电路分析同步习题集含简要答案

1-1-

第一1- 1-1-

R1 R1RiBCet； BetR1-1-1-1-

241- 应选

49.042W1-

4A0.5A0t1

t2 0t1cLi0.5 1st2s，cL

(t4t2)A1st2

2

t2s1- 1-1-

L1L2，CL1L

第二2- K

=6

K

=5A2-

R2- KRi

iK2-2-

(a3.733k；(b9；(c12.667；(d222-

(a)1.25

3R42-2-2-2-

V3127

2-

12-

2-3-3-3-3-3-3-3-3-3-3-3-3-3-3-4-4-4-4-

U7.3V8A23V

第三第四4-4-4-4-4-4-4-4-4-4-4-4-

16V323V5A5-

第五5-

uo4

3

mA5-

uo

R1R2R2R3RaRf(u

u)5-5-

uo

5-

uo

R2R4 5-5-

uou

(R3R4)R1RfR1R2

第六6I1m，k6

，U1m

U2m6-6-

6- 6-6-6-6-6-6-6-6-6-6-6-

22.36/26.565V8.485/45V，6/0A。3.71/15.95V，2.47/1 (5j5)A，(500j1500)VA。 6-6-6-6-

u

di1M

第七

1

U1jL1I1 ；uL2M；

7-

LLM 1 M2(b)j 1 ；(cRjL1 7-

L1L2 C

L2i 7-7-7-

I2.23/51.34A，I11.18419.34A；(2C=0.0697F7-7-7-7-7-7-7-

1.562cost1i0.8952sin103t26.565A1(a(19+j32)；(b)(200+j100)；(c)(15j48)；(d)163n58-28-2

第八AIBAIC355.92cos314t61.4V8-

UA220/0

/458-8-8-8-8-8-8-8-8-8-8-8-

(2338.3123V；(38975.91W)A8.1417.3/30179.5A(取UBC=3800V)aUm

第九9-

a2U

02k ( i(t)ImIm；9-

k1a

Umcos(k)coscos(k)ksinsin(k Umsin2

1k Umkcos(k)sinsin(k)cos k2bUm(sincos) m，Im，Im m，9- 9-9-9-

i(t)10 20.3sin100t84.3P1001W i3(t)552sin3t90A，I3

2A；(2P500W2u(t)210sint 25.48sin3t75.4VU=11.4V9-9-

9-

U2

36.1V29-9-9-

AI2i(t10+5sin2t63.4A，i(t 5sin2t63.4A2 29-9-9-9-9-9-

359.8 7.7 Up76.2V，Ul506122.5V，Ip7.22A，Io4.47

V，U V122.5V，I

V23222 232229-

7.58A200V50V(a)是；(b)

第十 1(a)Z= 1，Y 8

3

83 Z=R3 Z= jL-1

-j1 C

C(d)Z -j -j1 C

(a)T=

Z，H

1 T=

0，H 1 jC jLLM2 jL

M2

M1 1

1 1 T=M

，H=L

1

2

j 1 T 8 8 8

178 3 10-10-10-

12U11VU22V 22(1)T= 30 22

24V10-

R0.561L0.067H 4T=

3 10-10-10-10-11-

31u12e2tV1N1:N2g2:

第十一11-

，Vuc2VuL2，u(0)12.5

(0)2.5

(0)

0 11-

11-11-

iL1(0iL2(00.8Au8e-

24V11-11-

u4e-tV，u2e-tV11-11-

(a1.5s(b3s11- 11-11-11-11-11-11-

0t1 i510et0591Aki2.5et452.5etAk

t111-

11-

uc(02.5Vu66et(tV，i3et(tA11-

0.51e20t 0t2i

025+

20(t2)

2t311-

- 0.

t311-11-

i22etAL Lu(t)1et2(t)41e(t4 411- 11-11-

iL(t)15e5t(t)A,i(t) i

R2(RL)t (t)A11-

t2

t0t1t11-

2t3

第十二，u(0)6 ，12-

d

LLC

L12-

dt

R2d 2 C25 C2

i12-

dt

C u2002e103tsin103tV 412- 12-

R112-12-12-12-

CCCu20etcos2tCCu5e2t5e4tVC12-

uC

20

12

t(t)V323

3第十三313-

11e2

(s

1s

cos(sa)sin(sa)22

(6)ea(s1)cossin(s1)22。s22。(7)

s2213-

51eT2s 1e1eTTs0.41e1eT

1eT2sTseT 2Ts21eT2s2

A

e2se6ses。13-

Ts2 (1)e2t2e3t5

s2 41(3)1(t)etet

1et4e2t 1 e e2cost3sin

e2t4etcost

1te3t1e3t1e2tcos

(t)3(t)et2tsint2(t1)

1

2cos5(t) sin5(t)(t)5 2 513-13-

1220e2t2e5tV42e2tA2e6tcos8t5e6tsin8tV 13-13-13-13-13-13-13-13-13-13-13-

2418e100tV1.890.86e57t2.56e931tA1etsint(t)V25e3t14e2tV32u(t0.21et4sin0.97tV32tu3(t) sin0.072t60t3.1et1.29e055t1.78e245tV2.08e13t1.4e04tV20(t10etV 13-H(s)

113-

s23s2ete2tA，2et5e2t1.6cos2108.4A 13-

h(t)0.4et0.8e4t(t)Vus(t)50cos2t(tU

s213-

H(s 1U 5s45s21 R 13-

p1,22L

13-

H(s)2s27s2U12u(t)2e74t2

334

14e7

3340.215e03t2.2e32tu(t)4sint2e74t

33t

e7

337 70.02e03t2e32t4sintV U0U0 jCKg3g313-

H(s)

CsKg3g3

；Hj) 13-

4s219ss1s24s

19

s

2

14- 图(a)：状态变量为uC、

第十四 1u1u u iR2iLuR2R2iLi1u-1u-i uiL2

- 1 uC

CuC (a)

1

R

L

2

L 14-

L00uC1

1C1u(b)

R L1

L1 14-

1

1C2R RC3

2

1 iR1

1

C2R2

0

C3uC

i

L1 L2 14-

14- u

1u

3C

2

C22(t)iL 1iL 1 1 1

2 2Ci