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FundamentalsofHypothesisTesting:One-SampleTestsChapter9ObjectivesInthischapter,youlearn:
ThebasicprinciplesofhypothesistestingHowtousehypothesistestingtotestameanorproportionTheassumptionsofeachhypothesis-testingprocedure,howtoevaluatethem,andtheconsequencesiftheyareseriouslyviolatedPitfallsðicalissuesinvolvedinhypothesistestingHowtoavoidthepitfallsinvolvedinhypothesistestingWhatisaHypothesis?Ahypothesisisaclaim (assertion)abouta populationparameter:populationmeanpopulationproportionExample:Themeanmonthlycellphonebillinthiscityisμ=$42Example:Theproportionofadultsinthiscitywithcellphonesisπ=0.68DCOVATheNullHypothesis,H0StatestheclaimorassertiontobetestedExample:Themeandiameterofamanufacturedboltis30mm()Isalwaysaboutapopulationparameter,notaboutasamplestatistic
DCOVATheNullHypothesis,H0BeginwiththeassumptionthatthenullhypothesisistrueSimilartothenotionofinnocentuntil
provenguiltyReferstothestatusquoorhistoricalvalueAlwayscontains“=“,or“≤”,or“≥”signMayormaynotberejected(continued)DCOVATheAlternativeHypothesis,H1Istheoppositeofthenullhypothesise.g.,Themeandiameterofamanufacturedboltisnotequalto30mm(H1:μ≠30)ChallengesthestatusquoNevercontainsthe“=“,or“≤”,or“≥”signMayormaynotbeprovenIsgenerallythehypothesisthattheresearcheristryingtoproveDCOVATheHypothesisTestingProcessClaim:Thepopulationmeanageis50.H0:μ=50, H1:μ≠50Samplethepopulationandfindthesamplemean.PopulationSampleDCOVATheHypothesisTestingProcessSupposethesamplemeanagewasX=20.Thisissignificantlylowerthantheclaimedmeanpopulationageof50.Ifthenullhypothesisweretrue,theprobabilityofgettingsuchadifferentsamplemeanwouldbeverysmall,soyourejectthenullhypothesis.Inotherwords,gettingasamplemeanof20issounlikelyifthepopulationmeanwas50,youconcludethatthepopulationmeanmustnotbe50.(continued)DCOVATheHypothesisTestingProcess
μ
=50If
H0istrueIfitisunlikelythatyouwouldgetasamplemeanofthisvalue......thenyourejectthenullhypothesisthatμ=50.20...Wheninfactthiswere
thepopulationmean…SamplingDistributionofXX(continued)DCOVATheTestStatisticand
CriticalValuesIfthesamplemeanisclosetothestatedpopulationmean,thenullhypothesisisnotrejected.Ifthesamplemeanisfarfromthestatedpopulationmean,thenullhypothesisisrejected.Howfaris“farenough”torejectH0?Thecriticalvalueofateststatisticcreatesa“lineinthesand”fordecisionmaking--itanswersthequestionofhowfarisfarenough.DCOVATheTestStatisticand
CriticalValuesCriticalValues“TooFarAway”FromMeanofSamplingDistributionSamplingDistributionoftheteststatisticRegionofRejectionRegionofRejectionRegionofNon-RejectionDCOVARisksinDecisionMakingUsingHypothesisTestingTypeIError
RejectatruenullhypothesisAtypeIerrorisa“falsealarm”TheprobabilityofaTypeIErroris
CalledlevelofsignificanceofthetestSetbyresearcherinadvanceTypeIIErrorFailuretorejectafalsenullhypothesisTypeIIerrorrepresentsa“missedopportunity”TheprobabilityofaTypeIIErrorisβDCOVAPossibleErrorsinHypothesisTestDecisionMakingPossibleHypothesisTestOutcomesActualSituationDecisionH0TrueH0FalseDoNotRejectH0NoErrorProbability1-αTypeIIErrorProbabilityβRejectH0TypeIErrorProbabilityαNoErrorPower1-β(continued)DCOVAPossibleErrorsinHypothesisTestDecisionMakingTheconfidencecoefficient(1-α)istheprobabilityofnotrejectingH0whenitistrue.Theconfidencelevelofahypothesistestis(1-α)*100%.Thepowerofastatisticaltest(1-β)istheprobabilityofrejectingH0whenitisfalse.(continued)DCOVATypeI&IIErrorRelationship
TypeIandTypeIIerrorscannothappenatthesametimeATypeIerrorcanonlyoccurifH0istrueATypeIIerrorcanonlyoccurifH0isfalse
IfTypeIerrorprobability(
),then TypeIIerrorprobability(β)DCOVAFactorsAffectingTypeIIErrorAllelseequal,
βwhenthedifferencebetweenhypothesizedparameteranditstruevalue
β when
β whenσ
β whennDCOVALevelofSignificance
andtheRejectionRegionLevelofsignificance=aThisisatwo-tailtestbecausethereisarejectionregioninbothtailsH0:μ=30H1:μ≠30CriticalvaluesRejectionRegion/230a/2aDCOVAHypothesisTestsfortheMeanKnownUnknownHypothesisTestsfor(Ztest)(ttest)DCOVAZTestofHypothesisfortheMean(σKnown)Convertsamplestatistic()toaZSTAT
teststatistic
XσUnknownHypothesisTestsforUnknownTheteststatisticis:σKnownKnown(Ztest)(ttest)DCOVACriticalValue
ApproachtoTestingForatwo-tailtestforthemean,σknown:Convertsamplestatistic()toteststatistic(ZSTAT)DeterminethecriticalZvaluesforaspecified
levelofsignificance
fromatableorbyusingcomputersoftwareDecisionRule:Iftheteststatisticfallsintherejectionregion,rejectH0;otherwisedonotrejectH0
DCOVADonotrejectH0RejectH0RejectH0Therearetwocutoffvalues(criticalvalues),definingtheregionsofrejectionTwo-TailTests
/2-Zα/20H0:μ=30H1:μ
¹30+Zα/2
/2 Lowercriticalvalue Uppercriticalvalue30ZXDCOVA6Stepsin
HypothesisTestingStatethenullhypothesis,H0andthealternativehypothesis,H1Choosethelevelofsignificance,
,andthesamplesize,n.ThelevelofsignificanceisbasedontherelativeimportanceofTypeIandTypeIIerrorsDeterminetheappropriateteststatisticandsamplingdistributionDeterminethecriticalvaluesthatdividetherejectionandnonrejectionregionsDCOVA6Stepsin
HypothesisTestingCollectdataandcomputethevalueoftheteststatisticMakethestatisticaldecisionandstatethemanagerialconclusion.Iftheteststatisticfallsintothenonrejectionregion,donotrejectthenullhypothesisH0.Iftheteststatisticfallsintotherejectionregion,rejectthenullhypothesis.Expressthemanagerialconclusioninthecontextoftheproblem(continued)DCOVAHypothesisTestingExampleTesttheclaimthatthetruemeandiameterofamanufacturedboltis30mm.(Assumeσ=0.8)1. Statetheappropriatenullandalternative hypothesesH0:μ=30H1:μ≠30(Thisisatwo-tailtest)2.SpecifythedesiredlevelofsignificanceandthesamplesizeSupposethat
=0.05andn=100arechosenforthistestDCOVAHypothesisTestingExample3. DeterminetheappropriatetechniqueσisassumedknownsothisisaZtest.4. DeterminethecriticalvaluesFor
=0.05thecriticalZvaluesare±1.965.
CollectthedataandcomputetheteststatisticSupposethesampleresultsare n=100,X=29.84(σ=0.8isassumedknown)Sotheteststatisticis:(continued)DCOVARejectH0DonotrejectH06.Istheteststatisticintherejectionregion?/2=0.025-Zα/2=-1.960RejectH0ifZSTAT<-1.96orZSTAT>1.96;otherwisedonotrejectH0HypothesisTestingExample(continued)/2=0.025RejectH0+Zα/2=+1.96Here,ZSTAT=-2.0<-1.96,sotheteststatisticisintherejectionregionDCOVA6(continued).Reachadecisionandinterprettheresult-2.0SinceZSTAT=-2.0<-1.96,rejectthenullhypothesisandconcludethereissufficientevidencethatthemeandiameterofamanufacturedboltisnotequalto30HypothesisTestingExample(continued)RejectH0DonotrejectH0
=0.05/2-Zα/2=-1.960
=0.05/2RejectH0+Zα/2=+1.96DCOVAp-ValueApproachtoTestingp-value:ProbabilityofobtainingateststatisticequaltoormoreextremethantheobservedsamplevaluegivenH0istrueThep-valueisalsocalledtheobservedlevelofsignificanceItisthesmallestvalueof
forwhichH0canberejectedDCOVAp-ValueApproachtoTesting:
Interpretingthep-valueComparethep-valuewith
Ifp-value<
,rejectH0Ifp-value
,donotrejectH0RememberIfthep-valueislowthenH0mustgoDCOVAThe5Stepp-valueapproachto
HypothesisTestingStatethenullhypothesis,H0andthealternativehypothesis,H1Choosethelevelofsignificance,
,andthesamplesize,n.ThelevelofsignificanceisbasedontherelativeimportanceoftherisksofatypeIandatypeIIerror.DeterminetheappropriateteststatisticandsamplingdistributionCollectdataandcomputethevalueoftheteststatisticandthep-valueMakethestatisticaldecisionandstatethemanagerialconclusion.Ifthep-valueis<αthenrejectH0,otherwisedonotrejectH0.StatethemanagerialconclusioninthecontextoftheproblemDCOVAp-valueHypothesisTestingExampleTesttheclaimthatthetruemeandiameterofamanufacturedboltis30mm.(Assumeσ=0.8)1. Statetheappropriatenullandalternative hypothesesH0:μ=30H1:μ≠30(Thisisatwo-tailtest)2.SpecifythedesiredlevelofsignificanceandthesamplesizeSupposethat
=0.05andn=100arechosenforthistestDCOVAp-valueHypothesisTestingExample3. DeterminetheappropriatetechniqueσisassumedknownsothisisaZtest.4.
Collectthedata,computetheteststatisticandthep-valueSupposethesampleresultsare n=100,X=29.84(σ=0.8isassumedknown)Sotheteststatisticis:(continued)DCOVAp-ValueHypothesisTestingExample:
Calculatingthep-value4.(continued)Calculatethep-value.HowlikelyisittogetaZSTATof-2(orsomethingfurtherfromthemean(0),ineitherdirection)ifH0istrue?p-value=0.0228+0.0228=0.0456P(Z<-2.0)=0.02280-2.0Z2.0P(Z>2.0)=0.0228DCOVA(continued)5.Isthep-value<α?Sincep-value=0.0456<α=0.05RejectH05.(continued)Statethemanagerialconclusioninthecontextofthesituation.Thereissufficientevidencetoconcludethemeandiameterofamanufacturedboltisnotequalto30mm.p-valueHypothesisTestingExample(continued)DCOVAConnectionBetweenTwoTailTestsandConfidenceIntervalsFor
X=29.84,σ=0.8andn=100,the95%confidenceintervalis:
29.6832≤μ
≤29.9968Sincethisintervaldoesnotcontainthehypothesizedmean(30),werejectthenullhypothesisat
=0.05DCOVADoYouEverTrulyKnowσ?Probablynot!Invirtuallyallrealworldbusinesssituations,σisnotknown.Ifthereisasituationwhereσisknownthenµisalsoknown(sincetocalculateσyouneedtoknowµ.)Ifyoutrulyknowµtherewouldbenoneedtogatherasampletoestimateit.DCOVAHypothesisTesting:
σUnknownIfthepopulationstandarddeviationisunknown,youinsteadusethesamplestandarddeviationS.Becauseofthischange,youusethetdistributioninsteadoftheZdistributiontotestthenullhypothesisaboutthemean.Whenusingthetdistributionyoumustassumethepopulationyouaresamplingfromfollowsanormaldistribution.Allothersteps,concepts,andconclusionsarethesame.DCOVAtTestofHypothesisfortheMean(σUnknown)Convertsamplestatistic()toatSTAT
teststatistic
XTheteststatisticis:HypothesisTestsforσKnownσUnknownKnownUnknown(Ztest)(ttest)Theteststatisticis:HypothesisTestsforσKnownσUnknownKnownUnknown(Ztest)(ttest)Theteststatisticis:HypothesisTestsforσKnownσUnknownKnownUnknown(Ztest)(ttest)DCOVAExample:Two-TailTest
(Unknown)
TheaveragecostofahotelroominNewYorkissaidtobe$168pernight.Todetermineifthisistrue,arandomsampleof25hotelsistakenandresultedinanXof$172.50andanSof$15.40.Testtheappropriatehypothesesat
=0.05.
(Assumethepopulationdistributionisnormal)H0:μ
=168H1:μ¹168DCOVAa=0.05n
=25,df=25-1=24isunknown,souseatstatisticCriticalValue:±t24,0.025=±2.0639ExampleSolution:
Two-TailtTestDonotrejectH0:insufficientevidencethattruemeancostisdifferentfrom$168RejectH0RejectH0a/2=.025-t24,0.025DonotrejectH00a/2=.025-2.06392.06391.46H0:μ
=168H1:μ¹168t24,0.025DCOVAToUsethet-testMustAssumethePopulationIsNormalAslongasthesamplesizeisnotverysmallandthepopulationisnotveryskewed,thet-testcanbeused.Toevaluatethenormalityassumption:Determinehowcloselysamplestatisticsmatchthenormaldistribution’stheoreticalproperties.Constructahistogramorstem-and-leafdisplayorboxplotoranormalprobabilityplot.Section6.3hasmoredetailsonevaluatingnormality.DCOVAExampleTwo-TailtTestUsingAp-valuefromExcelSincethisisat-testwecannotcalculatethep-valuewithoutsomecalculationaid.TheExceloutputbelowdoesthis:p-value>αSodonotrejectH0DCOVAExampleTwo-TailtTestUsingAp-valuefromMinitabDCOVAOne-SampleTTestofmu=168vsnot=168NMeanStDevSEMean95%CITP25172.5015.403.08(166.14,178.86)1.460.157p-value>αSodonotrejectH01234ConnectionofTwoTailTeststoConfidenceIntervalsFor
X=172.5,S=15.40andn=25,the95%confidenceintervalforµis:172.5-(2.0639)15.4/25to172.5+(2.0639)15.4/25
166.14≤μ
≤178.86SincethisintervalcontainstheHypothesizedmean(168),wedonotrejectthenullhypothesisat
=0.05DCOVAOne-TailTestsInmanycases,thealternativehypothesisfocusesonaparticulardirectionH0:μ≥3H1:μ<3H0:μ≤3H1:μ>3Thisisalower-tailtestsincethealternativehypothesisisfocusedonthelowertailbelowthemeanof3Thisisanupper-tailtestsincethealternativehypothesisisfocusedontheuppertailabovethemeanof3DCOVARejectH0DonotrejectH0Thereisonlyonecriticalvalue,sincetherejectionareaisinonlyonetailLower-TailTestsa-Zαor-tα0μH0:μ≥3H1:μ<3ZortXCriticalvalueDCOVARejectH0DonotrejectH0Upper-TailTestsaZα
ortα0μH0:μ≤3H1:μ>3Thereisonlyonecriticalvalue,sincetherejectionareaisinonlyonetailCriticalvalueZortX_DCOVAExample:Upper-TailtTest
forMean(
unknown)Aphoneindustrymanagerthinksthatcustomermonthlycellphonebillshaveincreased,andnowaverageover$52permonth.Thecompanywishestotestthisclaim.(Assumeanormalpopulation)H0:μ≤52themeanisnotover$52permonthH1:μ>52themeanisgreaterthan$52permonth
(i.e.,sufficientevidenceexiststosupportthe manager’sclaim)Formhypothesistest:DCOVARejectH0DonotrejectH0Supposethat=0.10ischosenforthistestandn=25.Findtherejectionregion:
=0.101.3180RejectH0RejectH0iftSTAT>1.318Example:FindRejectionRegion(continued)DCOVAObtainsampleandcomputetheteststatisticSupposeasampleistakenwiththefollowingresults:n=25,X=53.1,andS=10
Thentheteststatisticis:Example:TestStatistic(continued)DCOVARejectH0DonotrejectH0Example:Decision
=0.101.3180RejectH0DonotrejectH0sincetSTAT=0.55<1.318thereisnotsufficientevidencethatthemeanbillisover$52tSTAT=0.55Reachadecisionandinterprettheresult:(continued)DCOVAExample:UtilizingThep-valueforTheTestCalculatethep-valueandcompareto
(p-valuebelowcalculatedusingexcelspreadsheetonnextpage)
RejectH0
=.10DonotrejectH01.3180RejectH0tSTAT=.55p-value=.2937DonotrejectH0sincep-value=.2937>=.10DCOVAExcelSpreadsheetCalculatingThep-valueforTheUpperTailtTestDCOVAUsingMinitabtocalculateThep-valueforTheUpperTailtTestDCOVA1234One-SampleTTestofmu=52vs>52 95%LowerNMeanStDevSEMeanBoundTP2553.1010.002.00 49.680.550.294p-value>αSodonotrejectH0HypothesisTestsforProportionsInvolvescategoricalvariablesTwopossibleoutcomesPossessescharacteristicofinterestDoesnotpossesscharacteristicofinterestFractionorproportionofthepopulationinthecategoryofinterestisdenotedbyπDCOVAProportionsSampleproportioninthecategoryofinterestisdenotedbyp
Whenbothnπandn(1-π)areatleast5,p
canbeapproximatedbyanormaldistributionwithmeanandstandarddeviation
(continued)DCOVAThesamplingdistributionofpisapproximatelynormal,sotheteststatisticisaZSTATvalue:HypothesisTestsforProportionsnπ5andn(1-π)5HypothesisTestsforpnπ<5orn(1-π)<5NotdiscussedinthischapterDCOVAAnequivalentformtothelastslide,butintermsofthenumberinthecategoryofinterest,X:ZTestforProportioninTermsofNumberinCategoryofInterestX5andn-X5HypothesisTestsforXX<5orn-X<5NotdiscussedinthischapterDCOVAExample:ZTestforProportionAmarketingcompanyclaimsthatitreceives8%responsesfromitsmailing.Totestthisclaim,arandomsampleof500weresurveyedwith25responses.Testatthe
=0.05significancelevel.Check:n
π=(500)(.08)=40n(1-π)=(500)(.92)=460
DCOVAZTestforProportion:Solutiona
=0.05n=500,p=0.05RejectH0at
=0.05H0:π=0.08H1:π
¹0.08CriticalValues:±1.96TestStatistic:Decision:Conclusion:z0RejectReject.025.0251.96-2.47Thereissufficientevidencetorejectthecompany’sclaimof8%responserate.-1.96DCOVADonotrejectH0RejectH0RejectH0
/2
=.0251.960Z=-2.47Calculatethep-valueandcompareto
(Foratwo-tailtestthep-valueisalwaystwo-tail)(continued)p-value=0.0136:p-ValueSolutionRejectH0sincep-value=0.0136<=0.05Z=2.47-1.96
/2
=.0250.00680.0068DCOVAQuestionsToAddressInThePlanningStageWhatisthegoalofthesurvey,study,orexperiment?Howcanyoutranslatethisgoalintoanullandanalternativehypothesis?Isthehypothesistestoneortwotailed?Canarandomsamplebeselected?Whattypesofdatawillbecollected?Numerical?Categorical?Whatlevelofsignificanceshouldbeused?Istheintendedsamplesizelargeenoughtoachievethedesiredpower?Whatstatisticaltestprocedureshouldbeusedandwhy?Whatconclusions&interpretationscanyoureachfromtheresultsoftheplannedhypothesistest?FailingtoconsiderthesequestionscanleadtobiasorincompleteresultsStatisticalSignificancevsPracticalSignificanceStatisticallysignificantresults(rejectingthenullhypothesis)arenotalwaysofpracticalsignificanceThisismorelikelytohappenwhenthesamplesizegetsverylargePracticallyimportantresultsmightbefoundtobestatisticallyinsignificant(failingtorejectthenullhypothesis)ThisismorelikelytohappenwhenthesamplesizeisrelativelysmallReportingFindings&EthicalIssuesShoulddocument&reportbothgood&badresultsShouldnotjustreportstatisticallysignificantresultsReportsshoulddistinguishbetweenpoorresearchmethodologyandunethicalbehaviorEthicalissuescanarisein:TheuseofhumansubjectsThedatacollectionmethodThetypeoftestbeingusedThelevelofsignificancebeingusedThecleansinganddiscardingofdataThefailuretoreportpertinentfindingsChapterSummaryInthischapterwediscussed:
ThebasicprinciplesofhypothesistestingHowtousehypothesistestingtotestameanorproportionTheassumptionsofeachhypothesis-testingprocedure,howtoevaluatethem,andtheconsequencesiftheyareseriouslyviolatedPitfallsðicalissuesinvolvedinhypothesistestingHowtoavoidthepitfallsinvolvedinhypothesistestingTwo-SampleTestsandOne-WayANOVAChapter10ObjectivesInthischapter,youlearn:
HowtousehypothesistestingforcomparingthedifferencebetweenThemeansoftwoindependentpopulationsThemeansoftworelatedpopulationsTheproportionsoftwoindependentpopulationsThevariancesoftwoindependentpopulationsThemeansofmorethantwopopulationsTwo-SampleTestsTwo-SampleTestsPopulationMeans,IndependentSamplesPopulationMeans,RelatedSamplesPopulationVariancesGroup1vs.Group2Samegroupbeforevs.aftertreatmentVariance1vs.Variance2Examples:PopulationProportionsProportion1vs.Proportion2DCOVADifferenceBetweenTwoMeansPopulationmeans,independentsamplesGoal:Testhypothesisorformaconfidenceintervalforthedifferencebetweentwopopulationmeans,μ1–μ2
ThepointestimateforthedifferenceisX1–X2*σ1andσ2unknown,assumedequalσ1andσ2unknown,notassumedequalDCOVADifferenceBetweenTwoMeans:IndependentSamplesPopulationmeans,independentsamples*UseSptoestimateunknownσ.UseaPooled-Variance
ttest.σ1andσ2unknown,assumedequalσ1andσ2unknown,notassumedequalUseS1andS2toestimateunknownσ1andσ2.UseaSeparate-variancettestDifferentdatasourcesUnrelatedIndependentSampleselectedfromonepopulationhasnoeffectonthesampleselectedfromtheotherpopulationDCOVAHypothesisTestsfor
TwoPopulationMeansLower-tailtest:H0:μ1
μ2H1:μ1<μ2i.e.,H0:μ1–μ2
0H1:μ1–μ2
<0Upper-tailtest:H0:μ1≤μ2H1:μ1
>
μ2i.e.,H0:μ1–μ2
≤0H1:μ1–μ2
>0Two-tailtest:H0:μ1=μ2H1:μ1
≠
μ2i.e.,H0:μ1–μ2
=0H1:μ1–μ2
≠0TwoPopulationMeans,IndependentSamplesDCOVATwoPopulationMeans,IndependentSamplesLower-tailtest:H0:μ1–μ2
0H1:μ1–μ2
<0Upper-tailtest:H0:μ1–μ2
≤0H1:μ1–μ2
>0Two-tailtest:H0:μ1–μ2
=0H1:μ1–μ2
≠0aa/2a/2a-ta-ta/2tata/2RejectH0iftSTAT<-taRejectH0iftSTAT>taRejectH0iftSTAT<-ta/2
ortSTAT>ta/2
Hypothesistestsforμ1–μ2
DCOVAPopulationmeans,independentsamplesHypothesistestsforµ1-µ2withσ1andσ2unknownandassumedequalAssumptions:
SamplesarerandomlyandindependentlydrawnPopulationsarenormallydistributedorbothsamplesizesareatleast30Populationvariancesareunknownbutassumedequal*σ1andσ2unknown,assumedequalσ1andσ2unknown,notassumedequalDCOVAPopulationmeans,independentsamplesThepooledvarianceis:Theteststatisticis:WheretSTAThasd.f.=(n1+n2–2)(continued)*σ1andσ2unknown,assumedequalσ1andσ2unknown,notassumedequalHypothesistestsforµ1-µ2withσ1andσ2unknownandassumedequalDCOVAPopulationmeans,independentsamplesTheconfidenceintervalfor
μ1–μ2is:Wheretα/2hasd.f.=n1+n2–2*Confidenceintervalforµ1-µ2withσ1andσ2unknownandassumedequalσ1andσ2unknown,assumedequalσ1andσ2unknown,notassumedequalDCOVAPooled-VariancetTestExampleYouareafinancialanalystforabrokeragefirm.IsthereadifferenceindividendyieldbetweenstockslistedontheNYSE&NASDAQ?Youcollectthefollowingdata:
NYSE
NASDAQ
Number2125Samplemean 3.272.53Samplestddev 1.301.16Assumingbothpopulationsareapproximatelynormalwithequalvariances,is
thereadifferenceinmean
yield(
=0.05)?DCOVAPooled-VariancetTestExample:CalculatingtheTestStatisticTheteststatisticis:(continued)H0:μ1-μ2=0i.e.(μ1=μ2)H1:μ1-μ2≠0i.e.(μ1≠μ2)DCOVAPooled-VariancetTestExample:HypothesisTestSolutionH0:μ1-μ2=0i.e.(μ1=μ2)H1:μ1-μ2≠0i.e.(μ1≠μ2)
=0.05df=21+25-2=44CriticalValues:t=±2.0154TestStatistic:Decision:Conclusion:RejectH0ata=0.05Thereisevidenceofadifferenceinmeans.t02.0154-2.0154.025RejectH0RejectH0.0252.040DCOVAPooled-VariancetTestExample:ConfidenceIntervalforµ1-µ2SincewerejectedH0canwebe95%confidentthatµNYSE>µNASDAQ?95%ConfidenceIntervalforµNYSE-µNASDAQSince0islessthantheentireinterval,wecanbe95%confidentthatµNYSE>µNASDAQDCOVAPopulationmeans,independentsamplesHypothesistestsforµ1-µ2withσ1andσ2unknown,notassumedequalAssumptions:
SamplesarerandomlyandindependentlydrawnPopulationsarenormallydistributedorbothsamplesizesareatleast30Populationvariancesareunknownandcannotbeassumedtobeequal*σ1andσ2unknown,assumedequalσ1andσ2unknown,notassumedequalDCOVAPopulationmeans,independentsamples(continued)*σ1andσ2unknown,assumedequalσ1andσ2unknown,notassumedequalHypothesistestsforµ1-µ2withσ1andσ2unknownandnotassumedequalDCOVATheformulaeforthistestarenotcoveredinthisbook.Seereference8fromthischapterformoredetails.ThistestutilizestwoseparatesamplevariancestoestimatethedegreesoffreedomforthettestSeparate-VariancetTestExampleYouareafinancialanalystforabrokeragefirm.IsthereadifferenceindividendyieldbetweenstockslistedontheNYSE&NASDAQ?Youcollectthefollowingdata:
NYSE
NASDAQ
Number2125Samplemean 3.272.53Samplestddev 1.301.16Assumingbothpopulationsareapproximatelynormalwithunequalvariances,is
thereadifferenceinmean
yield(
=0.05)?DCOVASeparate-VariancetTestExample:CalculatingtheTestStatistic(continued)H0:μ1-μ2=0i.e.(μ1=μ2)H1:μ1-μ2≠0i.e.(μ1≠μ2)DCOVASeparate-VariancetTestE
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