C语言程序设计教程李含光郑关胜清华大学出版社习题答案解析习题答案解析完美打印版

1、完美.格式.编辑第1章习题参考答案1 单项选择题(1) A(2) C (3) D(4) C (5) B2 填空题(1) 函数(2) 主函数(ma in)(3) printf(), scanf()第2章习题参考答案1 单项选择题1-5 CBCCC 6-10 CDCDC 11-13 DBB2 填空题(1) 1( 2) 26( 3) 6,4, 2(4) 10 , 6( 5) 3.000000(6)双精度(double ) (7) 9 (8)字母，数字，下划线(9) 13.700000(10) 11 (11) ( m/10) %10 *100+ ( m/100) *10+m%10( 12) 0(13)

2、 10,9 ,11( 15) (x<0&&y<0)|(x<0&&z<0)|(y<0|z<0)(16) double(17) x=0 (18) sqrt(fabs(a-b)/(3*(a+b)(19) sqrt(x*x+y*y)/(a+b)第3章习题参考答案1 单项选择题1-5 CCCDD 6-10 BCDBC 11-15 BCBBB 16 A2 填空题(1)用；表示结束(2) (3) y=x<0?1:x=0?0:-1(4) y%4=0&&y%100!=0|y%400=0 (5)上面未配对(6) defaul

3、t 标号(7) while , do while , for (8) do while (9)本次(10)本层3 阅读程序，指出结果(1) yes (2) *& (3) ABother (4) 28 70(5) 2, 0 (6) 8 (7) 36(8) 1 (9) 3, 1, -1 , 3, 1 , -1 (10) a=12 , y=12 (11) i=6 , k=4(12) 1 , -24.程序填空(1) x: y, u : z(2) m=n, m ! =0, m=m/10(3) t<eps ,t*n/(2*n+1), printf(“ %lfn” ,2*s)(4) m%5=0

4、 , printf(“ %d n”，k)(5) cx=getchar() , cx!=front , cx专业.资料.整理(6) double s=0 , 1.0/k , %lf(7) s>=0, s<gmin ,5 .编程题(1).#in elude <stdio.h>int mai n()double x,y;scan f("%lf", &x);if(x<1)y=x;else if(x>=1.0&& x<10) y=2*x-11;elsey=3*x-11;prin tf("%lfn",

5、y); return 0;(2) .#in elude <stdio.h>int mai n()double x,y, z,mi n;scan f("%lf%lf%lf", &x, &y,& z); if(x>y) mi n=y;elsemi n=x;if(mi n>z)mi n=z;prin tf("mi n=%lfin",mi n); return 0;(3) .#in elude <stdio.h>int mai n()int y,m,d,flag,s=0,w,i;sea nf("

6、;%d%d%d", &y,&m,& d); flag=(y%4=0&& y%100!=0|y%400=0);w=(y-1)*365+(y-1)/4-(y-1)/100+(y-1)/400)%7;for(i=1;i<=m;i+)switeh(i)ease 1:s=d;break;ease 2:s=31+d;break;ease 3:s=59+d;break;ease 4:s=90+d;break;ease 5:s=120+d;break;ease 6:s=151+d;break;ease 7:s=181+d;break;ease 8:s=2

7、12+d;break;ease 9:s=243+d;break;ease 10:s=273+d;break;ease 11:s=304+d;break;ease 12:s=334+d;break;if(flag=1 &&m>2)s=s+1;s=(w+s)%7;if(s=0)printf("星期日 n");elseprintf("星期 %dn",s);return 0;(4 )#in elude <stdio.h>int mai n()float p,r;scan f("%f",&p);if(p

8、<=10)r=p*0.1;else if(p>10&&p<=20) r=10*0.1+(p-10)*0.075;else if(p>20&&p<=40)r=10*0.1+10*0.075+(p-20)*0.055else if(p>40&&p<=60)r=10*0.1+10*0.075+20*0.05+(p- 40)*0.03;else if(p>6 0&&p<=100)r=10*0.1+10*0.075+20*0.05+20* 0.03+(p-60)*0.015;else i

9、f(p>100)r=10*0.1+10*0.075+20*0.05+20*0.03+40*0.015+(p-100)*0.01;prin tf("%fn",r);return 0;(5) #in clude <stdio.h>int mai n()char c;while(c=getchar()!='n')if(c>='a'&&c<='z')c=c-32;putchar(c);return 0;(6) #in clude<stdio.h>int mai n()int m

10、,k=2;printf(" 输入一个正整 数:n");sca nf("%d",&m);while(k<m)if(m%k=0)prin tf("%4d",k);m=m/k;elsek+;prin tf("%4dn",m);return 0;(7) #in clude<stdio.h>int mai n()int a,n, s=0,p=0,i;scanf("%d %d",&n,&a);for(i=1;i<=n ;i+)p=p*10+a;s=s+p;pr

11、in tf("%dn",s);return 0;(8) .#in clude<stdio.h>int mai n()int i,j,k;for(i=1;i<=9;i+)for(j=0;j<=9;j+) for(k=0;k<=9;k+)prin tf("%5d",100*i+10*j+k); return 0;(9) .#in clude<stdio.h>#in clude<math.h>int mai n()floata=-10,b=10,x,f1,f2,f;f1=(2*a-4)*a+3)*a)-6;

12、f2=(2*b-4)*b+3)*b)-6; dox=(a+b)/2;f=(2*x-4)*x+3)*x)-6;if(f*f1<0)b=x;f2=f;elsea=x;f1=f;while(fabs(f)>=1e-6);prin tf("%6.2fn",x);return 0;(10).#in clude<stdio.h>#in clude<math.h>int mai n()int n=2;double eps,t,s=0,x;sca nf("%lf %lf", &x, &eps); t=x;s=t;whi

13、le(fabs(t)>=eps)t=-t*(2* n-3)*x*x/(2* n-2);s=s+t/(2* n);n+;prin tf("%d,%lfn", n,s);return 0;(11).#in clude<stdio.h>int mai n()un sig ned long s,t=0,p=1; sca nf("%u", &s);while(s!=0)if(s%10)%2!=0)t=t+(s%10)*p;p=p*10;s=s/10;prin tf("%un",t);return 0;第4章习题参考答案

14、1 单项选择题1-5 DDDBD 6-10 BADCD 11-14 BDAB2 填空题(1) 2 (2)嵌套，递归(3 )全局变量，局部变量 ，(4) auto , static , register , extern(5)外部变量(6)编译 ，运行静态变量动态变量30,x+y,x-y , z+y,z-y3 阅读程序，指出结果(1) 15(2)5(3)5, 4，3(4) i=5i=2i=2i=4i=2(5) 求水仙花数(6)-5*5*5( 7)(8) 0 101 112 124. 程序填空(1) float fun (float , float)(2) x ,x*x+1(3) s=0 , a=

15、a+b5 .编程题(1 )#in clude<stdio.h>un sig nedintfun(un sig nedin t);int mai n()un sig ned int s;scan f("%u", &s);prin tf("%un",fu n(s);un sig ned int fun(un sig ned ints)un sig ned int p=0;while(s!=0)p=p+s%10;s=s/10;return 0;return p;(2 )#in clude<stdio.h>#in clude<

16、;stdlib.h>#in clude<math.h>voidf1(float,float,float,float);voidf2(float,float,float,float);voidf3(float,float,float,float);i nt mai n()float a,b,c,d;scan f("%f %f %f",&a,&b,&c); if(a=0)printf(”不是一元二次方程n");exit(0);d=b*b-4*a*c;if(d>0) f1(a,b,c,d);else if(d=0)f2(a

17、,b,c,d);elsef3(a,b,c,d);return 0;void f1(float a,float b,floatc,float d)float x1,x2;prin tf("%.2f ,%.2fn",x1,x2);void f2(float a,float b,float c,float d)float x1,x2;x1=-b/(2*a);x2=-b/(2*a);prin tf("%.2f ,%.2fn",x1,x2);void f3(float a,float b,float c,float d)float x1,x2;x1=-b/(2*a

18、); x2=sqrt(-d)/(2*a);prin tf("%.2f+i*%.2fn",x1,x2)5prin tf("%.2f-i*%.2fn",x1,x2)5(3).#in clude<stdio.h>double p(i nt,double);int mai n()int n;double x;dox1= (-b+sqrt(d)/(2*a); x2=(-b-sqrt(d)/(2*a);scan f("%d", &n);while( * 0);scan f("%lf", &x);pr

19、in tf("%lfn",p( n,x);return 0;double p(i nt n, double x)double pn;if(n=0)pn=1;else if(n=1)pn=x;elsepn=(2* n-1)*x*p( n-1,x)-( n-1)* p(n-2,x)/n;return pn;(4).#in clude<stdio.h>#defi ne RATE 0.053double fun( float);void display(float,i nt);int mai n()float dep;int seas on;scan f("%

20、f %d", &dep, &seaso n);display(dep,seas on);return 0;double fu n(float d)return d*RATE;void display(float d,i nt s)int i;prin tf(" 季度 利 余额n");printf("n");for(i=1;i<=s;i+)prin tf("%-4d%-.2f%-.2fn",i,fu n( d),fu n(d)*i+d);printf("n");(5).#in clud

21、e<stdio.h>double fun( void);int mai n()prin tf("%lfn",fu n();return 0;double fun( void)double s=0;int n=1;while(double)(2* n-1)/(2* n)*(2* n)>1e-4)s=s+(double)(2* n-1)/(2* n)*(2*n);n+;return s;(6).#in clude<stdio.h>int fun (i nt);int mai n()int w;scan f("%d"，&w

22、);m=m/10;p=p*10;n+;return w%p;第5章习题参考答案1、选择题：1-5 C (B C) BBA 6-8 DDB2、填空题(1)0，9( 2)in tArray1000(3)运算符sizeofprin tf("%dn",fu n(w); return 0;int fun (i nt w)int n=1,p=1,m;m=w;while(m>10)float realArray100,charstrArray16,i nt(4)6字节3、阅读程序，写出下面程序的运行结果(1) aabbcc dd(2) abcd(3) ahAMa(4)0010(5)

23、 1 3 4 5(6)This is the title.Name 1 is Rosali ndaName 2 is ZekeThe biggest n ame alpabetically is ZekeBoth n ames are Rosali nda Zeke(7)000000 000123456 70256810 748140369121518 :21048121620242805101520177 303506121824303642071421283542494、程序填空(1) aij != aji , 1(2) 0, ai < amini , maxi = i , amax

24、i = aminibi+(3) int a, int b, bi = ai, -999, arraycopy(a,b),(4) a<sizeof(ch), if5、编程题(1)#in clude<stdio.h>int mai n ( )1 int a34 = 0, 2,9,7,5,13,6,8,27,11,1,3;int i,j,temp;for(i=0,j=0;j<4;j+)temp = a2-ij;a2-ij = aij;aij = temp;for(i=0;i<3;i+)for(j=0;j<4;j+)prin tf("%3d",a

25、ij);prin tf("n ”);return 0;(2)#in clude<stdio.h> int mai n ( )static int a66;int i,j,t=1;for(i=0;i<6;i+)t = i+1;for(j=0;j<i+1;j+)aij = t-;for(i=0;i<6;i+)for(j=0;j<6;j+)prin tf("%3d",aij);prin tf("n ”);return 0;(3)#in elude <stdio.h>#defi ne M 3#defi ne N 4

26、#defi ne R 5int mai n( )static int aMN,bNR,cMR; int i,j,k;2prin tf("Matrix a:n");for( i = 0; i < M; i+ )for( j = 0; j < N; j+ )scanf( "%d",&aij);prin tf("Matrix b:n");for( i = 0; i < N; i+ )for( j = 0; j < R; j+ )scanf( "%d",&bij);for( i =

27、0; i < M; i + )for( j = 0; j < N; j+ )for( k = 0; k < R; k+)cik += aij*bjk;for( i = 0; i < M; i+ )for( j = 0; j < R; j+ )prin tf( "%3d",cij);prin tf("n");return 0;(4)#in elude <stdio.h>#defi ne M 5int mai n( )static int aM;int i,max = -1,min = 100,maxi,mini,t

28、emp;for( i = 0; i < M; i+ )scan f( "%d",&ai ); 099间的值for( i = 0; i < M; i+ )if( max < ai )max = ai;maxi = i;if( min > ai )min = ai;mini = i;temp = amaxi;amaxi = ami ni;ami ni = temp;for( i = 0; i < M; i+ )prin tf( "%3d",ai);return 0;3 (5)#in clude <stdio.h&g

29、t;#defi ne M 3#defi ne N 4int mai n( )static int aMN;int max = -1,sumcol=0,sumrow=0; int i,j,maxi,col;for( i = 0; i < M; i+ )sumrow = 0;for( j = 0; j < N; j+ )scan f( "%d",&aij);sumrow += aij;if ( max < sumrow )max = sumrow;maxi = i;printf("which col sum will be caculated

30、?(>O)");scan f("%d", &col);for( i = 0; i < M; i + )sumcol += aicol-1;prin tf("The %dth row's sum is max, max=%dn",maxi+1,max);printf("The %dth column's sum=%dn",col,sumcol); return 0;(6)#in clude <stdio.h>#defi ne M 81int mai n( )static char

31、 strM;int i,co unt = 0;char ch;gets(str);fflush(stdi n); /清空输入缓冲区，以便读入字符数据prin tf("Which character will be fou nd?");ch = getchar();for( i = 0; i < strle n(str); i+ )if( ch = stri)coun t+;prin tf( "The nu mber of character '%c' is %dn ”,ch,co unt );4 return 0;(7)#in clude &

32、lt;stdio.h>#in elude <stdlib.h>#defi ne N 10/同学人数#defi ne M 5/课程数void en ter_scores(void);void sort_scores(i nt scoreM, i nt averageN3);void disp_scores(i nt scoreM);void histogram(i nt n, int scoreM);void prin tchar(i nt n);static int scoreNM;3列为均static int averN3; /第1列为均值，第2列原始顺序，第值逆序int

33、main()int course;en ter_scores();prin tf("n=Ori ngenal Score Start=n");disp_scores(score);prin tf("n=Ori ngenal Score En d=n “)；prin tf("n=Sorted Score Start=n");sort_scores(score,aver);prin tf("n=Sorted Score En d=n");printf("nWhich class will be statisticed?

34、n");scan f("%d", &course);histogram(course, score);system("Pause");return 0;/*输入成绩*/void en ter_scores()int i, j;for(i=0; i<N; i+) for(j=0; j<M; j+)scan f("%d", &scoreij);averi0 += scoreij;for( i = 0; i < N; i+ )for ( j = 1; j < 3; j+ )完美.格式.编辑5

35、 averij = i;/*成绩排序 */void sort_scores(i nt scoreM, i nt averageN3)int i,j,t;int temp,temp in dex;for( i = 0; i < N - 1; i+ )for( j = 0; j < N - 1 - i; j+ )if ( averagej0 < averagej+10)temp = averagej0;averagej0 = averagej+10;averagej+10 = temp;temp in dex = averagej2;averagej2 = averagej+12

36、;averagej+12 = temp in dex;prin tf("nScore1 Score2 Score3 Score4 Score5n");for( i = 0; i < N; i+ )t = averagei2;for( j = 0;j < M; j+ )prin tf("%8d", scoretj);prin tf("n ”);/*输出成绩*/void disp_scores(i nt scoreM)int i, j;prin tf("nScorel Score2 Score3 Score4 Score5n&

37、quot;);for( i = 0; i < N; i+ )for( j = 0;j < M; j+ )prin tf("%8d", scoreij);专业资料整理完美.格式.编辑专业.资料.整理prin tf("n");void prin tchar(i nt n)6 int i;for (i = 0; i < n; +i) putchar('*');void histogram(i nt course, int scoreM)int i,temp;int segs 5 = 0;int scN;for( i = 0;

38、i < N; i+ )sci = scoreicourse;for (i = 0; i < N; i+)/*temp = (in t)sci/10;segs temp<6?0:temp-5+; /*prin tf("nSegme nt Number' n");for (i = 0; i < 5; i+) /*printf("<%3d: %5d| ", (i+1)*10+50, segsi);prin tchar(segsi);putchar('n');putchar('n');(8)#

39、in clude <stdio.h>统计各分段人数*/成绩/10,将成绩分段*/输出直方图，每段的人数 */#defi ne M 81int main()static char strM; int i,co unt = 0;char ch = 0;gets(str);for（ i = 0; i < strle n（str）; i+ ）if（ ch < stri）ch = stri;for（ i = 0; i < strle n（str）; i+ ）if（ ch = stri）coun t+;printf（” max = '%c' ,co unt =

40、 %dn ”,ch,co unt ）; return 0;7第6章习题参考答案1、选择题：1-5 BBDDA 6-10 CCABD 11-15 CBCDA 16 A2、填空题a0,a3(1) 常量，变量(2) 指针(3) 2 (4) 12, 12 (5)3、阅读程序，写出下面程序的运行结果（1）5（2）6（3）abcdefglkjih（4）976531（5）5,9（6）2,4,5,7,6,0,11,9,7,3,（7）string_a=l am a teacher.stri ng_b=You are a stude nt.stri ng_a=l am a teacher.stri ng_b=l

41、am a teacher.4、程序填空（1）*p != '0', *p-'0', j（2）i <strlen（str）,戸,k+1（3）a+i, （char）（n%10） + 'O'（4）*pk = i, a,n,i+1,pk（5）s1+, *s2, s仁p5、编程题(1)#in elude <stdio.h>int mai n()int a=3,b=7,c=2;int *ptra = & a,*ptrb = & b,*ptrc = &c;int temp;prin tf("a=%d,b=%d,

42、c=%dn",a,b,c);prin tf("*ptra=%d,*ptrb=%d,*ptrc=%dn",*ptra,*ptrb,*ptrc);if ( *ptra > *ptrb )temp = *ptra;*ptra = *ptrb;1 *ptrb = temp;if ( *ptra > *ptrc )temp = *ptra;*ptra = *ptrc;*ptrc = temp;if ( *ptrb > *ptrc )temp = *ptrb;*ptrb = *ptrc;*ptrc = temp;prin tf("a=%d,b=%d

43、,c=%dn",a,b,c);prin tf("*ptra=%d,*ptrb=%d,*ptrc=%dn",*ptra,*ptrb,*ptrc); return 0;(2)#in clude <stdio.h>#in clude <stdlib.h>void in putdata(i nt a,i nt n);void process(i nt a,i nt n);void outputdata(i nt a,i nt n);int mai n()int a10, n=10;in putdata(a, n);outputdata(a, n);

44、process(a ,n);outputdata(a, n);system("Pause");return 0;void in putdata(i nt a,i nt n) 099之间的数int i;for( i = 0; i < n; i+ )scan f("%d",a+i);void outputdata(i nt *ptr,i nt n)int i;2printf("n=OutPut Data Start=n");for( i = 0; i < n; i+ )prin tf("%4d",*ptr+

45、);prin tf("n=OutPut Data En d=n"); void process(i nt *ptr,i nt n)int i,maxi,mini;int max=-1, min=101;for( i = 0; i < n; i+ )if ( max < *(ptr+i)max = *(ptr+i);maxi= i;if ( min > *(ptr+i)min = ptri;mi ni= i;if ( mini != 0)i = ptrO;ptrO = ptrmi ni;ptrmi ni = i;if (maxi != n-1)i = ptr

46、 n-1;ptr n-1 = ptrmaxi;ptrmaxi = i;if (maxi = 0 && mini = n-1)i = ptrmaxi;ptrmaxi = ptrmi ni;ptrmi ni = i;(3)#in clude<stdio.h>3int strLe ngth (char *);int mai n()static char str81;gets(str);printf("string "%s" length:%3dn",str,strLength(str); system("Pause&quo

47、t;);return 0;int strLe ngth (char *s)char *p=s;while (*p) p+ ;return (p-s);(4)#in clude <stdio.h>#defi ne M 3#defi ne N 4void Transpose (int (*a)N,int (*T)M);int main()static int aMN,TNM;int i,j;for( i = 0; i < M; i+ )for( j = 0; j < N; j+ )scanf( "%d",&aij);prin tf("n

48、=Ori nginal Matrix Start=n “);for( i = 0; i < M; i + )for( j = 0; j < N; j+ )prin tf( "%4d",aij);prin tf("n ”);prin tf("n=Ori nginal Matrix En d=n");Tran spose(a, T);printf("n=Transpose Matrix Start=n");for( i = 0; i < N; i + )for( j = 0; j < M; j+ )pri

49、n tf( "%4d",Tij);prin tf("n ”);4 prin tf("n=Tra nspose Matrix En d=n"); return 0;void Tran spose (in t (*a)N,i nt (*T)M)int i,j;for( i = 0; i < N; i+ )for( j =0; j < M; j+ )Tij = aji;(5)#in clude <stdio.h>int mai n()static char source81,target81; int result;gets(

50、source);gets(target);result = Strcmp(source,target);if (result)if( result < 0 )prin tf("%s < %sn ",source,target); elseprin tf("%s > %sn ",source,target); elseprin tf("%s = %sn",source,target); return 0;int Strcmp(char *s,char *t)while (*s && *t &&a

51、mp; (*s = *t)s+;t+;return *s - *t;(6)#in clude <stdio.h>5#defi ne M 5#defi ne N 3int sum (int *a)int mai n()static int aMN;int i,j;for( i = 0; i < M; i+ )for( j = 0; j < N; j+ )scan f（ "%d",&aij）;for（ i = 0; i < M; i + ）printf（"Row %d sum: %3dn", i, sum（ai）;ret

52、urn 0;int sum （int *ptr）int i,result = 0;for（ i = 0; i < N; i+ ）result += *（ptr+i）;return result; 6第7章习题答案1、选择题：1-5 CCDBA 6-10 CBADB 11-13 DDA2、判断题1-5 xWxV6-10xVxW第8章习题答案1、选择题：1-5 CDAAD 6-8 CDB2、填空题（1）.（成员域访问运算符），-（成员域间接访问运算符）（2）4, 6.0（3）enum（4）typedef（5）<person+3, old=p->age, q->name,q-

53、>age3、阅读程序，写出下面程序的运行结果（1）p!=NULL, c+, p-> next（2）p1- >n ext, p1- >n ext, p1- >n ext4、程序阅读题（1）7,3（2）zhangping 20（3）Li:3Zha ng:3Wan g:25 .编程题#in elude <stdio.h> #in elude <stdlib.h> #defi ne N 10/*#defi ne M 3/*struct stu /* char n ame15; char nu m6; float scoreM;学生人数*/ 课程数*

54、/定义结构体类型*/float aver; stude ntN; /* 说明结构体变量 */ struct stu fin dmax(struct stu stude nt);void in put(struct stu stude nt); void output(struct stu stude nt); int mai n()struct stu temp;in put(stude nt);output(stude nt);temp = fin dmax(stude nt);prin tf("Max is:n ”);prin tf("%15s%8s%7.2f%7.2f

55、%7.2f%7.2f',temp. name,temp. num, 1temp.score0,temp.score1,temp.score2,temp.aver/M);system("Pause");return 0;struct stu fin dmax(struct stu stude nt)float max = 0.0;int i,maxi;for(i=0; i<N; i+)if(max < stude nti.aver)max = stude nti.aver; maxi = i;retur n stude ntmaxi;void in put(struct stu stude nt)int i,j;prin tf("i n