模块化程序设计1411班李睿尹伊君孙浩然

1、模块化程序设计（成绩管理）土木类1411班 李睿 0121406261127 尹伊君 0121406261125 孙浩然 0121406261128实验要求：要求输入不超过35个学生的学号及成绩，对这些成绩进行管理。1. 输入学号及成绩2. 找出最高分3. 求出平均分4. 对成绩进行排序5. 对成绩进行等级评估6. 根据学号查找某一个学生的成绩程序实现编程 （二维数组）#include<stdio.h>#include<conio.h>#dcfinc n 35void input (int score2, int n);void output (int score2,

2、int n);void sort (int score2, int n);int max(int score2, int n);float average (int score2, int n);void stat(int score2, int n);void find (int score2, int n)int i;for(i=0;i<n;i+)if(scorci0=n)printf ("id=%d, score=%ct, n, scorei1);void main () int scoren2, choice;int n;printfc欢迎进入学生成绩管理系统n)； p

3、rintf (学生人数:);scanf (d, &n);printfc输入学生学号及成绩n)；input (score, n);doprintf c 1. maxn，z);printf (“2. averagen/z);printf (，z3. sortn)；printf c 4. statistic analysisnz/);printf (“0.exit");printf (/zyour choice is(0-4):)；seanf (%d, &choice);swi tch(choice)case 0:printf cexit!“);break;case 1:

4、printf (max=%dmax (score, n) ; break;case 2:printf (“average=%. 2fn，average(score, n) ;break;case 3:sort (score, n);printf("sorted:);output(score, n);break;case 4:stat(score, n);break;default:printf (，zerror choice, try againn)；while(choice!=0);printf (zzn输入要查找学生的学号:)；scanf (d，&n);find(scor

5、e,n);getch();void input(int score2, int n) int i;for(i=0;i<n;i+) scanf(d%d", &scorei0,&scorei1); void output(int scorc2, int n)int i;for(i=0;i<n;i+)printf (，%d%5d/，, scorei 0, scorei 1) ;printf (n)；void sort(int score2, int n) int i, j, t;for(i=0;i<nl;i+)for(j=0;j<n-i-l;j+)i

6、f (scorej1<scorej+l 1) t=scorej1;scorejl=scorej+1 1;scorej+ll=t;int max(int scorc2, int n) int i, m=score0 1;for (i=l;i<n;i+)if (m<scorei 1)m二scorei 1;rcturn m;float average(int score2, int n)int i,sum=0;for(i=0;i<n;i+)sum+=scorci 1;return (float)sum/n;void stat (int score2, int n) int i

7、;int a, b, c, d;a=b=c=d=o;for(i=0;i<n;i+) if (scorei1>=85)a+;else if(scoreil>=70)b+;else if(scorei1>=60)c+;else if(scorei1<60)d+;printf c等级： a (>=85) b (>=70) c 0=60) d «60) n，z);printf(z，n)；printf (，z人数：%2d%2d%2d%2dn，a, b, c, d);printf (/z所占百分比： %4. if%4. if%4. if%4. lfn，(

8、float)a/n*100,(float)b/n*100, (float)c/n*100, (float)d/n*100);运行结果欢迎进入学生成绩管理系统学生人数：6输入学生学号及成绩1234j6556857896981 .max2. auerage3. sort4. statistic analysis0.exityour choice is<0-4>：1max=981 .nax2. average3. sort4. statistic analsfsisb.exityour choice is<0-4>：2average =79.671 .nax2. averag

9、e3. sort4. statistic analysis0.exityour choice is<0-4>：3sorted：! 982963854785656561 .max2. average3. sort4. statistic analsis0.exityour choice is<0-4>：4等级： a<>=85>b<>=70>c<>=60>d«60>人数：听占百分比：1 .max2. average3. sort4. statistic350.0116.7116.7116.7analysi

10、sscore=85q.exityour choice is<0-4：0 exit? ? 输入要查找学生的学号：3 id=3,模块解释主函数部分 (小组成员共同完成)#include<stdio. h>#include<conio. h>define n 35 void main() int scoren2, choice;int n;printfc欢迎进入学生成绩管理系统)；printf ("学生人数:”);scanf ("%d： &n); printfc输入学生学号及成绩n);input (score, n);do printf (，

11、z1. maxn，z);printf (，z2. avcragcnz，);printf (，z3. sortn，z);printf (，z4. statistic analysisn，z);printf c 0.exit");printf(，zyour choice is(0-4):)；seanf ("%d", &choice);switch(choice) case 0:printf (z，exit! !“);break;case 1:printf (“max=%dn", max (score, n) ;break;case 2: printf

12、 (，zaverage=%. 2frt, average (score, n) ; break;case 3:sort (score, n);printf("sorted:);output (score, n);break;case 4:stat (score, n);break;default:printf (，zerror choice, try againn)；while(choice!=0);printf (zzn输入要查找学生的学号:)；scanf (d，&n);find(score,n);gctcho ;函数声明部分void input (int scorc2,

13、int n);void output (int score2, int n);void sort (int score2, int n);int max(int score2, int n);float average(int score2, int n);void stat (int scorc2, int n);学号及成绩输入输出模块 void input(int scorc2, int n) int i;for(i=0;i<n;i+) scanf(d%d", &scorei0, &scorei1); void output(int score2, int

14、n)int i;for(i=0;i<n;i+)printf (d%5d", scorei0, scorei1) ;printf (n)；成绩排序模块void sort (int score2, int n)int i, j, t;for (i=0;i<n-l;i+)for (j=0;j<n-i-l;j+)if (scorej1<scorej+l1) t=scorej1;scorej1二scorej+l1;scorej+ll=t;找出最高分模块int max(int score2, int n) int i, m=scorc01;for(i=l;i<n;i

15、+)if(m<scorei 1)m=scorei 1;return m;求平均数模块float average (int score2, int n)int i,sum二0;for(i=0;i<n;i+)sum+=scorei 1;return (float)sum/n;成绩评估模块void stat (int score2, int n)int i;int a, b, c, d;a=b=c=d=o;for(i=0;i<n;i+) i f (scorei1>=85)a+；else if(scoreil>=70)b+;else if(scorei1>=60)c+;else if(scorei1<60)d+;printf c等级： a (>=85) b (>=70) c 0=60) d «60) n，z);printf(z，n)；printf (，z人数：%2d%2d%2d%2dn，a, b, c, d);printf (/z所占百分比： %4. if%4. if%4. if%4. lfn，(float)a/n*100,(float)b/n*100