版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领
文档简介
DigitalLogicCircuits数字逻辑电路知到智慧树章节测试课后答案2024年秋南京理工大学第一章单元测试
Thenumberofvaluesthatcanbeassignedtoabitare(
)
A:three
B:one
C:ten
D:two
答案:two
Comparedtoanalogsystems,digitalsystems(
)
A:canhandlemuchhigherpower
B:
alloftheabove
C:
canrepresentaninfinitenumberofvalues
D:arelesspronetonoise
答案:arelesspronetonoise
Thetermbitmeans(
)
A:binarydigit
B:
bothanswers(b)and(c)
C:asmallamountofdata
D:a1ora0
答案:
bothanswers(b)and(c)
Aquantityhascontinuousvalueis(
)
A:ananalogquantity
B:anaturalquantity
C:abinaryquantity
D:adigitalquantity
答案:ananalogquantity
VerilogHDLisa(
)
A:computerlanguage
B:
hardware
C:logicdevice
D:programminglogicdevice
答案:computerlanguage
Acategoryofdigitalintegratedcircuitshavingfunctionsthatcanbealteredisknownasfixed-functionlogic.
A:对B:错
答案:错Dataareinformationonlyinnumeric.
A:对B:错
答案:错Twobroadtypesofdigitalintegratedcircuitsarefixed-functionandprogrammble.
A:对B:错
答案:对Thenonrecurringengineering(NRE)costforanASICdesignisnormallylow.
A:对B:错
答案:错Thereisan“invalid”regionbetweentheinputrangesforlogic0andlogic1
A:错B:对
答案:对
第二章单元测试
Forthebinarynumber10000,theweightofthecolumnwiththe1is(
)
A:16B:10C:
4
D:8
答案:16The2’scomplementof1000is(
)
A:0111B:1001C:1000D:1010
答案:1000Thefractionalbinarynumber0.11hasadecimalvalueof(
)
A:
¼
B:¾
C:noneoftheabove
D:
½
答案:¾
Thenumber1100inBCDis(
)
A:
equaltodecimaleight
B:invalid
C:equaltodecimalten
D:equaltodecimaltwelve
答案:invalid
Anexampleofanunweightedcodeis(
)
A:binary
B:decimal
C:BCD
D:Graycode
答案:Graycode
Anexampleofanalphanumericcodeis(
)
A:ASCII
B:CRC
C:hexadecimal
D:BCD
答案:ASCII
Theoverflowoccurswhenaddingthefollowing8-bittwo’scomplementnumber:01011101+00110001
A:错B:对
答案:对TheoverflowdoesNOToccurwhenaddingthefollowing8-bittwo’scomplementnumber:10111111+11011111
A:错B:对
答案:对Ingeneral,weneedatmostbitstoexpresstheproductwhenmultiplyingann-bitnumberbyanm-bitnumber.
A:对B:错
答案:错Anadditionoverflowsiftheaddends’signsarethesamebutthesum’ssignisdifferentfromtheaddends’.
A:错B:对
答案:对
第三章单元测试
TheBooleanexpressionA
.
1isequalto(
).
A:A
B:0C:BD:1
答案:A
TheBooleanexpressionA
+1isequalto(
).
A:1B:BC:AD:0
答案:1TheBooleanequationAB+AC=A(B+C)illustrates(
)
A:
thecommutativelaw
B:
theassociativelaw
C:DeMorgan’stheorem
D:thedistributionlaw
答案:thedistributionlaw
Theassociativelawforadditionisnormallywrittenas(
)
A:AB=BA
B:A+AB=A
C:
(A+B)+C
=A
+(B+C)
D:A+B=B+A
答案:
(A+B)+C
=A
+(B+C)
ABooleanexpressionthatisinstandardSOPformis(
)
A:haseveryvariableinthedomainineveryterm
B:containsonlyoneproductterm
C:theminimumlogicexpression
D:noneoftheabove
答案:haseveryvariableinthedomainineveryterm
AdjacentcellsonaKarnaughmapdifferfromeachotherby
A:threevariables
B:answerdependsonthesizeofthemap
C:twovariables
D:
onevariable
答案:
onevariable
SOPstandardformisusefulforconstructingtruthtablesorforimplementinglogicinPLDs.
A:错B:对
答案:对LogicsimplificationisstillusefulinnowadaysFPGAdesigns.
A:对B:错
答案:错Insynthesis,anetlistwillbegeneratedtodescribethecircuitcompletely.
A:对B:错
答案:对InFPGAdesign,thestepthat“maps”thedesignfromthenetlisttofitittoatargetdeviceisknownas"programming".
A:对B:错
答案:错
第四章单元测试
The74138decodercanalsobeusedas(
).
A:
aMUX
B:
anencoder
C:noneoftheabove
D:aDEMUX
答案:aDEMUX
Assumeyouwanttodecodethebinarynumber0011withanactive-LOWdecoder.Themissinggateshouldbe(
).
A:anORgate
B:
anANDgate
C:aNORgate
D:aNANDgate
答案:aNANDgate
Toexpanda2-bitparalleladdertoa4-bitparalleladder,youmust(
).
A:usetwo2-bitaddersandconnectthesumoutputsofonetothebitinputsoftheother
B:usetwo2-bitadderswithnointerconnections
C:usefour2-bitadderswithnointerconnections
D:usetwo2-bitadderswiththecarryoutputofoneconnectedtothecarryinputoftheother
答案:usetwo2-bitadderswiththecarryoutputofoneconnectedtothecarryinputoftheother
Ifanhex-to-binarypriorityencoderhasits0,3,6,and14inputsattheactivelevel,theactive-HIGHbinaryoutputis(
).
A:0011
B:0110
C:1110
D:0000
答案:1110
ThecontinuousassignmentassignOUT=
select?A:B;specifiestheconditionthatOUT=
()
ifselect=
1,elseOUT=
()
ifselect=
0.
A:
0,1
B:B,A
C:1,0
D:
A,B
答案:
A,B
Considertheinitial
blockinthefollowing:initialbeginA=0;B=0;#10A=1;#20A=0;B=1;EndThenatt=30,Ais
changedto(
)andBto(
).
A:1,0
B:
1,1
C:0,0
D:0,1
答案:0,1
Theinitialstatementexecutesonlyonce,startingfrom
simulationtime0,andmaycontinuewithanyoperationsthataredelayedbyagiven
numberoftimeunits.
A:错B:对
答案:对InVerilogHDL,thedefinitionsofmodulesareallowedtobenested.
A:错B:对
答案:错ThevaluezrepresentsanunknownlogicvalueinVerilogHDL.
A:错B:对
答案:错InVerilogHDL,~(1010)is(0101),and!(1010)is0.
A:对B:错
答案:对
第五章单元测试
TheoutputofaDlatchwillnotchangeif(
).
A:
theoutputisLOW
B:alloftheabove
C:DisLOW
D:Enableisnotactive
答案:Enableisnotactive
TheDflip-flopshownwill(
).
A:toggleonthenextclockpulse
B:latchonthenextclockpulse
C:setonthenextclockpulse
D:resetonthenextclockpulse
答案:toggleonthenextclockpulse
FortheJ-Kflip-flopshown,thenumberofinputsthatareasynchronousis(
).
A:3B:1C:4D:2
答案:2AssumetheoutputisinitiallyHIGHonaleadingedgetriggeredJ-Kflipflop.Fortheinputsshown,theoutputwillgofromHIGHtoLOWonwhichclockpulse?
A:1B:2C:3D:4
答案:3Thetimeintervalillustratediscalled(
).
A:tPLH
B:holdtime
C:tPHL
D:set-uptime
答案:tPLH
TheadvantageofdynamicRAMoverstaticRAMisthat(
).
A:itdoesnotrequirerefreshingB:itismuchfasterC:itissimplerandcheaperD:alloftheabove
答案:itissimplerandcheaperAnasynchronous
resetsignalwilloverridetheclockonaFF.
A:对B:错
答案:对InVerilogHDL,aninitialbehavioralstatementexecutesonlyonce.
A:对B:错
答案:对InaMoore
model,theoutputsofthesequentialcircuitarenotsynchronizedwiththe
clock.
A:错B:对
答案:错TheoutputoftheMealy
machineisthevaluethatispresentimmediatelybeforethe
activeedgeoftheclock.
A:错B:对
答案:对
第六章单元测试
TocauseaDflip-floptotoggle,connectthe(
).
A:clocktotheD
input
B:C:clocktothepresetinput
D:
Q
outputtotheD
input
答案:A4-bitbinarycounterhasaterminalcountof(
).
A:15B:10C:4D:16
答案:15Assumetheclockfora4-bitbinarycounteris80kHz.Theoutputfrequencyofthefourthstage(Q3)is(
).
A:5kHz
B:10kHz
C:20kHz
D:320kHz
答案:5kHz
A4-bitparallel-in/parallel-outshiftregisterwillstoredatafor(
).
A:2clockperiods
B:4clockperiods
C:3clockperiods
D:1clockperiod
答案:1clockperiod
AnadvantageofaringcounteroveraJohnsoncounteristhattheringcounter(
).
A:allowsonlyonebittochangeatatime
B:isself-decoding
C:isclearedaftereachcycle
D:hasmorepossiblestatesforagivennumberofflip-flops
答案:isself-decoding
Apossiblesequencefora4-bitringcounteris(
).
A:…1111,1110,1101…
B:…0000,0001,0010…
C:
…0001,0011,0111…
D:
…1000,0100,0010…
答案:
…1000,0100,0010…
Adivide‐by‐N-counterisacounterthatgoesthrougharepeated
sequenceofNstates,anditisalsoknownasamodulo‐Ncounter.
A:对B:错
答案:对Forcounterswithunusedstates,itisnecessarytoensurethatthecircuiteventuallygoesintooneofthevalidstatessothatitcanresumenormaloperation.
A:错B:对
答案:对Fortransmission,datafromaUARTissentin
synchronousparallelform.
A:错B:对
答案:错Themaximummodulusofacounteris,
wherenisthenumberofstages(flip-flops)inthecounter.
A:对B:错
答案:错
第七章单元测试
StaticRAMis(
).
A:nonvolatilereadonlymemory
B:volatileread/writememory
C:volatilereadonlymemory
D:
nonvolatileread/writememory
答案:volatileread/writememory
Anonvolatilememoryisonethat(
)
A:
requiresaclock
B:
retainsdatawithoutpowerapplied
C:mustberefreshedregularly
D:alloftheabove
答案:
retainsdatawithoutpowerapplied
TheadvantageofdynamicRAMoverstaticRAMisthat(
).
A:alloftheabove
B:itdoesnotrequirerefreshing
C:itismuchfaster
D:itissimplerandcheaper
答案:itissimplerandcheaper
A4-bitparallel-in/parallel-outshiftregisterwillstoredatafor(
).
A:1clockperiod
B:2clockperiodC:4clockperiodD:3clockperiod
答案:1clockperiod
WhendataisreadfromRAM,thememorylocationis(
).
A:settoall1’safterthereadoperation
B:clearedafterthereadoperation
C:destroyed
D:unchanged
答案:unchanged
Thefirststepinareadorwriteoperationforarandomaccessmemoryisto(
).
A:startarefreshcycle
B:
sendorobtainthedata
C:placeavalidaddressontheaddressbus
D:enablethememory
答案:placeavalidaddressontheaddressbus
AddressmultiplexingcanreducethenumberofpinsintheICpackage.
A:对B:错
答案:对OneofthemajorapplicationsofSRAMsisincachememoriesincomputers.
A:对B:错
答案:对RAMisusedinacomputerto
storetheBIOS(BasicInput/Output
System.
A:对B:错
答案:错Memoryexpansion
isaccomplishedbyaddinganappropriatenumberofmemorychipstotheaddress,data,
andcontrolbuses.
A:对B:错
答案:对
第八章单元测试
Thenumberofcomparatorsrequiredina10-bitflashADCis(
).
A:511
B:4095
C:1023
D:255
答案:1023
Ifananti-aliasingfilterisnotusedindigitizingasignaltherecoveryprocess(
)
A:mayincludealiassignals
B:isslowed
温馨提示
- 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
- 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
- 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
- 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
- 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
- 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
- 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
评论
0/150
提交评论