TYPE,5ESURFALLSFINI/SOLU!进入求解器 D,ALL,UZ D,ALL,ROTX D,ALL,ROTYNSEL,S, LOC,XNSEL,R, LOC,YD,ALL,UY,-0.08D,ALL,UXD,ALL,UZALLSCSYS,4ASEL,S, LOC,Y,-2,0.3/2+0.01NSLA,S,1D,ALL,ALLALLS ANTYPE,TRANS NEQIT,100 LNSRCH,ON NLGEOM,ONTIME,1AUTOT,ON NSUBST,30,80,20KBC,0OUTRES,AL
46、L,ALLSOLVE!以下模拟下辊转动,驱动钢板前进CSYS,4ASEL,S, LOC,Y,-2,0.3/2+0.01 NSLA,S,1DDELE,ALL,ALLALLSD,ALL,UZD,ALL,ROTXD,ALL,ROTYNSEL,S ,L OC,X,0NSEL,R, LOC,YD,ALL,ROT Z,-3.1415926D,ALL,UXD,ALL,UYAnsys 综合实例29ALLSWPOFF,0.54NSEL,S ,L OC,X,0 NSEL,R, LOC,Y D,ALL,UX D,ALL,UYD,ALL,ROT Z,-3.1415926TIME,2ALLSKBC,0NSUBST,20
47、0,1000,100SOLVEACEL,0,9.8CSYS,0NSEL,S, LOC,XNSEL,R, LOC,YD,ALL,UY,-0.06D,ALL,UXD,ALL,UZD,ALL,ROTXD,ALL,ROTYALLSKBC,0NSUBST,20,300,10TIME,2.1SOLVEFINI!查看结果/POST1SET,LAST PLNS,U,SUMANTIME,50,0.5,1,2,0,2.1FINI第五章热应力计算第 21 例瞬态热分析实例一水箱本例提示 通过实例介绍了利用 ANSY 进行瞬态热分析的方法和步骤, 介绍 了瞬态热分析时材料模型所包含的内容,介绍了模型边界条件、初始温度
48、的施加 方法。/CLEAR/FILNAME,EXAMPLE21/PREP7ET,1,PLANE77 MP,KXX,1,383 MP,DENS,1,8889MP,C,1,390 MP,KXX,2,70 MP,DENS,2,7833MP,C,2,448 MP,KXX,3,2MP,DENS,3,996MP,C,3,4185RECTNG,0,0.6,0,0.5RECTNG,0.15,0.225,0.225,0.27RECTNG,0.342,0.42,0.225,0.27AOVLAP,ALLAnsys 综合实例30AATT,1,1,1 MSHAPE,0 MSHKEY,1 ESIZE,0.01 AMESH
49、,2 AATT,2,1,1AMESH,3 AATT,3,1,1 MSHKEY,0 ESIZE,0.03 AMESH,4 FINISH/SOLUANTYPE,TRANS TIMINT,OFF TIME,0.01DELTIM,0.01ESEL,S,MAT,3NSLE,SD,ALL,TEMP,20ESEL,S,MAT,2NSLE,SD,ALL,TEMP,500ESEL,S,MAT,1NSLE,SD,ALL,TEMP,400ALLSELSOLVETIME,3600TIMINT,ONDELTIM,50,10,200 AUTOTS,ON DDELET,ALL,TEMP OUTRES,ALL,ALLSOLV
50、ESAVEFINISH/POST26NSOL,2,106,TEMP,TEMP_106 PLVAR,2FINISHAnsys 综合实例31第 22 例 在结构上直接施加温度载荷进行热应力分析实例一双金属簧片/CLEAR/FILNAME,EXAMPLE22/PREP7ET,1,SOLID186MP,EX,1,2E11MP,NUXY,1,0.3MP,ALPX,1,10E-6MP,EX,2,1.1E11MP,NUXY,2,0.34MP,ALPX,2,16E-6BLOCK,0,0.04,0,0.0005,0,0.005BLOCK,0,0.04,0.0005,0.001,0,0.005VGLUE,ALLM
51、SHKEY,1MSHAPE,0ESIZE,0.0005VATT,1,1,1VMESH,3VATT,2,1,1VMESH,1FINISH/SOLUDA,5,ALLDA,16,ALLBFV,ALL,TEMP,100TREF,0SOLVEFINISH/POST1PLDISP,2FINISHAnsys 综合实例32第 23 例热应力分析(间接法)实例一液体管路/CLEAR /FILNAME,EXAMPLE23/PREP7ET,1,77,1 MP,KXX,1,70 MP,KXX,2,0.02 RECTNG,0.14,0.15,0,1RECTNG,0.15,0.2,0,1 AGLUE,ALLESIZE,0
52、.01MSHKEY,1 MSHAPE,0AATT,1,1,1 AMESH,1AATT,2,1,1 AMESH,3 FINISH/SOLUSFL,4,CONV,1,70 SFL,6,C0NV,0.5,-40 SOLVEFINISH/PREP7ETCHG,TTSKEYOPT,1,3,1 MP,EX,1,2E11 MP,NUXY,1,0.3 MP,ALPX,1,1.2E-5MP,EX,2,2E10 MP,NUXY,2,0.4 MP,ALPX,2,1.2E-6 FINISH/SOLUDL,1,UYDL,3,UYDL,9,UYDL,10,UY SFL,4,PRES,3E5 LDREAD,TEMP,RTH
53、 TREF,20SOLVE FINISH/POST1PLNSOL,S,EQVFINISH第 24 例热应力分析(直接法)实例一液体管路本例提示介绍了利用直接法进行热应力计算的方法和步骤。与间接法相比 直接法步骤更简洁,但要使用耦合单元进行非线性分析,计算容量较大。/CLEAR/FILNAME,EXAMPLE24/PREP7ET,1,13,4,1MP,KXX,1,70MP,EX,1,2E11MP,NUXY,1,0.3MP,ALPX,1,1.2E-5MP,KXX,2,0.02MP,EX,2,2E10MP,NUXY,2,0.4MP,ALPX,2,1.2E-6RECTNG,0.14,0.15,0,1R
54、ECTNG,0.15,0.2,0,1AGLUE,ALLAnsys 综合实例33ESIZE,0.01MSHKEY,1MSHAPE,0AATT,1,1,1AMESH,1AATT,2,1,1AMESH,3FINISH/SOLUSFL,4,CONV,1,70SFL,6,C0NV,0.5,-40DL,1,UYDL,3,UYDL,9,UYDL,10,UYSFL,4,PRES,3E5TREF,20SOLVEFINISH/POST1PLNSOL,S,EQVFINISHAnsys 综合实例34第六章综合应用第 25 例用物理环境法进行流体结构耦合分析实例一液压缸本例提示通过本例介绍了利用物理环境法对流体一结构耦
55、合问题进行分 析的方法和步骤。从本例读者可以了解物理环境文件的内容、创建和读取方法, 了解在不同物理环境间数据、载荷的传递方法。YECEW皿代矣*KUiO/CLEAR/FILNAME,EXAMPLE25/CONFIG,NRES,2000!创建包括结构和流体区域的完整有限元模型*/PREP7SHPP,OFFET,1,FLUID141,1ET,2,PLANE42,1RECT,0,0.25,0,0.005RECT,0,0.25,0.005,0.3RECTNG,0,0.25,0.3,1AGLUE,ALLLESIZE,13,0.03,.4!设定线上单元尺寸控制LESIZE,14,0.03,.4ESIZE
56、,0.01!设定总体单元尺寸控制MSHAPE,0 选择单元形状为四边形MSHKEY,1 映射网格AATT,2,2,2!指定单元属性AMESH,1 对活塞矩形面划分网格AATT,1,1,1AMESH,4,5 对流体矩形面划分网格ALLS!选择所有FINI!退出前处理器ANJON U点M11I40J03. .Bi -|小I訓耶甲J |Il nr I I I I巾训平肿讪!I fu叩ITiPPi M 济体速度分布Ansys 综合实例35/PREP7ET,1,141,1ET,2,0FLDATA1,S0LU,FL0W,1FLDA,S0LU,TURB,1FLDATA4,TIME,GLOB,20FLDA,P
57、ROT,DENS,CONSTANTFLDA,PROT,VISC,CONSTANTFLDA,NOMI,DENS,1000 FLDA,NOMI,VISC,0.001NSEL,S ,L OC,Y,1NSEL,R, LOC,X,0.05,0.25LSEL,S,13,15,2NSLL,A,1D,ALL,VX,0D,ALL,VY,0NSEL,S ,L OC,Y,1NSEL,R ,L OC,X,0.05,0D,ALL,PRES,0ALLSLSEL,S,14,16,2NSLL,S,1D,ALL,VXALLSFINISAVE 保存数据库文件PHYSICS,WRITE,FLUID,FLUIDPHYSICS,CLE
58、ARFINI/PREP7ET,1,0ET,2,PLANE42,1MP,EX,2,2.0E11!定义结构分析的材料模型;弹性模量MP,DENS,2,7800E-9MP,PRXY,2,0.3!泊松比ASEL,S,1!选择结构上所有节点NSLA,S,1D,ALL,UX!约束 X 方向自由度ALLSFINI/SOLUANTYPE,TRA N 瞬态分析KBC,0!斜坡载荷LNSRCH,ONOUTRES,ALL,ALL 输出控希 9NSUBST,10,20,5FINISAVEAnsys 综合实例36PHYSICS,WRITE,STRUC,STRUCPHYSICS,CLEAR! 定义参幺组*LSEL,S,3
59、!选择结构、流体分界线上节点NSLL,S,1*GET,N0DE_C0UNT,N0DE,0,C0UNT*GET,NODE_MAX,NODE,0,NUM,MAX*GET,NODE_MIN,NODE,0,NUM,MIN*DIM,VXX,ARRAY,NODE_COUNT*DIM,VYY,ARRAY,NODE_COUNT*DIM,NODE_NUM,ARRAY,NODE_COUNTALLSDISMIN0=0 分界线节点位移最小值变量赋初值DISMIN1=0 分界线节点位移最小值变量赋初值TIME=0.0002!分析时间V=3!活塞速度*DO,K,1,50PHYSICS,READ,STRUC/SOLU!进入
60、求解器*IF,K,GT,1,THENLSEL,S,3NSLL,S,1ESEL,S,TYPE,2!选择结构单元LDREAD,PRES,LAST,RFLALLS*ENDIFLSEL,S,2!选择活塞上 2 号线所有节点NSLL,S,1D,ALL,UY,V*TIME!施加位移载荷ALLSELTIME,TIME!指定分析时间SOLVE 解 答FINI!迭代收敛检查-/POST1SET,LAST 读最后载荷子步结果到数据库LSEL,S,3!选择结构、流体分界线上节点NSLL,S,1III=1NSORT,U,Y,0,1!对节点位移排序*GET,DISMIN1,SORT,0,MIN*IF,ABS(DISMI
温馨提示
- 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
- 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
- 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
- 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
- 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
- 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
- 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
最新文档
- 2025赤峰市林西县招聘14名专职消防员模拟笔试试题及答案解析
- 深度解析(2026)《GBT 26831.5-2017社区能源计量抄收系统规范 第5部分:无线中继》(2026年)深度解析
- 深度解析(2026)《GBT 26020-2010金废料分类和技术条件》(2026年)深度解析
- 2025云南昆明市第三人民医院“凤凰引进计划”高层次人才招引考试笔试备考题库及答案解析
- 2025年12月江苏南京江北新区教育局所属部分事业单位招聘教师20人参考考试试题及答案解析
- 2025甘肃中兰能投有限公司贵州分公司招聘备考考试试题及答案解析
- 2025天津市西青经开区投资促进有限公司第二批次招聘工作人员3人考试笔试备考题库及答案解析
- 锦江区新兴领域党建工作专员招募(20人)参考考试题库及答案解析
- 2025安徽淮北濉溪县龙华高级中学教师招聘20人备考笔试题库及答案解析
- 2025重庆大学高端装备机械传动全国重点实验室科研团队劳务派遣技术人员招聘考试参考试题及答案解析
- 2025中原农业保险股份有限公司招聘67人笔试备考重点试题及答案解析
- 2025中原农业保险股份有限公司招聘67人备考考试试题及答案解析
- 2025年度河北省机关事业单位技术工人晋升高级工考试练习题附正确答案
- 交通运输布局及其对区域发展的影响课时教案
- 2025年中医院护理核心制度理论知识考核试题及答案
- GB/T 17981-2025空气调节系统经济运行
- 比亚迪储能项目介绍
- 2025 年高职酒店管理与数字化运营(智能服务)试题及答案
- 2025年9月广东深圳市福田区事业单位选聘博士11人备考题库附答案
- 糖尿病足溃疡VSD治疗创面氧自由基清除方案
- 《公司治理》期末考试复习题库(含答案)
评论
0/150
提交评论