C语言推箱子代码

1、#include<stdio.h>#include<stdlib.h>int i,j,steps = 0,gk = 1;char command,t,m = 0,n = 0;int map_1811,map811 = 0,0,0,0,0,0,0,0,0,0,0,1,1,1,1,0,0,0,0,0,0,0,1,0,0,1,1,1,1,1,0,0,0,1,0,0,6,0,0,4,1,0,0,0,1,3,0,2,0,0,4,1,0,0,0,1,0,0,1,1,1,1,1,0,0,0,1,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0;int

2、 map_2811 = 0,0,0,1,1,1,1,0,0,0,0,0,0,0,1,4,0,1,0,0,0,0,1,1,1,1,0,0,1,1,0,0,0,1,0,0,0,3,2,0,1,0,0,0,1,0,1,1,0,0,0,1,0,0,0,1,0,6,0,0,0,0,1,1,0,0,1,1,1,1,0,0,0,4,1,0,0,0,0,0,1,1,1,1,1,1,0,0;int map_3811 = 0,0,0,1,1,1,1,0,0,0,0,0,0,0,1,4,4,1,0,0,0,0,1,1,1,1,0,0,1,1,0,0,0,1,0,0,0,0,0,0,1,0,0,0,1,0,0,0,0

3、,0,0,1,1,0,0,1,1,1,0,1,6,2,0,1,0,0,0,0,1,0,0,3,0,0,1,0,0,0,0,1,1,1,1,1,1,1,0,0;typedef struct positionint x;int y;location;location agg3;/ 全部通过void clearance()if(mapagg1.xagg1.y = 5&&mapagg2.x + nagg2.y + m = 5&&gk =printf(" 你赢了！ n"); system("pause");exit(0); / 判断

4、是否通过void control_adopt() if(mapagg1.xagg1.y = 5&&mapagg2.x + nagg2.y + m = 5) if(gk != 3)for(i = 0;i < 8;i+)for(j = 0;j < 11;j+)mapij = map_2ij; map_2ij = map_3ij; map_1ij = mapij;gk+;steps = 0;/ 重新开始void control_reset(char reset_1) if(reset_1 = 'f') for(i = 0;i < 8;i+)for(j

5、 = 0;j < 11;j+) mapij = map_1ij;steps = 0; / 结束void control_end(char end_0) if(end_0 = 't')exit(0);/ 控制方向 + 箱子堵住陷阱void control_direction(char direction_)= 's')if(direction_ = 'd'|direction_= 'w'|direction_= 'a'|direction_if(direction_ = 'd')m = 1;if

6、(direction_ = 'a')m = -1;if(direction_ = 'w')n = -1; if(direction_ = 's')n = 1;if(agg0.x + n = agg1.x&&(agg0.y + m) = agg1.y&&mapagg1.x + nagg1.y + m != 1&&mapagg1.xagg1.y != 5)if(mapagg1.x + nagg1.y + m = 4)mapagg1.xagg1.y = 0; mapagg1.x + nagg1.y + m

7、 = 5; agg1.y = agg1.y + m; agg1.x = agg1.x + n;elset = mapagg1.x + nagg1.y + m;mapagg1.x + nagg1.y + m = mapagg1.xagg1.y; mapagg1.xagg1.y = t;agg1.y = agg1.y + m; agg1.x = agg1.x + n;/ 第二个箱子的判断条件if(agg0.x + n = agg2.x&&(agg0.y + m) = agg2.y&&mapagg2.x + nagg2.y + m != 1&&mapa

8、gg2.xagg2.y != 5)if(mapagg2.x + nagg2.y + m = 4) mapagg2.xagg2.y = 0; mapagg2.x + nagg2.y + m = 5; agg2.y = agg2.y + m; agg2.x = agg2.x + n;elset = mapagg2.x + nagg2.y + m;mapagg2.x + nagg2.y + m = mapagg2.xagg2.y; mapagg2.xagg2.y = t;agg2.y = agg2.y + m;agg2.x = agg2.x + n; if(mapagg0.x + nagg0.y +

9、 m = 0)t = mapagg0.x + nagg0.y + m;mapagg0.x + nagg0.y + m = mapagg0.xagg0.y; mapagg0.xagg0.y = t;agg0.y = agg0.y + m; agg0.x = agg0.x + n;steps+; m = 0; n = 0;/ 输出 , 寻找 1,2,3 void control_output()printf(" 关卡 %d： n",gk); printf(" 步数： %dn",steps);for(i = 0;i < 8;i+)for(j = 0;j

10、< 11;j+)if(mapij = 1) printf(" ");if(mapij = 0) printf(" ");if(mapij = 2) printf(" ");agg1.x = i; agg1.y = j; if(mapij = 3)prin tf(”O");agg0.x = i; agg0.y = j; if(mapij = 4)printf("");if(mapij = 5) printf("");if(mapij = 6) printf(" "

11、;); agg2.x = i; agg2.y = j;printf("n"); printf("w,a,s,d 控制方向， t 退出游戏， f 重新开始！ n");/ 输入指令void input_command()while(1) scanf("%c",&command);if(command = 'w'|command = 'a'|command = 's'|command = 'd'|command = 't'|command = 'f')break;main()for(i = 0;i < 8;i+)for(j = 0;j < 12;j+) map_1ij = mapij; while(1) control_