VB程序设计编程考试题及答案

1、vb程序设计编程考试题及答案1. 输入3个数，输出最大的数private sub command1_click()dim maxfor i = 1 to 3n = val(inputbox("输入第" & i & "个数")if n > max thenmax = nend ifnextprint "三个数中最大的数是" ; maxend sub2. 有一元二次方程：ax2+bx+c=0，依次输入a，b，c，判断此方程是否有实根private sub command1_click()dim a, b, c, na

2、 = text1b = text2c = text3n = b * b - 4 * a * cif n >= 0 thenlabel4 = "方程有根" else label4 = "方程无根"end ifend sub3. 输入一个百分制的成绩，若大于等于60，则用消息框弹出，显示“恭喜！成绩通过！”，若小于60，则弹出消息框，显示“抱歉！成绩没有通过！private sub form_load()text1 = ""end subprivate sub command1_click()dim nn = text1if n &

3、gt; =60 thenval (msgbox("恭喜！成绩通过！")elseval (msgbox("抱歉！成绩没有通过！")end ifend sub4. 输入一年份，判断它是否为闰年，并显示有关信息。（判断闰年的条件是：年份能被4整除但不能被100整除，或者能被400整除）private sub command1_click()dim y%y = inputbox("请输入年份")if y mod 4 = 0 and y mod 100 <> 0 or y mod 400 = 0 thenval (msgbox(&q

4、uot;闰年！")elseval (msgbox("平年！")end ifend sub5. 输入学生的百分制成绩，转换输出为五级制成绩，90100分转换为优秀，8089转换为良好，7079转换为中等，6069转换为及格，060转换为不及格。private sub command1_click()a = val(inputbox("请输入成绩")if a > 100 then print "超出范围"if a >= 90 and a <= 100 then print "优秀"if a

5、>= 80 and a < 90 then print "良好"if a >= 70 and a < 80 then print "中等"if a >= 60 and a < 70 then print "及格"if a < 60 then print "不及格"end sub6. 随机产生一个三位正整数，然后逆序输出，产生的数与逆序数同时显示。例如，产生246，输出是642。private sub command1_click()dim x%, x1%, x2%, x3%

6、x = text1x1 = x mod 10x2 = (x mod 100) 10x3 = x 100label1 = x1 * 100 + x2 * 10 + x3end sub7. 输入两个整数，求它们的最大公约数。private sub command1_click() n1 = inputbox("输入n") m1 = inputbox("输入m") if m1 > n1 then m = m1: n = n1 else m = n1: n = m1 end if r = m mod n do while r <> 0 m =

7、n n = r r = m mod n loopprint "m n 的最大公约数是：" nend sub8. 编程求200-400范围内5的倍数或7的倍数之和。(一个数如果同时是7和5的倍数，则只能加一次。private sub command1_click()for i = 200 to 400if i mod 5 = 0 or i mod 7 = 0 thensum = sum + iend ifnext ifor i = 200 to 400if i mod 5 = 0 and i mod 7 = 0 thensum = sum - iend ifnext ipri

8、nt “倍数之和=”; sumend sub9. 计算100300之间所有能被3和7整除的数之和private sub command1_click()dim isum = 0for i = 100 to 300if i mod 3 = 0 and i mod 7 = 0 thensum = sum + iend ifnext iprint sumend sub10. 分别统计1-100中，满足3的倍数、7的倍数的数各有多少。private sub command1_click()dim i, s3, s7s3 = 0s7 = 0for i = 1 to 100if i mod 3 = 0 t

9、hens3 = s3 + 1end ifnext ifor i = 1 to 100if i mod 7 = 0 thens7 = s7 + 1end ifnext iprint "3的倍数" s3print "7的倍数" s7end sub11. 某次歌曲大奖赛，有7个评委。如果分别输入7个评委对某个参赛者的打分数，按照去掉一个最高分和一个最低分的计算办法，求出该参赛者的平均得分。private sub command1_click()dim max, a(1 to 7), min, sfor i = 1 to 7a(i) = val(inputbox

10、("输入第" & i & "个数")next imax = a(1)min = a(1)s = a(1)for i = 2 to 7if a(i) > max then max = a(i)if a(i) < min then min = a(i)s = s + a(i)next is = s - min - maxs = s / 5print "平均分" send sub12. 输入一串字符，统计其中字母a(不区分大小写)出现的次数。private sub command1_click()dim c as

11、 string, a as integerb = inputbox("请输入字符")for i = 1 to len(b) c = ucase(mid(b, i, 1) if c = "a" then a = a + 1 end if next i print "a出现的次数：" aend sub13. 我国目前有13亿人口，按人口年增长率0.8%计算，多少年后我国人口将超过26亿。private sub command1_click()dim a, ia = 13i = 0do while a < 26 a = a * (1.

12、008)i = i + 1loopprint iend sub14. 小猴有桃若干，第一天吃掉一半多一个；第二天吃剩下桃子的一半多一个；以后每天都吃尚存桃子的一半多一个，到第7天只剩一个，问小猴原有桃多少？private sub command1_click()dim a, ia = 1for i = 1 to 6a = 2 * (a + 1)next iprint "小猴原有桃" a;”只”end sub15. 求100以内的素数private sub command1_click()dim i, jfor i = 2 to 100for j = 2 to i - 1if

13、 i mod j = 0 then exit fornext jif j = i then print inext iend sub16. 百元买百鸡问题。假定小鸡每只5角，公鸡每只2元，母鸡每只3元，编程求解购鸡方案。private sub command1_click()print "小鸡" " " "母鸡" " " "公鸡"print ""for x = 1 to 100for y = 1 to 100for z = 1 to 100if 0.5 * x + 2 * y

14、 + 3 * z = 100 thenprint "" x; " " y; " " zend ifnext znext ynext xend sub17. 编程求斐波那契数列前11项。（斐波那契数列：f(0)=f(1)=1, f(n)=f(n-1)+f(n-2) n>=2 ）private sub command1_click()dim f(11), i as longf(0) = 1f(1) = 1for i = 2 to 10f(i) = f(i - 1) + f(i - 2)next ifor i = 0 to 11pri

15、nt f(i);next iend sub18. 将输入的字符串以反序显示。例如：输入“asdfgt”，显示“tgfdsa”private sub command1_click()dim a, b, c, d, na = inputbox("输入字符串")n = len(a)for b = 1 to int(n 2)c = mid(a, b, 1)mid(a, b, 1) = mid(a, n - b + 1, 1) mid(a, n - b + 1, 1) = cnext bprint aend sub19. 随机产生10个30,100内的整数，求最大值及所对应的下标pr

16、ivate sub command1_click()dim a(1 to 10), mrandomizefor i = 1 to 10a(i) = int(rnd * 71) + 30print a(i)next imax = a(1)for i = 2 to 10if a(i) > max then max = a(i): m = inext iprint "max=" maxprint "max的下标为" mend sub20. 随机产生10个30,100内的整数，求最大值、最小值和平均值。private sub command1_click(

17、)dim a(1 to 10)for i = 1 to 10a(i) = int(rnd * 71) + 30print a(i)next imax = a(1)min = a(1)avg = a(1)for i = 2 to 10if a(i) > max then max = a(i)if a(i) < min then min = a(i) avg = avg + a(i)next iavg = avg / 10print "max=" maxprint "min=" minprint "avg=" avgend s

18、ub 21. 随机产生10个30,100内的整数，求最小值及所对应的下标。private sub command1_click()dim a(1 to 10), mrandomizefor i = 1 to 10a(i) = int(rnd * 71) + 30print a(i)next imin = a(1)for i = 2 to 10if a(i) < min then min = a(i): m = inext iprint "min=" minprint "min的下标为" mend sub22. 随机生成一个整型的二维数组，范围在10

19、,20之间，以下三角形式输出该数组。private sub command1_click()dim a(1 to 10, 1 to 10), i, j as integerfor i = 1 to 10for j = 1 to 10a(i, j) = int(rnd *11 + 10)nextnextfor i = 1 to 10for j = 1 to iprint spc(3); a(i, j);nextprintnextend sub23. 随机产生10个1100的正整数放入数组，显示产生的数，求最大值、最小值、平均值。private sub command1_click()dim a(

20、1 to 10)for i = 1 to 10a(i) = int(rnd * 101) + 1print a(i)next imax = a(1)min = a(1)avg = a(1)for i = 2 to 10if a(i) > max then max = a(i)if a(i) < min then min = a(i) avg = avg + a(i)next iavg = avg / 10print "max=" maxprint "min=" minprint "avg=" avgend sub24. 利

21、用随机函数生成一个4×4的矩阵(即二维矩阵),范围是20,50内的整数,输出该矩阵所有数据之和private sub command1_click()dim a%(4, 5), sumfor i = 1 to 4for j = 1 to 4a(i, j) = int(rnd * 31) + 20print a(i, j);sum = sum + a(i, j)next jprint '换行next iprint "sum=" sumend sub25. 已知有序数组a()，编程插入x（x的值为14）。数组a中的元素分别为12，6，4，89，75，63，10

22、0，20，31。private sub command1_click()dim a(), i%, k%, x%, n%a = array(4, 6, 12, 20, 31, 63, 75, 89, 100)n = ubound(a)x = val(inputbox("请输入所要插入数")for k = 0 to nif x < a(k) then exit fornext kredim preserve a(n + 1)for i = n to k step -1a(i + 1) = a(i)next ia(k) = xfor i = 0 to n + 1print

23、a(i);next iend sub26. 编写一函数，计算double类型一维数组所有元素的平均值。27. 编一子过程procmin,求一维数组a中的最小值，子过程的形参自己确定private sub command1_click()dim a(1 to 10), min, i%for i = 1 to 10a(i) = int(rnd * 101)print a(i);next icall procmin(a(), min)printprint "min =" minend sub sub procmin(b(), min)dim i%min = b(lbound(b)for i = lbound(b) + 1 to ubound(b)if b(i