高中数学必修1全套同步练习(人教版)

高中数学必修1全套同步练习(人教版)§1.1集合的含义及其表示（1）课后训练【感受理解】1．给出下列命题(其中N为自然数集)：①N中最小的元素是1②若a∈N则-aN③若a∈N,b∈Nx212x的解可表示为（4）{1,1}，其中正确的命题个数为2．用列举法表示下列集合①小于.12的质数构成的集合；②平方等于本身的数组成的集合；|a||b|③由(a,bR)所确定的实数的集合；abyx22x1x(为小于④抛物线5的自然数)上的点组成的集合3.若方程x2-5x+6=0和方程x2-x-2=0的解为元素的集合为M，则Ma的取值可以是A，A中含有a2,2a,4组成一个集合4．由3个元素，则【思考应用5．由实数】x,x,x2,x33所组成的集合里最多有个元素6.由“x,xy,xy”组成的集合与由是否确定的？若确定，请求出来，若不确定，说明理由“0,|x|,y”组成的集合是同一个集合，.7．定义集合运算：求集合AB{zzxy(xy),xA,yB}，设集合AB.1()S1Sa9.2SSaS121a1S34SS.1.12x=a|b||c||abc||a|bcabc1abc{1,3,5,7,9}23..10{0}234123{123}{312}{112(x1)2(x2)20{x4x5}.1()7.1{2}2{310{xxx,x5xZ}{(x,y)xy6,xN*,y345{3,1,1,3,5}Ax|x2pxq0,Bx|x2pxq0.A89.10a,bN*,1()AxA,10xA11AA1234AA1.21MMM12{123}{123456}0={0}0{0}{1}{123}{12}{123}A{x|1x2}B{x|xa}AB3ABBA1}45={13x}={x2M={(x,y)|x+y<0xy>0}N={(x,y)|x<0y<0}______________A={x|x=a2B-4a+5aR}={y|y=4b+4b+3bR}261()11A={24xA={234}2BB2-5x+9}B={3x2+ax+a}C={x2+(a+1)x-3x123a,xAa,xB=CAx|2x5,Bx|m1x2m1,12.Ax|2x5,Bx|m1x2m1,().1.221()CM67U={12345}M={14}U1U{xx1,nN*}A{xx,nN*}22n2naZ,A{(x,y)axy3}(2,1)A,(1,4)A89P{xx1x3},B{xmxm1}U=RCM.MUUR,Ax|x1,Bx|xa1,CA10.12UU2,3,a22a3,A2,b,CA5,UBU{5}A{0,1}101()1.31U{1,2,3,4,5},A{1,3,5},B{2,4,5},(CA)I(C123UAIBA{x|x5,xN},B{x|x1,xN}P{y|yx22x1,xN},Q{y|yx22x1,xN}(1)PIQ;(2)PIQ{0};(3)PIQ{1};(4)PIQN45A={x|-5<x<5}B={x|-7<x<a}C={x|b<x<2}AB=CaU={1234}ABUAB(A,B)(B,A)AB{13AB(A,B)(B..P,T16PT.Ax,y|yx2,xR,Bx,y|yx,xR,AI7Px|2x5,Qx|k1xk1,P8..131()U{5},A{x|x25x60},B11.pAUB.CAUB{1,3,4,5},U12A={x|x<3}B={x|x<a}AB=AaaAB=BCACBaRR1.32A0,1,2,4,5,7,B1,3,6,8,9,C3,7,8,A12AICB1,8,CAIBUx|x8,xN,UUCAICB4,7,AB.UU3.P={y|y=x2+1xN}Q={y|y=x2+1xN}PQ=1()750ABABA3AB1AB8A={xx23x+2=0xR}B={xxAUBA,AUCC2ax+a1=0xR}.a,mxR}A{x1ax2},B{xx1},ABB9.10.A{xx22xm0}ARm1()2.1.111.1xy,yxxR,yZ;xy,y2x,xN,yR23xyxx{x|0x6}y{y|0y3}14xyxx{x|0x6}y{y|0y3}61f(x)x1.2.2xxzx[1,4]3.4.f(x)=x1x2yy3x3y(x)2xyxfxaxbf37,f51,f0,f15.1()L8.yx.f(x)2x(xR)[2,4]9.123{4,8,2}f(a1),f(2x1).1()2.1.12y1xxyx1.2..24x.x10xxy3.4.2y______________x1yx2,x1,325.6._________________________1y32xx2x21____________7.8.x21f(2x)x10,2g(x)f(x)x2f(1)f(1)f(1)f(2)f(3)32f(x)9.1x2f(x)2x21,g(x)x1.10.fg(2)gf111()132f(x)x2x21,bb12.f(x)x2x1.13.f(x)5f(x)f(a)x1xRa2.2.1.131..1f(x)2x1,x[1,2)f(x)1,x(0,12x1()2.M={x|0x2}N={y|0y3}N.().f(x)h(x)xf(x)f(0)5(2,1)f(x)3.(2,0)(3,0)h(0)34.5.f(x)=yax2byaxb(a0,b0).yyyxxxyx16.f(g(1))7.xf(x),g(x).x13x123g(x)1()f(x)ax2bxc(a0)D(s9.a.x1x1yf(x)yx10.x2,f(x)=1,x0,x0,11.1,x0.x12f(1),f(-1),ff(-1)f(a)4a3.yxxaay1212.2.1.21x2x0f(x)1f(3)=3x1x01()f(x)x21f(x1)=f(x)ff(x)781f(x)x2x1x2x5(x6)f(x2)(x6)f(x)f(3)9.f(x)f(2)3,f(2)7,f(0)3,10x21f(b)bf(x)(a,bN*)f(b)11.ax2bf(x)ax2bxcf(x)f(0)0f(x1)12xR1()x2(x1)f(x)x2(1x2)2x(x2)f(x)3x3.4.5.xyyxABBytyyytttooo(2)(1)(3)63(A)y|x1|(0x2)233yy22|x1|(0x2)(B)(C)(D)3|x1|(0x2)2y1|x1|(0x2)fx3fx12fx12x177.8.1fxxfx2f1fx1()11.MABCDAD=2aBC=aABCDBAD=45ABCDNAM=x,MN.12.f(x)Rf(xy)f(x)f(y)(1)f(0)f(1)1f()x(2)f(x)(3)f(2)pf(3)q(pq)f(36)2.1.312y12___________________________.______________________xy2xx121()1f(x).6x1f(x)4x2mx1(,2][2,)78f(x)axb20,,.1g(x)1,.91x1f(x)x0,1011.x1(,1)f(x)x(a1)x5221f(x)x12..x1()f(x)x22x82.3.1xf(x)1xyx2x14._____________.f(x)4x2mx5m[2,)f(x)(0,)f(a2a1)f(x)f(x)05.6.7.3f()4R1y32f(x)y1yf2(x)yf(x)R.2f(x)x(0,1]8.9..xyx22|x|1x24x,4xx2,x0x0f(2a2)f(a),10.11.f(x)f(x)1x2xR1()2.1.31fxxf(x)12RACBDyfxxR1aafaafaafABC[a,b][b,a]34ABCDfx[5,5]x[0,5],fx.f(x)0fxRfx2fx05f7.5.67f(x)=ax5+bx3+cx5(a,b,c)f(7)7,f7=1yx3y2x112x1()9f(x),g(x),{x|xx1,R}f(x)=____,g(x)=______.x22(x0)y0(x0)10x22(x0)2.1.32f(x)2xbb1.2.abRf(4)0f(3)f(x)ax3bx1,0yf(x)f(x)3.1a,2af(x)ax2bxc4.b________1()f(x)f(x){x|x0}2f(x)f(1)xx10Rx,yf(xy)f(x)2.1.41ABAA=RB=R+f:BA=R+B=RfDA=QB={1CA=R+B=Rf:xX32fA={246810}B={19254981ABAf:x(2x-1)Cf:x-2x-12Bf:x(2x-3)234A=NB*B={}f:ABAAC1717A3B5D93xy,x3xx,yf221()89A={a,b,c},B={1,2},ABff(a)+f(ABN*f:ABB2n+nB320A2C4D510fA={x|axb}B={y|cyd}(acd)b,ABBA2.2.114x22xx12(32)2003(32)20043b234a212ab9b2a63A2a3bB3b2aC(2a31()(x1)24(x1)43(1x)39xy2xy10xyxyyx2.2.121ABCa5a52a5aa5a6a5a5a2521x(x)2(x0)1ACB6y2y(y0)3x44(1)3(x0)x31Dx33x(x0)1()10x3,10y410xy5631316124100814a0,b05a15a5a1(a712111111(1)(1)(1)(1)(1)(1)8922162822232421111ABCD12264263226511111(x2x1)(x2x41)(xx21)42212212a3b34xa3a3b3yb3a3b3(xy)3.101()1y32x1227(A)(2,)(B)[1,)(C)(,1](D)(,2)(a2a2)x(a2a2)1xx3f(x)f(xx)f(x)f(x)xx41212121.50.2,1.30.7,(2)3135y5x161y15x2f(x)a2x3x4,g(x)a(a0,a1)x72x2x2211aba,b1812a12b1y4x22x5x[0,2]91()2.1.12yaxybxycxydxA0ab1cdB0ba1dcC1abcdD0ab1dcyaxyax12ABC()1y()x41y212x34AC1BD0.50.5yax(b1)(a0,a1)1a,b1()abc(B)2a2b(C)2a2cf(x)|2x1|f(a)f(c)f(b)8()(A)2a2c(D)2a2cy32x23x69f(x)ax(a0,a1)10f(xx2)122.1.1312201A.511B.512C.1023D.1024ABA20%960BAB80C803.20%A25%B20%C30%D15%42002200436%199254.85.1()812.25%20%0.0159650%yt12101002.3.11..1log5125=32log3=-2133log10a=-1.6994ln15=b1()210(1)3log273.4.13lga11,a__________5.log22______________3x,x1,x,x1,f(x)f(x)2x6.7.9x63x70logloglogx0x8.643f(x)(lga)x22x4lga9.3a2.3.115100(2)lg(1)log2(4725)1()1lgx2((lga3lgb)lgcx62lg23lg91(lg27lg8lg1000)lg0.3lg1.27.11112lg+log39log5125log44100log238.log6427alog9.lgalgb2lg(a2b),4bk1f(lg)_____2f(x)2(kR),10.f(lg2)0,x1()2.3.1log25log8log91.2.___________235lg4lg5lg20(lg5)2=log843log843=3.4.22(log5log0.2)(log2log0.5)245251blg2a,log103a,blog65.5alog2log82log6a336.7.3logx1,logx2,logx3logxabcabclog27a,log16.8.9.126112m2a5bm,1()lg54a,lg63b,lg84c,a,b,clg212.13.ablg(ab)(lglgalgb2x24x10a,b,clogaloga2logaloga14.cbccbbccb2.3.21f(x)log(x1)1.213f(x)log3xx11()log4log4m,n10.mnxxf(x)(log)(log)11.42222.3.2(2)log(2x1)1x1.23yl