单服务排队系统MATLAB仿真程序

1、单服务台系统MATLAB真一、引言排队是日常生活中经常遇到的现象。通常，当人、物体或是信息的到达速率大于完成服务的速率时，即出现排队现象。排队越长,意味着浪费的时间越多，系统的效率也越低。在日常生活中，经常遇到排队现象，如开车上班、在超市等待结账、工厂中等待加工的工件以及待修的机器等。总之，排队现象是随处可见的。排队理论是运作管理中最重要的领域之一，它是计划、工作设计、存货控制及其他一些问题的基础。Matlab是MathWorks公司开发的科学计算软件，它以其强大的计算和绘图功能、大量稳定可靠的算法库、简洁高效的编程语言以及庞大的用户群成为数学计算工具方面的标准，几乎所有的工程计算领域，Mat

2、lab都有相应的软件工具箱。选用Matlab软件正是基于Matlab的诸多优点。二、排队模型三、仿真算法原理(1) 顾客信息初始化根据到达率入和服务率来确定每个顾客的到达时间间隔和服务时间问隔。服务间隔时间可以用负指数分布函数exprnd()来生成。由于泊松过程的时间间隔也服从负指数分布，故亦可由此函数生成顾客到达时间间隔。需要注意的是exprnd()的输入参数不是到达率入和服务率而是平均到达时间间隔1/入和平均服务时间1/。根据到达时间问隔，确定每个顾客的到达时刻.学习过C语言的人习惯于使用FOR循环来实现数值的累加，但FOR循环会引起运算复杂度的增加而在MATLABggt环境中，提供了一个

3、方便的函数cumsum()来实现累加功能读者可以直接引用对当前顾客进行初始化。第1个到达系统的顾客不需要等待就可以直接接受服务其离开时刻等于到达时刻与服务时间之和。(2) 进队出队仿真在当前顾客到达时刻，根据系统内已有的顾客数来确定是否接纳该顾客。若接纳则根据前一顾客的离开时刻来确定当前顾客的等待时间、离开时间和标志位；若拒绝，则标志位置为0.流程图如下：四、程序实现单服务台服务，服务参数M/M/1,入=，排队规则为FIFO,以分为单位，仿真时间240分钟。仿真程序代码如下咨、仿真时间Total_time=240;雍U达率与服务率lambda=;mu=;%乎均到达时间与平均服务时间arr_me

4、an=1/lambda;ser_mean=1/mu;初能到达的最大顾客数(round:四舍五入求整数)arr_num=round(Total_time*lambda*2);9倾客事件表初始化events=;%$负指数分布产生各顾客达到时间间隔events(1,:)=exprnd(arr_mean,1,arr_num);%各顾客的到达时刻等于而问间隔的象积和events(1,:)=cumsum(events(1,:);9敞负指数分布产生各顾客服务时间events(2,:)=exprnd(ser_mean,1,arr_num);%计算仿真顾客个数，即到达时刻在仿真时间内的顾客数len_sim=su

5、m(events(1,:)<=Total_time);%*%计算第1个顾客的信息%*9第1个顾客进入系统后直接接受服务，无需等待events(3,1)=0;冲离开时刻等于其到达时刻与服务时间之和events(4,1)=events(1,1)+events(2,1);%其肯定被系统接纳，此时系统内共有1个顾客，故标志位唯1events(5,1)=1;沮进入系统后，系统内已有成员序号为1member=1;%*%计算第i个顾客的信息%*fori=2:arr_num淤口果第i个顾客的到达时间超过了仿真时间，则跳出循环ifevents(1,i)>Total_timebreak;淤口果第i个顾

6、客的到达时间未超过仿真时间，则计算在其%1U达时刻系统中已有的顾客个数elsenumber=sum(events(4,member)>events(1,i);淤口果系统已满，则系统拒绝第i个顾客，其标志位置0ifnumber>=N+1events(5,i)=0;淤口果系统为空，则第i个顾客直接接受服务elseifnumber=0沮等待时间为0events(3,i)=0;冲离开时刻等于到达时刻与服务时间之和events(4,i)=events(1,i)+events(2,i);%其标志位置1events(5,i)=1;member=member,i;淤口果系统有顾客正在接受服务，且系

7、统等待队列未满，则9第i个顾客进入系统elselen_mem=length(member);沮等待币问等于队列中前一个顾客的离开时刻减去其到%4时刻events(3,i)=events(4,member(len_mem)-events(1,i);%其离开时刻等于队列中前一个顾昴的离开时刻加上其服%务时间events(4,i)=events(4,member(len_mem)+events(2,i);%S识位表示其进入系统后，系统何共有的顾客数events(5,i)=number+1;member=member,i;endendendend五、仿真结果events=number=1number=

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