版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领
文档简介
1、140套模拟试题的简单应用和综合应用的答案一:2(1): index n n+2 n f12(2): s s,s1 str(n) 3:private sub c1_click() dim x as integer x = 17999 do while x 3:dim i as integer, j as integer, n as integer for i = 1 to 7 for j = 1 to 7 if i = 1 or i = 7 or j = 1 or j = 7 then sum = sum + a(i, j) if a(i, j) mod 7 = 0 then n = n +
2、1 end if next j next i lblfirst.caption = str(n)lblsecond.caption = str(sum)三:2(1): or num 2(2):avg is=85 is=60 end select n-13:dim b(20) as single, i as integer, j as integer dim max as integer140套模拟试题的简单应用和综合应用的答案一:2(1): index n n+2 n f12(2): s s,s1 str(n) 3:private sub c1_click() dim x as integer
3、 x = 17999 do while x 3:dim i as integer, j as integer, n as integer for i = 1 to 7 for j = 1 to 7 if i = 1 or i = 7 or j = 1 or j = 7 then sum = sum + a(i, j) if a(i, j) mod 7 = 0 then n = n + 1 end if next j next i lblfirst.caption = str(n)lblsecond.caption = str(sum)三:2(1): or num 2(2):avg is=85
4、is=60 end select n-13:dim b(20) as single, i as integer, j as integer dim max as integer140套模拟试题的简单应用和综合应用的答案一:2(1): index n n+2 n f12(2): s s,s1 str(n) 3:private sub c1_click() dim x as integer x = 17999 do while x 3:dim i as integer, j as integer, n as integer for i = 1 to 7 for j = 1 to 7 if i =
5、1 or i = 7 or j = 1 or j = 7 then sum = sum + a(i, j) if a(i, j) mod 7 = 0 then n = n + 1 end if next j next i lblfirst.caption = str(n)lblsecond.caption = str(sum)三:2(1): or num 2(2):avg is=85 is=60 end select n-13:dim b(20) as single, i as integer, j as integer dim max as integer140套模拟试题的简单应用和综合应用
6、的答案一:2(1): index n n+2 n f12(2): s s,s1 str(n) 3:private sub c1_click() dim x as integer x = 17999 do while x 3:dim i as integer, j as integer, n as integer for i = 1 to 7 for j = 1 to 7 if i = 1 or i = 7 or j = 1 or j = 7 then sum = sum + a(i, j) if a(i, j) mod 7 = 0 then n = n + 1 end if next j ne
7、xt i lblfirst.caption = str(n)lblsecond.caption = str(sum)三:2(1): or num 2(2):avg is=85 is=60 end select n-13:dim b(20) as single, i as integer, j as integer dim max as integer140套模拟试题的简单应用和综合应用的答案一:2(1): index n n+2 n f12(2): s s,s1 str(n) 3:private sub c1_click() dim x as integer x = 17999 do whil
8、e x 3:dim i as integer, j as integer, n as integer for i = 1 to 7 for j = 1 to 7 if i = 1 or i = 7 or j = 1 or j = 7 then sum = sum + a(i, j) if a(i, j) mod 7 = 0 then n = n + 1 end if next j next i lblfirst.caption = str(n)lblsecond.caption = str(sum)三:2(1): or num 2(2):avg is=85 is=60 end select n
9、-13:dim b(20) as single, i as integer, j as integer dim max as integer140套模拟试题的简单应用和综合应用的答案一:2(1): index n n+2 n f12(2): s s,s1 str(n) 3:private sub c1_click() dim x as integer x = 17999 do while x 3:dim i as integer, j as integer, n as integer for i = 1 to 7 for j = 1 to 7 if i = 1 or i = 7 or j =
10、1 or j = 7 then sum = sum + a(i, j) if a(i, j) mod 7 = 0 then n = n + 1 end if next j next i lblfirst.caption = str(n)lblsecond.caption = str(sum)三:2(1): or num 2(2):avg is=85 is=60 end select n-13:dim b(20) as single, i as integer, j as integer dim max as integer140套模拟试题的简单应用和综合应用的答案一:2(1): index n
11、 n+2 n f12(2): s s,s1 str(n) 3:private sub c1_click() dim x as integer x = 17999 do while x 3:dim i as integer, j as integer, n as integer for i = 1 to 7 for j = 1 to 7 if i = 1 or i = 7 or j = 1 or j = 7 then sum = sum + a(i, j) if a(i, j) mod 7 = 0 then n = n + 1 end if next j next i lblfirst.capt
12、ion = str(n)lblsecond.caption = str(sum)三:2(1): or num 2(2):avg is=85 is=60 end select n-13:dim b(20) as single, i as integer, j as integer dim max as integer140套模拟试题的简单应用和综合应用的答案一:2(1): index n n+2 n f12(2): s s,s1 str(n) 3:private sub c1_click() dim x as integer x = 17999 do while x 3:dim i as int
13、eger, j as integer, n as integer for i = 1 to 7 for j = 1 to 7 if i = 1 or i = 7 or j = 1 or j = 7 then sum = sum + a(i, j) if a(i, j) mod 7 = 0 then n = n + 1 end if next j next i lblfirst.caption = str(n)lblsecond.caption = str(sum)三:2(1): or num 2(2):avg is=85 is=60 end select n-13:dim b(20) as s
14、ingle, i as integer, j as integer dim max as integerfor i = 1 to 20 for j = 1 to 5 b(i) = b(i) + a(i, j) next j b(i) = b(i) / 5 next i max = b(1) for i = 2 to 20 if max b(j) then t = b(i) b(i) = b(j) b(j) = t end if next j next i五:2(1): x y2(2):list1,list2 l1.text l1.listindex list1.listcount-13:for
15、 i = 1 to n for j = 1 to n if i = j or i + j = 8 then if a(i, j) mod 3 = 0 then counter = counter + 1 end if if i = j then sum = sum + a(i, j) next j next ifor i = 1 to 20 for j = 1 to 5 b(i) = b(i) + a(i, j) next j b(i) = b(i) / 5 next i max = b(1) for i = 2 to 20 if max b(j) then t = b(i) b(i) = b
16、(j) b(j) = t end if next j next i五:2(1): x y2(2):list1,list2 l1.text l1.listindex list1.listcount-13:for i = 1 to n for j = 1 to n if i = j or i + j = 8 then if a(i, j) mod 3 = 0 then counter = counter + 1 end if if i = j then sum = sum + a(i, j) next j next ifor i = 1 to 20 for j = 1 to 5 b(i) = b(
17、i) + a(i, j) next j b(i) = b(i) / 5 next i max = b(1) for i = 2 to 20 if max b(j) then t = b(i) b(i) = b(j) b(j) = t end if next j next i五:2(1): x y2(2):list1,list2 l1.text l1.listindex list1.listcount-13:for i = 1 to n for j = 1 to n if i = j or i + j = 8 then if a(i, j) mod 3 = 0 then counter = co
18、unter + 1 end if if i = j then sum = sum + a(i, j) next j next ifor i = 1 to 20 for j = 1 to 5 b(i) = b(i) + a(i, j) next j b(i) = b(i) / 5 next i max = b(1) for i = 2 to 20 if max b(j) then t = b(i) b(i) = b(j) b(j) = t end if next j next i五:2(1): x y2(2):list1,list2 l1.text l1.listindex list1.list
19、count-13:for i = 1 to n for j = 1 to n if i = j or i + j = 8 then if a(i, j) mod 3 = 0 then counter = counter + 1 end if if i = j then sum = sum + a(i, j) next j next ifor i = 1 to 20 for j = 1 to 5 b(i) = b(i) + a(i, j) next j b(i) = b(i) / 5 next i max = b(1) for i = 2 to 20 if max b(j) then t = b
20、(i) b(i) = b(j) b(j) = t end if next j next i五:2(1): x y2(2):list1,list2 l1.text l1.listindex list1.listcount-13:for i = 1 to n for j = 1 to n if i = j or i + j = 8 then if a(i, j) mod 3 = 0 then counter = counter + 1 end if if i = j then sum = sum + a(i, j) next j next ifor i = 1 to 20 for j = 1 to
21、 5 b(i) = b(i) + a(i, j) next j b(i) = b(i) / 5 next i max = b(1) for i = 2 to 20 if max b(j) then t = b(i) b(i) = b(j) b(j) = t end if next j next i五:2(1): x y2(2):list1,list2 l1.text l1.listindex list1.listcount-13:for i = 1 to n for j = 1 to n if i = j or i + j = 8 then if a(i, j) mod 3 = 0 then
22、counter = counter + 1 end if if i = j then sum = sum + a(i, j) next j next ifor i = 1 to 20 for j = 1 to 5 b(i) = b(i) + a(i, j) next j b(i) = b(i) / 5 next i max = b(1) for i = 2 to 20 if max b(j) then t = b(i) b(i) = b(j) b(j) = t end if next j next i五:2(1): x y2(2):list1,list2 l1.text l1.listinde
23、x list1.listcount-13:for i = 1 to n for j = 1 to n if i = j or i + j = 8 then if a(i, j) mod 3 = 0 then counter = counter + 1 end if if i = j then sum = sum + a(i, j) next j next ifor i = 1 to 20 for j = 1 to 5 b(i) = b(i) + a(i, j) next j b(i) = b(i) / 5 next i max = b(1) for i = 2 to 20 if max b(j
24、) then t = b(i) b(i) = b(j) b(j) = t end if next j next i五:2(1): x b(i) then min = b(i) next i label3.caption = str(n) label4.caption = str(min)八:2(1):len asc b 2 x(i).caption2(2):la.listcount la la3: eof(1) str(a(i)dim i as integer, j as integer, t as integerfor i = 1 to 9 for j = i + 1 to 10 if a(
25、i) a(j) then lblfirst.caption = str(counter)lblsecond.caption = str(sum)六:2(1): 2 true flag2(2): 0 sellength t text2.text3:for k = 1 to 100 for i = 2 to a(k) - 1 if a(k) mod i = 0 then exit for next i if i = a(k) then num = num + 1 b(num) = a(k) end if next k七:2(1):true height false2(2):tmp*a tmp xn
26、(t,i) str(z)3:dim i as integer, min as integer dim b(40) as integer, n as integer for i = 1 to 40 if prime(arr(i) then n = n + 1 b(n) = arr(i) end if next i min = b(1) for i = 2 to n if min b(i) then min = b(i) next i label3.caption = str(n) label4.caption = str(min)八:2(1):len asc b 2 x(i).caption2(2):la.listcount la la3: eof(1) str(a(i)dim i as integer, j as integer, t as integerfor i = 1 to 9 for j = i + 1 to 1
温馨提示
- 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
- 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
- 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
- 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
- 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
- 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
- 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
最新文档
- 计算机科学与技术专业职业生涯规划书
- 拉脱维亚语专业职业生涯规划书
- 临床 瘢痕按摩 实操实训|手把手教学操作指南
- 【新情境新趋势】教科版科学三年级下册学科素养评价卷(原卷)
- 教育机构教师培训课程设计实施标准方案
- 语言学习方法与应用手册
- 公共场所治安事情紧急处置预案
- 筑牢防线防溺水于未然小学六年级主题班会课件
- 物联网技术在企业信息化管理中的应用指南
- 2026年员工培训与发展计划声明8篇
- 2026年营养师《公共营养》测试卷(含答案)专项训练
- 2026年甘肃省三支一扶招聘考试(1800人)考试参考题库及答案详解
- (2026年)检验检测机构资质认定“一单一库”的学习与解读(2026年实施)课件
- 24J113-1 内隔墙-轻质条板(一)
- 花瓶墩专项施工方案
- 药品生产验证指南
- GB/T 3003-2017耐火纤维及制品
- GB/T 30008-2013节能型船舶能效设计指数基准线值
- GB/T 20303.1-2016起重机司机室和控制站第1部分:总则
- GB 12983-2004国旗颜色标准样品
- 2023年石柱土家族自治县(中小学、幼儿园)教师招聘笔试题库及答案解析
评论
0/150
提交评论