程序设计仿真练习题-答案

8086程序设计仿真练习题数组STRAING中存放着多个8位有符号数，以“$”结束，要求分成正数组和负数组分别存放，并统计两个数组的个数，分别存于正、负数组的第一个字节。DATASEGMENTSTARINGDB25H,0BDH,02H,80H,7FH,94H,65H,0A5H,$DA2DB20DUP(0);正数DA3DB20DUP(0);负数DA4DB8DATAENDSCODESEGMENTASSUMECS:CODEDS:DATASTART:MOVAX,DATAMOVDS,AXLEABX,STARINGLEASI,DA2LEADI,DA3MOVCX,0MOVCL,DA4LOP1:CMP[BX],80HJBLOP2INC[DA3]MOVAL,[BX]INCDIMOV[DI],ALJMPLOP3LOP2:INC[DA2]MOVAL,[BX]INCSIMOV[SI],ALLOP3:INCBXLOOPLOP1CODEENDSENDSTART将数据块DAT1中的20个单字节数，复制到DAT2中，并从中检索与2EH相同的数，将此单元的数换成空格符。如有多个与2EH相同的数，要求统计出个数，存在寄存器DL中。DATASEGMENTDAT1DB25H,0BDH,02H,80H,7FH,94H,65H,0A5H,00H,31HDB2EH,33H,2EH,76H,78H,98H,23H,7AH,98H,38HDAT2DB20DUP(0)DAT3DB20DATAENDSCODESEGMENTASSUMECS:CODEDS:DATASTART:MOVAX,DATAMOVDS,AXLEASI,DAT1LEADI,DAT2MOVDX,0MOVCX,0MOVCL,DAT3LOP1:MOVAL,[SI]MOV[DI],ALCMP[DI],2EHJZLOP2JMPLOP3LOP2:MOV[DI],0INCDLLOP3:INCSIINCDILOOPLOP1CODEENDSENDSTART将变量VAR1中的16位二进制数取反，并统计原数中1的个数，将个数存在变量VAR2中。DATASEGMENTVAR1DW3425HVAR2DB0DATAENDSCODESEGMENTASSUMECS:CODEDS:DATASTART:MOVAX,DATAMOVDS,AXMOVAX,VAR1LEABX,VAR2MOVCX,0MOVDX,0MOVCL,16CLCLOP1:ROLAX,1JNCLOP2INCDLLOP2:LOOPLOP1NOTAXMOVVAR1,AXMOV[BX],DLCODEENDSENDSTART找出数据块DAT1中的15个8位有符号数中，最大的偶数和最小的奇数，分别存在变量MAX和MIN中。DATASEGMENTDAT1DB81H,8DH,78H,2AH,27H,034H,80H,90H,24HDB43H,7FH,7EH,23H,76H,54HDAT2EQU15MAXDB0MINDB0DATAENDSCODESEGMENTASSUMECS:CODEDS:DATASTART:MOVAX,DATAMOVDS,AXLEASI,DAT1MOVCX,0MOVAX,0MOVCL,DAT2LOP1:MOVAL,[SI]ANDAL,01HJZOUSHULEADI,MINMOVDL,[DI]MOVAL,[SI]CMPAL,DLJGLOP2MOV[DI],ALJMPLOP2OUSHU:LEADI,MAXMOVDL,[DI]MOVAL,[SI]CMPAL,DLJLLOP2MOV[DI],ALLOP2:INCSILOOPLOP1CODEENDSENDSTART将变量VAR1中的16位二进制数，变成4个ASCⅡ码，存在VAR2开始的4内存单元中。DATASEGMENTVAR1DW23E5HVAR2DB4DUP(0)NUMEQU4DATAENDSCODESEGMENTASSUMECS:CODEDS:DATASTART:MOVAX,DATAMOVDS,AXMOVDX,VAR1LEASI,VAR2MOVCX,0MOVCL,NUMLOP1:MOVAX,DXANDAL,0FHORAL,30HCMPAL,3AHJBLOP2ADDAL,07HLOP2:MOV[SI],ALINCSIRORDX,4LOOPLOP1CODEENDSENDSTART6、将数据块DAT1中的多个8位有符号数，数据块以0结尾（数据块不包括0），按照从小到大的顺序排列DATASEGMENTDAT1DB34H,0A2H,76H,80H,01H,02H,08H,04H,00HDATAENDSCODESEGMENTASSUMECS:CODE,DS:DATASTART:MOVAX,DATAMOVDS,AXLEABX,DAT1XORCX,CXLOP1:MOVAL,[BX]INCBXINCCLCMPAL,0JNZLOP1DECCXDECCXXORBX,BXLOP2:MOVDX,CXLOP3:MOVAL,DAT1[BX]CMPAL,DAT1[BX+1]JLCONTXCHGAL,DAT1[BX+1]MOVDAT1[BX],ALCONT:INCBXLOOPLOP3MOVCX,DXMOVBX,0LOOPLOP2CODEENDSENDSTART7、内存单元X中有一个8位有符号数，按下式计算Y值，并将Y值存于其后的单元（注意数据的大小）。编写完整的汇编语言程序。DATASEGMENTXDB0F6H;-10YDW0DATAENDSCODESEGMENTASSUMECS:CODE,DS:DATASTART:MOVAX，DATAMOVDS，AXMOVAL，XMOVAH，0CMPAL，0;用AL不可用AXJLLOP1JLELOP2MOVBX，AXMOVCL，2SHLBX，CLADDBX，AXMOVAX，BXSUBAX，30JMPLOP3LOP1:MOVBL，2IMULBLADDAX，25JMPLOP3LOP2:MOVAX,0LOP3:MOVY，AXHLTCODEENDSENDSTART8、数组BUF1中有10个BCD码，求出其累加和及平均值，分别存在变量SUM和AVER中。DATASEGMENTBUF1DB34H,12H,76H,80H,01H,02H,08H,04H,78H,56HSUMDW0AVERDW0DATAENDSCODESEGMENTASSUMECS:CODE,DS:DATASTART:MOVAX,DATAMOVDS,AXLEABX,BUF1MOVCX,10CLCMOVAX,0LOP1:ADDAL,[BX]DAAJNCLOP2INCAHLOP2:INCBXLOOPLOP1LEASI,SUMMOV[SI],AXSHRAX,4LEASI,AVERMOV[SI],AXCODEENDSENDSTART9、数据块X中有8个8位无符号数，分别为记为X1、X2、…..X8,试计算Y=X1+X2+X3-X4-X5+X6-X7+X8的值，并存在内存中。DATASEGMENTXDB04H,01H,01H,01H,01H,20H,01H,01HYDW0DATAENDSCODESEGMENTASSUMECS:CODE,DS:DATASTART:MOVAX,DATAMOVDS,AXLEABX,XMOVCX,8MOVDL,11100101BCLCMOVAX,0LOP1:SHLDL,1JNCLOP2ADDAL,[BX]JNCJWEI1INCAHJWEI1:INCBXLOOPLOP1JMPLOP3LOP2:SUBAL,[BX]JNCJWEI2DECAHJWEI2:INCBXLOOPLOP1LOP3:LEASI,YMOV[SI],AXCODEENDSENDSTART10、利用调用子程序的方法，将不大于9999的一个16位二进制数转换成十进制数，以组合BCD码的形式存在2个内存单元中。DATASEGMENTXDW0A0AHYDB2DUP(0)DATAENDSCODESEGMENTASSUMECS:CODE,DS:DATASTART:MOVAX,DATAMOVDS,AXMOVAX,0CALLCHULICHULIPROCNEARPUSHAXPUSH