c++程序设计钱能第二版习题解答(多解法).doc

/=/课本第23页1题。/输出“I am a student./=#includeusing namespace std;/-int main()coutI am a student.n;return 0;/=/=/课本第23页2题。/多行输出*/=#includeusing namespace std;/-int main()cout * n; cout * n; cout * n; cout*endl; cout * n; cout * n; cout * n;return 0;/=/=/练习二第01题。/计算级数。/=#include #include using namespace std;/-int main()double x;cinx;double sum = 1;double t = x;int i = 2;while (abs(t) 1e-8)sum += t;t *= (-1)*x/i;i +;cout.precision(8);coutfixedx=x, sum=sumn;return 0;/=/=/练习二第01题。/计算级数。/=#include #include using namespace std;/-int main()double x;cinx;double sum = 1;double t = x;for (int i = 2;abs(t) 1e-8;i +)sum += t;t *= (-1)*x/i;cout.precision(8);coutfixedx=x, sum=sumn;return 0;/=/=/练习二第01题。/计算级数。/=#include #include using namespace std;/-int main()double x,sum = 1,t;cinx;t = x;for (int i = 2;abs(t) 1e-8;t *= (-1)*x/i+)sum += t;cout.precision(8);coutfixedx=x, sum=sumn;return 0;/=/=/练习二第01题。/计算级数。/=#include #include #include using namespace std;/-int main()double x;cinx;double sum = 1,item = -1;for (int i = 1;abs(item) 1e-8;i +)item *= (-1)*x/i;sum += item;coutfixedsetprecision(8)x=x, sum=sumn;return 0;/=/=/练习二第01题。/计算级数。/函数版。/=#include #include #include using namespace std;/-int fact(int n);/-int main()double x,sum=1,item=1,po;cinx;for(int n=1,sign=1;abs(item)1e-8;n+,sign *= -1)po= pow(x,n);item=sign*po/(fact(n);sum += item;coutjs=setiosflags(ios:fixed)setprecision(8)sumendl;return 0;/=int fact(int n)if(n=1)return(1);elsereturn(fact(n-1)*n);/=/=/练习二第02题。/1!+2!+3!+.+12!/=#include using namespace std;/-int main()int sum = 0;for(int i=1;i = 12;i +)int t = 1;for (int j = 1;j = i; + j)t = t * j;sum = sum + t;cout1!+2!+3!+.+12!=sumendl;return 0;/=/=/练习二第02题。/1!+2!+3!+.+12!/=#include using namespace std;/-int main()int sum = 0;for(int i = 1,t = 1;i = 12;t *= + i)sum += t;cout1!+2!+3!+.+12!=sumendl;return 0;/=/=/练习二第02题。/1!+2!+3!+.+n!/=#include using namespace std;/-int main()int n,s,i,t;coutn;s=0;t=1;for(i=1;i=n;i+)t *= i;s += t;cout1!+2!+3!+.+n!=sendl;return 0;/=/=/练习二第03题。/求“水仙花数”。/=#include using namespace std;/-int main()int n,a,b,c;for(n = 100;n 1000;n +)a = n/100;b = n%100/10;c = n%10;if(a*a*a + b*b*b + c*c*c = n)coutn is a narcissus number.endl;return 0;/=/=/练习二第03题。/求“水仙花数”。/=#include using namespace std;/-int main()for(int i = 1;i = 9;i +)for (int j =0;j = 9;j +)for (int k = 0;k = 9;k +)int a = 100*i + 10*j + k;if (i*i*i + j*j*j + k*k*k = a)couta is a narcissus number.endl;return 0;/=/=/练习二第04题。/求1000内“完数”。/=#include using namespace std;/-int main()int n,a,sum;for(n = 1;n = 1000;n +)for(a = 1,sum = 0;a = n/2;a +)if(!(n%a)sum += a;if(sum = n)coutn is a wanshu.endl;return 0;/=/=/练习二第04题。/求1000内“完数”。/=#include using namespace std;/-int main()for (int i = 2;i = 1000;i +)int sum = 1;for (int j = 2;j = i/2;j +)if (i % j = 0)sum += j;if (sum = i)couti is a wanshu.endl;return 0;/=/=/练习二第05题。/求3位对称素数。/=#include using namespace std;/-bool isPrime(int n)for (int i = 2;i n;+ i)if (n % i = 0)return false;return true;/-int main()for (int i = 100;i 1000;+ i)if (i/100 = i%10) & isPrime(i)couti是一个对称的素数!endl;return 0;/=/=/练习二第05题。/求3位对称素数。/=#include #include using namespace std;/-bool isPrime(int n)int m = sqrt(double(n);for (int i = 3;i = m;i += 2)if (n % i = 0)return false;return true;/-int main()for (int i = 1;i = 9;i += 2)for (int j = 0;j = 9;+ j)int k = 101*i + 10*j;if (isPrime(k)coutk是一个对称的素数!endl;return 0;/=/=/练习二第05题。/求3位对称素数。/=#include #include /包含数学运算的函数头文件using namespace std; /使用标准的命名空间/-int isPrime(int a);/判断是否为素数的函数声明/-int main()int num;int i,j,k; /i,j,k分别代表百位、十位、个位的位数for(num = 100;num 1000;num +)i = num/100;j = (num - i*100)/10;k = (num - i*100 - j*10)/1; /当然这里可以不用除以1if(i = k)&isPrime(num)coutnum是一个对称的素数!endl; /输出3位对称的素数return 0;/=int isPrime(int a)/判断是否为素数的函数定义int i,result; /result中0代表a不是素数、1代表a是素数for(i = 2;i = sqrt(a);i +)if(a%i = 0)result = 0;break;else result = 1;return result;/=/=/练习二第06题。/猴子吃桃。/=#include using namespace std;/-int main()int day,former,beh = 1;for(day = 9;day = 1;day -)former = (beh + 1)*2;beh = former;cout猴子共摘下桃子：formerendl;return 0;/=/=/练习二第06题。/猴子吃桃。/=#include using namespace std;/-int main()int peachs = 1;for(int i = 1;i 10;i +)peachs = (peachs + 1)*2;cout猴子共摘下桃子：peachsendl;return 0;/=/=/练习二第07题。/打印图形。/=#include #include using namespace std;/-int main()for(int i = 1;i = 10;i +)coutstring(10 - i, );coutstring(2*i - 1,%);cout= 1;j -)coutstring(10 -j, );coutstring(2*j - 1,%);coutn;return 0;/=/=/练习二第07题。/打印图形。/=#include #include using namespace std;/-int main()for(int i = 1,j = 1;i = 19;+ i,j = (i 10) ? i:20-i)coutstring(10 - j, );coutstring(2*j - 1,%);coutn;return 0;/=/=/练习二第07题。/打印图形。/=#include #include using namespace std;/-int main()for(int i = 1,j = 1;i = 19;+ i,j = (i 10) ? i:20-i)coutstring(10 - j, ) + string(2*j - 1,%)+n;return 0;/=/=/练习二第07题。/打印图形。/=#include #include using namespace std;/-int main()for(int n = 1;n = 10;n +)coutsetfill( )setw(11 - n) setfill(%)setw(2*n - 1)%endl;for(int m=1;m=9;m+)coutsetfill( )setw(m + 1) setfill(%)setw(19 - 2*m)%endl;return 0;/=/=/练习二第0801题。/打印图形。/=#include #include using namespace std;/-int main()for(int n = 1;n = 10;n +)coutsetfill( )setw(11-n) setfill(#)setw(n)# setfill( )setw(4) setfill($)setw(n)$endl;return 0;/=/=/练习二第0801题。/打印图形。/=#include #include using namespace std;/-int main()for(int n = 1;n = 10;n +)coutstring(10 -n, )+string(n,#)+ +string(n,$)+n;return 0;/=/=/练习二第0802题。/print STS./=#include #include using namespace std;/-int main()for(int n = 1;n = 10;+ n)/行循环coutstring(n, );/输出空格for(int i = 1;i = 21 - 2*n;+ i)/行内字符位循环if(i%2)coutS;/输出“”elsecoutT;/输出“”coutendl;return 0;/=/=/练习二第0802题。/print STS./=#include #include using namespace std;/-int main()for(int i = 1;i = 10;+ i)/行循环coutstring(i - 1, );for (int j = 1;j = 21 - 2*i;+ j)cout(j&1 ? S:T);coutn;return 0;/=/=/练习二第0802题。/print STS./=#include #include using namespace std;/-int main()for(int i = 1;i = 10;+ i)/行循环coutstring(i - 1, ) + S;for (int j = 1;j = 10 - i;+ j)coutTS;coutn;return 0;/=/=/练习二第09题。/求解母牛问题。/=#include using namespace std;/-int main()int c = 1,n;coutn;for (int i = 4,a = 1,b = 1,temp;i = n;i +)temp = a + c;a = b;b = c;c = temp;coutn year later,there are cows: cendl;return 0;/=/=/练习二第09题。/求解母牛问题。/=#include using namespace std;/-int main()int n, a = 1, b = 1, sum = 1, temp;/定义变量 coutn;/输入n for(int i = 4; i = n; i +)temp = a + sum; a = b; b = sum; sum = temp;/计算母牛数coutn year later,there are cows: sumendl;/输出return 0;/=/=/练习二第10题。/球下落。/=#include using namespace std;/-int main()double sum = 100,height = 100;for(int i = 1;i 10;i +,height /= 2)sum += height;cout球在第9次落地时，共经过sum米。endl;cout球在第9次落地后的反弹高度是height/2米。endl;return 0;/=/=/练习二第10题。/球下落。/=#include using namespace std;/-int main()int n;coutn;double s = -100,h = 100;for(int i = 1;i = n;i +)s = s + 2*h;h = h/2;cout球在第n次落地时，共经过s米。endl;cout球在第n次落地后的反弹高度是h米。endl;return 0;/=/=/练习二第11题。/兑钱。/=#include using namespace std;/-int main()int n = 0;for (int i10 = 1;i10 = 9;i10 +)for (int i5 = 1;i5 = 17;i5 +)for (int i1 = 1;i1 = 85;i1 +)if (10*i10 + 5*i5 + i1 = 100)n +;coutnn;return 0;/=/=/练习二第11题。/兑钱。/=#include using namespace std;/-int main()cout81n;return 0;/=/=/练习二第11题。/兑钱。/=#include using namespace std;/-int main()for(int shiyuan = 1;shiyuan = 9;+ shiyuan)for(int wuyuan = 1;wuyuan = 1)coutshiyuan:shiyuan wuyuan:wuyuan yiyuan:100 - shiyuan*10 - wuyuan*5endl;return 0;/=/=/练习二第1201题。/打印矩阵。/=#include #include using namespace std;/-int main()for(int i = 1;i = 6;i +)coutisetfill( )setw(2) ;for(int j = 1;j = 7;j +)coutsetfill( )setw(3) (i + j - 2)%7;coutendl;return 0;/=/=/练习二第1201题。/打印矩阵。/=#include using namespace std;/-int main()for(int i = 1;i 7;i +)couti ;for(int j = i - 1;j i + 6;j +)coutj%7 ;coutendl;return 0;/=/=/练习二第1202题。/打印矩阵。/=#include using namespace std;/-int main()for(int i = 1;i = 6;i +)/行循环for(int j = 1;j = 7;+ j)/列循环cout(i,j) ;/输出矩阵coutendl;return 0;/安全返回/=/=/练习二第1301题。/打印九九乘法表。/=#include #include #include using namespace std;/-int main()cout*;/输出*for(int j = 1;j = 9;+ j)/制表头横行coutsetw(5)setfill( )j;/输出有间隔的顺序数字coutendl;coutstring(46,-) + n;/打印分隔线for(int i = 1;i = 9;i +)/行循环couti;for(int k = 1;k = i;k +)/表内列循环coutsetw(5)setfill( )i*k;/输出coutendl;return 0;/安全返回/=/=/练习二第1302题。/打印九九乘法表。/=#include #include #include using namespace std;/-int main()cout*;/输出*for(int j = 1;j = 9;+ j)/制表头横行coutsetw(5)setfill( )j;/输出有间隔的顺序数字coutendl;coutstring(46,-)+n;/打印分隔线for(int i = 1;i = 9;i +)/行循环coutistring(5*(i - 1), );/留出空格for(int k = i;k = 9;k +)/表内列循环coutsetw(5)setfill( )i*k;/输出coutendl;return 0;/安全返回/=/=/打印整数-1234567的二