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1、2013-2014学年安徽省宿州市泗县中学七年级(下)第一次月考试卷一、选择题(每小题3分,共30分)1下列运算正确的是()aa2a3=a6b(x5)2=x7c(-3c)2=9c2d(a-2b)2=a2-2ab+4b2显示解析2下列式子中,不成立的是()a2x23x=6x3b(-6x4)(3x2)=-18x6c(2x+1)(2x-1)=2x2-1d(12ab2c3)214a2b4c6显示解析3若a2b214,ab12,则a+b的值为()a12b12c1d2显示解析4计算:(19)201392014=()a19b9c1d94027显示解析5利用平方差公式计算20122-20132011的结果是(

2、)a-1b1c-2d2显示解析6已知(x+a)(x+b)=x2-11x+18,则a+b的值是()a-11b11c-18d18显示解析7方程x(x-3)+2(x-3)=x2-8的解为()ax=2bx=-2cx=4dx=-4显示解析8将正方形的边长由acm增加6cm,则正方形的面积增加了()a36cm2b12acm2c(36+12a)cm2d以上都不对显示解析9已知x+1x2,则下列等式成立的有()x2+1x22;x4+1x42;x8+1x82;x1x0abcd显示解析10如图在边长为a的正方形中挖掉一个边长为b的小正方形(ab),把剩下的部分拼成一个矩形,通过计算两处图形的面积,验证了一个等式,

3、此等式是()aa2-b2=(a+b)(a-b)b(a+b)2=a2+2ab+b2c(a-b)2=a2-2ab+b2d(a+2b)(a-b)=a2+ab+b2显示解析二、填空题(每小题3分,共24分)11有一道计算题:(-a4)2,李老师发现全班有以下四种解法,(-a4)2=(-a4)(-a4)=a4a4=a8;(-a4)2=-a42=-a8;(-a4)2=(-a)42=(-a)8=a8;(-a4)2=(-1a4)2=(-1)2(a4)2=a8;你认为其中完全正确的是(填序号)显示解析12若(am+1bn+2)(a2n-1b2m)=a3b5,则m+n的值是显示解析13如果单项式-4x2ay2与1

4、4x4y3a2b是同类项,则这两个单项式的积为显示解析14已知长方体长为4102毫米,宽为3102毫米,高为2102毫米,这个长方体的体积是立方毫米显示解析15已知10m=2,10n=3,则103m+2n=显示解析16若m+4n-2=0,则3m81n=显示解析17已知2x+y=1,代数式(y+1)2-(y2-4x)的值为显示解析18如图所示,正方形abcd和正方形cefg的边长分别为a、b,如果a+b=17,ab=60,那么阴影部分的面积是显示解析三、解答题(共66分)19计算(1)(a-2)2+4(a-1)(2)(a+2)(a+2)-a(a+1)(3)(a-b-1)(a+b-1)(4)(x+

5、2y)2(x-2y)显示解析20解下列方程(组)(x+3)2-2(x-3)(x+2)+(x-2)2=5显示解析21化简,求值(1)先化简,再求值:(x+3)(x-3)-x(x-2),其中x=4;(2)先化简,再求值:(2a-b)2-b2,其中a=2,b=3;(3)已知210=a2=4b,化简(14a+15b)(14a15b)(14a+15b)2,并求值显示解析22已知x3m=4,y3n=5,求:(x2m)3+(yn)3-x2mynx4my2n的值显示解析23(1)多项式a2+b2-4a+6b+13=0,求a+b值(2)已知(x+y)2=25,(x-y)2=9,求xy与x2+y2的值显示解析24

6、观察下列等式:32-12=8=81;52-32=16=82;72-52=24=83;92-72=32=84这些等式反映了正整数的某种规律(1)设n为正整数,试用含m的式子,表示你发现的规律;(2)验证你发现规律的正确性,并用文字归纳出这个规律显示解析25小明将一个底为正方形,高为m的无盖盒子展开,如图所示,测得其边长为n,(1)请你计算无盖纸盒的表面展开图的面积s1(即图中阴影部分的面积)(2)将阴影部分拼成一个长方形如图所示,这个长方形的长和宽分别是多少?面积s2是多少?(3)比较(1)、(2)的结果,你得出什么结论?显示解析26下列运算正确的是()a3x-2x=1b(-2a+1)2=4a2

7、+4a+1c(-a)2a3=a6d(-a2)3=-a6显示解析27下列各式中,与(a-1)2相等的是()aa2-1ba2-2a+1ca2-2a-1da2+1显示解析28下列运算正确的是()ax3x4=x12b(-6x6)(-2x2)=3x3c2a-3a=-ad(x-2)2=x2-4显示解析29计算(-x)2x3所得的结果是()ax5b-x5cx6d-x6显示解析30计算(ab2)3的结果是()aab5bab6ca3b5da3b6显示解析31下列式子中是完全平方式的是()aa2+ab+b2ba2+2a+2ca2-2b+b2da2+2a+1显示解析32下列各式计算正确的是()a2a2+a3=3a5

8、b(3xy)2(xy)=3xyc(2b2)3=8b5d2x3x5=6x6显示解析333(x3)2(y2)3(13xy)=显示解析34若a2+a=0,则2a2+2a+2007的值为显示解析35一个长方形的面积是(x2-9)平方米,其长为(x+3)米,用含有x的整式表示它的宽为米显示解析36先化简,再求值:(a+b)(a-b)+b(b-2),其中a=-1,b=1显示解析37若a0且ax=2,ay=3,则ax-y的值为()a-1b1c23d32显示解析38已知x+y=-5,xy=6,则x2+y2的值是()a1b13c17d25显示解析39定义.abcd.=ad-bc,上述记号就叫做2阶行列式若.x+

9、1x11xx+1.=6,x=显示解析40计算:(-2a-2)3b22a-8b-3显示解析41如图,正方形卡片a类,b类和长方形卡片c类若干张,如果要拼一个长为(a+2b),宽为(a+b)的大长方形,则需要c类卡片张 tgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgk tgz7r4i30ka1dkaghn3xtk

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12、hn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92

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15、chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2tgz7

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17、fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav

18、2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2eo8wgqv7xav2ohum32wgeauwydiawger4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3

19、xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgk

20、qcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkaggeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkag

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22、gkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav hhi92tgkqcw

23、a3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydia

24、wger4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3p

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