微机原理上机作业_编写8086汇编程序_将寄存器AX的高8位传送到寄存

1、.上机作业1、 编写8086汇编程序，将寄存器AX的高8位传送到寄存器BL，AX的低8位传送到寄存器DL。CODE SEGMENTASSUME CS:CODESTART:MOV BL,AH;寄存器AX的高8位传送到寄存器BLMOV DL,AL ;AX的低8位传送到寄存器DLINT 20H ;结束CODE ENDSEND START2、 将DX寄存器的内容从低位到高位顺序分成4组，且将各组数分别送到寄存器AL、BL、CL和DL。MOV AL,0MOV BL,0MOV CL,04ADD AL,DLADD BL,DLAND AL,0FHAND BL,0F0HSHL BL,CLMOV CL,0ADD

2、CL,DHADD DL,DHAND CL,0FHAND DL,0F0HMOV AH,CLMOV CL,4SHL DL,CLMOV CL,AH3、 判断MEN单元的数据，编程将奇数存入MENA单元，将偶数存入MENB单元。DATAS SEGMENTMEN DW 11H,12H,13H,14H,15H,16HMENA DW 5 DUP (?)MENB DW 5 DUP (?)DATAS ENDSCODES SEGMENTASSUME CS:CODES,DS:DATASSTART:MOV AX,DATASMOV DS,AXMOV CX,6MOV SI,OFFSET MENAA1: MOV BX,SI

3、INC SITEST BX,0001HJZ AA2MOV MENA,BXLOOP AA1AA2:MOV MENB,BXINC SILOOP AA1MOV AH,4CHINT 21HCODES ENDSEND START4、 试统计9个数中的偶数的个数，并将结果在屏幕上显示。DATAS SEGMENTDATA DB 1,4,5,13,16,21,28,35,41;DATAS ENDSSTACKS SEGMENT;STACKS ENDSCODES SEGMENTASSUME CS:CODES,DS:DATAS,SS:STACKSSTART: MOV AX,DATASMOV DS,AXMOV CX,

4、9MOV DX,0LEA SI,DATAPANDUAN:MOV AL,SISHR AL,1JC NEXTINC DLNEXT:INC SILOOP PANDUANCMP CX,0JNZ PANDUANMOV AH,02HADD DL,30HINT 21H;MOV AH,4CHINT 21HCODES ENDSEND START5、 试将一串16位无符号数加密，加密方法是将每个数乘2。DATAS SEGMENTSTRING1 DB 1234567891234567$STRING2 DB 16 DUP(?)DATAS ENDSCODES SEGMENTASSUME CS:CODES,DS:DATA

5、SSTART: MOV AX,DATASMOV DS,AXMOV ES,AXMOV CX,16LEA SI,STRING1LEA DI,STRING2L:LODSBSHL AL,1STOSBLOOP LMOV AH,4CHINT 21HCODES ENDSEND START6、 根据DL寄存器的D3位，完成两个压缩BCD数X和Y的加减运算。D3=0时，作加法；D3=1时，作减法，并将结果存入寄存器DL。DATAS SEGMENTX DB 2Y DB 1DATAS ENDSSTACKS SEGMENTSTACKS ENDSCODES SEGMENTASSUME CS:CODES,DS:DATAS

6、,SS:STACKSSTART:MOV AX,DATASMOV DS,AXMOV AL,YTEST DL,08HJZ JIASBB AL,XDASJMP JIANJIA: ADC AL,XDAAMOV DL,ALJMP LOPJIAN: MOV DL,ALJMP LOPLOP:MOV AH,02HADD DL,30HINT 21HMOV AH,4CHINT 21HCODES ENDSEND START7、 统计BLOCK1和BLOCK2两个单元数据中，对应位不同的有多少位？DATAS SEGMENTBLOCK1 DB 123456789BLOCK2 DB 987456123DATAS ENDS

7、STACKS SEGMENTSTACKS ENDSCODES SEGMENTASSUME CS:CODES,DS:DATAS,SS:STACKSSTART: MOV AX,DATASMOV DS,AXMOV BX,0MOV CX,9LEA SI,BLOCK1LEA DI,BLOCK2LOP: LODSBCMP AL,DIJE NEXTINC BXNEXT:INC DIDEC CLJNZ LOPMOV AH,2ADD BL,30HMOV DL,BLINT 21H;MOV AH,4CHINT 21HCODES ENDSEND START8、 完成10个压缩BCD数相加，且将结果显示出来。DATAS

8、 SEGMENTDATA DB 0,1,2,3,4,5,6,7,8,9;DATAS ENDSSTACKS SEGMENTSTACKS ENDSCODES SEGMENTASSUME CS:CODES,DS:DATAS,SS:STACKSSTART:MOV AX,DATASMOV DS,AXMOV CX,10LEA SI,DATAMOV AL,0LOP:ADC AL,SIDAAJMP NEXTNEXT:INC SILOOP LOPMOV CL,4MOV BL,ALSHR AL,CLMOV AH,02HADD AL,30HMOV DL,ALINT 21HAND BL,0FHMOV AH,02HADD BL,30HMOV DL,BLINT 21HMOV AH,4CHINT 21HCODES ENDSEND START9、 编写程序，将一串凌乱的字母按从小到大的顺序排列。DATAS SEGMENTDATA DB gfed$DATAS ENDSCODES SEGMENTASSUME CS:CODES,DS:DATASSTART:MOV AX,DATASMOV DS,AXMOV SI,1LOP1: MOV DI,SIINC DIMOV AL,DATASI-1LOP2: CMP AL,DATADI-1JBE LOP3XCHG DATADI-1,ALMOV DATASI