新高考数学二轮复习函数培优专题04 函数的解析式（含解析）

专题04函数的解析式专项突破一待定系数法1．设SKIPIF1<0为一次函数，且SKIPIF1<0．若SKIPIF1<0，则SKIPIF1<0的解析式为（

）A．SKIPIF1<0或SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．幂函数SKIPIF1<0的图象经过函数SKIPIF1<0SKIPIF1<0且SKIPIF1<0所过的定点，则SKIPIF1<0的值等于（

）A．8 B．4 C．2 D．13．已知函数SKIPIF1<0是定义在SKIPIF1<0上的增函数，且SKIPIF1<0，SKIPIF1<0，则SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．2 D．34．已知二次函数f（x）的图象经过点（-3，2），顶点是（-2，3），则函数f（x）的解析式为___________.5．已知函数SKIPIF1<0恒过定点P，点P恰好在幂函数SKIPIF1<0的图象上，则SKIPIF1<0___________.6．（1）已知SKIPIF1<0是一次函数，且SKIPIF1<0，求SKIPIF1<0；（2）已知SKIPIF1<0是二次函数，且满足SKIPIF1<0，求SKIPIF1<0.7．已知SKIPIF1<0是二次函数，且满足SKIPIF1<0，SKIPIF1<0，SKIPIF1<0.(1)求函数SKIPIF1<0的解析式；(2)当SKIPIF1<0时，表示出函数SKIPIF1<0的最小值SKIPIF1<0，并求出SKIPIF1<0的最小值.8．已知函数SKIPIF1<0为二次函数，不等式SKIPIF1<0的解集是SKIPIF1<0，且SKIPIF1<0在区间SKIPIF1<0上的最小值为SKIPIF1<0.(1)求SKIPIF1<0的解析式；(2)设函数SKIPIF1<0在SKIPIF1<0上的最大值为SKIPIF1<0，求SKIPIF1<0的表达式.9．已知一次函数SKIPIF1<0满足SKIPIF1<0，SKIPIF1<0.(1)求实数a､b的值；(2)令SKIPIF1<0，求函数SKIPIF1<0的解析式.专项突破二换元法1．设函数SKIPIF1<0，则SKIPIF1<0的表达式为（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．已知SKIPIF1<0，则SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．若SKIPIF1<0，则SKIPIF1<0的解析式为（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．若SKIPIF1<0，则SKIPIF1<0等于（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．已知SKIPIF1<0是定义域为SKIPIF1<0上的单调增函数，且对任意SKIPIF1<0，都有SKIPIF1<0，则SKIPIF1<0的值为（

）A．12 B．14 C．SKIPIF1<0 D．186．已知函数SKIPIF1<0，那么SKIPIF1<0的表达式是___________.7．已知SKIPIF1<0，则SKIPIF1<0______.8．若SKIPIF1<0，则SKIPIF1<0______．9．若函数SKIPIF1<0，则SKIPIF1<0______．10．已知定义在SKIPIF1<0上的单调函数SKIPIF1<0，若对任意SKIPIF1<0都有SKIPIF1<0，则SKIPIF1<0_____专项突破三配凑法1．已知函数SKIPIF1<0，则SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．已知函数SKIPIF1<0满足SKIPIF1<0，则SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．已知SKIPIF1<0求SKIPIF1<0=（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．若函数SKIPIF1<0满足SKIPIF1<0，则SKIPIF1<0的解析式是__________5．已知SKIPIF1<0，则SKIPIF1<0______．6．已知函数SKIPIF1<0，则函数SKIPIF1<0的解析式为SKIPIF1<0______.7．若SKIPIF1<0，则SKIPIF1<0______.8．已知函数y＝f(x)满足SKIPIF1<0，求函数y＝f(x)的解析式．专项突破四构造方程组法1．已知SKIPIF1<0，则SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．若函数SKIPIF1<0满足SKIPIF1<0，则SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．已知函数SKIPIF1<0满足SKIPIF1<0，则SKIPIF1<0___________.4．若SKIPIF1<0，则SKIPIF1<0______．5．设函数SKIPIF1<0是SKIPIF1<0→SKIPIF1<0的函数，满足对一切SKIPIF1<0，都有SKIPIF1<0，则SKIPIF1<0的解析式为SKIPIF1<0______．6．已知函数SKIPIF1<0对SKIPIF1<0的一切实数都有SKIPIF1<0，则SKIPIF1<0______．专项突破五利用奇偶性1．已知SKIPIF1<0是定义在SKIPIF1<0上的奇函数，且当SKIPIF1<0时，SKIPIF1<0，则当SKIPIF1<0时，SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．设SKIPIF1<0为奇函数，且当SKIPIF1<0时，SKIPIF1<0，则当SKIPIF1<0时，SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．已知SKIPIF1<0是定义在SKIPIF1<0上的偶函数，当SKIPIF1<0时，SKIPIF1<0，则当SKIPIF1<0时，SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．若SKIPIF1<0是定义在SKIPIF1<0的奇函数，且SKIPIF1<0是偶函数，当SKIPIF1<0时，SKIPIF1<0，则SKIPIF1<0时SKIPIF1<0的解析式为（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<05．若定义在R上的偶函数SKIPIF1<0和奇函数SKIPIF1<0满足SKIPIF1<0，则SKIPIF1<0的解析式为SKIPIF1<0___________.6．已知函数SKIPIF1<0是SKIPIF1<0上的奇函数，当SKIPIF1<0时，SKIPIF1<0