Matlab练习及答案(最新整理)

1、matlab 练习一1、一个三位整数各位数字的立方和等于该数本身，则称该数为水仙花数。试编写程序找到并输出全部水仙花数。2、若一个数等于它的各个真因子之和，则称该数为完数，如6=1+2+3，所以6 是完数。求1 500之间的全部完数。3、写一个函数pifun 计算下列级数：f(n)=4*(1-1/3+1/5-1/7+.)并使用tic 和toc 指令来测量pifun(1000000)的计算时间。4、输入一个百分制成绩，要求输出成绩等级为ae，即90100 为a，8089 为b，7079 为c，6069 为d，60 以下为e。5、输入x,y 的值，并将它们的值互换后输出。6、某商场对顾客所购买的商

2、品实行打折销售，标准如下(商品价格用price 来表示)： price200 没有折扣；200price500 3%折扣；500price1000 5%折扣； 1000price2500 8%折扣；2500price=90 & a=80 & a=70 & a=60 & a=0 & a60 disp(e); elsedisp(输入数据有误，请核对);end end endendend5x = input(x=);y = input(y=);disp (x,y); t=x;x=y; y=t;disp (x,y);6.x=input(price:) if x200f=x;else if x500f=

3、x*0.97; else if x1000f=x*0.95;else if x2500 f=x*0.92;else if x0.5 ai=i; aj=j; aij=i,jendendend8.sum=0;for m=1:10 i=1;for n=1:mi=i*n;end sumend sum=sum+i;10.a=zeros(1,10); for i=1:10a(i)=input(please enter number);endfor i=1:10if (rem(a(i),7)=0) a(i)breakendendif (i=0&rem(a(i),7)=0) disp(not exist)en

4、d“”“”at the end, xiao bian gives you a passage. minand once said, people who learn to learn are very happy people. in every wonderful life, learning is an eternal theme. as a professional clerical and teaching position, i understand the importance of continuous learning, life is diligent, nothing ca

5、n be gained, only continuous learning can achieve better self. only by constantly learning and mastering the latest relevant knowledge, can employees from all walks of life keep up with the pace of enterprise development and innovate to meet the needs of the market. this document is also edited by my studio professionals, ther