明渠恒定非均匀渐变流水面线的计算-逐段试算法

（2）已知流段一端水深及两断面间的距离，求另一端的水深。计算例题某一边墙成直线收缩的矩形渠道，渠长 60m，进口宽b1为8m，出口宽b2为4m，渠底计算中间断面的水深；已知中间断面宽度b=6m，今假定其水深h为1.8m，按下A=bhχ=b+2hEs=h+αv2/2gR=A/χ0.52/3△S=△E/(i-均值J）CR=R/nv=Q/AJv2C2Rv22g确定中间断面水深h用一下表格进行水面试算时，要注意，当计算进口断面计算QbhAχRvnαv2/2g断面(m3/s)(m)(m)(m2)(m）(m）(m/s)(m)进口188216121.3331.1250.0140.0645071861.810.89.61.1251.6670.0140.141579中间1861.8511.19.71.1441.6220.0140.1340291861.8611.169.721.1481.6130.0140.1325921861.911.49.81.1631.5790.0140.1270681841.66.47.20.8892.8130.0140.403168出口1841.556.27.10.8732.9030.0140.4295981841.5670.85730.0140.4587161841.455.86.90.8413.1030.0140.490897，渠底为逆坡，i为-0.001,糙率系数n为0.014.当Q为18m3/s时，进口水深h1为2m，要求计，按下列表格进行试算试算时，要注意，当计算中间断面时，求平均 J时，是试算的各个断面的 J与进口断面的J计算，而在计算下一个断面0.5iJ平均J(J1+J2)/2i-平均JEs给定的△sCR(×10-4）（×10-4）（×10-4）（×10-4）(m)(m)86.5296-101.6903482.06450693077.2634-104.65318383.171765919-13.17176591.94157893078.1459-104.30612662.99823734-12.99823731.98402943078.3196-104.24107012.965709079-12.96570911.99259213079.0056-103.99410682.842227441-12.84222742.0270683066.0344-1018.14030111.06720409-21.06720412.0031683065.2571-1019.7927711.8934385-21.89343851.97959843064.4526-1021.66511312.82961013-22.82961011.95871563063.6196-1023.79614213.89512457-23.89512461.940896630要求计算中间断面及出口断面水深。算，而在计算下一个断面时，求平均 J时，又是下个断面各个试算断面与上个断面的 J（最用△Es 由假设计算得△s(m)-0.122928 93.32688854-0.080477 61.91415496-0.071915 55.46537392-0.037439 29.15292435-0.0239 11.34466042-0.04747 21.682